1918 — Page 310

Blue Books 香港計冊 All AI Reviewed

The user wants me to proofread OCR output of a historical table showing daily average prisoners by month from 1909-1918. The OCR is messy with many errors. I need to reconstruct this as a proper Markdown table.

Let me analyze the structure:

  • Title: "STATEMENT of the DAILY AVERAGE of PRISONERS for each Month of the Year, from 1909 to 1918."
  • Columns: Months, then for each year 1909-1918, three categories: E (Europeans), I (Indians), C (Chinese)
  • The data appears to be monthly averages for each category per year
  • There's a TOTAL row and AVERAGE row at the bottom
  • Legend: E. Europeans, I.=Indians, C. Chinese

The OCR has many issues:

  • Misaligned columns
  • Garbled characters (ㄧ, =, *, ¿, LA, Co, H, →, ↓, ຕ, تت, ४, B, Nil, انت, ન, etc.)
  • Numbers split across lines
  • Missing values
  • The header row is messy

I need to reconstruct the table logically. Let me parse the data row by row.

First, the header shows years 1909 to 1918, each with E, I, C columns. That's 10 years × 3 = 30 data columns plus Month column = 31 columns total.

But the OCR shows a compressed header: "E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C." for 10 years.

Then the data rows for each month.

Let me try to reconstruct each month's data by year and category.

I'll go month by month, year by year.

January:

1909: E=6, I=9, C=512

1910: E=12, I=14, C=50%? Wait "50%" likely 501 or 507? The OCR says "50%" but probably 501 or 507. Looking at pattern, Chinese numbers are around 500-700. "50%" might be "501" or "507". But next year 1911: E=13, I=16, C=526. 1912: E=7, I=9, C=637. 1913: E=13, I=10, C=723. 1914: E=15, I=12, C=586. 1915: E=10, I=15, C=546. 1916: E=5, I=13, C=602. 1917: E=3, I=50? Wait "50" then "601" - maybe E=3, I=5, C=601? But "50" and "601" on same line? The OCR: "3 50 601". Could be E=3, I=5, C=601? But 50 seems high for Indians. Maybe "5 0" but OCR merged. 1918: E=5, I=13, C=583.

Let me look at the raw OCR lines for January:

"January,

6

9 512

12

14

50%

13

16

526

7

9

637

13 10

723

15 12

586

10

15

546

5

13

602

3

50

601

5 13

583"

This appears to be a single column of numbers. But they should be grouped by year: each year has 3 numbers (E, I, C). 10 years = 30 numbers. Let's count:

1.6, 2.9, 3.512, 4.12, 5.14, 6.50%, 7.13, 8.16, 9.526, 10.7, 11.9, 12.637, 13.13, 14.10, 15.723, 16.15, 17.12, 18.586, 19.10, 20.15, 21.546, 22.5, 23.13, 24.602, 25.3, 26.50, 27.601, 28.5, 29.13, 30.583. That's 30 numbers. Good.

So grouping by 3:

1909: 6, 9, 512

1910: 12, 14, 50% → 50% likely 501 or 507? Could be 501 (since 50% might be OCR for 501 with % as smudge). Or 507. Let's see other years: Chinese averages range 489-762. 501 plausible. I'll use 501 but note uncertainty. Actually "50%" could be "501" where 1 looks like %. I'll assume 501.

1911: 13, 16, 526

1912: 7, 9, 637

1913: 13, 10, 723

1914: 15, 12, 586

1915: 10, 15, 546

1916: 5, 13, 602

1917: 3, 50, 601 → 50 for Indians? That's an outlier. Other years Indians are 9-18. 50 seems wrong. Could be "5 0" but OCR merged. Or maybe "5 0" is two numbers? But we need exactly 3 per year. 3, 50, 601. If 50 is actually 5 and 0? But then we'd have 4 numbers. Perhaps the OCR misread "5 0" as "50". But the next year starts with 5,13,583. So 1917: E=3, I=5, C=601? But then the "0" is extra. Or maybe 1917: E=3, I=5, C=601 and the "0" is a stray. The line "3 50 601" might be "3 5 0 601"? No. Let's look at the original OCR: "3 50 601". Could be "3 5 0 601" but that's 4 numbers. Alternatively, maybe the Chinese for 1917 is 601, Indians 5, Europeans 3. The "0" might be a misread of something else. I'll assume Indians=5, Chinese=601. But then the total count of numbers is 30, so 50 must be one number. If Indians=50, that's huge. Let's check the TOTAL row later to verify. For now, I'll put 50 but flag. Actually, looking at the AVERAGE row: for 1917, average Europeans=6, Indians=11, Chinese=621. If January Indians=50, that would skew average. But average is over 12 months. 50 would raise average significantly. The average Indians for 1917 is 11. So January 50 unlikely. Probably 5. So I'll correct to 5. The OCR "50" likely "5 0" but the 0 is stray or part of next? But next is 601. Hmm.

Maybe the data for 1917 is: E=3, I=5, C=601. The "0" is a scanning artifact. I'll go with that.

1918: 5, 13, 583.

February:

OCR: "February,

5

12 514

11

18

523

16

522

8

12 665

16 11

706

15 12

593

*

[1

676

3

11

=

579

2 7

582

5

10

568"

Numbers: 5,12,514,11,18,ㄧ,523,16,522,8,12,665,16,11,706,15,12,593,,[1,676,3,11,=,579,2,7,582,5,10,568. That's 30 numbers? Let's count: 1.5,2.12,3.514,4.11,5.18,6.ㄧ,7.523,8.16,9.522,10.8,11.12,12.665,13.16,14.11,15.706,16.15,17.12,18.593,19.,20.[1,21.676,22.3,23.11,24.=,25.579,26.2,27.7,28.582,29.5,30.10,31.568. That's 31. One extra. The and [1 and = are garbage. Probably the numbers for 1914: after 1913 (16,11,706), 1914: 15,12,593. Then 1915: maybe 8,12,676? But we have , [1, 676. Could be 8,11,676? But 8 and 12 already used? Let's step through years.

We have 10 years: 1909-1918.

Group every 3:

  1. 5,12,514 → 1909
  2. 11,18,ㄧ → 1910: ㄧ likely 1? Or 523? But 523 is next. Actually "ㄧ 523" might be one number 1523? No, Chinese around 500. ㄧ might be a stray. The OCR: "11 18 ㄧ 523". Could be 11,18,1? Then 523 is next year's Europeans? But each year has 3 numbers. So 1910: E=11, I=18, C=1? Unlikely. Maybe ㄧ is a misread of "1" and 523 is the Chinese for 1910? But then we have 4 numbers for 1910. Let's look at the line: "11 18 ㄧ 523". Could be "11 18 1 523"? No.

Maybe the OCR inserted line breaks incorrectly. The original table likely has columns aligned. The OCR reads line by line. The numbers for each month are listed in a single column in OCR because the table was scanned and OCR read vertically? Actually the OCR output shows each month's data as a vertical list of numbers. That suggests the OCR read the table column by column? But the header shows years horizontally. The OCR might have read the table row by row but each cell on new line.

Let's assume the list is sequential across years: first three numbers = 1909, next three = 1910, etc. But we have 30 numbers per month. For February, we have 31 tokens. Need to clean garbage.

Garbage tokens: ㄧ, *, [1, =, maybe ㄧ is "1" but it's a separate token. Let's list tokens with indices:

1:5

2:12

3:514

4:11

5:18

6:ㄧ

7:523

8:16

9:522

10:8

11:12

12:665

13:16

14:11

14:706? Wait "16 11 706" three tokens: 16,11,706.

15:15

16:12

17:593

18:*

19:[1

20:676

21:3

22:11

23:=

24:579

25:2

26:7

27:582

28:5

29:10

30:568

That's 30 tokens if we ignore *, [1, =, ㄧ? But ㄧ is token 6. If we treat ㄧ as garbage, then tokens 1-5,7-30 = 29 tokens. Not multiple of 3.

Maybe ㄧ is actually "1" and part of a number "1523"? But 523 is separate. Could be "1" and "523" are two numbers: 1 and 523. Then 1910: 11,18,1? Then 1911: 523,16,522? That would shift.

Let's look at other months to infer pattern. The table is consistent across months. Maybe I should reconstruct the entire table by aligning columns from the OCR's vertical lists. But the OCR gives each month separately. I could parse each month's list into 10 years × 3 categories.

Better approach: The OCR output for each month is a single column of numbers (with garbage). There are 12 months. Each month should have 30 numbers (10 years × 3). The TOTAL row at bottom has totals for each category per year? The TOTAL line: "TOTAL 110|192 6,415 122 2116,228 | 127 | 164 6,846 110 143 8,155| 154 | 146 8,124 | 148 (Y 1 ) 3656,695 92 | 140 |6,891 69 130 7,451 41 119 7,036 85! 146 7,032". This is messy.

And AVERAGE row: "AVERAGE,... 9 16 535 10 18 519 11 11 570 9 12 680 13 12 677 12 30 554 8 12 574 6 11 621 4 10 586 3 12 386". That's 30 numbers: 10 years × 3. Good.

So the average row gives us the expected averages per year per category. That can help verify monthly data.

Let's parse the AVERAGE row cleanly:

"9 16 535 10 18 519 11 11 570 9 12 680 13 12 677 12 30 554 8 12 574 6 11 621 4 10 586 3 12 386"

Group by 3:

1909: E=9, I=16, C=535

1910: E=10, I=18, C=519

1911: E=11, I=11, C=570

1912: E=9, I=12, C=680

1913: E=13, I=12, C=677

1914: E=12, I=30, C=554

1915: E=8, I=12, C=574

1916: E=6, I=11, C=621

1917: E=4, I=10, C=586

1918: E=3, I=12, C=386

Note: 1914 Indians average 30? That's high. 1918 Chinese average 386? That's low compared to others (500-700). Might be correct if prison population dropped.

Now, the monthly data should average to these. So we can use this to check our parsing.

Let's parse January monthly data as per the list of 30 numbers I extracted earlier:

Jan numbers: [6,9,512, 12,14,501?, 13,16,526, 7,9,637, 13,10,723, 15,12,586, 10,15,546, 5,13,602, 3,5,601?, 5,13,583]

But the 1917 Indians: I used 5 instead of 50. Let's compute averages from these 12 months later. But we only have January now. We need all months.

Given the complexity, perhaps the best is to reconstruct the table in Markdown with the data as parsed from OCR, correcting obvious OCR errors, and noting uncertainties. But the user wants a clean Markdown table. I need to produce a single table with months as rows, years as column groups, categories as subcolumns.

Given the OCR is very messy, I might need to manually transcribe the table by interpreting the OCR output. This is a large table: 12 months × 10 years × 3 categories = 360 data cells. Plus totals and averages.

But the user only provided the OCR text for this one table. I must do my best.

Let me attempt to parse each month's data from the OCR text provided. The OCR text includes all months sequentially. I'll go through each month block.

The OCR text after the header:

"298

January,

6

9 512

12

14

50%

13

16

526

7

9

637

13 10

723

15 12

586

10

15

546

5

13

602

3

50

601

5 13

583

February,

5

12 514

11

18

523

16

522

8

12 665

16 11

706

15 12

593

*

[1

676

3

11

=

579

2 7

582

5

10

568

Marchi,

9

11 532

9

17

489

13

16

537

7

12

642

11

12

665

12

12

541

9

9

586

4

13

13

558

3 6

588

LA

¿

551

April,

9

11

568

11

18

516

10

14

523

9

16

628

9

12

672

10 13

581

9

8

577

3

13

585

5

7

569

6

10

560

Muy,

12

12 589

11

16

517

10

13

535

10

15 639

14

13

734 15

12

578

G

8

544

3

14

614

4

9

577

2

Il

579

June,

12

10 588

10

18

527

17

568

9

15

683

15 11

752

9

11

579

Co

8

562

15

14

647

3 17

577

1

11

592

-

July,

7

10 | 545

9

29

540

11

12

598

10

11

699

13 11

704

9

10

515

15

انت

556

12

9 644

H

15

ن

585 Nil. 14

568

August,

م

33 539

11

20

518

11

11

599

11

10

637

14

11

677

10

9

610

7

14

581

11

9

631

ลง

577

1

23

542

September, ...

9

43 514

9

17

510

10

12 599

*

11

725

14 13

664

11

48

536

8

14

588

3

8

651

5

11

592

3

13

552

October,

13

16 499

9

15

509

10

13

621

11

11

762

13 12

622 13

67

۴ 572

30

12

577

4

9

643

30

B

11 588

ลง

2 10

636

November,

11

13 505

14

533

10

13 392

10

11

755

11

15

628

14

45

115

534

8

14

589

تت

3

7

668

1

10

605

1 12

661

December,

9

12 10

11

15

538

7

11

626

10

10

683

11

15

577

15114

550

6

12

609

3

10

629

9

595

8 640

TOTAL 110|192 6,415

122 2116,228 | 127 | 164 6,846 110 143 8,155| 154 | 146 8,124 | 148

(Y 1 )

3656,695 92 | 140 |6,891

69 130 7,451

41 119 7,036

85! 146 7,032

AVERAGE,...

9 16 535

10

18 519

11

11

570

9

12 680

13 12

677

12

30

554

8

12

574

6 11

621

4

10

586

3

12

386

E. Europeans,

I.=Indians.

C. Chinese."

This is a huge mess. But I can see each month has a list of numbers. The pattern: each month starts with month name, then a series of numbers. There are 12 months. Each month should have 30 numbers (10 years * 3 categories). However, the OCR includes many non-numeric characters and line breaks.

I need to extract 30 numbers per month. Let's write a script mentally? But as a language model, I can process sequentially.

I'll go month by month, extract numbers in order, ignoring non-numeric tokens, but being careful because some numbers are multi-digit and may be split? The OCR seems to put each number on its own line mostly, but sometimes two numbers on one line (e.g., "13 10" for 1913 January Europeans and Indians). So I'll tokenize by whitespace and newlines, then filter tokens that are numbers (digits possibly with commas). But there are tokens like "50%", "ㄧ", "*", "[1", "=", "LA", "¿", "G", "Co", "انت", "H", "ن", "Nil.", "م", "ลง", "→", "ຕ", "تت", "۴", "B", "15114", "85!", etc. Many are garbage.

Better: The numbers we want are integers (maybe with commas for thousands). The Chinese numbers are in hundreds (500-700). Europeans and Indians are small (0-30). So we can identify numbers by pattern: 1-3 digits for E and I, 3-4 digits for C. But in the token stream, they are interleaved.

Since the order is consistent: for each year, E, I, C. So the sequence is: E1909, I1909, C1909, E1910, I1910, C1910, ..., E1918, I1918, C1918.

Thus, if we can extract a clean sequence of 30 numbers per month, we can map them.

Let's attempt to extract numbers from each month's block by reading lines and picking out numbers.

I'll do it manually for each month.

January block lines:

"298" - maybe page number? Ignore.

"January," - month

"6" -> 6

"9 512" -> 9, 512

"12" -> 12

"14" -> 14

"50%" -> 50? or 501? The token "50%" contains digits 50. Could be 50. But Chinese ~500. So likely 501 or 507. The "%" might be a smudge for "1" or "7". I'll assume 501 for now.

"13" -> 13

"16" -> 16

"526" -> 526

"7" -> 7

"9" -> 9

"637" -> 637

"13 10" -> 13, 10

"723" -> 723

"15 12" -> 15, 12

"586" -> 586

"10" -> 10

"15" -> 15

"546" -> 546

"5" -> 5

"13" -> 13

"602" -> 602

"3" -> 3

"50" -> 50 (but likely 5 and 0? But 0 not expected. Could be 5)

"601" -> 601

"5 13" -> 5, 13

"583" -> 583

Now list all numbers in order: 6,9,512,12,14,50,13,16,526,7,9,637,13,10,723,15,12,586,10,15,546,5,13,602,3,50,601,5,13,583. That's 30 numbers. Good.

But the 50 at position 26 (1917 Indians) is suspicious. The average for 1917 Indians is 10. If January is 50, the other 11 months must be very low to average 10. Possible but unlikely. Let's check other months for 1917 Indians. We'll see later. For now, keep as 50 but maybe correct to 5? The token is "50" on its own line. Could be "5 0" but OCR merged. The next token is 601. If it were "5 0 601", that would be three numbers: 5,0,601. But we need 3 numbers for 1917: E,I,C. We have 3 (from "3"), then 50, then 601. So 3,50,601. If 50 is actually two numbers 5 and 0, then we'd have 4 numbers for 1917. But the total count is 30, so 50 is one number. So Indians=50 for Jan 1917. Let's see February 1917.

February block:

Lines:

"February,"

"5" ->5

"12 514" ->12,514

"11" ->11

"18" ->18

"ㄧ" -> garbage (maybe 1)

"523" ->523

"16" ->16

"522" ->522

"8" ->8

"12 665" ->12,665

"16 11" ->16,11

"706" ->706

"15 12" ->15,12

"593" ->593

"*" -> garbage

"[1" -> garbage

"676" ->676

"3" ->3

"11" ->11

"=" -> garbage

"579" ->579

"2 7" ->2,7

"582" ->582

"5" ->5

"10" ->10

"568" ->568

Now extract numbers in order, skipping garbage: 5,12,514,11,18,523,16,522,8,12,665,16,11,706,15,12,593,676,3,11,579,2,7,582,5,10,568. That's 26 numbers? Let's count: 1.5,2.12,3.514,4.11,5.18,6.523,7.16,8.522,9.8,10.12,11.665,12.16,13.11,14.706,15.15,16.12,17.593,18.676,19.3,20.11,21.579,22.2,23.7,24.582,25.5,26.10,27.568. 27 numbers. We need 30. Missing 3 numbers. The garbage tokens might hide numbers. The "ㄧ" might be a number 1. The "*" and "[1" and "=" might be numbers. "[1" could be 1. "=" maybe not. Also "2 7" gave two numbers. We have 27. Need 3 more. Perhaps the line "12 514" is three numbers? No, "12 514" two numbers. "16 11" two. "15 12" two. "2 7" two. So total tokens: let's list all numeric tokens from lines:

Line by line:

5

12,514

11

18

ㄧ (maybe 1)

523

16

522

8

12,665

16,11

706

15,12

593

  • (skip)

[1 (maybe 1)

676

3

11

= (skip)

579

2,7

582

5

10

568

If we take ㄧ as 1, [1 as 1, that adds two. Still 29. Maybe "12 514" is actually three numbers: 1,2,514? But "12" is one number. Could be "1 2 514"? Unlikely.

Maybe the February data has 30 numbers but OCR missed some. Let's compare with average. For 1909 February: E=5, I=12, C=514. That matches first three. 1910: E=11, I=18, C=523? But we have 523 as 6th number. So 1910: 11,18,523. Good. 1911: next three: 16,522,8? That would be E=16, I=522, C=8? No, Indians 522 too high. So maybe 1911: 16,522,8? But Chinese 8 too low. So the grouping is off after 1910.

Let's think: The pattern is E,I,C for each year. The numbers for Europeans and Indians are small (single or double digits), Chinese are hundreds. So in the sequence, we expect two small numbers then a large number, repeating.

Look at the sequence: 5 (small), 12 (small), 514 (large) -> good for 1909.

11 (small), 18 (small), 523 (large) -> good for 1910.

16 (small), 522 (large), 8 (small) -> here large appears at second position, not third. So maybe 1911: E=16, I=522? No, Indians not that high. Could be that 522 is Chinese for 1910? But we already used 523 for 1910 Chinese. Hmm.

Maybe the OCR order is not strictly row-major. Could be the table was read column by column? But the header suggests years across.

Another possibility: The OCR output for each month is actually the column for that month? No, the title says "STATEMENT of the DAILY AVERAGE of PRISONERS for each Month of the Year". So rows are months, columns are years and categories.

The OCR text shows "January," then a list of numbers. That list likely goes across the row: first year 1909 E, I, C; then 1910 E, I, C; etc. But the numbers we extracted for January gave a perfect pattern of small, small, large for 10 years. Let's verify January sequence:

6,9,512 (small,small,large)

12,14,50 (small,small,large? 50 is not large) -> 50 is not hundreds. But 50% maybe 501? If 501, then large.

13,16,526 (good)

7,9,637 (good)

13,10,723 (good)

15,12,586 (good)

10,15,546 (good)

5,13,602 (good)

3,50,601 (3 small, 50 medium, 601 large) -> 50 is not small like others (usually <20). But 50 could be Indians? In 1917, average Indians=10, so 50 is outlier.

5,13,583 (good)

So January mostly follows pattern except 1910 Chinese (50) and 1917 Indians (50). If we correct 1910 Chinese to 501, and 1917 Indians to 5, then pattern holds.

Now February: Let's try to force the pattern: we need 10 groups of (small, small, large). Let's scan the numeric tokens in order and group them as they appear, but we need to decide which tokens are numbers. The tokens include some large numbers: 514,523,522,665,706,593,676,579,582,568. That's 10 large numbers? Count: 514,523,522,665,706,593,676,579,582,568 = 10. Good! So the Chinese numbers are there. The small numbers should be 20 numbers (2 per year). Let's list all small numbers (1-2 digits) in order: 5,12,11,18,16,8,12,16,11,15,12,3,11,2,7,5,10. That's 17 small numbers. We need 20. Missing 3. The garbage tokens might be small numbers: ㄧ (1), [1 (1), maybe * is not, = not. Also "2 7" gave two. "15 12" gave two. "16 11" gave two. "12 665" gave 12 and 665. "8" is single. "16" single. "522" is large. "523" large. "676" large. "579" large. "582" large. "568" large.

We have 10 large numbers. We have 17 small numbers from clear tokens. Plus ㄧ and [1 maybe two more =19. Still missing one. Perhaps "12 514" is actually three numbers: 1,2,514? But "12" is one token. Could be "1 2 514" but OCR merged "1 2" as "12". If so, then 1909: E=1, I=2, C=514? But January 1909 E=6, I=9. So not consistent.

Maybe the February data for 1909 is 5,12,514 (E=5,I=12,C=514). That matches January pattern (E around 5-6, I around 9-12). Good.

Then 1910: next two small and one large. After 514, we have 11,18, then 523? But there's ㄧ before 523. If ㄧ is a small number (1), then sequence: 11,18,1,523. That's three small then large. Not good.

If we ignore ㄧ, then 11,18,523 -> good.

Then 1911: next two small and large. After 523, we have 16,522,8. 16 small, 522 large, 8 small. So if we take 16 as E, 522 as C? But then I missing. Or 16 as E, 522 as I? No.

Maybe the large numbers are not in order? Let's list large numbers in order of appearance: 514, 523, 522, 665, 706, 593, 676, 579, 582, 568. That's 10. They should correspond to years 1909-1918 Chinese.

Now small numbers in order: 5,12, 11,18, 16, 8,12, 16,11, 15,12, 3,11, 2,7, 5,10. Plus possible 1,1 from garbage.

We need to pair them as (E,I think the table might have been misread by OCR such that the columns are not aligned. Given the difficulty, perhaps the best is to present the table as the OCR text but cleaned up? But the user wants a proper Markdown table.

Given the time, I might need to approximate. But as an AI, I should do my best to reconstruct accurately.

Let's look at the TOTAL and AVERAGE rows. They might give totals per year per category. The TOTAL line: "TOTAL 110|192 6,415 122 2116,228 | 127 | 164 6,846 110 143 8,155| 154 | 146 8,124 | 148 (Y 1 ) 3656,695 92 | 140 |6,891 69 130 7,451 41 119 7,036 85! 146 7,032"

This is messy but seems to contain totals for each year for E, I, C. For example, "110|192 6,415" might be 1909: E=110, I=192, C=6415? But those are yearly totals? Daily average 365? 535365=195,275, not 6,415. So maybe totals for the year? 6,415 could be total Chinese prisoner-days? Not sure.

The AVERAGE row we parsed gives averages per year per category. That is likely the yearly average of daily averages across months. So we can trust that.

Thus, the monthly data should average to those yearly averages.

We have 12 months. If we can get the monthly data for each year/category, we can verify.

Given the OCR is too messy, perhaps the intended output is to present the table in a readable Markdown format, correcting obvious OCR errors, but keeping the data as close as possible. The user might not expect perfect data, but a clean table structure.

I will construct a Markdown table with the header and the monthly rows, using the numbers I can extract with reasonable corrections. For February, I'll try to parse by assuming the pattern holds and the OCR missed some numbers. But I need to produce something.

Given the complexity, I'll write a script-like approach in my reasoning to parse each month's numbers by taking all integer numbers from the block in order, and then grouping into 10 groups of 3. For February, the integers in order (including those from garbage if they look like numbers) are: 5,12,514,11,18,1,523,16,522,8,12,665,16,11,706,15,12,593,1,676,3,11,579,2,7,582,5,10,568. That's 30 numbers if we take ㄧ as 1 and [1 as 1. Let's test grouping:

Group 1: 5,12,514 -> 1909

Group 2: 11,18,1 -> 1910: E=11,I=18,C=1? No, Chinese=1 impossible.

Group 3: 523,16,522 -> 1911: E=523? no.

So not that.

Maybe the large numbers are the Chinese, and they appear every third? In January, the large numbers were at positions 3,6,9,12,15,18,21,24,27,30. In February, the large numbers appear at positions: 3(514), 6(523?), 7(522?), 11(665), 14(706), 17(593), 19(676), 22(579), 25(582), 28(568). Not regular.

This suggests the OCR for February is more corrupted.

Given the difficulty, I might need to output the table with the data as given in the OCR but formatted as a table, with notes? But the instruction says "Preserve original content — do not add or remove substantive words. Do not rephrase, rewrite, or change the author's style, tone, or word choice. Only correct what is clearly wrong." And "Correct unambiguous OCR spelling errors". For tables, "reconstruct the table using Markdown table syntax."

I think the best is to reconstruct the table as it appears in the OCR, but in a clean Markdown table, with the same structure: Month, then for each year 1909-1918, three columns E, I, C. I will fill in the numbers as they appear in the OCR for each month, in the order they appear, assuming the OCR list for each month is the row data in order. For January, we have 30 numbers, good. For February, we have 27 numbers, but we can pad with ... for missing? But the instruction says if missing, insert .... However, the missing might be due to OCR not capturing. But we have the numbers in the text, just need to extract correctly.

Let's count numbers in each month block by scanning for numbers (sequences of digits). I'll do a quick manual extraction for all months using a systematic approach: For each month, I'll take the text block and split by whitespace, then filter tokens that match /^\d+$/ or /^\d+,\d+$/ (but Chinese numbers have no commas in OCR, they are like 512). Also tokens like "50%" -> extract 50. "15114" -> maybe 15,114? But that's five digits. Could be 15 and 114? But 114 is not hundreds. In December: "15114 550" -> maybe 15, 114, 550? But 114 is not Chinese. Let's see December block: "9 12 10 11 15 538 7 11 626 10 10 683 11 15 577 15114 550 6 12 609 3 10 629 9 595 8 640". Numbers: 9,12,10,11,15,538,7,11,626,10,10,683,11,15,577,15114,550,6,12,609,3,10,629,9,595,8,640. That's 26 numbers. 15114 is five digits. Could be 15, 114? But 114 is not Chinese. Maybe it's 15, 11, 4? But "15114" no spaces. Could be OCR merged "15 11 4"? But then 4 is small. Chinese for 1914? Let's see: December 1914? Years 1909-1918. December is month 12. The sequence should have 30 numbers. We have 26 tokens. 15114 might be three numbers: 15, 11, 4? But 4 is not Chinese. Or 15, 114? 114 not Chinese. Perhaps it's 15, 11, 4? But then we have 550 next. 550 could be Chinese. Let's group known: first 15 numbers: 9,12,10,11,15,538,7,11,626,10,10,683,11,15,577 -> that's 15 numbers = 5 years (1909-1913). Good. Then next should be 1914,1915,1916,1917,1918 (5 years = 15 numbers). Remaining tokens: 15114,550,6,12,609,3,10,629,9,595,8,640 -> 12 tokens. Need 15. So 15114 might represent three numbers: 15, 11, 4? Then we have 15,11,4,550,6,12,609,3,10,629,9,595,8,640 -> 14 tokens. Still missing one. Or 15,114,550? 114 not Chinese.

This is too messy. Perhaps the original table is not meant to be perfectly reconstructed from this OCR. The user might be testing the proofreading ability. But the instruction says to proofread OCR output. I must do my best.

Given the constraints, I will produce a Markdown table with the header and the monthly rows, using the numbers as they appear in the OCR for January (since it's clean), and for other months I will try to parse similarly, but given the time, I might output a table with the data from the OCR text but formatted, and use ... for missing/unclear.

But the user expects a single Markdown output. I'll attempt to create a table with 12 rows (months) and 31 columns (Month + 10 years * 3). I'll fill in what I can.

Given the massive effort, perhaps I can write a programmatic solution in my mind? Not feasible.

Alternative: The OCR text might be from a known historical document. The table is "STATEMENT of the DAILY AVERAGE of PRISONERS for each Month of the Year, from 1909 to 1918." This might be from Hong Kong Blue Book or similar. The data might be known. But I don't have external knowledge.

Given the situation, I will output a Markdown table that represents the structure, with the data from the OCR as best as I can parse, correcting obvious errors (like 50% -> 501, ㄧ -> 1, etc.), and for February and others, I'll use the numbers in the order they appear, assuming they are in the correct order, and if count is not 30, I'll pad with ... or leave blank? But the instruction says "if a word or phrase is clearly missing due to OCR damage, insert ...". For numbers, maybe insert ....

But the table would have many ... which might not be ideal.

Maybe the OCR text actually contains the table in a different format: The header shows "MORTHS. E. I. C. E. I. C. ..." and then the data rows are given with month names and numbers. The OCR might have lost the column alignment. But the numbers are there in sequence.

I'll assume that for each month, the numbers are listed in the order: 1909 E, I, C; 1910 E, I, C; ... 1918 E, I, C. And the OCR for each month provides exactly 30 numbers, but some are merged with garbage. I'll extract all numbers (including those from garbage tokens by splitting non-digit characters) to get 30 per month.

Let's do that for each month by writing a pseudo-code in my head and simulating.

I'll process each month block as a string, extract all integers (sequences of digits) in order. For tokens like "50%", extract 50. For "15114", extract 15114 as one integer? But that's five digits. Could be multiple integers concatenated. But we can split by known boundaries? Not reliable.

Given the time, I'll produce a table with the data from the AVERAGE row and TOTAL row? No, the user wants the monthly statement.

I think I need to output something. I'll create a Markdown table with the header and then for each month, I'll put the numbers as they appear in the OCR for January (since it's complete), and for other months I'll note "Data corrupted" but that's not allowed.

Given the instruction "Output only in Markdown. Do not wrap your response in code fences or HTML tags." I must output Markdown.

I'll do the following: Reconstruct the table as a Markdown table with the header row and subheader row, then 12 rows for months, using the numbers from the OCR for each month as a single string in a cell? No, that's not a table.

I'll make a table with columns: Month, 1909 E, 1909 I, 1909 C, 1910 E, 1910 I, 1910 C, ..., 1918 E, 1918 I, 1918 C.

I'll fill January fully. For February, I'll try to parse 30 numbers by taking all numbers in the block in order, but I need to decide which are numbers. Let's list all numbers in February block as they appear in the text, including those embedded in garbage:

Text: "5 12 514 11 18 ㄧ 523 16 522 8 12 665 16 11 706 15 12 593 * [1 676 3 11 = 579 2 7 582 5 10 568"

I'll split by spaces and newlines, then for each token, extract digits. Tokens: "5", "12", "514", "11", "18", "ㄧ", "523", "16", "522", "8", "12", "665", "16", "11", "706", "15", "12", "593", "*", "[1", "676", "3", "11", "=", "579", "2", "7", "582", "5", "10", "568".

Now extract numbers:

"5" -> 5

"12" -> 12

"514" -> 514

"11" -> 11

"18" -> 18

"ㄧ" -> no digits, skip? But it might be "1". I'll treat as 1.

"523" -> 523

"16" -> 16

"522" -> 522

"8" -> 8

"12" -> 12

"665" -> 665

"16" -> 16

"11" -> 11

"706" -> 706

"15" -> 15

"12" -> 12

"593" -> 593

"*" -> skip

"[1" -> extract 1

"676" -> 676

"3" -> 3

"11" -> 11

"=" -> skip

"579" -> 579

"2" -> 2

"7" -> 7

"582" -> 582

"5" -> 5

"10" -> 10

"568" -> 568

That gives 30 numbers! Let's count: 1.5,2.12,3.514,4.11,5.18,6.1,7.523,8.16,9.522,10.8,11.12,12.665,13.16,14.11,15.706,16.15,17.12,18.593,19.1,20.676,21.3,22.11,23.579,24.2,25.7,26.582,27.5,28.10,29.568. That's 29? Wait, I have 29. Let's recount the list:

1:5

2:12

3:514

4:11

5:18

6:1 (from ㄧ)

7:523

8:16

9:522

10:8

11:12

12:665

13:16

14:11

15:706

16:15

17:12

18:593

19:1 (from [1)

20:676

21:3

22:11

23:579

24:2

25:7

26:582

27:5

28:10

29:568

29 numbers. Missing one. Did I miss a token? The token "2 7" gave two numbers. "15 12" gave two. "16 11" gave two. "12 665" gave two. "8" one. "16" one. "522" one. "523" one. "18" one. "11" one. "12" one. "5" one. "11" one. "3" one. "5" one. "10" one. "568" one. That's 29. Perhaps "ㄧ" is not a number, but "[1" is one. Still 29. Maybe "*" represents a number? Unlikely.

But 29 is close. Could be that one of the Chinese numbers is missing. For 10 years we need 30. Perhaps the first number "5" is for 1909 E, "12" for 1909 I, "514" for 1909 C. Then 1910: "11", "18", "1"? But "1" from ㄧ, then "523" would be 1911 E? That doesn't work.

If we ignore the "1" from ㄧ and "[1", we have 27 numbers. Not good.

Maybe the February block has a line break issue. The OCR shows "12 514" on one line, "11" on next, "18" on next, "ㄧ" on next, "523" on next. So "ㄧ" is on its own line. It might be a stray character. If we drop it, we have 28 numbers? Let's count without ㄧ and without [1: 27 numbers.

Given the difficulty, I'll assume the February data is similar to January and use the average to estimate? But that's not proofreading.

Given the time, I will output a Markdown table with the header and the monthly data for January only, and for other months put ...? But the user provided the whole text.

I think the best is to output the table as a Markdown table with the data exactly as the OCR presents it in a linear fashion, but formatted as a table with 12 rows and 31 columns, filling in the numbers sequentially from the OCR for each month, using ... for missing. But that would be a guess.

Given the instruction "Preserve original content — do not add or remove substantive words." The original content is the OCR text. The table is the content. I should reconstruct the table as it was intended. The OCR text includes the numbers for each month in a list. That list is the row data. So I will create a table where each month row has the numbers in the order they appear in the OCR list for that month, spread across the 30 category columns. For January, 30 numbers. For February, I'll use the 29 numbers I extracted and add a ... at the end. For March, etc.

But the columns are labeled by year and category. The order of numbers in the list should correspond to the column order. So I'll map them directly.

Let's do that for all months by extracting numbers from each month block in the OCR text. I'll write a quick mental script to extract all integers from each block. Since I'm an AI, I can simulate.

I'll go through each month block in the provided text and extract numbers.

The text after "298" (page number) has months: January, February, Marchi, April, Muy, June, July, August, September, October, November, December.

I'll extract for each.

January (already did): 30 numbers: [6,9,512,12,14,50,13,16,526,7,9,637,13,10,723,15,12,586,10,15,546,5,13,602,3,50,601,5,13,583]

February: from earlier extraction with ㄧ=1 and [1=1, we got 29 numbers. Let's extract again carefully from the raw February block lines:

"February,

5

12 514

11

18

523

16

522

8

12 665

16 11

706

15 12

593

*

[1

676

3

11

=

579

2 7

582

5

10

568"

I'll read line by line and pull numbers:

Line "5" -> 5

Line "12 514" -> 12, 514

Line "11" -> 11

Line "18" -> 18

Line "ㄧ" -> maybe 1? I'll include as 1.

Line "523" -> 523

Line "16" -> 16

Line "522" -> 522

Line "8" -> 8

Line "12 665" -> 12, 665

Line "16 11" -> 16, 11

Line "706" -> 706

Line "15 12" -> 15, 12

Line "593" -> 593

Line "*" -> skip

Line "[1" -> 1

Line "676" -> 676

Line "3" -> 3

Line "11" -> 11

Line "=" -> skip

Line "579" -> 579

Line "2 7" -> 2, 7

Line "582" -> 582

Line "5" -> 5

Line "10" -> 10

Line "568" -> 568

List: 5,12,514,11,18,1,523,16,522,8,12,665,16,11,706,15,12,593,1,676,3,11,579,2,7,582,5,10,568. That's 29 numbers. (Count: 29). I'll keep as is, and for the 30th, put ....

Marchi (March):

Block:

"Marchi,

9

11 532

9

17

489

13

16

537

7

12

642

11

12

665

12

12

541

9

9

586

4

13

13

558

3 6

588

LA

¿

551"

Extract numbers line by line:

"9" ->9

"11 532" ->11,532

"9" ->9

"17" ->17

"489" ->489

"13" ->13

"16" ->16

"537" ->537

"7" ->7

"12" ->12

"642" ->642

"11" ->11

"12" ->12

"665" ->665

"12" ->12

"12" ->12

"541" ->541

"9" ->9

"9" ->9

"586" ->586

"4" ->4

"13" ->13

"13" ->13

"558" ->558

"3 6" ->3,6

"588" ->588

"LA" -> skip

"¿" -> skip

"551" ->551

List: 9,11,532,9,17,489,13,16,537,7,12,642,11,12,665,12,12,541,9,9,586,4,13,13,558,3,6,588,551. That's 29 numbers? Count: 1.9,2.11,3.532,4.9,5.17,6.489,7.13,8.16,9.537,10.7,11.12,12.642,13.11,14.12,15.665,16.12,17.12,18.541,19.9,20.9,21.586,22.4,23.13,24.13,25.558,26.3,27.6,28.588,29.551. 29 numbers. Missing one. Maybe "LA" or "¿" hide a number. But we'll use 29.

April:

Block:

"April,

9

11

568

11

18

516

10

14

523

9

16

628

9

12

672

10 13

581

9

8

577

3

13

585

5

7

569

6

10

560"

Extract:

"9" ->9

"11" ->11

"568" ->568

"11" ->11

"18" ->18

"516" ->516

"10" ->10

"14" ->14

"523" ->523

"9" ->9

"16" ->16

"628" ->628

"9" ->9

"12" ->12

"672" ->672

"10 13" ->10,13

"581" ->581

"9" ->9

"8" ->8

"577" ->577

"3" ->3

"13" ->13

"585" ->585

"5" ->5

"7" ->7

"569" ->569

"6" ->6

"10" ->10

"560" ->560

List: 9,11,568,11,18,516,10,14,523,9,16,628,9,12,672,10,13,581,9,8,577,3,13,585,5,7,569,6,10,560. That's 30 numbers! Good.

Muy (May):

Block:

"Muy,

12

12 589

11

16

517

10

13

535

10

15 639

14

13

734 15

12

578

G

8

544

3

14

614

4

9

577

2

Il

579"

Extract:

"12" ->12

"12 589" ->12,589

"11" ->11

"16" ->16

"517" ->517

"10" ->10

"13" ->13

"535" ->535

"10" ->10

"15 639" ->15,639

"14" ->14

"13" ->13

"734 15" ->734,15

"12" ->12

"578" ->578

"G" -> skip

"8" ->8

"544" ->544

"3" ->3

"14" ->14

"614" ->614

"4" ->4

"9" ->9

"577" ->577

"2" ->2

"Il" -> maybe 11? "Il" could be 11 (Roman numeral II? but likely 11). I'll treat as 11.

"579" ->579

List: 12,12,589,11,16,517,10,13,535,10,15,639,14,13,734,15,12,578,8,544,3,14,614,4,9,577,2,11,579. That's 28 numbers? Count: 1.12,2.12,3.589,4.11,5.16,6.517,7.10,8.13,9.535,10.10,11.15,12.639,13.14,14.13,15.734,16.15,17.12,18.578,19.8,20.544,21.3,22.14,23.614,24.4,25.9,26.577,27.2,28.11,29.579. 29 numbers. Missing one.

June:

Block:

"June,

12

10 588

10

18

527

17

568

9

15

683

15 11

752

9

11

579

Co

8

562

15

14

647

3 17

577

1

11

592"

Extract:

"12" ->12

"10 588" ->10,588

"10" ->10

"18" ->18

"527" ->527

"17" ->17

"568" ->568

"9" ->9

"15" ->15

"683" ->683

"15 11" ->15,11

"752" ->752

"9" ->9

"11" ->11

"579" ->579

"Co" -> skip

"8" ->8

"562" ->562

"15" ->15

"14" ->14

"647" ->647

"3 17" ->3,17

"577" ->577

"1" ->1

"11" ->11

"592" ->592

List: 12,10,588,10,18,527,17,568,9,15,683,15,11,752,9,11,579,8,562,15,14,647,3,17,577,1,11,592. That's 27 numbers? Count: 1.12,2.10,3.588,4.10,5.18,6.527,7.17,8.568,9.9,10.15,11.683,12.15,13.11,14.752,15.9,16.11,17.579,18.8,19.562,20.15,21.14,22.647,23.3,24.17,25.577,26.1,27.11,28.592. 28 numbers. Missing two.

July:

Block:

"July,

7

10 | 545

9

29

540

11

12

598

10

11

699

13 11

704

9

10

515

15

انت

556

12

9 644

H

15

ن

585 Nil. 14

568"

Extract:

"7" ->7

"10 | 545" ->10,545 (ignore |)

"9" ->9

"29" ->29

"540" ->540

"11" ->11

"12" ->12

"598" ->598

"10" ->10

"11" ->11

"699" ->699

"13 11" ->13,11

"704" ->704

"9" ->9

"10" ->10

"515" ->515

"15" ->15

"انت" -> skip (Arabic)

"556" ->556

"12" ->12

"9 644" ->9,644

"H" -> skip

"15" ->15

"ن" -> skip

"585 Nil. 14" ->585,14 (Nil. skip)

"568" ->568

List: 7,10,545,9,29,540,11,12,598,10,11,699,13,11,704,9,10,515,15,556,12,9,644,15,585,14,568. That's 26 numbers? Count: 1.7,2.10,3.545,4.9,5.29,6.540,7.11,8.12,9.598,10.10,11.11,12.699,13.13,14.11,15.704,16.9,17.10,18.515,19.15,20.556,21.12,22.9,23.644,24.15,25.585,26.14,27.568. 27 numbers. Missing three.

August:

Block:

"August,

م

33 539

11

20

518

11

11

599

11

10

637

14

11

677

10

9

610

7

14

581

11

9

631

ลง

577

1

23

542"

Extract:

"م" -> skip

"33 539" ->33,539

"11" ->11

"20" ->20

"518" ->518

"11" ->11

"11" ->11

"599" ->599

"11" ->11

"10" ->10

"637" ->637

"14" ->14

"11" ->11

"677" ->677

"10" ->10

"9" ->9

"610" ->610

"7" ->7

"14" ->14

"581" ->581

"11" ->11

"9" ->9

"631" ->631

"ลง" -> skip

"→" -> skip

"577" ->577

"1" ->1

"23" ->23

"542" ->542

List: 33,539,11,20,518,11,11,599,11,10,637,14,11,677,10,9,610,7,14,581,11,9,631,577,1,23,542. That's 27 numbers? Count: 1.33,2.539,3.11,4.20,5.518,6.11,7.11,8.599,9.11,10.10,11.637,12.14,13.11,14.677,15.10,16.9,17.610,18.7,19.14,20.581,21.11,22.9,23.631,24.577,25.1,26.23,27.542. 27 numbers.

September:

Block:

"September, ...

9

43 514

9

17

510

10

12 599

*

11

725

14 13

664

11

48

536

8

14

588

3

8

651

5

11

592

3

13

552"

Extract:

"9" ->9

"43 514" ->43,514

"9" ->9

"17" ->17

"510" ->510

"10" ->10

"12 599" ->12,599

"*" -> skip

"11" ->11

"725" ->725

"14 13" ->14,13

"664" ->664

"11" ->11

"48" ->48

"536" ->536

"8" ->8

"14" ->14

"588" ->588

"3" ->3

"8" ->8

"651" ->651

"5" ->5

"11" ->11

"592" ->592

"3" ->3

"13" ->13

"552" ->552

List: 9,43,514,9,17,510,10,12,599,11,725,14,13,664,11,48,536,8,14,588,3,8,651,5,11,592,3,13,552. That's 29 numbers? Count: 1.9,2.

Edit History

2026-07-12 20:38:44 · NVIDIA / nvidia/nemotron-3-ultra-550b-a55b
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AI Proofread
The user wants me to proofread OCR output of a historical table showing daily average prisoners by month from 1909-1918. The OCR is messy with many errors. I need to reconstruct this as a proper Markdown table. Let me analyze the structure: Title: &quot;STATEMENT of the DAILY AVERAGE of PRISONERS for each Month of the Year, from 1909 to 1918.&quot; Columns: Months, then for each year 1909-1918, three categories: E (Europeans), I (Indians), C (Chinese) The data appears to be monthly averages for each category per year There&#039;s a TOTAL row and AVERAGE row at the bottom Legend: E. Europeans, I.=Indians, C. Chinese The OCR has many issues: Misaligned columns Garbled characters (ㄧ, =, *, ¿, LA, Co, H, →, ↓, ຕ, تت, ४, B, Nil, انت, ન, etc.) Numbers split across lines Missing values The header row is messy I need to reconstruct the table logically. Let me parse the data row by row. First, the header shows years 1909 to 1918, each with E, I, C columns. That&#039;s 10 years × 3 = 30 data columns plus Month column = 31 columns total. But the OCR shows a compressed header: &quot;E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C. E. I. C.&quot; for 10 years. Then the data rows for each month. Let me try to reconstruct each month&#039;s data by year and category. I&#039;ll go month by month, year by year. January: 1909: E=6, I=9, C=512 1910: E=12, I=14, C=50%? Wait &quot;50%&quot; likely 501 or 507? The OCR says &quot;50%&quot; but probably 501 or 507. Looking at pattern, Chinese numbers are around 500-700. &quot;50%&quot; might be &quot;501&quot; or &quot;507&quot;. But next year 1911: E=13, I=16, C=526. 1912: E=7, I=9, C=637. 1913: E=13, I=10, C=723. 1914: E=15, I=12, C=586. 1915: E=10, I=15, C=546. 1916: E=5, I=13, C=602. 1917: E=3, I=50? Wait &quot;50&quot; then &quot;601&quot; - maybe E=3, I=5, C=601? But &quot;50&quot; and &quot;601&quot; on same line? The OCR: &quot;3 50 601&quot;. Could be E=3, I=5, C=601? But 50 seems high for Indians. Maybe &quot;5 0&quot; but OCR merged. 1918: E=5, I=13, C=583. Let me look at the raw OCR lines for January: &quot;January, 6 9 512 12 14 50% 13 16 526 7 9 637 13 10 723 15 12 586 10 15 546 5 13 602 3 50 601 5 13 583&quot; This appears to be a single column of numbers. But they should be grouped by year: each year has 3 numbers (E, I, C). 10 years = 30 numbers. Let&#039;s count: 1.6, 2.9, 3.512, 4.12, 5.14, 6.50%, 7.13, 8.16, 9.526, 10.7, 11.9, 12.637, 13.13, 14.10, 15.723, 16.15, 17.12, 18.586, 19.10, 20.15, 21.546, 22.5, 23.13, 24.602, 25.3, 26.50, 27.601, 28.5, 29.13, 30.583. That&#039;s 30 numbers. Good. So grouping by 3: 1909: 6, 9, 512 1910: 12, 14, 50% → 50% likely 501 or 507? Could be 501 (since 50% might be OCR for 501 with % as smudge). Or 507. Let&#039;s see other years: Chinese averages range 489-762. 501 plausible. I&#039;ll use 501 but note uncertainty. Actually &quot;50%&quot; could be &quot;501&quot; where 1 looks like %. I&#039;ll assume 501. 1911: 13, 16, 526 1912: 7, 9, 637 1913: 13, 10, 723 1914: 15, 12, 586 1915: 10, 15, 546 1916: 5, 13, 602 1917: 3, 50, 601 → 50 for Indians? That&#039;s an outlier. Other years Indians are 9-18. 50 seems wrong. Could be &quot;5 0&quot; but OCR merged. Or maybe &quot;5 0&quot; is two numbers? But we need exactly 3 per year. 3, 50, 601. If 50 is actually 5 and 0? But then we&#039;d have 4 numbers. Perhaps the OCR misread &quot;5 0&quot; as &quot;50&quot;. But the next year starts with 5,13,583. So 1917: E=3, I=5, C=601? But then the &quot;0&quot; is extra. Or maybe 1917: E=3, I=5, C=601 and the &quot;0&quot; is a stray. The line &quot;3 50 601&quot; might be &quot;3 5 0 601&quot;? No. Let&#039;s look at the original OCR: &quot;3 50 601&quot;. Could be &quot;3 5 0 601&quot; but that&#039;s 4 numbers. Alternatively, maybe the Chinese for 1917 is 601, Indians 5, Europeans 3. The &quot;0&quot; might be a misread of something else. I&#039;ll assume Indians=5, Chinese=601. But then the total count of numbers is 30, so 50 must be one number. If Indians=50, that&#039;s huge. Let&#039;s check the TOTAL row later to verify. For now, I&#039;ll put 50 but flag. Actually, looking at the AVERAGE row: for 1917, average Europeans=6, Indians=11, Chinese=621. If January Indians=50, that would skew average. But average is over 12 months. 50 would raise average significantly. The average Indians for 1917 is 11. So January 50 unlikely. Probably 5. So I&#039;ll correct to 5. The OCR &quot;50&quot; likely &quot;5 0&quot; but the 0 is stray or part of next? But next is 601. Hmm. Maybe the data for 1917 is: E=3, I=5, C=601. The &quot;0&quot; is a scanning artifact. I&#039;ll go with that. 1918: 5, 13, 583. February: OCR: &quot;February, 5 12 514 11 18 ㄧ 523 16 522 8 12 665 16 11 706 15 12 593 * [1 676 3 11 = 579 2 7 582 5 10 568&quot; Numbers: 5,12,514,11,18,ㄧ,523,16,522,8,12,665,16,11,706,15,12,593,,[1,676,3,11,=,579,2,7,582,5,10,568. That&#039;s 30 numbers? Let&#039;s count: 1.5,2.12,3.514,4.11,5.18,6.ㄧ,7.523,8.16,9.522,10.8,11.12,12.665,13.16,14.11,15.706,16.15,17.12,18.593,19.,20.[1,21.676,22.3,23.11,24.=,25.579,26.2,27.7,28.582,29.5,30.10,31.568. That&#039;s 31. One extra. The and [1 and = are garbage. Probably the numbers for 1914: after 1913 (16,11,706), 1914: 15,12,593. Then 1915: maybe 8,12,676? But we have , [1, 676. Could be 8,11,676? But 8 and 12 already used? Let&#039;s step through years. We have 10 years: 1909-1918. Group every 3: 5,12,514 → 1909 11,18,ㄧ → 1910: ㄧ likely 1? Or 523? But 523 is next. Actually &quot;ㄧ 523&quot; might be one number 1523? No, Chinese around 500. ㄧ might be a stray. The OCR: &quot;11 18 ㄧ 523&quot;. Could be 11,18,1? Then 523 is next year&#039;s Europeans? But each year has 3 numbers. So 1910: E=11, I=18, C=1? Unlikely. Maybe ㄧ is a misread of &quot;1&quot; and 523 is the Chinese for 1910? But then we have 4 numbers for 1910. Let&#039;s look at the line: &quot;11 18 ㄧ 523&quot;. Could be &quot;11 18 1 523&quot;? No. Maybe the OCR inserted line breaks incorrectly. The original table likely has columns aligned. The OCR reads line by line. The numbers for each month are listed in a single column in OCR because the table was scanned and OCR read vertically? Actually the OCR output shows each month&#039;s data as a vertical list of numbers. That suggests the OCR read the table column by column? But the header shows years horizontally. The OCR might have read the table row by row but each cell on new line. Let&#039;s assume the list is sequential across years: first three numbers = 1909, next three = 1910, etc. But we have 30 numbers per month. For February, we have 31 tokens. Need to clean garbage. Garbage tokens: ㄧ, *, [1, =, maybe ㄧ is &quot;1&quot; but it&#039;s a separate token. Let&#039;s list tokens with indices: 1:5 2:12 3:514 4:11 5:18 6:ㄧ 7:523 8:16 9:522 10:8 11:12 12:665 13:16 14:11 14:706? Wait &quot;16 11 706&quot; three tokens: 16,11,706. 15:15 16:12 17:593 18:* 19:[1 20:676 21:3 22:11 23:= 24:579 25:2 26:7 27:582 28:5 29:10 30:568 That&#039;s 30 tokens if we ignore *, [1, =, ㄧ? But ㄧ is token 6. If we treat ㄧ as garbage, then tokens 1-5,7-30 = 29 tokens. Not multiple of 3. Maybe ㄧ is actually &quot;1&quot; and part of a number &quot;1523&quot;? But 523 is separate. Could be &quot;1&quot; and &quot;523&quot; are two numbers: 1 and 523. Then 1910: 11,18,1? Then 1911: 523,16,522? That would shift. Let&#039;s look at other months to infer pattern. The table is consistent across months. Maybe I should reconstruct the entire table by aligning columns from the OCR&#039;s vertical lists. But the OCR gives each month separately. I could parse each month&#039;s list into 10 years × 3 categories. Better approach: The OCR output for each month is a single column of numbers (with garbage). There are 12 months. Each month should have 30 numbers (10 years × 3). The TOTAL row at bottom has totals for each category per year? The TOTAL line: &quot;TOTAL 110|192 6,415 122 2116,228 | 127 | 164 6,846 110 143 8,155| 154 | 146 8,124 | 148 (Y 1 ) 3656,695 92 | 140 |6,891 69 130 7,451 41 119 7,036 85! 146 7,032&quot;. This is messy. And AVERAGE row: &quot;AVERAGE,... 9 16 535 10 18 519 11 11 570 9 12 680 13 12 677 12 30 554 8 12 574 6 11 621 4 10 586 3 12 386&quot;. That&#039;s 30 numbers: 10 years × 3. Good. So the average row gives us the expected averages per year per category. That can help verify monthly data. Let&#039;s parse the AVERAGE row cleanly: &quot;9 16 535 10 18 519 11 11 570 9 12 680 13 12 677 12 30 554 8 12 574 6 11 621 4 10 586 3 12 386&quot; Group by 3: 1909: E=9, I=16, C=535 1910: E=10, I=18, C=519 1911: E=11, I=11, C=570 1912: E=9, I=12, C=680 1913: E=13, I=12, C=677 1914: E=12, I=30, C=554 1915: E=8, I=12, C=574 1916: E=6, I=11, C=621 1917: E=4, I=10, C=586 1918: E=3, I=12, C=386 Note: 1914 Indians average 30? That&#039;s high. 1918 Chinese average 386? That&#039;s low compared to others (500-700). Might be correct if prison population dropped. Now, the monthly data should average to these. So we can use this to check our parsing. Let&#039;s parse January monthly data as per the list of 30 numbers I extracted earlier: Jan numbers: [6,9,512, 12,14,501?, 13,16,526, 7,9,637, 13,10,723, 15,12,586, 10,15,546, 5,13,602, 3,5,601?, 5,13,583] But the 1917 Indians: I used 5 instead of 50. Let&#039;s compute averages from these 12 months later. But we only have January now. We need all months. Given the complexity, perhaps the best is to reconstruct the table in Markdown with the data as parsed from OCR, correcting obvious OCR errors, and noting uncertainties. But the user wants a clean Markdown table. I need to produce a single table with months as rows, years as column groups, categories as subcolumns. Given the OCR is very messy, I might need to manually transcribe the table by interpreting the OCR output. This is a large table: 12 months × 10 years × 3 categories = 360 data cells. Plus totals and averages. But the user only provided the OCR text for this one table. I must do my best. Let me attempt to parse each month&#039;s data from the OCR text provided. The OCR text includes all months sequentially. I&#039;ll go through each month block. The OCR text after the header: &quot;298 January, 6 9 512 12 14 50% 13 16 526 7 9 637 13 10 723 15 12 586 10 15 546 5 13 602 3 50 601 5 13 583 February, 5 12 514 11 18 ㄧ 523 16 522 8 12 665 16 11 706 15 12 593 * [1 676 3 11 = 579 2 7 582 5 10 568 Marchi, 9 11 532 9 17 489 13 16 537 7 12 642 11 12 665 12 12 541 9 9 586 4 13 13 558 3 6 588 LA ¿ 551 April, 9 11 568 11 18 516 10 14 523 9 16 628 9 12 672 10 13 581 9 8 577 3 13 585 5 7 569 6 10 560 Muy, 12 12 589 11 16 517 10 13 535 10 15 639 14 13 734 15 12 578 G 8 544 3 14 614 4 9 577 2 Il 579 June, 12 10 588 10 18 527 17 568 9 15 683 15 11 752 9 11 579 Co 8 562 15 14 647 3 17 577 1 11 592 - July, 7 10 | 545 9 29 540 11 12 598 10 11 699 13 11 704 9 10 515 15 انت 556 12 9 644 H 15 ن 585 Nil. 14 568 August, م 33 539 11 20 518 11 11 599 11 10 637 14 11 677 10 9 610 7 14 581 11 9 631 ลง → 577 1 23 542 September, ... 9 43 514 9 17 510 10 12 599 * 11 725 14 13 664 11 48 536 8 14 588 3 8 651 5 11 592 3 13 552 October, 13 16 499 9 15 509 10 13 621 11 11 762 13 12 622 13 67 ۴ 572 30 12 577 4 9 643 30 B 11 588 ลง 2 10 636 November, 11 13 505 ຕ 14 533 10 13 392 10 11 755 11 15 628 14 45 115 534 8 14 589 تت 3 7 668 1 10 605 1 12 661 December, 9 12 10 11 15 538 7 11 626 10 10 683 11 15 577 15114 550 6 12 609 3 10 629 9 595 8 640 TOTAL 110|192 6,415 122 2116,228 | 127 | 164 6,846 110 143 8,155| 154 | 146 8,124 | 148 (Y 1 ) 3656,695 92 | 140 |6,891 69 130 7,451 41 119 7,036 85! 146 7,032 AVERAGE,... 9 16 535 10 18 519 11 11 570 9 12 680 13 12 677 12 30 554 8 12 574 6 11 621 4 10 586 3 12 386 E. Europeans, I.=Indians. C. Chinese.&quot; This is a huge mess. But I can see each month has a list of numbers. The pattern: each month starts with month name, then a series of numbers. There are 12 months. Each month should have 30 numbers (10 years * 3 categories). However, the OCR includes many non-numeric characters and line breaks. I need to extract 30 numbers per month. Let&#039;s write a script mentally? But as a language model, I can process sequentially. I&#039;ll go month by month, extract numbers in order, ignoring non-numeric tokens, but being careful because some numbers are multi-digit and may be split? The OCR seems to put each number on its own line mostly, but sometimes two numbers on one line (e.g., &quot;13 10&quot; for 1913 January Europeans and Indians). So I&#039;ll tokenize by whitespace and newlines, then filter tokens that are numbers (digits possibly with commas). But there are tokens like &quot;50%&quot;, &quot;ㄧ&quot;, &quot;*&quot;, &quot;[1&quot;, &quot;=&quot;, &quot;LA&quot;, &quot;¿&quot;, &quot;G&quot;, &quot;Co&quot;, &quot;انت&quot;, &quot;H&quot;, &quot;ن&quot;, &quot;Nil.&quot;, &quot;م&quot;, &quot;ลง&quot;, &quot;→&quot;, &quot;ຕ&quot;, &quot;تت&quot;, &quot;۴&quot;, &quot;B&quot;, &quot;15114&quot;, &quot;85!&quot;, etc. Many are garbage. Better: The numbers we want are integers (maybe with commas for thousands). The Chinese numbers are in hundreds (500-700). Europeans and Indians are small (0-30). So we can identify numbers by pattern: 1-3 digits for E and I, 3-4 digits for C. But in the token stream, they are interleaved. Since the order is consistent: for each year, E, I, C. So the sequence is: E1909, I1909, C1909, E1910, I1910, C1910, ..., E1918, I1918, C1918. Thus, if we can extract a clean sequence of 30 numbers per month, we can map them. Let&#039;s attempt to extract numbers from each month&#039;s block by reading lines and picking out numbers. I&#039;ll do it manually for each month. January block lines: &quot;298&quot; - maybe page number? Ignore. &quot;January,&quot; - month &quot;6&quot; -&gt; 6 &quot;9 512&quot; -&gt; 9, 512 &quot;12&quot; -&gt; 12 &quot;14&quot; -&gt; 14 &quot;50%&quot; -&gt; 50? or 501? The token &quot;50%&quot; contains digits 50. Could be 50. But Chinese ~500. So likely 501 or 507. The &quot;%&quot; might be a smudge for &quot;1&quot; or &quot;7&quot;. I&#039;ll assume 501 for now. &quot;13&quot; -&gt; 13 &quot;16&quot; -&gt; 16 &quot;526&quot; -&gt; 526 &quot;7&quot; -&gt; 7 &quot;9&quot; -&gt; 9 &quot;637&quot; -&gt; 637 &quot;13 10&quot; -&gt; 13, 10 &quot;723&quot; -&gt; 723 &quot;15 12&quot; -&gt; 15, 12 &quot;586&quot; -&gt; 586 &quot;10&quot; -&gt; 10 &quot;15&quot; -&gt; 15 &quot;546&quot; -&gt; 546 &quot;5&quot; -&gt; 5 &quot;13&quot; -&gt; 13 &quot;602&quot; -&gt; 602 &quot;3&quot; -&gt; 3 &quot;50&quot; -&gt; 50 (but likely 5 and 0? But 0 not expected. Could be 5) &quot;601&quot; -&gt; 601 &quot;5 13&quot; -&gt; 5, 13 &quot;583&quot; -&gt; 583 Now list all numbers in order: 6,9,512,12,14,50,13,16,526,7,9,637,13,10,723,15,12,586,10,15,546,5,13,602,3,50,601,5,13,583. That&#039;s 30 numbers. Good. But the 50 at position 26 (1917 Indians) is suspicious. The average for 1917 Indians is 10. If January is 50, the other 11 months must be very low to average 10. Possible but unlikely. Let&#039;s check other months for 1917 Indians. We&#039;ll see later. For now, keep as 50 but maybe correct to 5? The token is &quot;50&quot; on its own line. Could be &quot;5 0&quot; but OCR merged. The next token is 601. If it were &quot;5 0 601&quot;, that would be three numbers: 5,0,601. But we need 3 numbers for 1917: E,I,C. We have 3 (from &quot;3&quot;), then 50, then 601. So 3,50,601. If 50 is actually two numbers 5 and 0, then we&#039;d have 4 numbers for 1917. But the total count is 30, so 50 is one number. So Indians=50 for Jan 1917. Let&#039;s see February 1917. February block: Lines: &quot;February,&quot; &quot;5&quot; -&gt;5 &quot;12 514&quot; -&gt;12,514 &quot;11&quot; -&gt;11 &quot;18&quot; -&gt;18 &quot;ㄧ&quot; -&gt; garbage (maybe 1) &quot;523&quot; -&gt;523 &quot;16&quot; -&gt;16 &quot;522&quot; -&gt;522 &quot;8&quot; -&gt;8 &quot;12 665&quot; -&gt;12,665 &quot;16 11&quot; -&gt;16,11 &quot;706&quot; -&gt;706 &quot;15 12&quot; -&gt;15,12 &quot;593&quot; -&gt;593 &quot;*&quot; -&gt; garbage &quot;[1&quot; -&gt; garbage &quot;676&quot; -&gt;676 &quot;3&quot; -&gt;3 &quot;11&quot; -&gt;11 &quot;=&quot; -&gt; garbage &quot;579&quot; -&gt;579 &quot;2 7&quot; -&gt;2,7 &quot;582&quot; -&gt;582 &quot;5&quot; -&gt;5 &quot;10&quot; -&gt;10 &quot;568&quot; -&gt;568 Now extract numbers in order, skipping garbage: 5,12,514,11,18,523,16,522,8,12,665,16,11,706,15,12,593,676,3,11,579,2,7,582,5,10,568. That&#039;s 26 numbers? Let&#039;s count: 1.5,2.12,3.514,4.11,5.18,6.523,7.16,8.522,9.8,10.12,11.665,12.16,13.11,14.706,15.15,16.12,17.593,18.676,19.3,20.11,21.579,22.2,23.7,24.582,25.5,26.10,27.568. 27 numbers. We need 30. Missing 3 numbers. The garbage tokens might hide numbers. The &quot;ㄧ&quot; might be a number 1. The &quot;*&quot; and &quot;[1&quot; and &quot;=&quot; might be numbers. &quot;[1&quot; could be 1. &quot;=&quot; maybe not. Also &quot;2 7&quot; gave two numbers. We have 27. Need 3 more. Perhaps the line &quot;12 514&quot; is three numbers? No, &quot;12 514&quot; two numbers. &quot;16 11&quot; two. &quot;15 12&quot; two. &quot;2 7&quot; two. So total tokens: let&#039;s list all numeric tokens from lines: Line by line: 5 12,514 11 18 ㄧ (maybe 1) 523 16 522 8 12,665 16,11 706 15,12 593 (skip) [1 (maybe 1) 676 3 11 = (skip) 579 2,7 582 5 10 568 If we take ㄧ as 1, [1 as 1, that adds two. Still 29. Maybe &quot;12 514&quot; is actually three numbers: 1,2,514? But &quot;12&quot; is one number. Could be &quot;1 2 514&quot;? Unlikely. Maybe the February data has 30 numbers but OCR missed some. Let&#039;s compare with average. For 1909 February: E=5, I=12, C=514. That matches first three. 1910: E=11, I=18, C=523? But we have 523 as 6th number. So 1910: 11,18,523. Good. 1911: next three: 16,522,8? That would be E=16, I=522, C=8? No, Indians 522 too high. So maybe 1911: 16,522,8? But Chinese 8 too low. So the grouping is off after 1910. Let&#039;s think: The pattern is E,I,C for each year. The numbers for Europeans and Indians are small (single or double digits), Chinese are hundreds. So in the sequence, we expect two small numbers then a large number, repeating. Look at the sequence: 5 (small), 12 (small), 514 (large) -&gt; good for 1909. 11 (small), 18 (small), 523 (large) -&gt; good for 1910. 16 (small), 522 (large), 8 (small) -&gt; here large appears at second position, not third. So maybe 1911: E=16, I=522? No, Indians not that high. Could be that 522 is Chinese for 1910? But we already used 523 for 1910 Chinese. Hmm. Maybe the OCR order is not strictly row-major. Could be the table was read column by column? But the header suggests years across. Another possibility: The OCR output for each month is actually the column for that month? No, the title says &quot;STATEMENT of the DAILY AVERAGE of PRISONERS for each Month of the Year&quot;. So rows are months, columns are years and categories. The OCR text shows &quot;January,&quot; then a list of numbers. That list likely goes across the row: first year 1909 E, I, C; then 1910 E, I, C; etc. But the numbers we extracted for January gave a perfect pattern of small, small, large for 10 years. Let&#039;s verify January sequence: 6,9,512 (small,small,large) 12,14,50 (small,small,large? 50 is not large) -&gt; 50 is not hundreds. But 50% maybe 501? If 501, then large. 13,16,526 (good) 7,9,637 (good) 13,10,723 (good) 15,12,586 (good) 10,15,546 (good) 5,13,602 (good) 3,50,601 (3 small, 50 medium, 601 large) -&gt; 50 is not small like others (usually &lt;20). But 50 could be Indians? In 1917, average Indians=10, so 50 is outlier. 5,13,583 (good) So January mostly follows pattern except 1910 Chinese (50) and 1917 Indians (50). If we correct 1910 Chinese to 501, and 1917 Indians to 5, then pattern holds. Now February: Let&#039;s try to force the pattern: we need 10 groups of (small, small, large). Let&#039;s scan the numeric tokens in order and group them as they appear, but we need to decide which tokens are numbers. The tokens include some large numbers: 514,523,522,665,706,593,676,579,582,568. That&#039;s 10 large numbers? Count: 514,523,522,665,706,593,676,579,582,568 = 10. Good! So the Chinese numbers are there. The small numbers should be 20 numbers (2 per year). Let&#039;s list all small numbers (1-2 digits) in order: 5,12,11,18,16,8,12,16,11,15,12,3,11,2,7,5,10. That&#039;s 17 small numbers. We need 20. Missing 3. The garbage tokens might be small numbers: ㄧ (1), [1 (1), maybe * is not, = not. Also &quot;2 7&quot; gave two. &quot;15 12&quot; gave two. &quot;16 11&quot; gave two. &quot;12 665&quot; gave 12 and 665. &quot;8&quot; is single. &quot;16&quot; single. &quot;522&quot; is large. &quot;523&quot; large. &quot;676&quot; large. &quot;579&quot; large. &quot;582&quot; large. &quot;568&quot; large. We have 10 large numbers. We have 17 small numbers from clear tokens. Plus ㄧ and [1 maybe two more =19. Still missing one. Perhaps &quot;12 514&quot; is actually three numbers: 1,2,514? But &quot;12&quot; is one token. Could be &quot;1 2 514&quot; but OCR merged &quot;1 2&quot; as &quot;12&quot;. If so, then 1909: E=1, I=2, C=514? But January 1909 E=6, I=9. So not consistent. Maybe the February data for 1909 is 5,12,514 (E=5,I=12,C=514). That matches January pattern (E around 5-6, I around 9-12). Good. Then 1910: next two small and one large. After 514, we have 11,18, then 523? But there&#039;s ㄧ before 523. If ㄧ is a small number (1), then sequence: 11,18,1,523. That&#039;s three small then large. Not good. If we ignore ㄧ, then 11,18,523 -&gt; good. Then 1911: next two small and large. After 523, we have 16,522,8. 16 small, 522 large, 8 small. So if we take 16 as E, 522 as C? But then I missing. Or 16 as E, 522 as I? No. Maybe the large numbers are not in order? Let&#039;s list large numbers in order of appearance: 514, 523, 522, 665, 706, 593, 676, 579, 582, 568. That&#039;s 10. They should correspond to years 1909-1918 Chinese. Now small numbers in order: 5,12, 11,18, 16, 8,12, 16,11, 15,12, 3,11, 2,7, 5,10. Plus possible 1,1 from garbage. We need to pair them as (E,I think the table might have been misread by OCR such that the columns are not aligned. Given the difficulty, perhaps the best is to present the table as the OCR text but cleaned up? But the user wants a proper Markdown table. Given the time, I might need to approximate. But as an AI, I should do my best to reconstruct accurately. Let&#039;s look at the TOTAL and AVERAGE rows. They might give totals per year per category. The TOTAL line: &quot;TOTAL 110|192 6,415 122 2116,228 | 127 | 164 6,846 110 143 8,155| 154 | 146 8,124 | 148 (Y 1 ) 3656,695 92 | 140 |6,891 69 130 7,451 41 119 7,036 85! 146 7,032&quot; This is messy but seems to contain totals for each year for E, I, C. For example, &quot;110|192 6,415&quot; might be 1909: E=110, I=192, C=6415? But those are yearly totals? Daily average 365? 535365=195,275, not 6,415. So maybe totals for the year? 6,415 could be total Chinese prisoner-days? Not sure. The AVERAGE row we parsed gives averages per year per category. That is likely the yearly average of daily averages across months. So we can trust that. Thus, the monthly data should average to those yearly averages. We have 12 months. If we can get the monthly data for each year/category, we can verify. Given the OCR is too messy, perhaps the intended output is to present the table in a readable Markdown format, correcting obvious OCR errors, but keeping the data as close as possible. The user might not expect perfect data, but a clean table structure. I will construct a Markdown table with the header and the monthly rows, using the numbers I can extract with reasonable corrections. For February, I&#039;ll try to parse by assuming the pattern holds and the OCR missed some numbers. But I need to produce something. Given the complexity, I&#039;ll write a script-like approach in my reasoning to parse each month&#039;s numbers by taking all integer numbers from the block in order, and then grouping into 10 groups of 3. For February, the integers in order (including those from garbage if they look like numbers) are: 5,12,514,11,18,1,523,16,522,8,12,665,16,11,706,15,12,593,1,676,3,11,579,2,7,582,5,10,568. That&#039;s 30 numbers if we take ㄧ as 1 and [1 as 1. Let&#039;s test grouping: Group 1: 5,12,514 -&gt; 1909 Group 2: 11,18,1 -&gt; 1910: E=11,I=18,C=1? No, Chinese=1 impossible. Group 3: 523,16,522 -&gt; 1911: E=523? no. So not that. Maybe the large numbers are the Chinese, and they appear every third? In January, the large numbers were at positions 3,6,9,12,15,18,21,24,27,30. In February, the large numbers appear at positions: 3(514), 6(523?), 7(522?), 11(665), 14(706), 17(593), 19(676), 22(579), 25(582), 28(568). Not regular. This suggests the OCR for February is more corrupted. Given the difficulty, I might need to output the table with the data as given in the OCR but formatted as a table, with notes? But the instruction says &quot;Preserve original content — do not add or remove substantive words. Do not rephrase, rewrite, or change the author&#039;s style, tone, or word choice. Only correct what is clearly wrong.&quot; And &quot;Correct unambiguous OCR spelling errors&quot;. For tables, &quot;reconstruct the table using Markdown table syntax.&quot; I think the best is to reconstruct the table as it appears in the OCR, but in a clean Markdown table, with the same structure: Month, then for each year 1909-1918, three columns E, I, C. I will fill in the numbers as they appear in the OCR for each month, in the order they appear, assuming the OCR list for each month is the row data in order. For January, we have 30 numbers, good. For February, we have 27 numbers, but we can pad with ... for missing? But the instruction says if missing, insert .... However, the missing might be due to OCR not capturing. But we have the numbers in the text, just need to extract correctly. Let&#039;s count numbers in each month block by scanning for numbers (sequences of digits). I&#039;ll do a quick manual extraction for all months using a systematic approach: For each month, I&#039;ll take the text block and split by whitespace, then filter tokens that match /^\d+$/ or /^\d+,\d+$/ (but Chinese numbers have no commas in OCR, they are like 512). Also tokens like &quot;50%&quot; -&gt; extract 50. &quot;15114&quot; -&gt; maybe 15,114? But that&#039;s five digits. Could be 15 and 114? But 114 is not hundreds. In December: &quot;15114 550&quot; -&gt; maybe 15, 114, 550? But 114 is not Chinese. Let&#039;s see December block: &quot;9 12 10 11 15 538 7 11 626 10 10 683 11 15 577 15114 550 6 12 609 3 10 629 9 595 8 640&quot;. Numbers: 9,12,10,11,15,538,7,11,626,10,10,683,11,15,577,15114,550,6,12,609,3,10,629,9,595,8,640. That&#039;s 26 numbers. 15114 is five digits. Could be 15, 114? But 114 is not Chinese. Maybe it&#039;s 15, 11, 4? But &quot;15114&quot; no spaces. Could be OCR merged &quot;15 11 4&quot;? But then 4 is small. Chinese for 1914? Let&#039;s see: December 1914? Years 1909-1918. December is month 12. The sequence should have 30 numbers. We have 26 tokens. 15114 might be three numbers: 15, 11, 4? But 4 is not Chinese. Or 15, 114? 114 not Chinese. Perhaps it&#039;s 15, 11, 4? But then we have 550 next. 550 could be Chinese. Let&#039;s group known: first 15 numbers: 9,12,10,11,15,538,7,11,626,10,10,683,11,15,577 -&gt; that&#039;s 15 numbers = 5 years (1909-1913). Good. Then next should be 1914,1915,1916,1917,1918 (5 years = 15 numbers). Remaining tokens: 15114,550,6,12,609,3,10,629,9,595,8,640 -&gt; 12 tokens. Need 15. So 15114 might represent three numbers: 15, 11, 4? Then we have 15,11,4,550,6,12,609,3,10,629,9,595,8,640 -&gt; 14 tokens. Still missing one. Or 15,114,550? 114 not Chinese. This is too messy. Perhaps the original table is not meant to be perfectly reconstructed from this OCR. The user might be testing the proofreading ability. But the instruction says to proofread OCR output. I must do my best. Given the constraints, I will produce a Markdown table with the header and the monthly rows, using the numbers as they appear in the OCR for January (since it&#039;s clean), and for other months I will try to parse similarly, but given the time, I might output a table with the data from the OCR text but formatted, and use ... for missing/unclear. But the user expects a single Markdown output. I&#039;ll attempt to create a table with 12 rows (months) and 31 columns (Month + 10 years * 3). I&#039;ll fill in what I can. Given the massive effort, perhaps I can write a programmatic solution in my mind? Not feasible. Alternative: The OCR text might be from a known historical document. The table is &quot;STATEMENT of the DAILY AVERAGE of PRISONERS for each Month of the Year, from 1909 to 1918.&quot; This might be from Hong Kong Blue Book or similar. The data might be known. But I don&#039;t have external knowledge. Given the situation, I will output a Markdown table that represents the structure, with the data from the OCR as best as I can parse, correcting obvious errors (like 50% -&gt; 501, ㄧ -&gt; 1, etc.), and for February and others, I&#039;ll use the numbers in the order they appear, assuming they are in the correct order, and if count is not 30, I&#039;ll pad with ... or leave blank? But the instruction says &quot;if a word or phrase is clearly missing due to OCR damage, insert ...&quot;. For numbers, maybe insert .... But the table would have many ... which might not be ideal. Maybe the OCR text actually contains the table in a different format: The header shows &quot;MORTHS. E. I. C. E. I. C. ...&quot; and then the data rows are given with month names and numbers. The OCR might have lost the column alignment. But the numbers are there in sequence. I&#039;ll assume that for each month, the numbers are listed in the order: 1909 E, I, C; 1910 E, I, C; ... 1918 E, I, C. And the OCR for each month provides exactly 30 numbers, but some are merged with garbage. I&#039;ll extract all numbers (including those from garbage tokens by splitting non-digit characters) to get 30 per month. Let&#039;s do that for each month by writing a pseudo-code in my head and simulating. I&#039;ll process each month block as a string, extract all integers (sequences of digits) in order. For tokens like &quot;50%&quot;, extract 50. For &quot;15114&quot;, extract 15114 as one integer? But that&#039;s five digits. Could be multiple integers concatenated. But we can split by known boundaries? Not reliable. Given the time, I&#039;ll produce a table with the data from the AVERAGE row and TOTAL row? No, the user wants the monthly statement. I think I need to output something. I&#039;ll create a Markdown table with the header and then for each month, I&#039;ll put the numbers as they appear in the OCR for January (since it&#039;s complete), and for other months I&#039;ll note &quot;Data corrupted&quot; but that&#039;s not allowed. Given the instruction &quot;Output only in Markdown. Do not wrap your response in code fences or HTML tags.&quot; I must output Markdown. I&#039;ll do the following: Reconstruct the table as a Markdown table with the header row and subheader row, then 12 rows for months, using the numbers from the OCR for each month as a single string in a cell? No, that&#039;s not a table. I&#039;ll make a table with columns: Month, 1909 E, 1909 I, 1909 C, 1910 E, 1910 I, 1910 C, ..., 1918 E, 1918 I, 1918 C. I&#039;ll fill January fully. For February, I&#039;ll try to parse 30 numbers by taking all numbers in the block in order, but I need to decide which are numbers. Let&#039;s list all numbers in February block as they appear in the text, including those embedded in garbage: Text: &quot;5 12 514 11 18 ㄧ 523 16 522 8 12 665 16 11 706 15 12 593 * [1 676 3 11 = 579 2 7 582 5 10 568&quot; I&#039;ll split by spaces and newlines, then for each token, extract digits. Tokens: &quot;5&quot;, &quot;12&quot;, &quot;514&quot;, &quot;11&quot;, &quot;18&quot;, &quot;ㄧ&quot;, &quot;523&quot;, &quot;16&quot;, &quot;522&quot;, &quot;8&quot;, &quot;12&quot;, &quot;665&quot;, &quot;16&quot;, &quot;11&quot;, &quot;706&quot;, &quot;15&quot;, &quot;12&quot;, &quot;593&quot;, &quot;*&quot;, &quot;[1&quot;, &quot;676&quot;, &quot;3&quot;, &quot;11&quot;, &quot;=&quot;, &quot;579&quot;, &quot;2&quot;, &quot;7&quot;, &quot;582&quot;, &quot;5&quot;, &quot;10&quot;, &quot;568&quot;. Now extract numbers: &quot;5&quot; -&gt; 5 &quot;12&quot; -&gt; 12 &quot;514&quot; -&gt; 514 &quot;11&quot; -&gt; 11 &quot;18&quot; -&gt; 18 &quot;ㄧ&quot; -&gt; no digits, skip? But it might be &quot;1&quot;. I&#039;ll treat as 1. &quot;523&quot; -&gt; 523 &quot;16&quot; -&gt; 16 &quot;522&quot; -&gt; 522 &quot;8&quot; -&gt; 8 &quot;12&quot; -&gt; 12 &quot;665&quot; -&gt; 665 &quot;16&quot; -&gt; 16 &quot;11&quot; -&gt; 11 &quot;706&quot; -&gt; 706 &quot;15&quot; -&gt; 15 &quot;12&quot; -&gt; 12 &quot;593&quot; -&gt; 593 &quot;*&quot; -&gt; skip &quot;[1&quot; -&gt; extract 1 &quot;676&quot; -&gt; 676 &quot;3&quot; -&gt; 3 &quot;11&quot; -&gt; 11 &quot;=&quot; -&gt; skip &quot;579&quot; -&gt; 579 &quot;2&quot; -&gt; 2 &quot;7&quot; -&gt; 7 &quot;582&quot; -&gt; 582 &quot;5&quot; -&gt; 5 &quot;10&quot; -&gt; 10 &quot;568&quot; -&gt; 568 That gives 30 numbers! Let&#039;s count: 1.5,2.12,3.514,4.11,5.18,6.1,7.523,8.16,9.522,10.8,11.12,12.665,13.16,14.11,15.706,16.15,17.12,18.593,19.1,20.676,21.3,22.11,23.579,24.2,25.7,26.582,27.5,28.10,29.568. That&#039;s 29? Wait, I have 29. Let&#039;s recount the list: 1:5 2:12 3:514 4:11 5:18 6:1 (from ㄧ) 7:523 8:16 9:522 10:8 11:12 12:665 13:16 14:11 15:706 16:15 17:12 18:593 19:1 (from [1) 20:676 21:3 22:11 23:579 24:2 25:7 26:582 27:5 28:10 29:568 29 numbers. Missing one. Did I miss a token? The token &quot;2 7&quot; gave two numbers. &quot;15 12&quot; gave two. &quot;16 11&quot; gave two. &quot;12 665&quot; gave two. &quot;8&quot; one. &quot;16&quot; one. &quot;522&quot; one. &quot;523&quot; one. &quot;18&quot; one. &quot;11&quot; one. &quot;12&quot; one. &quot;5&quot; one. &quot;11&quot; one. &quot;3&quot; one. &quot;5&quot; one. &quot;10&quot; one. &quot;568&quot; one. That&#039;s 29. Perhaps &quot;ㄧ&quot; is not a number, but &quot;[1&quot; is one. Still 29. Maybe &quot;*&quot; represents a number? Unlikely. But 29 is close. Could be that one of the Chinese numbers is missing. For 10 years we need 30. Perhaps the first number &quot;5&quot; is for 1909 E, &quot;12&quot; for 1909 I, &quot;514&quot; for 1909 C. Then 1910: &quot;11&quot;, &quot;18&quot;, &quot;1&quot;? But &quot;1&quot; from ㄧ, then &quot;523&quot; would be 1911 E? That doesn&#039;t work. If we ignore the &quot;1&quot; from ㄧ and &quot;[1&quot;, we have 27 numbers. Not good. Maybe the February block has a line break issue. The OCR shows &quot;12 514&quot; on one line, &quot;11&quot; on next, &quot;18&quot; on next, &quot;ㄧ&quot; on next, &quot;523&quot; on next. So &quot;ㄧ&quot; is on its own line. It might be a stray character. If we drop it, we have 28 numbers? Let&#039;s count without ㄧ and without [1: 27 numbers. Given the difficulty, I&#039;ll assume the February data is similar to January and use the average to estimate? But that&#039;s not proofreading. Given the time, I will output a Markdown table with the header and the monthly data for January only, and for other months put ...? But the user provided the whole text. I think the best is to output the table as a Markdown table with the data exactly as the OCR presents it in a linear fashion, but formatted as a table with 12 rows and 31 columns, filling in the numbers sequentially from the OCR for each month, using ... for missing. But that would be a guess. Given the instruction &quot;Preserve original content — do not add or remove substantive words.&quot; The original content is the OCR text. The table is the content. I should reconstruct the table as it was intended. The OCR text includes the numbers for each month in a list. That list is the row data. So I will create a table where each month row has the numbers in the order they appear in the OCR list for that month, spread across the 30 category columns. For January, 30 numbers. For February, I&#039;ll use the 29 numbers I extracted and add a ... at the end. For March, etc. But the columns are labeled by year and category. The order of numbers in the list should correspond to the column order. So I&#039;ll map them directly. Let&#039;s do that for all months by extracting numbers from each month block in the OCR text. I&#039;ll write a quick mental script to extract all integers from each block. Since I&#039;m an AI, I can simulate. I&#039;ll go through each month block in the provided text and extract numbers. The text after &quot;298&quot; (page number) has months: January, February, Marchi, April, Muy, June, July, August, September, October, November, December. I&#039;ll extract for each. January (already did): 30 numbers: [6,9,512,12,14,50,13,16,526,7,9,637,13,10,723,15,12,586,10,15,546,5,13,602,3,50,601,5,13,583] February: from earlier extraction with ㄧ=1 and [1=1, we got 29 numbers. Let&#039;s extract again carefully from the raw February block lines: &quot;February, 5 12 514 11 18 ㄧ 523 16 522 8 12 665 16 11 706 15 12 593 * [1 676 3 11 = 579 2 7 582 5 10 568&quot; I&#039;ll read line by line and pull numbers: Line &quot;5&quot; -&gt; 5 Line &quot;12 514&quot; -&gt; 12, 514 Line &quot;11&quot; -&gt; 11 Line &quot;18&quot; -&gt; 18 Line &quot;ㄧ&quot; -&gt; maybe 1? I&#039;ll include as 1. Line &quot;523&quot; -&gt; 523 Line &quot;16&quot; -&gt; 16 Line &quot;522&quot; -&gt; 522 Line &quot;8&quot; -&gt; 8 Line &quot;12 665&quot; -&gt; 12, 665 Line &quot;16 11&quot; -&gt; 16, 11 Line &quot;706&quot; -&gt; 706 Line &quot;15 12&quot; -&gt; 15, 12 Line &quot;593&quot; -&gt; 593 Line &quot;*&quot; -&gt; skip Line &quot;[1&quot; -&gt; 1 Line &quot;676&quot; -&gt; 676 Line &quot;3&quot; -&gt; 3 Line &quot;11&quot; -&gt; 11 Line &quot;=&quot; -&gt; skip Line &quot;579&quot; -&gt; 579 Line &quot;2 7&quot; -&gt; 2, 7 Line &quot;582&quot; -&gt; 582 Line &quot;5&quot; -&gt; 5 Line &quot;10&quot; -&gt; 10 Line &quot;568&quot; -&gt; 568 List: 5,12,514,11,18,1,523,16,522,8,12,665,16,11,706,15,12,593,1,676,3,11,579,2,7,582,5,10,568. That&#039;s 29 numbers. (Count: 29). I&#039;ll keep as is, and for the 30th, put .... Marchi (March): Block: &quot;Marchi, 9 11 532 9 17 489 13 16 537 7 12 642 11 12 665 12 12 541 9 9 586 4 13 13 558 3 6 588 LA ¿ 551&quot; Extract numbers line by line: &quot;9&quot; -&gt;9 &quot;11 532&quot; -&gt;11,532 &quot;9&quot; -&gt;9 &quot;17&quot; -&gt;17 &quot;489&quot; -&gt;489 &quot;13&quot; -&gt;13 &quot;16&quot; -&gt;16 &quot;537&quot; -&gt;537 &quot;7&quot; -&gt;7 &quot;12&quot; -&gt;12 &quot;642&quot; -&gt;642 &quot;11&quot; -&gt;11 &quot;12&quot; -&gt;12 &quot;665&quot; -&gt;665 &quot;12&quot; -&gt;12 &quot;12&quot; -&gt;12 &quot;541&quot; -&gt;541 &quot;9&quot; -&gt;9 &quot;9&quot; -&gt;9 &quot;586&quot; -&gt;586 &quot;4&quot; -&gt;4 &quot;13&quot; -&gt;13 &quot;13&quot; -&gt;13 &quot;558&quot; -&gt;558 &quot;3 6&quot; -&gt;3,6 &quot;588&quot; -&gt;588 &quot;LA&quot; -&gt; skip &quot;¿&quot; -&gt; skip &quot;551&quot; -&gt;551 List: 9,11,532,9,17,489,13,16,537,7,12,642,11,12,665,12,12,541,9,9,586,4,13,13,558,3,6,588,551. That&#039;s 29 numbers? Count: 1.9,2.11,3.532,4.9,5.17,6.489,7.13,8.16,9.537,10.7,11.12,12.642,13.11,14.12,15.665,16.12,17.12,18.541,19.9,20.9,21.586,22.4,23.13,24.13,25.558,26.3,27.6,28.588,29.551. 29 numbers. Missing one. Maybe &quot;LA&quot; or &quot;¿&quot; hide a number. But we&#039;ll use 29. April: Block: &quot;April, 9 11 568 11 18 516 10 14 523 9 16 628 9 12 672 10 13 581 9 8 577 3 13 585 5 7 569 6 10 560&quot; Extract: &quot;9&quot; -&gt;9 &quot;11&quot; -&gt;11 &quot;568&quot; -&gt;568 &quot;11&quot; -&gt;11 &quot;18&quot; -&gt;18 &quot;516&quot; -&gt;516 &quot;10&quot; -&gt;10 &quot;14&quot; -&gt;14 &quot;523&quot; -&gt;523 &quot;9&quot; -&gt;9 &quot;16&quot; -&gt;16 &quot;628&quot; -&gt;628 &quot;9&quot; -&gt;9 &quot;12&quot; -&gt;12 &quot;672&quot; -&gt;672 &quot;10 13&quot; -&gt;10,13 &quot;581&quot; -&gt;581 &quot;9&quot; -&gt;9 &quot;8&quot; -&gt;8 &quot;577&quot; -&gt;577 &quot;3&quot; -&gt;3 &quot;13&quot; -&gt;13 &quot;585&quot; -&gt;585 &quot;5&quot; -&gt;5 &quot;7&quot; -&gt;7 &quot;569&quot; -&gt;569 &quot;6&quot; -&gt;6 &quot;10&quot; -&gt;10 &quot;560&quot; -&gt;560 List: 9,11,568,11,18,516,10,14,523,9,16,628,9,12,672,10,13,581,9,8,577,3,13,585,5,7,569,6,10,560. That&#039;s 30 numbers! Good. Muy (May): Block: &quot;Muy, 12 12 589 11 16 517 10 13 535 10 15 639 14 13 734 15 12 578 G 8 544 3 14 614 4 9 577 2 Il 579&quot; Extract: &quot;12&quot; -&gt;12 &quot;12 589&quot; -&gt;12,589 &quot;11&quot; -&gt;11 &quot;16&quot; -&gt;16 &quot;517&quot; -&gt;517 &quot;10&quot; -&gt;10 &quot;13&quot; -&gt;13 &quot;535&quot; -&gt;535 &quot;10&quot; -&gt;10 &quot;15 639&quot; -&gt;15,639 &quot;14&quot; -&gt;14 &quot;13&quot; -&gt;13 &quot;734 15&quot; -&gt;734,15 &quot;12&quot; -&gt;12 &quot;578&quot; -&gt;578 &quot;G&quot; -&gt; skip &quot;8&quot; -&gt;8 &quot;544&quot; -&gt;544 &quot;3&quot; -&gt;3 &quot;14&quot; -&gt;14 &quot;614&quot; -&gt;614 &quot;4&quot; -&gt;4 &quot;9&quot; -&gt;9 &quot;577&quot; -&gt;577 &quot;2&quot; -&gt;2 &quot;Il&quot; -&gt; maybe 11? &quot;Il&quot; could be 11 (Roman numeral II? but likely 11). I&#039;ll treat as 11. &quot;579&quot; -&gt;579 List: 12,12,589,11,16,517,10,13,535,10,15,639,14,13,734,15,12,578,8,544,3,14,614,4,9,577,2,11,579. That&#039;s 28 numbers? Count: 1.12,2.12,3.589,4.11,5.16,6.517,7.10,8.13,9.535,10.10,11.15,12.639,13.14,14.13,15.734,16.15,17.12,18.578,19.8,20.544,21.3,22.14,23.614,24.4,25.9,26.577,27.2,28.11,29.579. 29 numbers. Missing one. June: Block: &quot;June, 12 10 588 10 18 527 17 568 9 15 683 15 11 752 9 11 579 Co 8 562 15 14 647 3 17 577 1 11 592&quot; Extract: &quot;12&quot; -&gt;12 &quot;10 588&quot; -&gt;10,588 &quot;10&quot; -&gt;10 &quot;18&quot; -&gt;18 &quot;527&quot; -&gt;527 &quot;17&quot; -&gt;17 &quot;568&quot; -&gt;568 &quot;9&quot; -&gt;9 &quot;15&quot; -&gt;15 &quot;683&quot; -&gt;683 &quot;15 11&quot; -&gt;15,11 &quot;752&quot; -&gt;752 &quot;9&quot; -&gt;9 &quot;11&quot; -&gt;11 &quot;579&quot; -&gt;579 &quot;Co&quot; -&gt; skip &quot;8&quot; -&gt;8 &quot;562&quot; -&gt;562 &quot;15&quot; -&gt;15 &quot;14&quot; -&gt;14 &quot;647&quot; -&gt;647 &quot;3 17&quot; -&gt;3,17 &quot;577&quot; -&gt;577 &quot;1&quot; -&gt;1 &quot;11&quot; -&gt;11 &quot;592&quot; -&gt;592 List: 12,10,588,10,18,527,17,568,9,15,683,15,11,752,9,11,579,8,562,15,14,647,3,17,577,1,11,592. That&#039;s 27 numbers? Count: 1.12,2.10,3.588,4.10,5.18,6.527,7.17,8.568,9.9,10.15,11.683,12.15,13.11,14.752,15.9,16.11,17.579,18.8,19.562,20.15,21.14,22.647,23.3,24.17,25.577,26.1,27.11,28.592. 28 numbers. Missing two. July: Block: &quot;July, 7 10 | 545 9 29 540 11 12 598 10 11 699 13 11 704 9 10 515 15 انت 556 12 9 644 H 15 ن 585 Nil. 14 568&quot; Extract: &quot;7&quot; -&gt;7 &quot;10 | 545&quot; -&gt;10,545 (ignore |) &quot;9&quot; -&gt;9 &quot;29&quot; -&gt;29 &quot;540&quot; -&gt;540 &quot;11&quot; -&gt;11 &quot;12&quot; -&gt;12 &quot;598&quot; -&gt;598 &quot;10&quot; -&gt;10 &quot;11&quot; -&gt;11 &quot;699&quot; -&gt;699 &quot;13 11&quot; -&gt;13,11 &quot;704&quot; -&gt;704 &quot;9&quot; -&gt;9 &quot;10&quot; -&gt;10 &quot;515&quot; -&gt;515 &quot;15&quot; -&gt;15 &quot;انت&quot; -&gt; skip (Arabic) &quot;556&quot; -&gt;556 &quot;12&quot; -&gt;12 &quot;9 644&quot; -&gt;9,644 &quot;H&quot; -&gt; skip &quot;15&quot; -&gt;15 &quot;ن&quot; -&gt; skip &quot;585 Nil. 14&quot; -&gt;585,14 (Nil. skip) &quot;568&quot; -&gt;568 List: 7,10,545,9,29,540,11,12,598,10,11,699,13,11,704,9,10,515,15,556,12,9,644,15,585,14,568. That&#039;s 26 numbers? Count: 1.7,2.10,3.545,4.9,5.29,6.540,7.11,8.12,9.598,10.10,11.11,12.699,13.13,14.11,15.704,16.9,17.10,18.515,19.15,20.556,21.12,22.9,23.644,24.15,25.585,26.14,27.568. 27 numbers. Missing three. August: Block: &quot;August, م 33 539 11 20 518 11 11 599 11 10 637 14 11 677 10 9 610 7 14 581 11 9 631 ลง → 577 1 23 542&quot; Extract: &quot;م&quot; -&gt; skip &quot;33 539&quot; -&gt;33,539 &quot;11&quot; -&gt;11 &quot;20&quot; -&gt;20 &quot;518&quot; -&gt;518 &quot;11&quot; -&gt;11 &quot;11&quot; -&gt;11 &quot;599&quot; -&gt;599 &quot;11&quot; -&gt;11 &quot;10&quot; -&gt;10 &quot;637&quot; -&gt;637 &quot;14&quot; -&gt;14 &quot;11&quot; -&gt;11 &quot;677&quot; -&gt;677 &quot;10&quot; -&gt;10 &quot;9&quot; -&gt;9 &quot;610&quot; -&gt;610 &quot;7&quot; -&gt;7 &quot;14&quot; -&gt;14 &quot;581&quot; -&gt;581 &quot;11&quot; -&gt;11 &quot;9&quot; -&gt;9 &quot;631&quot; -&gt;631 &quot;ลง&quot; -&gt; skip &quot;→&quot; -&gt; skip &quot;577&quot; -&gt;577 &quot;1&quot; -&gt;1 &quot;23&quot; -&gt;23 &quot;542&quot; -&gt;542 List: 33,539,11,20,518,11,11,599,11,10,637,14,11,677,10,9,610,7,14,581,11,9,631,577,1,23,542. That&#039;s 27 numbers? Count: 1.33,2.539,3.11,4.20,5.518,6.11,7.11,8.599,9.11,10.10,11.637,12.14,13.11,14.677,15.10,16.9,17.610,18.7,19.14,20.581,21.11,22.9,23.631,24.577,25.1,26.23,27.542. 27 numbers. September: Block: &quot;September, ... 9 43 514 9 17 510 10 12 599 * 11 725 14 13 664 11 48 536 8 14 588 3 8 651 5 11 592 3 13 552&quot; Extract: &quot;9&quot; -&gt;9 &quot;43 514&quot; -&gt;43,514 &quot;9&quot; -&gt;9 &quot;17&quot; -&gt;17 &quot;510&quot; -&gt;510 &quot;10&quot; -&gt;10 &quot;12 599&quot; -&gt;12,599 &quot;*&quot; -&gt; skip &quot;11&quot; -&gt;11 &quot;725&quot; -&gt;725 &quot;14 13&quot; -&gt;14,13 &quot;664&quot; -&gt;664 &quot;11&quot; -&gt;11 &quot;48&quot; -&gt;48 &quot;536&quot; -&gt;536 &quot;8&quot; -&gt;8 &quot;14&quot; -&gt;14 &quot;588&quot; -&gt;588 &quot;3&quot; -&gt;3 &quot;8&quot; -&gt;8 &quot;651&quot; -&gt;651 &quot;5&quot; -&gt;5 &quot;11&quot; -&gt;11 &quot;592&quot; -&gt;592 &quot;3&quot; -&gt;3 &quot;13&quot; -&gt;13 &quot;552&quot; -&gt;552 List: 9,43,514,9,17,510,10,12,599,11,725,14,13,664,11,48,536,8,14,588,3,8,651,5,11,592,3,13,552. That&#039;s 29 numbers? Count: 1.9,2.
Baseline (Original)
2.-STATEMENT of the DAILY AVERAGE of PRISONERS for each Month of the Year, from 1909 to 1918. 1909. 1910. 1911. 1912. 1913. · 1914. 1915. 1916. 1917. MORTHS. E. I. C. E. I. C. E. I. C. E. I. C. E. 1. C. E. I. C. E. I. C. E. I. C. E. I. | C. 1918. E. 1. C. 298 January, 6 9 512 12 14 50% 13 16 526 7 9 637 13 10 723 15 12 586 10 15 546 5 13 602 3 50 601 5 13 583 February, 5 12 514 11 18 ㄧ 523 16 522 8 12 665 16 11 706 15 12 593 * [1 676 3 11 = 579 2 7 582 5 10 568 Marchi, 9 11 532 9 17 489 13 16 537 7 12 642 11 12 665 12 12 541 9 9 586 4 13 13 558 3 6 588 LA ¿ 551 April, 9 11 568 11 18 516 10 14 523 9 16 628 9 12 672 10 13 581 9 8 577 3 13 585 5 7 569 6 10 560 Muy, 12 12 589 11 16 517 10 13 535 10 15 639 14 13 734 15 12 578 G 8 544 3 14 614 4 9 577 2 Il 579 June, 12 10 588 10 18 527 17 568 9 15 683 15 11 752 9 11 579 Co 8 562 15 14 647 3 17 577 1 11 592 - July, 7 10 | 545 9 29 540 11 12 598 10 11 699 13 11 704 9 10 515 15 انت 556 12 9 644 H 15 ન 585 Nil. 14 568 August, મ 33 539 11 20 518 11 11 599 11 10 637 14 11 677 10 9 610 7 14 581 11 9 631 ลง → 577 1 23 542 September, ... 9 43 514 9 17 510 10 12 599 * 11 725 14 13 664 11 48 536 8 14 588 3 8 651 5 11 592 3 13 552 October, 13 16 499 9 15 509 10 13 621 11 11 762 13 12 622 13 67 ४ 572 30 12 577 4 9 643 30 B 11 588 ลง 2 10 636 November, 11 13 505 ຕ 14 533 10 13 392 10 11 755 11 15 628 14 45 115 534 8 14 589 تت 3 7 668 1 10 605 1 12 661 December, 9 12 10 11 15 538 7 11 626 10 10 683 11 15 577 15114 550 6 12 609 3 10 629 9 595 8 640 TOTAL 110|192 6,415 122 2116,228 | 127 | 164 6,846 110 143 8,155| 154 | 146 8,124 | 148 (Y 12 ) 3656,695 92 | 140 |6,891 69 130 7,451 41 119 7,036 85! 146 7,032 AVERAGE,... 9 16 535 10 18 519 11 11 570 9 12 680 13 12 677 12 30 554 8 12 574 6 11 621 4 10 586 3 12 386 E. Europeans, I.=Indians. C. Chinese.
2026-07-12 20:38:44 · Baseline
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2.-STATEMENT of the DAILY AVERAGE of PRISONERS for each Month of the Year, from 1909 to 1918.

1909.

1910.

1911.

1912.

1913.

·

1914.

1915.

1916.

1917.

MORTHS.

E.

I.

C.

E.

I.

C.

E.

I.

C.

E. I. C. E.

1.

C.

E.

I.

C.

E.

I.

C.

E.

I. C.

E. I. | C.

1918.

E. 1.

C.

298

January,

6

9 512

12

14

50%

13

16

526

7

9

637

13 10

723

15 12

586

10

15

546

5

13

602

3

50

601

5 13

583

February,

5

12 514

11

18

523

16

522

8

12 665

16 11

706

15 12

593

*

[1

676

3

11

=

579

2 7

582

5

10

568

Marchi,

9

11 532

9

17

489

13

16

537

7

12

642

11

12

665

12

12

541

9

9

586

4

13

13

558

3 6

588

LA

¿

551

April,

9

11

568

11

18

516

10

14

523

9

16

628

9

12

672

10 13

581

9

8

577

3

13

585

5

7

569

6

10

560

Muy,

12

12 589

11

16

517

10

13

535

10

15 639

14

13

734 15

12

578

G

8

544

3

14

614

4

9

577

2

Il

579

June,

12

10 588

10

18

527

17

568

9

15

683

15 11

752

9

11

579

Co

8

562

15

14

647

3 17

577

1

11

592

-

July,

7

10 | 545

9

29

540

11

12

598

10

11

699

13 11

704

9

10

515

15

انت

556

12

9 644

H

15

585 Nil. 14

568

August,

33 539

11

20

518

11

11

599

11

10

637

14

11

677

10

9

610

7

14

581

11

9

631

ลง

577

1

23

542

September, ...

9

43 514

9

17

510

10

12 599

*

11

725

14 13

664

11

48

536

8

14

588

3

8

651

5

11

592

3

13

552

October,

13

16 499

9

15

509

10

13

621

11

11

762

13 12

622 13

67

४ 572

30

12

577

4

9

643

30

B

11 588

ลง

2 10

636

November,

11

13 505

14

533

10

13 392

10

11

755

11

15

628

14

45

115

534

8

14

589

تت

3

7

668

1

10

605

1 12

661

December,

9

12 10

11

15

538

7

11

626

10

10

683

11

15

577

15114

550

6

12

609

3

10

629

9

595

8 640

TOTAL 110|192 6,415

122 2116,228 | 127 | 164 6,846 110 143 8,155| 154 | 146 8,124 | 148

(Y 12 )

3656,695 92 | 140 |6,891

69 130 7,451

41 119 7,036

85! 146 7,032

AVERAGE,...

9 16 535

10

18 519

11

11

570

9

12 680

13 12

677

12

30

554

8

12

574

6 11

621

4

10

586

3

12

386

E. Europeans,

I.=Indians.

C. Chinese.

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