( 19 )育教 聞港日七初月一十年日己磨夏
報日僑華
一期星 日四月二十(九八九一年八十七國民華中
育教日~
並致詞,隨後歡宴,氣泵洋溢。
主席榮产太平紳士,大會首長致送紀念品與仇 圍:旺角區同鄉宗親會聯誼食宴賀仇輝
e
香港出版業協會選出
八九至九〇年度執委
人大會,並選出一九八 儿至九章财政年慶行
十一月十日行3年2
香港出版業協會於
·圖 将出任主一颗,
代替頁本網誌領導及山人藥雞館,鄉氕生
華 加拿大雷立得事務所
主理拉丁美洲業務。
拿大移民簽世之顧客。 加拿大雷立得移民事務所之創辦人立得 十四噶風月軒設宴駐守其六十名已成功取得如 辦移民晚宴欸待顧客 KLEINER ROTH BARR
加拿大雷立得移民民事務所於一九八九年
十一月二十四日(星鼐五),寧怡東酒和春來 ·
亞洲商資雜誌(遠東貿易出版有限公司) 位,及後在班亞戋任蔭副總裁狖轉經理,全權
DEGFIE<PAUL HOLDEN 工作,而南華早報的貝萊讵到爲秘。 大亞灣財務出版社出版人饨候莉、亞洲週刊 — 執行委員會成員尙包括亞洲商出版(香
别香江南栩鬻一班志同道台之朋友,凄瘐习司,免有些轉任,全部
,就業情况,激寕,各待移民更可精此概會於 香港出版業協會於一九八二年成立,代表 之定義一迓講解加大之移民法律,殺務問題 人質黑及亞洲蔡爾街IX出版人高偉照。
TARR & Go One限公司出版人和維鑑、賽馬大工有限公司吕版
後於他鄉可互相照顧。
辦之加车大移民城功率達百分馆。 加拿大雷立得移民事務所於加拿大已有二 十年歷史其香港辦事處離成立天有二年,但所
[〇八室,電話五十四五八〇二六。 ,或預約會面。地址爲香港中淑太子大廈一四 事務所歡迎任何人仕查詢有關移民資料 圖:加拿天還立馬移民事務所舉辦狱晚
躲焕
福特的室內無錢電話,無論何
,經由你信管理局認可,是市面上接收力 和記傳照爲用戶精選推出的樂聲室内無
接收力特强使用簡便
樂聲牌室内無線電話
一米範圍內告接收清晰,
十四名獨立會員。 公司,如印刷,飛告凡公共關係公司,與及四
冬秋
色特
譜食
一正是淮補好時候
宮冬色譜,宗華國際酒店
之中菜廳
淮揚美食節後,推出全新的秋冬特色菜。 愁没有選擇,一系列濟宮期素如「翠竹冬些 和原怿瓦薛文洲有一番風味;感好弄食的出不 」,「竹筒肘子麼鮑翅」。此外,拜爐小雯和 「驚哒鏗风沙生祥」, 魚翅燉品方面種類也惭多,包括;福州佛紫紅 招牌名菜“妻宮三寶」,還有「良鄉上的」 唐宮秋冬菜諶包症各式各埭佳笑,如 1 - TP981.
」,「竹笙訊戀溪邊」等,亦街具特色 "
1990 中學會考預習專欄
Economic & Public Affair(9)
Types of
ownership
Compare
Sale
Proprietorship
和屯門大會堂演 感俺是「古雅醌↓li 有中樂團构和京胡首席,他如吹的啓發樂演咯。
梁況五重奏及其佔中樂作品;三日晚上八時及 ONE 活得,二胡的一出李越挺著長 「梁祝五雷淼與中樂金曲之夜」。稱者選曲大 曾任中央反族樂際獅奏演員,演麼精采的組合 參觀校方設備及宅和展
几台七時半在沙田大會堂及大丼文娛中心則是
由,演奏形式...獚特,一直到牧羊」
旺角同鄉宗親會
本·港 新聞
,你怎能錯過?
一角落,通話無開。
,用戶絕對不致因忘記按鈕而今電話不通,設 + 財筒在放回機座後動跳到“误 J 狀態 此外,樂媒郓境內無綫包括特有設計
报榮隆太平紳士與會者除生賓外,別有旺角逶 會前日假轵舂頓酒僭行賀旺角區議會仇泵一機座明白黏-
電 ),一按重撼功能等等。 視會聯誼人可發射電話淺)、自動-
虐功能彩蕯放回
宴賀仇輝神 達傳功能•行動保安系統(曉筒放到機座則維
•河灼湖,陳均,張廣,烟艄榮,業啓宮 才,王降温,易實,張襻辣,何錦泉,蔡文 凡,冼萊坤,蘇伯泉,陳漢宗·劉志民,陳 杨處劉傳魂,范頸,運舅,沿著衡,張覺
助旺角區闻郑宗親會聯誼會的工作 ·更不遺餘 席熱心仳區服務區地區事務而努力多年來對協 委員會張凡,溯著而致賀詞表示,仇振輝主 陳珍珠-彭博飩,有國及各會首長等執行
一:癸歪牌室內無綫電話。
Limited Company
Partnership
12. Continuity
limted and based on health of the owner
limited
MILL & DALE PRESS
Business Units {3}
Comparison
Types of
ownership
M. T. Kwok
13. Transfer of
ownership
at will of the owner
limited
14. Control of the firm
the owner has full power
Compare
1. Ease of formation
Sole Proprietorship
very easy and few legal procedures
an article of
Partnership
easy but have to draw
partnership
Limited Company
gifficult and a lot of logal procedures needed
15. Owner(s) and
manager(s)
owner = manager
16. Comon examples
Barber shop
- accounting
fin Lawyer
2. Cost of formation
little cost
little cost
highest because of
each partner has limited power
each partner shares sce duties
unlimited and may be perpetual
shares are transferable
shareholders control
through the Board of Directors
salaried managers
factories:
- Hong Kong Telephone
Company Limited
ineox poration and
log fees
热
3. Personal incentive
of owner(s)
very high
high
Tow
In 20
replace
item take ci form a
4. Credit standing
Bowest
Tow
Wigh
5. Liability of
owner(s)
unlimited liability
unlimited liability
limited liability
6. Size
7. Opportunity for
employees to be
promoted as owner(s)
8. Managerial
efficiency
9. Freedom of action
10. Prorptness of action
ST1
possible
enlimited size
Cossible
Types of
limited
Compare
company
No. of shareholders
inferior
11. Ease of dissolution
very free
immediate
very easy
bas
better because of ovision of labour hedulemeing partners
some limitation
high
much limitation
slowest
difficult, and have to follow legal procedures
Fand ratsing
Capital requirement
No. of directors
Transfer of ownership
Secrety
2 to 50
at least 1
privately tragsferred
not required to publish accourts on
mainly by extrag shareholders
smaller
sentenc
used Or
Exercis
Privats
ted Company
Public limited company
make fe
make oʻ
2 to unlimited
1. Pa
at least 2
läl
in stock exchange market
2.1
required to publish operation results on the press
inviting public to buy shares
larger
你
3. He
4. wh:
t
5. Th
1990 中學會考預習專欄
明德出版社
MILL & DALE PRESS
Physics(10)
30-
203
10
C. Y. Mak
Exercise 11 Speed, velocity and
acceleration
1.
An experiment. was performed to find the value of g by the free- fall method using a ticker-tape timer which produces 50 dots per second as shown in the figure (a). The paper tape obtained in the experiment is shown in figure (b).
fleker 1ner
5.
0-30
~2
-
= -6 as
car decelerates with -2 deceleration 6 ms
t = -4(rejected] or t = 10 After 10 it reaches the ground.
A stone is projected vertically (iv) acceleration 35-30 upwards with a speed of 30 ms1. Ong second later another stope was projected vertically upward from the same plait the sam speed.tennd where will the stones meat?
(b) Distance travelled with uniform
{a} let the time taken we t.
Solutions
1.
{a}
(i) Time
interval
between
two
consequent Jobs
time/s
1
=
50
= 0.02 $
(a) Find the acceleration of the car
along
(1) A8
(iii) cn
(iv) DE
(b) How far does the car travel with
un: form velocity?
(c) 1f DE "epresents the stage which the brake is applied until the car stops. find the braking distance.
peper tape
3.
-iron spherü
figure (a)
32. 23 cm
(a)(i) Find
figure (b)
the
e interval represented by AB. (ii) Find the value of g from this
experiment.
(b) How would the result of g obtained from this experiment if the iron sphere is replaced by made of sponge.
đ
sphere
The velocity-time graph of a car is given as shown in the graph below.
ball is thrown vertically upwards from the top of a building 200 m high with an initial speed 30 as*1.
Find
(a) the time taken to reach the
nighest paint,
(b) the maximum height reached.
(c) the position and velocity of the
ball after 65.
(d) tre time taken for the ball to reach the ground. (Given that acceleration:
TO gravity. 9-10 ms-2
4.
A stone is dropped freely from the top of a building 120 m high and at the same time another stone 15 projected vertically upwards from the foot of the building with a Speed of 40 ms-1. Find
Time interval represented by AB = 0.02 x 5
= 0.1 s
(Ans.)
{i} Let_u = speed of the sphere when
passes A.
Time taken from A to B is 0.1 s
.. 0.23 = u(0.1) + † g(0.1)2 .....(1)
Time Laken from A to Cis 0.2 s Distance between A and C is 32.8+ 23 = 55.8 cm = 0.558 m
0.558 = u(0.2) + 1⁄2 g(0.2) ....(2)
From (1)
speed
= area under BC
ㄓ
= (2010) (20)
= distance
= 200 m
(Ans.)
travelled by dropping stone
the
Popul
(A) G
=
(10)t
= 51.2
(c) Braking distance
= area under DE
3.
=
(301(35 - 30)
- 75 m
{Anse}
(a) At the highest point, speed = 0
Apply vu at
= distance travelled by
the
stone moving upwards
(40)t + (-10)t2
40t5tz
But
+ = 120
0 = 30 + (-10)t
.". 5t2 + (40°C - 5t?) = 120
40t = .120
t = 3s
(Ans.)
t = 3s (Ans.)
1
(b) Apply s = ut = at?
(b) sq
與
40(3) - 5(3)2
= 120 - 45
- 75 in
.. Maximum height reached
= (30)(3) + (-10)(3)z
= 90 - 45
= 45 m
.. Maximum height reached is 45 m !
above the top of the building.
0.46 = u(0.2) + g(0.1)2...(3)
(2) - (3)
{c} when t = 6
0.0989(0.2)2 - g(0.1)2
0.098 = 0.01g
App?y s = ut + atz
s = (30)(6) + (-10)(6)2
.. it returns to the same level of the point of projection.
=·0
-2
y = 9.8 ms
(Ans.)
(b) Smaller,
resistance significant compared weight of the sphere.
will
be
Appiy v = u + at
with the
(30) + (-10)(6)
-1
= -30 m$
They meet at 3 point 75 m above the ground.
-
put
pl:
41
Fot
5.
Let t be the time taken for the first stone.
..
time taken for the 2nd stone is (t 10
(B) D
Height reached by the first stone
= 30€ + + (-10)t2
= 30t - 5t2
.. it moves vertically downward
with 30 ms-1.
10-0 = 2 ms (Ans.) (d) Let the time taken ba t.
Height reached by the 2nd store
=
· 30(t − 1) + 1⁄2 (-10) (t − 1)2
= 40t5t2 - 35
=
-2
Hence
3 = -200
2.
(3) (i) acceleration =
20-0
(ii) acceleration =
20-20 20-10
= 0
(Ans.)
(b) where will the stones pass each
other. (g = 10 ms-2}
(iii) acceleration =
30-20 30-20
1 ms
(Ans.)
\t - t- 40 = 0 (t+4)(t-10)= 0
(a) when will the stones pass each
other.
−200 = 300 + 3 (−10}t*
30t St2 40t- 5t - 35
t = 3.5s
hp = hg = 30(3.5) - 5(3.5jz
- 43.75 m
(Ans.)
they meet at a height of 43.75 m above the ground.