頁二第張六第日二初月一十年子甲曆夏 WAH KIU YAT PO

1985

中學會考試題預習專欄

(十四)

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BIOLOGY (14)

WW.LEUNG

MILL & PALE PRESS LTD.

Unit 6 Perpetuation

of Species

4. The diagram below

represents the human male arinogenital. system.

(The parts

ave not

drawn to scale.)

a) Name A, B, C, D, E,

G. and H.

b)(i) Which organ is.

responsible for the production of sperm cella? (ii)Give another

function of this organ

c) which organ stores the

sperm cells?

d) By means of letters, list the sequence of structures through" which the spera cells pass out the body,

e) (i) Name the secretion

from B.

(ii)Give two functiona of this secretion,

f) What is the function

g) Which structure of flowering plant is

equivalent to

structure HP

h) State a surgical

contraception which is commonly practiaed:

man.

The diagram below

represents the human

female urinogenital

systemy

(The parts are not drave to scale.)

寄優全成 港四中車賺数校

本先日

優先薪高供膳歷照

Using the letters

marked on the diagram,

list the sequence of atructures through which the urine pass out the body.

b) Name A and state two functions of it.

e) Nace a fluid that

passes through thë E ¡óf man- but not woman,

d)(i) What type of cell

division can be found la D of a mature 'woman?. (ii)Which atructures

of a flowering plant carry the same type of cell division?

e) Give one function of:G

(i) during the

development of the embryo and

(11)during birth

r) (i) At which structure

will. fertilisation

s occur?

(ii)Give two

advantages of

having

fertilization taking place there?

The diagram below shows a half-flower and a longitudinal section of the ripe lop-sided fruit developed from the flower.

Fetal Anther

Filament

·・stigma-

Sepul

Receptacle Pedicle

Iv Plover

II Fruit

Describe a common way"

to prevent self-

fertilization in

flowers which have a

similar relative

让老聘

教職

學師 美

區灣 香月五

position of the anthers and the 分享

報日僑華

List two disadvantages of self-pollination. Name the parts of the. flower that give rise

to the structures A, B and D..

d) (i) What is structure

(ii)Describe briefly

how it is formed.

e)(i) Suggest a cause

for the aborted C.. (ii)Comment on the

relationship between the growth of C and fruit growth.

Suggested Answer:

A: urinary bladder B: prostate; gland Curethra

D: left kidney

ureter

E:

F; sperm duct

G. seminal vesicle I testis

b) (i)

(ii)It produces hormone

which côntrol the development of

secondary sexual

characters.

{d} H - F - G - C

(i) seminal fluid; (ii) It activates the (元)

sperm cells, ii.It supplies, the

sperm cells with nutrients.

e) For the temporary atorage of urine. Auther.

Each sperm duct is cut near the top of the scrotum and tied.

ABE F kidney.

i) It removes metabolic

wastes auch ás urea from the body.. (ii)It maintains a

relatively constaut osmotic pressure of the body fluid. Seminal fluidi

(i) Meiosis. (11)ovules and anthers.

During the develop- ment of the embryo, the uterus accommodates and protects the embryo (ii)At birth, the

contraction of uterine wall helpa the expelling of the s

mature embryo

箱中

(ii)i. The chance of

succes în

fertilization is greater.

日期星

The maternal body

provides a moist

and were ... environment for the growth of the fertilized egg.

The common way is for the anthers and stigma in the satie flower' not to ripen at the same tine

b). No variations would

arise since the

offsprings have

similor, genetical

compositions us

their parents.

ii.The species: may

become weakened

after a long period.

c) A: styles, stamens

and sepals,"

B: receptacle

D: peduncle":

(i) The seed

1)Pollen grains.

germinate on tie.

pollen tube grows down the style, towards the ovary and into the ovule. Male nucleus passes down the tube and fusea with the egg cell to

form a zygote. The fertilized ovule become a a seed.

() 'he ovule had not

been fertilized. (ii)Seed and fruit growth

are related. If the seed fails to develop that part of the fruit adjacent to it. also fails.

Answer for (7) Unit 2

The normal breathing: rate of the man is 11 breaths/minute. Carbon dioxide, Carbon dioxide has 漉 stimulatory effect on- the breathing rate. d) To increases the depth

-of breathing

e) (1) The medulla.

(ii)The intercostal musclea and the

diaphragm. f). For the victima who.

have difficulties in breathingi. forcing 95% oxygen into their lungs can make more

the fluid lining the alveoli and diffuse into the blood for

tissue respiration. On

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the other hand,

the 5%

carbon dioxide can

restore the breathing

movements of the victims.

Answer for (9) Duit 4 Q.1 (d) & {e}.

B

smaller larger | nucleus absent jpresent. (ii)B defends our body

against infection by engulfing the

invading bacteria or producing antibodies. to destroy them,

e) Blood clotting cannot

be initiated at a wound.

十四》

PHYSICS (14)

E.K.LO

̇MILL & DALE PRESS LTD,

Assume x kg of ice : arc melted.

Assuming, no heat

Isses to, or gains. from the surroundings- (0.2)(420)(20-0)) +(0,8)(4200)(20-0).

-336000x 20.23 Therefore,

0.3-0.23 0.07 kg of ice is still unmelted.

(b) Suppose y kg of steam

are blown into the mixture and raining. to 20°c

"Heat evolved by steam =2268000y+(4200)(80)y

-2604000y

Heat gained by the calorimeter and its contents

-0.07x(336000):

+(1.2)(420)(20) +(0,840,3)(4200)(20)

-126000

2604000-126000

y=0.0484

Ana. 0.0484 kg of steam

are required,

(a) Let the correct

length be x m' x=1(140.00002x30)

--1.0006

Ans. The correct length

is 1.0006 m:

(b) The cuefficient of

cubical

glass

expansion of

1~3x0000009

-0.000027°c 1

Capacity of the

flaek at 100°c

-50x(1+0.000027x100)

-50,135 cm)

文教 生

| 宁明

之道尖

7個名機東

機18念會留合程公地-號歴家資 會照聘計

Let the volume of

mercury required be.

V(1+0.00018x100)

-50.135

50.135

1.018

49.2485 cm3 (Ang.) (c) Apply the formula:

dt (1+rt)

(i) the density of water

at 54 C

1000

140.0005x50

1000

71.0259

-975.61 kgm2 (Ang.)

(ii)Coefficient of

cubical expansion, of glase

-3x0,000008.

-0.000024°c-1

Volume of water

contained capacity of

the flat54c. -1000(1+0.000024x50) -1001.2cm)

-1.0012x10-33

Mass of water in the flask-(975.61)

(1.00122103) (=0.97678 kg

(Ans.)

is the critical angle

.625

38°41 ii)b=180 -600

120° a+c+120 8+38-414120.

sini Gine

Since

the slope of m

against is

From the graph,

slope

蛋过

cm

(Ans.)

(a) Let the approximate frequency be f.the. wavelength of the '- note:emitted be (approx.)

(Ans.)

1.6

Bibi=1.6sin21 19o

=1.6x0.3636 -0.5818 i⭑35°29' (Ans.

(x) A=20; B=18.

C-16. D-15

15cm 0.23

16 cm ·0.3333-

10.5 18 cm

120,041 1036667)

30 cm-

36 cm

48 cm.

#240

As shown in the diagram,

-1.25

The approximate

wavelength:

The approximate frequency.

velocity of sound

pin air. approximate Wave=

Tength

·330.

=330 H2

(b) The actual frequency

of the tuning fork is

greater than the approximate: value obtained in (a) because end- correction is not taken into account in (a)

(*) The direction is

along the axis of the tube,

ay:0.5m) 7.5 maod

1.25 m frqcm, the

(b)

V

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