7. OX-
=24cm
1976中學會考試題預習專欄
·Since OP = 25cm
.*. DX — (25, = 24)cm
=1cm
女長波。
(11)
pectively
x+y=11
fron (2) x-y=1
(1)+ (3) 2x= 12
x=6:
8. Let the tenis digit and the unit
digit of the number be x and y res-
(10x+y)-(10y + x) = 9
新數學 (十)
MODERN MATHEMATICS
Solution to exercise 4
Section A
Section
日八廿月一年六七九一屣公年五十六國民華中 育教僑華 (ii) Let y=号== k
AB along the great circle.
博四第張七第 日八廿月二十年卯乙艇
WAH KIU YAT PO
報日僑華
三期星 c)//A0B= 2204*=0.3852
is -
Equation of the re-
=3960x0.3852 mi
x-2
quired straight line ig-
ive.5x+4y = 22
√25272 cm
數學科
(十一)
葉柏芳。
M
TRADITIONAL MATHEMATICS
(11)
1525 mi (2 mask")
-(1)
(2)
(3)
(1) OA = a
OB= a sec30°
OC = OR Bec 300
OE = OD sec300
日
x = 3k, y = 5k, 2= 4k,
and ky+ yz + zx = 47
(3k)(5k) + (5k)(4k)'+ (4k)(3k)
=47-
1.8. 13x2 +20x2 + 12k2 - 47
i.e. 47k2 = 47
i.e.k=+1
y=5, z = 4 or x=-3:y= -5, 24
11. Let the cost of the handbags be
$P perdozen.
the manufacturer sold them at
$1.3P per dozen to the retailery
The amount sold to the retailer =$1.39x1,000 $1,300P
The retailer returned 400 dozen at
half price, i.e. at $0.65P perdozen
=
the amount returned
$0.65P x 400
= $260P
The remainding amount
=
$(1,300-260)P = $1.040P
The amount was paid at 55 cents in
the dollar, i.e. at 55%
OD = OC
sec
300 = 2.
8
*33*
(ii) OEt OA = = 16 a: a = (111) AOAB=J0A. OB=
16:9
ive.
1
za a tan 300
300 tan
▲0BC = 70B• BC = 1⁄2• a •—a tan 30
tan 30° (4)
AOCD = doc
.CD =
tan 300
a2tan 30° (4)2
AODE = 20D+DE
8
cash paid to the manufacturer. $1040P. x 55% = $572P
the manufacturer sold 600.
dozen hand bags and received $572P
But the cost of 600 dozen. handbage iS $600P
he lost $(600-572)P
Now his loss was $11,200
28P 11,200 or P = 400
$28P
i.e. the cost of the hand bags was
$400 per dozen. Cost of 600 dozen handbags
1. Let =号=k
2.a)
a=.3k and t=5k
2 -262 (3k)2 - 2 (5k) 2
2ab
2(3k) (5k)
(x + 1 ) 22 - 2
-2 14
b) x2 + 1 = (x2 + − 1 ) 2 - 2
2 = 194.
3. The arithematic mean of pe and
2
The geometric mean of p and
2.2
is p qor pq
Since (p-q)=
2pq + qx?m
2
+q2pq
2.
土
2
ice. P+ ≥ pq
The arithmatic mean is not less
than the geometric mean.
4. Area of sector ACB
-162x sq.cm.
-3 sq. cm.
Area of AACD
3x6x4xsin 300 sq•cm*
-6 sq.cm.
Area of shaded part
(3 -:6)sq.cm.
5. Since 5000:7500:2500
=
2:3:1.
2
A receives $300 x.
pr $100.
6. Slope of line
4x-5y= 18. is
slope of PQ
(1) - (3) 2y = 10
y=5
The number is 65
Section B
9. Capacity of the test-tube
2.
Ta b +
2
3
-Ta2 (b+za) (2muka)
when the test-tube is half-full, the height
of the mark above the lowest
point of the test tube is
(a + b). – 2 722 (b + ₤a)
顥+如
ra
2
48+30: (2/2iks)
when the test-tube is one-quarter. full, the height of the mark above the lowest point of the test-tube is
(a+b)
za2(b+a)
=28+0 (5 marks)
when the test-tube is three-quarter full, the height of the mark above: the lowest point of the test tube is
(a+b)
5日
1 4
ma? (b + {e)
3D 4
10a +
12
(3 maks)
10. AC = CB=radius of the parallel
of latitude =3960 cos 67030 mi
1516 mi (A mock)
/ACB=70°-100=60°=1,04720
AB = 1516x1.0472 mi
1588 mi (3 maiks)
AD 1516 sin 30°
+
758 mi
AD 758
̇sin AOD = K0 - 3960
ZAOD=11921
ZAOB=22°4′ (3mok)
導務作鉏精鋼務在
(3 mask.)
3√3 35
12.
tan 300
-za tan 30o (4)3
the areas of AOAB,AOBC, NocD, and AODE are in G.P.
10.(i) 9x + y - 8ż = 0
4x8y+7z = 0
Applying the method of cross
multiplication
器
(1) (2)-(-8) (-8) = (-8)(4)(7) (99)
Z
= (9) (8) (4) (1)
ivex q#q= =32%63 = =72-4
1.e. -57-9576
x: y: z 35: 4.
$400 x 600 = $240,000
his loss percent =
11 240,
x100%
12.(i) (0.782) 0.1
..n log 0.7821og 0. i.e. n(T.893) 7.000 i.e. -0.107b < -1.
-0-107
i.e. n9-36
. least integral value satis-
fying the inequality is n-10) (ii) (10829+106,3) (108,4 + 108,2)
5
108.2+
log 2 log 4: log 9
·log 2
210g 2.
+
4108 3+ 10g 3) (1062 + 1082)
21og 2
log
log
、國團嚴及,會務
校一
譯由中國 茲部
際內謹實領培出租 及服,在導長會馓 交,分。能更更 業區部務友過宗爲 指股工團空服旨年
服六。的,導故發
四名照二人晴暴暴非法
上半 從的工計
一八三助工及在研陶之里一開
界並筵此
校學慈長佩管
雅七車選工数本程本箱
校長受持
用"
完曌對列綫起
愛的教育小組
檢討工作成績
(RE) TE
一。爲使選小組能更切震地去體驗,發缎問題及 | 向及目標,它越發明 我們要切實 一的教育一小粒日後之蚴】關心他們,與他們合作 寫對穬饔務。從中「愛一位敎師,接納他們, 筆辦過兩次研討會,五特別是校方,應葉重每 「青」已意半載,並先後其重要性是不容忽視,
【青」小組推行「愛的教」作,眞是任重而道送,
提出五點心得贤抛
救
能克服困難,驚成服務
|教師本赛悬推行之動力」小組熱切希望各界不
「吾之需求。可是別忘了後,「愛的教育
▲全面發證他們的花雞|意識,放藥小學教科醫 ◎認潸兒童飛別之獏具|推行一些有意娄之運動 (一)敦師敦學時及合作將神。 臺通童愛心以兒童食中「支持及協助 ,例如,培養學生寮深
給別人,這算是小
|從工作或經檢分享中香
我們若能將這個意
吝指教,俾能有效地實
基督敎學生合唱團
,它已擒起了醉世紀人
女士任指挥
一,向社會人士見證基督 ..厨合基督徒事由之力,一對養小姐為總統。在林 勵身努力規習,使合唱一外,更著風顧展之品游 彭博士在致阿中幼,一峯風音質,樂理之游赚 出战合唱團成立目的在一鄉群推導,黃進昌、並 y_韦羞洪雅會舉行成立典痛經,讀爲興
·乡孝顺博士致詞,指一何莫燕宜女士任指挥, 錄。由萬股神校長主持學證基協會主辦,敦 黃陽東伴奏,歐斯任
| 大學聯合書院扶輪青年」,設有幼稚爲及小一至
| 合唱團之任務。我嬴後一茶叙,饼况整闹。 下月下旬舉行 歡迎參 舉行國際日資料展覽 聯合書院扶輪青年團 品德及女性,方能完成十九人。典禮後,奉行 此外,更要保有美好的及面試後,選出關於三
[[畤訊香灣中文 | 七一年建校,樓高三層
下午三時,但美甲新邨負對人際孝義導報 |出合唱團於本月廿五日奉献禱告。最後由該團 └【倦讯)有敎學一由劉振盤博士爲合唱團
舉行成立典禮
國賓共卅九人由何萬燕宜
行 三 音格 : 除挑在
素奴仙柏爾阿款
主惡掃鋒急續教
角城罪横先集父父
麦草
呼聲最高
金像獎
高獎
AL PACINO
An Arts Entertainment: Complex Inc Production
DOG DAY
乐
AFTERNOON
今年
定請 座卽 彩七藝特
珠明
華
年龍接迎片鉅龍猛
映獻類天明
影電錄實案奇激刺險驚品出新最司公納華 中片 文上
! 本晴如結欲、萬黃獲銀打
南金得辖行
片看何果知
最最最最最最金外榮 佳佳佳佳佳佳託
導編男男男影
演劇新配主片 人角角
球國膺
榮膺荷李活
行銀劫械
·事眞人員約紐
1幕銀上搬
密盧尼薛
作傑大