REFERENCE LIBRARY
30 MAY 1974.
CITY HALL
目播育教真三第張五第日九初月四間年實甲麗夏 WAH KIU YAT PO
報日僑薯
>>E
物理科答案
堅道英文書院
四期星
日十三月五年四七九一层公年三十六面民鼎中 AHS= +[$ TUFDRLTS)}]
CD + CB+BB- CO-L Tan 30 - BC - AB.
1-3 to 0.
htan 30
250
Theoretical .. of the
machine
250
isneity of Hg at 25
h.(1 + 25 x.
V.R. of the machine - 250
►_b(1 + 0,005).
750 x 1,005 753.75 mm
(iii) Pascal:n Jaw atatas that praw
Beure applied to an enclosed fluid in transmitted undíning— lehud to every. portion of tha fluid and the walls of the containing vessel. So, when force I applies the increased pítésaures at I, Y and Z are
B: (1) the total number of nodes
(11) Wavelength of the
天干?
(花+) (2%+3)(1付)
放開支為A:经常费為Ki
12 15200 =
WAVA WIT
4 afro = 7000 Ku
= (I-X^) 證刖
·J^x (14%) 4x^(1+x+x^) + ··
(111)
Lamoy of oe0f11etion:
40 B
(*) -x9
Section
General Physics
(1) Let V = :common velocity of the
ball and the box just after impact.
By the law of conservation of momentum,
take the rightward direction to ba positive.
8 x 2 - 1 x 10 = (10 + 2)V
1610
12
1/8 (rightwarda)
but, before Papplies, there is a pressure difference dus to liquid-head. ?MANE
PrePу; PIP (due to differ- ence in level) therefore (Px+APx}C(P8+ API)
the pressure at z. in greater the other two,
(iv) Energy is required to move the liquid in the press in raining the load.
(iv) Wavelength of the sound in air produced by the vibrating string
我
frequency of the loaded fork
3666 360 H
fi 15200 =K, +300 × 2
K1 =15200-1207
= 140元 14000+号120000
́(11) E.E, ̈before impact
54 + 5 joulee
69 joules
K.E. after impact
• = = (10+2) × (1)2=1,5joules.
Tnergy lost during the
impact
(69 = 1,5) = 67.5 Joules-
(iii) Lost energy will be dissipated
as heat due to the friction betweem:the ball and the said. and work done in the penetra- tion.
b. Archimede's Principle
on
The Upthrust experienced by a "body, partially or wholly ins mersed in a fluid is equal to the weight of fluid displaced by the body.
(i) Mass of wood 800x0.5 -400k (ii) Mnes of the displaced 11quid
mass of the mood #400kg.
Applying P-as to the spaten. 3 = (0,2 + 0.1) a.*. B 10
the acceleration of the system as 10m5-
(iid). Volrime of wood appeare above
the surface
-volume of wood in-
0.503 meraad
-400 1200
((11) Applying as to the amaller
tangion in the thread between the blook. 0.1 ≈ 10 N IN
越
Lot 1 intial length of wire,
1- altered length of wire. Since f
27 = A3 0=1
(-X) (-Y)
(1-x) (1-x))
h Z+1 - (1-zx)* =[f(x(1+x)
267 48-1468 −28*+fx3 = [f(x)](/+x)
(2) (97. ^ 194 1-7
Hence the langth,of,
be increaNEZ
f(x)=2354x+32
pipe
0.6m.
微軟至
pipe B
(11) length of pipe B
2 (32 +228 + 988
um) (0.998)
(0996)
天使平布至5位小载
1-2×0.001)
50.602 (4)
(iii) Tet velocity of the block.
after being displaced"".
initial velocity of blocke
2x10x5
(iv) Upthmist in the wood when
totally submerged
.0.5.x 1200 x10 N.
6000 N
"minimum force required
400 x TON
Section&
60000 -2000: N
(iii) the frequsmoy of the furide: mental tone of pipe B
x frequency of the lat overtons of pipe B
x215
(1)各數字不可重覆使用:
4303
work done to block increage
in K.E.
- 2 0.2 (V2 - V2)
x 0.2 x 10010joules
(1) heat transferred to alcohol
Ma_Caf = a.)
(ii) heat Lost by calorimeter and
wata
1-320
a
(111) In Be = fco X&. L=2a
•BC == QUK+a2fCD=
(9-6)(y+4)
X=105 x=-
-7116 --4
+ ABC 1 - 2 }}+), LABC = 12.0°
8=20cm,BC=40cm. 在ABC三千 西上4月中に根付
Pg 2 (√7-1)π (m.
(01) BC所持超大面積為1000斤4m
JABC ABC = 120°.
·AB 200
Be #400m
1-151+18 <0. *-51+1
•2) (X-3)<0.
· AC = 20 +48 -2×2
400+1600+800
da(1)
and S, arrive in phase
F: (1) 3 / tano te tai 20 û ton 30.
tas 20 = Con (0+0}
CC = 2057 1871 = 5
BB = 20×₤11 - £L
(11) S and S. arrive with phase
differe Tat P
N = 2 × ($13! = 48
The result obtained is lower than the true value,
Ca is given by the expression:
數學科乙答案 聖道英女書院 容耀榮
155515) N=5
Lgs 1 4 Tom 20.
Cast ton b
- fotel Priotion of the blocks
➡ (0.2 + 0.1) ≈ 0.4 x 10 USZÁN Ipplying ca to the whole
system.
- (0.1 +0.2)
=
eleration of the system 6 ma
Heat is gained from the surgi
ounding during the transfer of alcohol. The actual témperat- ure, Gà "when mixed, with water should be higher, →→
If not because of this heat- gain, the temperature of the mixture should be Lower,
is larger, and.
is the values
by
of the hydraulic press
0.052 0.01
distance moved by the load.
10.1
0.0040
(15) Let P = thrust on the left-
han rèin.of the pres
Take moment about A, for the levar
P = 0.02 -(0.02 + 0.18) F
25
load = 25P = 25x102 -250F
中天艶九
(0 – 6_) da smaller due to
experimental error,
That
The true value of ca ghould be higher.
c. (1) Barometrie height will be
lower;
(ii) Barometric height will
increase.
flii) No effect on the Barometer.
columa
(iv) No. affeot on the Harometer
1974年香港中學會示
附加技术课程甲 試卷一冬套
~ (a) 21 94 4×10"
40:10-
24-102xy 40
99.10* = F = 0.628 X=1.
N = Ch.41 - 4P 120 - 40
如右图所示
LAPB =2BPC
為若干?!
奇手偶奇
N=
我证
BC
ala
四(@試用影響歸的法證制
1·3-513-5-7 57.9
+ Q = £ tam 28.
{2}-1}{38}4)(2013)
-0.2041
Rus = # [3-
za-ata
N=2, 2·448 = 13*357 * 745.
Since
RAS = $[3-3-7)=
Where h
barometric ht. at 00 1 barometrio ht. at25 0
部份!
什分為经常要用另一
d density of Hg at 0 0.
In 10=-02 (182).
生分版
在天五信 新者歌 高瑞四
·八冊小
署
,七冊及地,额与天夜者
分分齒邊及
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代 天巡十下辖。,
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好人下,效
她心中新類分,
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,新聞及
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•RG- FUNKEN
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凍氣材
十二時,全日牌
八時十分,教育館
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內配十卅 四十,, 十九 安二分 安一婦卅時速綍
曲
吃面颈与扇形 ACC
· 7 × (400 x) - 400)
).(1)我将3C00+4A20亿為
R Ai(B+A) 之形式,並求RYA
3600+4/10
5.((+8)
·5 A (0+A)
R=5.*A=A++ = 36°52'
V1) {L -A=0=/8-A, AÆKL
53°8