襄二第張五第日八十月四年丑癸腦
WAH KIU YAT PO
報日僑華
tc). Fuurehoren e uniforms U-tuba bəl
(a)
-
312
英中會考物理科試題
Нана преми
SECTION
| GENERAL MAVŠIC
sary aske
Thự Mock ta pulled abang, that inclined plane by a force ♬ acting parallel ja tha
ang 25 M, find"
The 200% bich ú
upside down, so thaa, vaa" of its "Žarby:
da la a brakes of passung, while the Other in a beaker of quia 4: The may loval in the pubo últim higher than that in beaker #, wise! The fiqulid. I the odier"
Ian Malur shan that an
bunker i
Șt almosphere prese and the "relativi
(le), 750 moilla
daralty of
soury It 136, find
EN - Quar permane'de moedig glaz
usy, face reade
En tur ir perjure us mucila autog
the milk of qu
imada.the be
thin the resides analy at the issual,
Figure
Refering to the diagram 19 (c) shave,.comsadel tach” of the filĺming zuten (1), (b) and (ha) segurly. In each case, mase with brief explanation what,
Gå ta kuhuras of lagu wild behand
1)
thermophile pressures.
if the mameter of the ideal the tube bryntainery liquid), 2., were murally)
· redused,
[basher Alaked Frog and beli Biru senest by the name anumani,
CYLON II. MEAT
pipia bakom abaws the saturation raposa · presnen, of water at waldus rompentu
maston given in this graph may be used; if deemary, for may part of a question.
TEMPERATURE IN, "O
SECTION C
三期星
the value of 'abudane
af temperluas da
exed by this min petisi
日十三月五年三七九一屦公年二十六國民華中育教儒龅
"To the tenders in Square' 5' la come qulozend wenny Choatead of mercury), and the leally & wall
*280 mms' as the point, wale wah kruf splenzilor, what difference fif 'anyi'you
obserye between the new rowing and that in (cyan,
妙
dhe sekrowai Mumpreetvie
fd, the team power.
WAVE HOTION, LIGHT ANI SOỤNG
Braun, dann week pertinent an
Zetterne de sekačky vad maagd In-
-
Two uning forka ze bed, and the shoneg, rawamating length. E ang kach, case li frunds
| aquency of fask
480 (J
24400 che +7-0km
What the advantage lamang
Twen föckt instead of he?
Fall What the pedemcity of wi
ven by time realis?
„Figure
•Thare wies:XY and Z of equal lengths zen stretched with the same terdap, aner 2. hai'a
Francy of
Xin veel wire frus 0:2,
★ in a steel wire of radiuạ, Brẻ con,
·2 11 4 cupper verd of radius 0-2 mm,
"The dertuty of Meelis 2000 by 17,
The density of copper le 4000 ay m”.
The schoolty of sound in air an tamen temperature in 330 a
- (0) Whine the fundamental frequericzes`ul
and 21.
ky', What it the wavelength of the sound worse produce
Cup What kind of oleomagne ou xavermal heve the mow ware
A contex ions_pland" 10 cm mai front of an uberi prudenza a viisual image of
3. What's the focal length of this?
Ca) What pint of the kieran ej e cortespond to the staphragmana Türs él a camer? -
(h). A studinii kan see an chức 7 denly at 0-15 m, but cannot se pʻla dagacity at 15 in from
Chủ tịch. Say whether the orman foomed by the ays in the fatter case in front of, on. i beland thi: reales of the eye. Mai, làng vị,jena should be cases) ze coned this
fective?
(10) Cumpare the method of focusing of the camera and thuit at the human ryw
1) "37 - or deposit on the cathode in 50 minut, and wheelcherat qve of her is 5-32 × 10 kg find the pleche
cleme
If theater in the circuit is faulty and reads, only ũng thị Muy carrycon should be. applant to ti reading? India where the suspective should be pe
new..
Flashows part of the tide of a patients may tube. An indledtng beam of
raye hits the sembra fuo.
beori col çaklausė szyn aikajat?
Why mua there be very tik što már ditando a zachondo isy fuine?,
Cu). If necal place. A is glyen,a' postive charge and rietal plate D Iv given a negative change, where will ha barn of techode..ful the siren Fiefer, axes shinwit -dlagiken)
· plated replaced by the quith poor of a magnéi and plate is replaced by the author pole of a paper; what will the beam of cathode rays but the keen?, frefer to the shown in the alapain)"
Figure 9 movenly Sfast Mesto The 'Lubar init and sew of the weten allseen by 113 eye in. Pigure.8: C4Dng anothei pair of
tal plates muler A. Ind &ch of a four plates "he" clis'ged tu- maka tha' brani 'vl' sathinde, rays “hic' she
paint-P
U'À and.. hieman charged in Carlin), had, 6° and D. are cont», - mcled in an allengstang voltage,, jnduzre'de ə qapanı sonlar bi Igure when you sell see the serere
Figure 25 disches n voetta kesilge used to find the 'redatriet át azot ef wae (C)-957 cm
and. B+) cần diameter. The sandali reistance, used for comparson' a 30.57.
seconds after
beached the slowl
[Regnant's 'hygrometer, na aknes
Piga 4, da ut və flod the dow
What is char purpose of bubbling ),
though the what?
Keely why tempera
: turg chenga will co
-Why k, the bottom of the 'tube'
• shade on a duétal sche
During the perimesi, - what-
· Kampukuizen rendbags should he'
"In order, 16, fnd. She
dew point necủƒMaŸyTM
SECTION 1
ELECTRICITY AND MAGNETISM'
Analectne podkor us, to Central rating codi each of 50
Sonnected Hyan ricetri surp of 200 th, and com resmess
ננו.
Tonly jane hænding roll working,
I by the operadom uf horen.
What factors will idinét té effeiency of a single vistag pilley systems? “Sale briefly how th efficiency in affected by each of these facias.
Take the weight of a 1 km mais at 10 No L‚Ñ="15"-dynas"
Matthiahly beween the force çembing s spring and the saestate the spring?
* Fipies 2, X and Y are parte springs each 501st long when wretched
man) Kg h záded so alone, its length changes from 10 cm to 60 cm. 201
1 đẹp bị mới cho cố ý phim, the len màu chung toàn sự em ra 25 em.
Aan Efrata picce of meal PZ.
15cm is then attached hu the
vo spraga ja shoes so ther degrace.
If cacti spring now 55 cm tons.
the ventos, ki sach, spalon, în
(i) the, difenac-of the centre
Baky vl PQ frani ki
Π
1978
中文中纜會考試題預習專欄
數學科 (卅二)
張正邦
續上期預習題解答
Z解方程式
(1-tan 0) = (1-3tan:0) CD20.
(0° <0.<360°)
tan
3 tano
Seczo
3 tons
3 tano..
1+ tam &- tano - tamo
tamo.
- tam 0-2 teist = 0 tan O ( tan Olan 0-2)=1 tano (tas 0+1) ( tano -2).
tamo
0=0:6326 135°
241°26′ 315°
3 (0) BC-12112 2060 A DA
(知)直径BC
$28 OF £292-85 MHE.
2 AE2 = AB2 + AC2 - 200 BC
(+) ZAE=ABTAC-200 BC (明)
AOTAE=r
2002+ 252= ABTAC (Pak+1})
AD=rAE.
2( "-AE)2 + 2r2 = AB2+AC2 ( WAGRU))
ZAE2+
'+ 4T (T-AE) = AB +AC (((3)(619)
BC=2r N-AE=AO
2 AE + ZBC AO = AB TAC2
2AE2 = AB2 +AC2 - 2BC-A0
DOABC BCBE-85BD=2DC.
BEBA AB2 + ZAC2 = 6CD2+3AD2
Fiewi
(b). If today's room tergambars in 30°C and joday's dew point bị 20°C;
Dulaliem, huzalilty?:
(Figues, de col
of a wiform this-plum tube
kanday old with a maccury viden,
,and Dixed to a half-metre rude.
The length of the `calume of based air gewaard al different. temperatures
St., İzmperatura
demo-point
280 Bun
+383 mm
"QAE2+2AC2 = 4AD2 + 4DC2 (60)}~@
? +AD +RAE take? = 4AD + 6DC2 + QAE?
(($)+(82)
AB2 + 2AC = BAD2 + 6C0? - AD2 AB2 +2AC2 = 6 CD2 + 3AD"
Q-ED
4(0) 福岡PDEL點とう切緑平行旅弦
DE X 2989 PDB PE ZEST MAX= A B 21 AC=CB = AD BE
( ~Ko) AB // DE-
ACB為目PDEシ切線
CCB=AD= BE
ACB為図PDEえ切線
CD, PC, CE
<1=23 (a@pk Fassn 262 War Baað
AB/DC (ZKP). 22-23(内錯角等)
(由(2)毎(4)代換)
44=42 (KB92 BOD
4-24 (86)5 (6) 18 #2)
AP BP = AC=CB ( = 1913-19385 +4 分其對邊成兩線段與其鄰邊成比例). AP: BP=AD BE (- Lak P4] =(918
一邊,則分他两置成间 AC CB AD=BE (8) 5) HHE).
Q.E.D
(b) ABC三角形一直線與BC→延長線 CA, AB DB KA P, Q.R; CX PROTE
ABAX 22 wtf - kk wrefx cax AB - 1
ff
PQ
cuit dongdon of cam
- (ú) Fed du, powi of the cooler as rich if the flitre case). You may isama-1/59
– reštstances of the pvi oni do not change with temperature
duike if the supply create and for cooking has a 22 ampere main. frue, too many
My mumkan with unly one beaning cull working may be sock at the saune tiene?
Devoplave a blown fuse wire with angger mitet
Fitsier
What precautomu dipula, de taken tuensvie
zugtā turface of a shum kyletmeal brass pud” you work unt
5(a) Pop = <ABK = <ACD LAKB=<ADE
證明 ACB興
△ADK相似
B (EXB) <ABK =<ACD,
<AKB =<ADO.
7
(foto) JACB NOADK.
LABK=LACP, ZAKB=LADC (ZXB)
DABK ~ ACD (-Ach ég h 角形之两角,则两三角形相似
AB = AE (KAM) = 1} <+ME (23) +141)
4 AR-AS (#)
AK
<DAC=<KAB (FAW) =}}} <]} {#)
<DAC=<DAK+ERAC
ZKA B=LKACTZCAB.
ZDAKTERAC=<KAC+ <CA!
49 <DAK-ZCAB
~AADK (BA-NI. 來出成比例,其两滴形相似)!
(b) AB, DC為梯形ABCD之平行星,平行於
·AB 310-11 CA CB XB KD HK,
DH DK KR ABR ABIL & SK HAKA =
X, Y XE AB=XY.
(ERD) ABIIHKIDC.
K (35) AB=XY.
(税
HKILXY CZKO HK ||AB)
2. LDH K=<DXY (9)
<DKH=<DYX
AR
·RB (孟氏定理)
(3ke) CXI/PRE
(税込
(6) U) BP
3. DD HK ~ ADXY (-2018
一角形之两角則两三再形相似.
DH
4. = BR
CP XR
HOL AR
QU = 1 CPX QAX RB
(孟氏定理)
QED.
(諮
6. CXI/PR.
2. BC
BC = BX
CP.
Bc
3. BC+Ce
BX TXR (AbE
CP
(84) BD = 2DC. (*5) AB2 + 2AC? =6CD2+3AD2 (JEP) EDYKE AXAE.
1.為BD之中點(作圈) 2. DABD¢ AB +AD2=RED2 + ZAE" 3 BD=2ED BD =2DC.
4. ·· 2ED =2DC & ED =DC.
5. AB2+AD2=2DC2 +. QAE2 (14) A^(2)).
122 AE2 + 2 AC2 = 4 AD2 + EC2
EC=ED + DC =2.DC.
(若一直線平行於角形一邊
則分他我是成比例)
XR
BC +CP-BP, BX TXR =BR.
5. LD - BR (10 (4)(?)
61 CA = XR (B) (2))
.....
7. BP x CQ - BR x XR (H)
CP
BP.
AR
х
8. Bex Cox AB =
RA
(11)
Q.E.D.
5 CH - #5
(與(44)同理可求)
DCP AB (2*p)
<HAX=<HCD ().
CH XA CHDC
DA HX NOCHD. (B (33))
DX=DH+HX, CA=CHTHA
12. BACA
d the reusiance of mod
Fine rastity of the
reference sa Figuro -101, plate, with, baef explanations, how the geniton së the
„punt. ♬ will be affected by each of the folowing changes.
The con C is heated up.
Bus. The palmaruvenci in akuntia.
· The im jetzgāt veserace of the fell 17 ínerzusés,
The caula replaced by inihre at
material, but greater thickness.
The volk, o'likeplaved by mother cost dusmista
material, a gentes Berigtḥ,
IND OF PAPER
6(a). I => [] 7} ABC 67€ AB, AC IS BRED. BE
12 BG = AD # BD CE OY % $ POY this.
(ERO) CABCDE=H1}
• (34) BE =ADE=:
求BD与CE交點P55 軌怎
談合所設條件的點為則在△ABD FODBCE & AB=BC, AD-BE. <BAD=LEBE
=60°. SAS O ABD ~ OBCE LADBELBEC 故ゆ鮖AEPD在同一国上 2 EPO+LA =180° DER LBPC = LEPD = 180 - LA=188-60. =120 ppp 36 to w BC1033 / 120°F AF 104 5.3 P3 BE
(2) ALE 3 F3 334 BCK 18FQ-85 P, £38 BP
CP其延長線各ACAB於DE則在
SABP FODBCEP, B = BPC=120° <PBC
+ & BCP=60 TE <PBC+ <PBE = 60° LABD = LBCE, & LA=LEBC=60°
AB OBC PASA SABO = ABLE; - AD=BE 即弧BC上的點都合所設件
(2)知所求的軌臨老BC為
32 to 120 na 169.8 13:34) BC.
(b) TEE & CHABE -86; AC =7 cm, CB=3
国目為の興AB相切族C.且興AB 為直径。每周心半圆相切求此园之半程。
(PKR) AC=7 cm
AB-AC+CB
CB =
B為直径,為目
p.
(全争者分量)
AC=7am CB-3 cm (ERR)
AB = 7 am +3 cm
1:0
OP =
OP = 1×10 Bm
=AB.
op=0Qtr
QQ = OP-r
·OQ = 5 cm -
((6) 4X179)
em.
Ao+oc= AC
OC=AC- AO
oc= 7am-5am = 2
12. OQOC & OQ2= OC2+r2 (BF77B)
(5 am-r)2 = 12 am) 2+ n2
(Þ (8), @Kλ(12)).
Q. E. D
1
DA
x 4 = 44
(4))
10
XH +DH-ANTCH (AW)
DH
10:
((1)代入(10))
(14), (5), (13) 4X #)
AB = XY 14.
Q.E.D.
DH CH
13. DH
DA = CH
DX HK
CA
14. HE - 4/5
=2 to Cm.