(27)育频 日五十月十年午庚慶夏
報日僑華
variable to be zerd if it is not defined. But it is not always (e) Subroutine
六期星、日一月二十(〇九九一)年九十七國民革中
青教化文日五十月十年午庚腦夏
Computer (9)
true. Therefore it is a good habit to put the initial value for variables
BASIC statement
Parts (a) to (d) may be put in the same program segment.
10 GOSUB 500
199】 中學會考預習專欄:
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Programming Exercise
1400 DATA "WONG SK", 1. 15. 170.49
write a program for the.P.Ev teacher to do the following jobs:
130
K CHOY
140
120 FOR 11 40 40
READ NAMS(1), SEX$(I), AGE(1), HEIGHT(1), WEIGHT(I)
IP-SEX$(I); = "M" THEN
BOY BOY +1%
ELSE GIRL GIRL: +49
150
IF ALI) 15 THEN OLD OLD
160
AAGE AAGE + ACC(11
"170
AWEIG AWE 16+ WEIGHT([}
(a) (using Jime number 100 to 190) to read, data in suitable
dimensjonen array. NAMS, SEXS, AGE, HEIGHT, WEIGHT,
(b), (Using Fine Aumber 200′ to 290) to count the numbers of boys ant
is in the classe
Boering. The-
number by 3338cading
500 REM BUBBLE SORT:
590 RETURN
A P.E teacher a secondary schicol try to use a computer to keep records of 40 students in a class. The fields in each record are int the order NAME SEX, AGE, HEIGHT WEIGHT. He wants to do some statistics on the data. Ho has typed some lines as the program segment..
1010 DATA CHAN STY
1020 DATE "ERENG TW".
"F", 13, 160, 47
165, 51
180 NEXT S
But it is suggest to follow the instructions given by the question. On the other hand, the structure may not be clear if it is all put na, a 1000.
The relationship between flowchart and BASIC.
(a) Séquence
Sige!!
FONDO
Program Segment.
Programming Exercise
Bubble sort
Write a program in BASIC that can do the following jobs. (a) A list of 20 names and marks are inout into
dimensional array.
a two-
(b) The list of names and marks are sorted according to the
decending order of märks..
(c) The sorted list should be printed out.
BASIC program
1c -
INFU "PLEASE INPUT A NUMBER
10
REM. INPUT- OF, MAMES AND--NARKS
20
DIM NAM$ (20)","MARK (20)
30
FOR 1 110 201
40
INPUT NAME OF STUDENT
MANSUI)
50
INPUT "MARK OF SINDENT MARKII)
GO
FRINT
RINE THE SQUARE OF)
AUMBER
70
NEXT
100
REM BODY OF BUBBLE SORT
110
FOR A TO ̊ (19)
120
FOR K 1 TO 20-3
130
140
150-
160
170
180
NEXT
Frantus"
INPUT PLEASE INPU PADIUS OF CIRCLE"!
200
210
220
FOR 1 10, 20: ·
IF RO THEN
230
LE MARK(K) > MARK-(K+1). THEN 170-
NEXT K
TNAMS NAMBIK) } TEMP. = MARK(K)
NÁMSIK) = NAMS(NIT). < MARKOK) = MARK(K+1) NANG(K+1) = TNAMS MARK(K+1) = TEMP,
REM PRINT THE SORTED LIST IN ORDER OF MARK,
PRINT THE SORTED LIST:"
PRINT NAMS(1), MARK(1)
NEXT A
(g). Using Pipe number 300 to 390 to count the number of students
who are older than 13,
(d) (Using line number (400" to 5901 to find the average age and
weight of the class,
((e) (Using line 600 to 690) to find the tallest student in the (b) Unconditional Branching, and Conditional Branching:
class. Output the name and height of the student. Assume no, two students have the same height)
100 REM CA) INPUT: OF DATA
110 DIM NAME(40), SEX$(40), AGE(40), HEIGHT(40),, WEIGHT(40),
120 FOR 1 TO 40
130 READ NAMS(0); SEX$IT), AGE(1), HEIGHT(1), NEIGHT(1)" 140 NEXT
700 RÈM B) COUNT FOR BOYS AND GIRLS
210 · BOY. -. D
220 GIRL = 0
230 FOR TU 40.
240 IF SEX$(1) THEN
BOY ROY 1.
ELSE GIRL GIRL AN
250 NEXT 1.
260 PRINT AT THE NUMBER OF BOYS.
270. PRINT THE NUMBER OF GIRLS
300 HEM 16) TO COUNT STUDENT OLDER THAN
301 VOLD =
32D FON 1.10. 40
330 IF ACT), 15 THEN OLD 2DLD
JAD NEXT!
350 PRINT THE NUMBER, OF STUDENTS OLDER THAN-
400 REM(D) TO FIND AVERAGE AGE, AND AVERAGE WEIGHT
410 AAGE-0
420 AWE LG 0
430, FOR 11 TO 40 M
440
450
46D NEXT
LARGE - MAGE + AGE(1).
AWEIG AWEIG +"WEIGHT(1)
470 AAGE AAGE/401.
480 AWEIG
AWE16/40.
490 PRINT "AVERAGE AGE : ANGE
500 PRINT "AVERAGE WEIGHT AWEIG
600-REM (E) FIND THE TALLEST, STUDENT 610 11
620 FOR J. 2. TO 40
630
IF HEIGHT(1)HEIGHT(J. THEN I
640 EX 3.
650 PRINT "THE TALLEST STUDENT IS" NAM$(1)
660 PRINT "THE HEIGHT IS: REIGHT(D). 670 END
Remarks:
HONG
Students are request to use meaningful variablega hot store the names, AGE for ages, etc.
This important to notice that the data format
and sex ane character strings while the others constants..
11.Lipe 240 may not, he executable, in APPLE le machine.
changed
dato-
240, 1F: SEX$(I)=M THEN BOY BOY + 1.
245 IF SEX$(F) = "F" THEN GIRL + GIRL +
The
IF THEN ELSE is accepted in the HKCĘĆ.
START
Program Segment.
GREA
1 x 3 is the conditional branching, the, branching depends on the dius as the condition. Line 20 is the corresponding BASIC statement.
(2) The flowline after pax 5 is the unconditional branching.
50 is the corresponding BASIC statemen
(c) Selection
(d) Implementation of Counter
NAMS
Lines 210, 220, 310, 410 and 420 are the initialization of Variables The initial value are given so that it is defined when it is used for the first time in later lines. Most students forget to do this. Some of the SASIC interpreter may assume the
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BASIC statement
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本中心學生另有折扣)
240-
.250 AND
Discussion:
(a) REM statements should be added whenever appropriate. The job
description of the following program segment is written,
cuctural programming a good practice so not hise to much TO statements. Otherwise you may get lost in the program Statements. Indentation or the program makes it clear that it is a loop.
FOR J TO 19.
FOR
1 TO 20-
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少脆骨,把那不地很容易殺手,這件事終於在台灣神了答案,台灣的酒專賣 例如一虎骨酒,據說是強身之物。但一向懷疑,那麼多的「虎骨酒」,要多 ,再說比難傷人,還是有用之扔,例如皮皮椅,虎皮地估,有特殊用途 -
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The structure make it easy
between 120 and 170 is the
Inner loop, and line teleaf110eacji 180: Ys "the outer loop. No inter-crossing of loopwill b
But it is aly true form
Arst versions of BASIC ONESTOG for ALE I user unless a set of machine code 15 kéred 13 ou ore requested to use structural programming style when answering questions in the HKCEE.
students using the Commodore PC-10 model of computer. Lines 140 to 160 can be replaced-by:
140 150
SWAP NAM$(K), NAMS(K+1} } SHAP-MARK(K), MARK{K+1} ====
The SWAP function exchange the lues of two variables However you are suggested to use this function in examination because.ft is not included in the reserved word list announced by the Hong Kong Examination Authority. You are encourage to use a wide varie functions provided by your. machine in the computer laboratory bút not in the examination.
Using, the sorted is! og landent names and marks in {}}} Write a subroutine program mang the algorithm of linear search to look for the-existence of a student and then print his mark and position.
500
510
520
530
REM SUBROUTE LINEAR SEARCH
INPUT "MARIE DEEMENT TO BE SEARCH"; NAS ·
FOR 1 TO
HEA NASZA NAMS (1) THEN 580
PRICE DAME OF STUDENT" NAME 1, 10)
550BRIN 'MARK" - MARK CI
PRINT "POSITION":
GOTO 660
570
580
NEXT I
$590.
660
END
PRINT THE STUDENT IS NOT IN THE LISTO
END
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199] 中學會考預習專欄
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