1984-11-07 — Page 26

頁二張七第日五十月十年子甲夏

考用 考服

WAH KIU YAT PO

報日僑

日七月一十年四八九一曆公年三十七國民華中 育僑華

阿職年的

已有下降的趨勢。 畢業生,從事公務員的 香港大學八三年的職公務員向比戰並沒有,不少畢業生對從事公務

近年來,政府放級榮蔥指出:八三年學 法院傳譯員 入職政府部門的比窄,一的有百分八路二八二 導處的發言人,均不約

兩大學及理工畢業學生 及理工學院的畢業生,畢業生中,為職公務導處及工學院學生補 招聘公務性,兩間大學院的二千六百七十個兩所大學的就業輔 年前的過去數年間,任腌商地指出:事實上有

入職政府部門比率下降 . 事實顯示學生對公務員職位感興趣

政府近年放緩招聘公務員

,八三年的畢業生古;任 了二點二四,中文大學控政府個安定的職業。 百分比,較八二年下降一公務員的畢業生其中称人機構降高,同時可有 一直都感興趣,原因與初

織府中從

入

綱機職

而分二至三 學院,雖然近兩、三年 過去四、五年平均下附一化驗師等,其餘部分常 們與政府有關部門開會 職公務員的比率,治療員,放射診療及業生活方面的期唉,他

配

政道

工作的比宇,並無顯著 的畢業生,在政府部門中大校外部主編

的下標名,包該學院 藝與美第二期

業生當公務員的比率,

比兩間大學為低。 畢業生的就業人數有八 統計資料顯示:八三年 |找港大就業輔導處

三期星

口

合訂本已出版

「第三期歡迎預訂

三位就業人數中,從究並為進修行課程參、漫畫·張向。八、近代 六。八二年在七百九十栋之送術欣賞與製作品」。七、「紐約客」中看 公務員的佔百分十四點,加强木 義之後是甚麽?风姿 百三十四人,其中任職一訂本現已出版發行,。六、繪畫,新的嘅生 「編之「癌與美」第二期 畫技法探討·劉欸柿 一中大校外進修部主 演變,楊建芳。五、水

11|| 位發言人指出:適发者及藝術家·其内容的

活

,五年來每年平均有一

石:略與外椭器

| 業生,而任職公務員的

器、銅器、漆器、硯石、徐熙[越烈花

法

徐祁達。三、路

王除游

BEOKE-OD

,但近兩年來,百分、築及各類設計等;

。四、石墨談龍,李天

政務主任及行政主任的文目錄列下 ‘◎的书龙生中,以從事開。茲將該刊各期一1荐成一 c她應;一發任職公務譯等;(四)藝術》卷辨偽·徐菲遠。六、

臺中均約下降至八和九 (三)熱海苔評、藝文 20五)楊懷素蕤曹格)

淡水白

義何去何從-----續維 【現代主

阿導處就業鞫導主任代大型立體石風格

比帝次之,部份則在消一種與美術研究有 GERHOUDERS HIRE150*(24) « 可选及人民入算事務處一關之中文期刊,莊牌,一段,莊:十,現代陶 政公署及磁敎署工作的一的啟用,陸味。二、後歡。八、炒蔟藝術, 福多,從事群察,在東路諾中國山水畫中管墨斯的八以十年葛形象, 三、八大山人書畫紀年[藝與生活,營高第

港書法名家梁鈞庸

出席台灣書法大會

. 行政院文化建設

並將在會上提出論文

在大會上提出論文。.「作的貢蓀。 掛架鈞盾,同時梁氏將「資深造詣與致力文化王,六六儿三六一代商· 香港中國背澉協會理事,以表揚其在書法上的话:三七 八 本港應邀出席者為:「文化獎章」一座雅射區中大校外语修部

內,舉行:「中國書法及獎金,近二十年來以 及香港等地則爲一二一條風出書法時,我教育「購處:九龍尖沙咀豢成 坡、馬來西亞、比利時 ̇士,去年返國在國家畫|一册,港幣廿五元。訂

·另日本五人,美國五一,國立歷史博物館柔譽 李文,內容豐富,正文 王壯设,江兆中等人外後獲教育部功般獎狀,王煜,該刊各期藝術」 除台灣木區有孔戀成、我國書股人七種重·其十、中國美學的特色 清八個國家學者出席,交流,不遒餘力,深為「風水,謝議佳、九、明 國際學術研討會」、落· 打造嫩園路如心 龍門、香港的建築與 天假台北國立師範大學得獎人·獲頒文藝獎章說中國古典園林,鍾莖 | 部特以鼓菡設置之金質湖六十七號安年大獲十

地民歸在楼軸• 李天馬

大家顏闻卿逝世干二一九七一年路教育出息,皆發考·徐邦達。六

·梁閔雅任華僑、選題跋的發展,就中、五

10.

漁農處教署下月聯合辦 鳳尾菇栽培專題研習班 主要爲中六生物科教師而設

-四商及

種項級香該研 議題 生月

图片 考區 習班 班恩·科目

生等班 形即合: 熊:科考內

商里程香,

日年毂

包起就赖十九 月與

蕭您日,四典

明日處

生·用作

名額有限最遲本月十五報名

會考),〔乙)用[班或其中之講座或研習

行程內容,中西及中五生物科學生|如有間,可電

習部分之資料,亦可供可獲優先取錄。

師校・題

食

玩五

五十六三九二四六二

西安製或名

名趣 研生 尢间 格动

色馬 明與並漫圖六五进藝、西港玉:第陶館

m) 8000+107(in m

蛋

可部班組欷罐於班

【動額席署:

者全 ·智物室,

1985

中學會考試題預習專欄

物理

CAS

明德出版社盧雄國 提供資料

PHYSICS (8)

H.K. LO

「MILL & DALE PRESS LTD.

Answers to Exercise 4

1. Form the given graph:

(a)In stage V, the

truck takes the: longest time, it takes. 40 seconds. (b)Stage IV and stage V

show.that the truck: travel the greatest distance (400m)- (c)Stage I and stage II

show that the truck travel in uniform: speed.

(1)Stage IV. obtains

the greatest speed (20 ms-1).

ii)Since the slope of

the graph represents the acceleration, therefore stage III shows the struck travels with.

greatest accele- ration for its slope is the greatest.

(iii)Stage TV shows that

|truek(obtains the greatest: kinetic. energy for its speed is the

greatest in this stage.

(e)Total distance:

travelled

=total area under

the graph +2(10)(30)+(10)(20)+

(10-20)(10)

= (20) (20) + (20) (40)

=1300.m

the centres of gravity

of the 50cm arm and

50 cm arm

respectively)

30 N=56K

GH=ACsing

=0.15sing

GQK=YBCcos6

0.25cos0:

3(0.15sin8)=

5(0.25cose)

sing 5(0.25)

cos9310.15)

tan↔-25=2.7778

0~70°12

(Ans.).

3. Let'the tension in the string be T, weight of the block be W, volume of the block be Viand the upthrust on the: block in water be B

T W

i)In fig. (a)

T-W

N

Infig. (b)

*=T+W

-248

10 N

(ii)B (P)(g)(V)

(Ans.

where P=density

of water

M

Mass of block A

-0.8 kg.

Total mass of the

combined body

=(M+0.8) kg

Since the combined body floats in water with the upper surface just covered by water, therefore the density of the. combined body is equal to the density. of water,

1000~

depth

M+0.8 [ 8000+10° 1.6

M

0.2286 kg.

(Ans.)

As shown in the fig.,. pressure at 3(P).

atmospheric pressure =760 mmHg P-760 mulig

Let the pressure at

B be P

V40A

B

Vp=(40−10)A = 30A

羅二品賴:的问艇 張细的恬九民。約 花文森紂存易、族八家 三一略為錄在。若化、

三練:「十丁問近中夜 二圈一王、行速代打發生

Wweight of the

copper block: =0.089 g

Wy=weight of the. iron block

By=Eouyant for force exerted on the copper block B-Rouvant force

exerted on the iron block Consider the copper block:

露

费

According to the Archimedes' Principle, Bouyant force=weight of equal volume of liquid displaced. Volume of copper block mass of copper block

density of copper. 0.089

8.9d

where d is the density of water

0.089 8.9d

=0.01 g

•T=W~0.01g-

-0.089 -0.01 g 20.089 g.. Similarly, consider the iron block T=Wg-B2.

-Let-m-beythe, ma se~40

the iron block

Volume of the iron block

蝦

7.84

where A is the cross-

sectional area of the tube.

7.9

Apply Boyles law

Dg

(Ans.)

TA

-1000 kgm

10=1000(10)(v)

V=1x10-3 3

(iii)Let the density

of block A be

•*-(P) (8) (V)=W

(A)(10)(1073)=8

A=800 kgm

Relative density of

block A

(Ans.)

800

10.00

=0.8

As shown in the fig., the angle between the. 30.cm arm and the

vertical is when the piece is in equilibrium.

Let

dudensity of the

metal rod in kgm

A cross-sectional area of the rod ... 2.

in m

Weight of the 30 cm

arm AC

=d(0.3)(a)(g)

-0.3dAg

Weight of the 50 cm

arm BC

=d(0.5)(A)(g)

0.5dAg

Moment of the weights of AC and BC about the vertical line through.P are equal in magnitude, 0.3dag (GH)

=0.5dAg(G¿K) (where Gy and Gy, are

(iv)Let the upthrust of

(Ans.)

block a in liquid X be B

From fig. (c) T+B_=W

0.5+B_-8

By=7.5 N(Ans-)

W Bx

(v)Let;the density

liquid x be A B-P(g)(V) 7-5-(P) (10) (10-3

£=750 kgm

Relative density of liquid X

750

1000

(b) Let the mass

liquired be M Volume of metal required

M 8000

(Ans.)

Total volume of the combined body.

•760(40A)=P(30A)

3040

B

But,

mmHg

pressure at B

watmospheric pressure

+pressure. due to

liquid column:

=760mmHg`+

pressure:

due to liquid colume

.Pressure due to

Fiquid colume

3040

760

760

mm Hg

=(13600) (10) (760) Nm

On the other hand, pressure due to liquid colúmn =(1200)(10)(ii) .(15600) (10) (760)

=(1200)(10)(h)

13600x760

3x1200

=2871.11

.Depth of the lake

2871.11, m+10

em

2871.11 0.1 m =2871.21 m *(Ans.)

diagram is constructed as following:

where

WW

FR

T =tension in

cord

)mg

=0.8718.

(2)

By equation (1).and

(2)

0.079g=0.8718mg

-0.079

"0.8718

enters

來

cell A.

可般與公

有私初務 『約腩輔

(ii)water in cell A

enters cell B.

e) Name the pressure

produced by the inflow of water into vessel D..

f) How does the soil

particle size affect. the amount of soil air?

2. The diagram below

represents a model which is used to demonstrate the process of ultrafiltration in human nephron.

water

(Prosti

An electric

pump

Tiny pin

・Plastic beads bag.

· suspendtá in

花穴

pricks on the-

rubber tube

Funnel

clip

•water from the pin pricks

a) which organ in the.

body does the electric pump represent? (i) What structural

feature of the arterioles in a nephron is being", demonstrated by the use of clip. X?

(ii)What is the

importance of this.feature?

(i) Why do the plastic

beads not pass. through the pin pricks?.

(ii)State two

substances .represented by.

the plastic beads.

Explain why the funnel cannot truly represent the kidney tubule.

(1)

生物 (八)

=0.0906 kg

明德出版社 梁偉宏提供資料

BIOLOGY (8)

W.W. LEUNG

MILL & DALE PRESS LTD.

Unit 3: Water, and Organisms

1. The diagram below.

shows the absorption of water in the root of a flowering plant.

Soil particle

·Film of

soil water i Cell B

A

Vessel

The arrows represent the pathway of water. What is the importance:

of the finger-like. appearance of ̇structure X?

b) Name, cell: A and vessel

D.

c) Why is the cell sap of A more concentrated than the soil water?

d) Explain in detail how

the

(i) water in soil

Name the fluid represented by

the water

draining out from

the pin pricks.

(ii) Give two

substances which

are present in this fluid but absent in urine, (iii)Explain their

absence in úrine..

13. The di belaw

shows a plant (Cactus) with adaptations which enable it to survive in certain physical conditions.

Leaf (non-green)

Bulky stem

•Ground level

) Which physical.

condition is the plant

wapted to?.

b) List 3 features

illustrated in the diagram, wliich enable the plant to survive. in the above.

condition. Give explanations.

e) Since the plant has

no. green leaves, which part of the plant carries out

photosynthesis?

Answers;

a) The finger-like

教

appearance of K increases the surface area of plant in contact with soil so that a better anchorage, efficient. gaseous exchange and absorption of water and minerals can be

obtained.

b) Cell A: root hair

cell. Vessel D: xylem

vessel

c) Because of the

presence of dissolved.

minerals and sugars, proteins in the cell

sap.

d)

i)Since the cell sap of

A is hypertonic to the surrounding soil

water, water enters cell A by osmosis. Hi)Since the diluted cell

sap of A is now hypotonic to the cell sap of B, water further enters cell B by osmosis.

Root pressure,

f) In general, the amount

of soil air increases. with the size of soil particles.

b):

Heart.

1)The greater diameter

of the afferent arteriole than the efferent arteriole is being demonstrated. ii)The feature leads to

c)

a high blood pressure inside the glomerulus, which forces water and dissolved substances through the capillary wall into the Bowman's capsule.

i)They are too large to

pass through the pin pricks.

ii)Plasma proteins and red blood cells.

d) The kidney tubule has

convolutions, semipermeability and ability of

e).

reabsorption, while the funnel has not any.

i)Glomerular filtrate. ii)Glucose and amino

acids. iii)They have been

reabsorbed by the wall of the tubules into the surrounding capillaries.

condition.

stem

to store

more water. ii)Spike leaves - to

reduce surface area so that less water. is transpirated. iii)Long roots - to

absorb water deep in. in the soil.

c) The stem containg: chlorophyll for photosynthesis..