育教僑華
真三第張四第日三十月五年酉辛屦夏
WAH KIU YAT PO
報日僑
日期星
日四十月六年一八九一层公年十七國民華中
3x+22.62
5600
(b)
1981
中學會考試題預習專欄
where `n` íg
any
-| (2x+3)αx
(x+1)
3y-9x=-1.14
y-3x 18 anıl
3-3x+38 ()
560"xn-29.62°.
附加數
(+3)(x+1)
120°x-8°(rathe
(試卷二》:
建議答案 明德社提供
Suggested Solucione
HK.C.E ERA,"
ADDITIONAL MATHEMATICS;
Paper-II
SECTION
nearest degrée)
(Ans)
+3)(x+1)
Area bounded by the curve and the y-axis
(c) As 0 gr £1
using
Bult
(b)
the required range ia (AaR.)
which is the locus er p.
(Ans.)
Sub
routa: 810+
(ii) Let x « √3tane
dxx
(P
(1)
Whenx
When
Product
Squaring pik sides of
Q+ësinëcose
DIX+2
(2)
Area of the shaded
1.0
A(4%)
(a) Substituting (1) into (2):
(m2+1)x2+hmx+)
(3)
(Ans.)
Let the roots of
and
G
(tan+1)
(e) Volume generated by the iine and the y-axis
about the *-*
Deb)
** (2x+3)2 4x
and (x,-X)
·221x+2y=8-0
Solving the equations
A(4,2)
hout the
Let D-
21
52.67.77
Volume generated by the
(1)
curve and jus
(2)
(1) 4 (2)
curve AR-
2(x-1)
1.6. 2x-y-10)
:(3)
Substituting (3) into (1),
+7(2x-1)
-4x+1+
aled
the point of contact
(Ane.) peated root
Aren under the
ACH
From(4),
When
(3)'. £8, £x-y-1 - 0 the
-[]
(Ana.)
20.95 T
the required volume,
32,671-20,951.
31.74
(a,b) and AG GD
5t-4
and t-6 m
(Stal Sta20)
(ADB)
(b) Equation of AK is gives
y+10-2(x-4)
3-3x+10
Since Glies on this line,
(t~6)-5(+)+:
D(3x2-4 3x2-20
(1-7)
aired common
(Ans...)
(1)
4755
the area of the shuded.
region
1.999-(-0.4755)
The length of TS
x = k(x-4)
Integrating
y = √x(x)dx
the length of AD
√(4-1)2+(2+7) 2
··√(8-6)2 + ( 3 8 +34) 2
2
190 3/10
Slope of AÐ ➡
(3)
2.378
Let u(x,y) be the mid-pulut,
since it passes through (~1, 4) and (0,1
(a) Considering AEHE,
cosine 1
Slope of AD
2
+ ((~1)2 (~1)}+0
+(rk)=»2rk'k¢os60°
tanŹBAD
2udu.
dx
Substituting into ((3),
12c6a3x-sin)x » room(3x+0)
( 24 ) * + (4*)
9-1
81x3
which is the required.
Focus.
SECTION B
(a) 1 m
Let y
When
When
-wine-dy.
k4 (Ans.)
required equation
k2(1-rer2)
#in45
(Ana..)
(kerk)**
(k-rk)2(})
(Ans)
ALBAD
(b)
(b)
**)~}}2 (1-r)2.
(An.)
In: AAEM,
-{{AC)®:
Áron of AARD
AHZADBIRLĦAD
- (14/8)(3/19) (73)
(7/2)(3/23)(-)
422
Area of ABC » 2x42
#x43 84
8q.unite A(442)
length of AB
(Aas..)
(b)
CO
(1) (1) meets (2) at 2 points
if and unl
AB × 0.
(Ana)
(11)(1) 18 a tangent to (2)
if and only if AB 0,
(Ans..)
(111) (1) does not meet (2)
if and only 17 AB 40 1.e. -/3ca43 (AMK)
(c) Substituting m = 2√3 into
(3),
For m
13 ±√48-48
2x4
(1)
Similarly
13(3x-313x)
13(nogens3x
-BinPath3x}
13. god.
22,029
Now
13ena(3x+22, 62°;
(Atis,)
-13
cpa(3x+22,62")
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2x+3= 2x-3x-2- (2x+1)(x-2)
or
7
Area bounded by the line,
(Ane.)
and the y-axis
器
Let be (*,*)
Area of å ̈ÅÞD
= (4y+ (~7×)+2-2x-
412
1.e. Jy-9x+30 - 284 3y-9x - 54 and
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equation of PQ is 2y-1-0,
(Ans.)
(d) The equation of family of"
cireles required ta
x2+y2=1+k(2y-1) = 0 {Ane.)
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