台一台電育教 頁三第張五第 日九初月正年申庚服
WAH KIU YAT PO
報日僑華
日期星
於
日四廿月二年〇八九一座公年九十六國民華中
和勞釀所著
秦藥糕&
龍翔劇團本週
港九新界演出
敬老大會演出兩天 間」和「雙打餅」。廿八日在尤朗運動塲下午八時,演出「花開富貴|橋曲目如下:: 下午七時,及十七日在九版土瓜灣落山通垛塲,下午八時,演出「其雄之一空中其台」,今選署 果塲 - 下午八時演 香港北角己照屿装 四:廿五日:在 过在港九新界演出 田亮涿社區會堂--播出由張花遒主持的 揖「骨肉賴」。 橫期一、二、四五 | 甘六日:在沙 等四天,上9十一時起 廿五日:忠
龍球鹅議於二月六日,七日兩天,在大事會堂,促教老大會演出等劇橫妙芝「迎春基 Si
J
天子情丫緻↓j文千
張月兒「花開帳春 『直上請客折桂花」; 養」-氷竪丶候游
廿六日:重播李麗
(上、下)話過祖在五號錄實實對台灣。
空中舞台
選播的曲目
香港電台站五者
陳好「荔枝記』; ↓「使題」;羸米英、
之璧];文餐評,林小 葉、家來主持「梨 「遙女婿] 女
拋花浞」;拓費裝、李、 馬
J;梁無色、滑無相
養牡丹開」。
花開鈽养姹鄣j; 廿九日:陳雲「
環業好「桃花仙子」: 廿八日:梁蔞山、
一;漢棠、書;白菊、郭廣莨「打 粉底帝體系;任 永堅、殷淑芳;花田帐、黏一花包括 買缺「江山美人」之「養矓塵談會」播出降間 于均等,「风
十分午間新ä之後, :期日中午十二時
座談會」出席講者!
面面觀座談會週日播出
聽者拜年。
「五號錄音室」
故事」後「人日家家喜
, 比起他們上一輩的时 「長龍蜜攒劃」播「大的改攒-
?敌們在洛·糍看法见?
陳,香港實年協 的價值取向女不會有黨一些問題,提出一些討論人,號外紹智法垭载 *有那些特點呢?他們」,會否有助於我們就這群者,有中報康編輯胡 年 - 在生活影裁方面 - 納七十尔代的生活蒍鹼|游行對沟,今次出的 陳冠中-新一代
八十年代的香港靑|些一飛?我們綜合和,將會就以上的問
「八十年代的香港青年」
磁娓里,挺希望今 香港代半大廳鸡里+^! | 肚變区;而想劃組各人可闖。是關人人都覺得「食不是鷸」及「醇酸在人 於春-相信人人都是張之聲+歌族之聲,到處|油價派橫車主舌」、「 所一年之計在一人仍然神采飛鹚「恭喜」、「露座有耳」、「
默-於馬秒种。劇組 間人工此各位及 |-今日一起來開工 緄「大情人」-「 - 金然彔習俗難朶啦: 感謝各位舊案長年營運」,上同究。「悲歡前 執筆降是年初五,作更多更佳廣播劇,以「杜」之「天懷的與潑 四天的假期,十五卿完。「義度升 4] SEƑNBAK)
「輝爭虎鬥」播「
廣播台花絮錄 財團, 少年,不过
今期每日介紹:一個完
—則搭「而感啊」
澳台主靡十大中文金曲頒獎音樂會,已於二月九日,在大專银盘举行
二月九日在大專會堂演出盛况
十大中文金曲頒獎
。王爲晚演出略況:
哈謝,為金曲狨览被影演現代舞, 找表演他那谮类;曲。(金立)畫幅橫談安演起訴得獎歌曲。但彩虹 荃從到回安手中組獎時攝。馬天波鎮頒獎給鄭少秋,(1右)蓋塔强積獎 張、文、陳百強、張惠關、願高群、修剪、邓縣-和潘志文。汪明 由上至下:邪和銀獎者與司儀會:伍家素、鄭江、
◎ 香港電台第一台的
戴了。
瀆點,吳正尤,吳章散 由左至右]爆若樂
轉播四場
足球比賽
香港冠台第一
「固面懟座談會」節目行幹事王石疇,市歎|
足球比量如下,廿
四日下午四時卅分
「逢三進一問答賽
由香港凡台舉辦之
「涵三淘一」問答比賽,將於11月廿四日星期
持-启二月三日啓播以及城出-敬瑰
,由於得庭各方方支
備受廣大聽衆歡迎
比賽之精彩過程
,治謝海 九日下午八诗卅分 -東方對東昇,世
一八日下午八時卅分 ,根對海峰。计
五日下午四時卅分
港台第二台特需肥 -
第以來,得悉未的歡迎,一年 的4日 - 即三月份的第一個星
素湯臣之刺激-麒業亦 故不但參加者糙感受比
之門導,以朱 雙台第一台播出,高容 午一時零五分,在香港 -該節目達產期日下 申請參加求,非常顯
一來,受大麟衆歡迎
J撬口號 - 歡迎參加。
,以「獎品、謝朱
「次事辦之公開問答比賽 三选一」,亦無港合首
界世樂聖
出播日週個一第三
中在古
天攤樂和
一,銅色日報,次唱片 - 萌僑仔無,鄭畫線,巴哈等的名作。本節目由梨在遥神父及王燕胜 但总期刊登於天天日報】果世界」中,我們畫介紹莫扎特,鼻叡-李斯特 | 參加表格 - 每月份撼!內容,也就是從未系改出的。在三個月的「 饮 小姐主持*
部份,是不能更改的·张谦租的
1980
Hence, the relative
atomic mass of H
84-(12-16x3)
=
中學會考試題預習專欄
= 24
(b)
化學
(二十)
明德出版社朱宏林提供資料
Chemistry (20)
Reginald w Cho
Hill & Dale Press Ltd
Solution to 9. 34.
(a)
+ 2HCl
MCL2
+ Hy() + Cl2 •
(ii) This is to saturate
the liquid in the flask with carbon dioxide first ro that none of the carbon dioxide liberated by action of hydrochloric acid on the metallic carbonate will dissolve in the liquid and the volume of carbon dioxide measured will be more accurate.
(iii) The reaction is'
fastest at the very beginning of the
reaction. (iv) It is because the'
導
reaction has completed and all of the metallic carbonate has been nged
tp..
The maximus volume of carbon dioxide obtained
3
is 1120em
*fviy No. of moles of loy
abtained
*
1120
=
22400
0.05
According to the
equation,
MCO
+ 2HCl
H2O
no. of moles of MCU3
reacted
-
mo, of moles of Cg whtained
= 0.05
of HCP
zaed is 4.2莲 mns of one mole af MCO.
4.2
骂
• That is, the relative
mass of MC, is 84.
84-16
(i) Add dilute sulphuric acid to the mixture; zinc will dissolve while copper will remain unaffected, Filter and
obtained as the solid the filter residue on
paper.
Zn + H2SO →→ ZnSO4 + H2 (ii) Bubble the gas mixture.
through cold, dilute sodium hydroxide; dinitrogen tetroxide will react with tfd9flkali while oxygen will pasa over unaffected,
Ng
+ 2H
- NONO2 + NoNO4 + 2H2O
(iii) Bubble the gas
mixture through sodium hydroxide solution; carbon dioxide will react with the alkali while nitrogen vill pass over unaffected. CO + 2NaOH
+
(iv) leat the mixture
gently in a beaker; ammonius chloride will sublime off while sodium bromide will leave behind.
NII,C1(.) :NHz(g)+ HCl(g)
(v) Add water to the
mixture; sodium: will dissolve while
calcium carbonate will not. Filter and recover sodium carbonate from the filtraté hy evapora- ting it to@dryness. (vi) Heat the liquid
mixture so an to distil nitric acid over because concentrated nitric acid is volatile while cone, sulphuric acid is non-volatile,
(vii) Pass the gas mixture
through conc. sulphuric acid; ethene will react with it to form ethyl hydrogen sulphate while ethane will pass, of unaffected, on warning the ethyl hydrogen sulphate, ethene will be liberated and recovered.
CH2=CH2
K-HSO4
CH3CHQHSOM
(viii) Pass the gas-
mixture through powdered palladium; hydrogen gas will he absorbed while carbon monoxide will not. On warming the palladium powder, hydrogen will be recovered
Add the solid mixture
some carhon disulphide; sulphur will dissolve while iron will not. Filter and evaporate the filtrate to dryness uver a.water-bnth to obtain the sulphur. (x) add the mixture to some Caustic soda or caustic potash; zine(II)oxide, heing amphoteric will diagolvs: While magnesium oxide.vill not do so, un filtering, magnesium oxide will leave behind as the 'reaidue.
ZnO + 2NaOH + HD
Na Zn(OH)
Solution to 0. 35
B(1) Some of the
copper(II)oxide turns from black to reddish- brown powder due to the formation of copper · powder.
(2) Anhydrous copper(11)sulphate turns from white to blue due to the presence of water. (ii)(1) CuO + Hy
*Cu + Hyd CuSO4 + 5Hgu
-CuSO4·5H20
(iii) This is to prevent
the moisture in air from entering into the apparatus.
(iv) Mass of water formed during the experiment
gain in mans of copper(II) sulphate tubes
-
·
(37.375-32.362) #
- 5.013g
(v) Mana of oxygen in the
water formed
- mass of oxygen taken from copper(II)oxide * lose in mass of
copper(II) oxide boat (16.590-12.147) ɛ
-4.4438
(vi)。
mass of water
formed
= 5.013g
and, oxygen in water
formed
4.4438
. mass of hydrogen in
water formed
Hence.
•
= (5.013-4,443) g
= 0.057 g
ratio by mass of H-to 0 in' water
- 1 : 7.79
= 1 : 7.8
44
(viii) This is to ensure
that any water detected must come from the reaction between copper(II) oxide and hydrogen gas.
(b)
(i) A saturated hydrocarbon
is a hydrocarbon (i,e.
a compound containing only hydrogen and carbon atoma) in which all the atoms are joined by single covalent bonds. (ii)(1) Ethannly
CH3CH2OH
(2) Propanoic acid,
CH JCHD COOH
(3) Ethene, CH2=CH2
(iii)(1) They arel
and
H H
1
H - C - C-H
C1 Cl 1,2-dichloroethane
H H
H-C-C - Cl
H Cl
1,1-dichloroethane
(2) They are known as
structural isomers because they have the same molecular formula but different structural formulae.
Solution to 0. 36
A is iron powder;
B is hydrogen gas;
C is iron(II) sulphate
crystal}
D is iron(II)hydroxide; E is iron(III) oxide;
} is iron(II)
sulphate;
G in iron(III) hydroxide;
X is sulphur dioxide;
Y is sulphur trioxide.
(ii)
(1) Fe
+
Hy SWA
最
Ho
-FeSO4
(2) 2reS04-7Hg
· Feq0% + SO2 ·
503 + 140
(3). Feguy + 3MnSO4
(4) Pen(SU)3
(5) Fes
+ бN&UH -2Fe(OH)3
+ 2NaOH
+
→ Fe(OH) 2 + Na
(6) 4Fe(OH)2
+
Na¿,504
2Feq03 + 41120
(iii) Use carbon monoxide (or hydrogen or carbon) which can reduce iron(III) oxide to iron."
Feyuy
+ 3cu
(b)
- 2Fe+ JC02
(i) The gas obtained at
the cathode is hydrogen and that at the anode is
oxygen. (ii) At the cathode:
2H + 2e
At the anode:
40R
280
→
H
(iii) (1) According to the equations in (ii), for the same amount of electricity used, number of moles of hydrogen gas liberated is twice Hя the number of moles of oxygen liberated. There- fore, according to the Avogadro's principle, kydrogen gas should have
a volume twice as that of oxygen gas.
(2) This is because both hydrogen and oxygen gases are slightly soluble in water, but they dissolve in water, to a different extent; so the '2:1 (Hy:by) Tatin cannot be obtained in practice.
(iv) The conduction of
electricity through ditute sulphuric acid mainly depends on the mobile ions in the liquid while that in
a copper wire is mainly due to the motion of 'the free electrons.
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