有教僑華 買三第張四第日七十月五年未己服
1979
WAH KIU YAT POI
邹日僑
●期星
cos20c082-0
Let
日一十月六年九七九一层公年八十六闔民鑒中
́. A(t, 2t) lies on (1)
中學會考試題預習專欄
n2+1
Differentiate
(1)
in20
2yy
附加數學科
建議參考資料(二)
明德出版社提供
ADDITIONAL MÄTHIS, (II)
2
COS: X
→ sin x
f'(x) ■(1+sin3z){2cosx)(-ainí)
(1+sin
x)(2sinx)cos7
(14sin x)
Bin2
2-27sin20
(1) is $20c
(sing+18) cos2k+1
2*ain20
(2winga cong+18)
√(2sing
sin20
†(20) du
Whe
Wher
# [1 − ( })"]
2+),
(21)
du
equation of tangent
A 18 ven hy
17.
- }]
(ii) Comparing
1-
with ty
(Ang.)
the sl
(Ans.
(2x)()
(1+(---)2)° /2
(-1)-(0)
2. (2x
The 5th term
°C, (2x2)^~^(-2x)
2n-12
Since this is constant
5th term
(Ans.)
be (h, k)
Pch,k)
sin20
•k+2
sin2
k+1
sin20
Putting k+1,
the last exp, s
cos20cos2
sin2+1
ain20
Since the statement holds
and if it holds
also holds
hence,
by mathematical induction,
it holds for all positive
integral values of a. (Ans.)
(i)
Lin (1
(1)
dz (x + 2y)
(Ans
dy
dx
·(2) (As)
(2) .(3)
dx
(x+2y)*
(1) and
-[(x+2y) (2+)]
[(2x+y) (1+2)]
(x+2y)
-2x-4y-xx-2y
(x-2)(x
require
- √
|x(2 - x)| dx
x) dr
(x+2y)2
(1) and (2) intersect at P(2,
(Ans,)
(x+2y)
3x dx – 3ý
(x+2y)
(2) and (3)
and (3)
(Ang.)
(** Py)3 ***
(2) and (3) intersect
at Q(1, 1),
(3x 11⁄2 – 3y)
+ 28 )3
(1) and (3) intersect at R(1, 11).
(Ans.)
2y
(3x dx - 3y)(x+2y)
3x(x+2y) dx - Jy(1+ 2y)
3x(x+2y) (-2)-3(x+2y)
(ii)
(2)
-6(x2+ xy + y2)
rom (1) (Ans.)
Q(12.03
The co-ordinates of M. are
(2x-12)2 + (2y)? 48x+144+4y2-16
-12x+32
which is the locüs
12-
2y
sq. units, (Ans.)
(cost,
.(1)
·(2)
cose, co
icose sing
80
ine cose
+25–10x+x: −80
é, sinė
2x
of roots.
~~(~2)
Where X X are the
x-co-ordinates of A and B
respectively¿
x-co-ordinate of M,
the mid-point of AB
cos(9, + 8,)+isin(0 +82)
cose1 +isine
+ isī
(cose, + isine,)
[com(-2)+1sin(-8)]
cos(0,-
(iii) Volume of the solid
generated by the 3 curves
Volume generated by the region PRS
Volume generated by the
egion PSQ
- xf" [(12- y)- 1] dy
-x" (11- y)dy
dy
In20
Whe
os28:
sin2
sinze
2sin20cos20
2 in20
cos20
is true for n
Assume that the statement
is true for n
cist -qis¤
From (1)
Mis (1, 4)
Now, slope of AN
slope of the line LAB-1
the line through MLAB
is given by
0
(1)(x - 1).
(Ans.)
x dx
7.(i) Let
cise, cise
cia(0
cia
- (@2+
(11) The argument of the
last expression is given by
Y
- 2x + 2x
16.12
10
cubic units.
(Ans.,)
4x
(i) Substituting
(t2, 2t) into (1),
(92
$20)
(1%, }) (Ans.)
(s2,25)
(iii) The tangent
is given
slope of the normal
S
This is also the slope of
normal from (3, R(S, 2S)
(1,-2)
11.(i) (1+ ax✦
(11).
[1+ 2(a + bx)]*
=(a+hx)
x2(a+bx)2
4x(a + bx)
bx
4ax+ 4hx
(4h+ 6a2)x2
(Ans,)
A(1+ a2
[1440x4{4b+6a2)x2+...]
(4b4
(Ans.)
Since
(48~1)
+ (4b+ 6a2- a)22= 0 when
is very smal) 0
4a-1
2
6a-
-32
The approximate root: required is
(Ans.)
Page 15Page 16
No comments yet.
Private notes are available after approval.