育教華華頁三第張九第 日一廿月四年午戊曆夏
M
新數學建議答案
MODERN MATHEMATICS:
SUGGESTED SOLUTIONS
TO MODERN MATHEMATICS, PAPER
1, H.K.C.E.E., 1978.
WAH KIU YAT PO the set of students
who are the members of
the Mathematics Club.
報日僑華
六期星
日七廿月五年八七九一公年七十六國民華中
4(x2 - 2x + 1)
4(x − 1)2 - 9
The width EF.
- GD
the set of students
who are the members of the Chess Club.
Since total number of
students is 41
AADE and A ABC are:
(ii) The minumin value of
(x + e) is 0.
(iii) The minimum value of
4(x − 1)2 is 0
The minimum value of
(b)
2GN
2 x 6 x 0,2588
3.1056
30
12 9
100%
(22 x)
(31 x)
x 18,
18, students are members
of both the Mathematics Club
and the Chess Club,
imilar
AD DE
AB
BC
x-9 (Ans.)
(b) Volume of the smaller cone
- (*)(3)2 (9)
The minimum value of
2
-8x-5
(9 (Ans.)
14. (a) The required probabi-
lity is (Ans.)
(b)(i) The required probabi-
lity is
8.(a) n(s)
- 36 (Ans.)
27
AB is the diameter of
(b) T =
{(1,1), (1,2), (1,3).
Volume of the larger
cone
the circle
LACB
90° (Angle in
(2,1),(2,2),(3,1)}
(ADB.)
- (*)(5)2 (15)
125
semi-circle)
Also,
Z ABC
SECTION B
Volume of the required
golid
ZADC
205
125 T
271
In rt, A ABC,
AC
AB
sin20
AB
AC
sin20
10 cm
0.342
29.2 cm
(Ann.)
2. (a)
are in A.P.
(Ans.)
From (a)
2b.
• †(x + a)
20:
2x 2x
2c
(Anz.)
(0.51
May
(a) Let the equation of the
straight line be
y = mx + C
the gradient of
the straight line
--2-
y-intercept of the
straight line
- 98T (Ans.)
11. (a)
(i) Tom gets } of the original
piece in the first opera-
tion o
(ii) Tom gets (1) of the
original piece
in the
second operation alone. (iii) Tom gets (†)" of the
original piece in the nth
operation alone.
(b) otally, Tom will get
(4) + (4)2+ (4)3,
(+).
(Ans.
(글) (금)
(Ans.)
(ii) The required proba-
Area of sector GOD
360°
- 300 D
#2
X (w) x 62
Area of sector AOC
(c) The required probability
30o
bility is
x ( ) x 902
360°
(글)(승) -륵
(Ano.:)
675 m
area of the piece of
(今) + ()(含)
grass
-9
(Ans.)
675
672 π
3π
(Ans.)
156(a)
Apply the formula
kể cả hồ
THE END
學能推理練習專欄
智慧社主編
文字推理練習二七
綜合練習
試選出下列每蒩最適當的答案,作爲該序列的 列的最後一項並在所選答案的下面畫一橫線
2a
(Ans.)
(Ans.)
1.飛翼游、鰭池、(A跳 B C#
·DŁ EA)
Al
16
3x
11i and
214 18j, then
- -2x + 5 (Ans.)
(b) Let r be the radius of
the circle.
12, Mean height
0Q
(100x101 + 150x103
(b).
450x105 + 200x107
(4-0)2
+50x109+ 50x111) 1000 105.2 cm (Ans。)
(b)
substitute these valu
into the results of (a)
2(111) + (21 + 18}) OP M
D# EST 15
3.布、縫合;紙、黏貼;鐵、(A鑽孔B垺
接C鎔鑄D結合E接駁。
4、既然、何必:由於、所以;雖然、{A甚至
B但是‘C直至故此E固然)。
5.-丈夫、妻子: 先生、女士,兒子、(A媳嫌
B父親C晚輩 D父母 E女兒)。
6.慷慨、吝啬;仁慈、殘忍:忠厚(P誠實
Q率直R仁愛 S好除 T騙干 )
下列每題有兩個空格,試從P、O、R、S: T五組中,選出最適當的答案;並在它的下面畫 一橫線。
DEBA
Ttil失學、
241 + 18j
81+ 63 (Ans.)
2(21 +
21 + 183) + (
(mi)
151 + 36
7 XT
51 12j (Ans.)
PU教育
RUTA
From the graph, 1000
520
(ii) Length of OP
480 children are taller
than the mean height.
62
.. (1) . (2)
48% of the children
are taller than the mean height. (Ans.)
13 (Ans.)
(c) From the graph, the
interquartile range
(iii)
OP, 00
Cose
Combine the two inequalities
X 7. (Ans.)
Let the number of 1-dollar
coins be 1,
..there are 2x 2-dollar
coins and: 3x 3-dollar coins,
The total amount of money in the bag
·5(3x) + 2(2x) + 1(x)
20x
the equation of the cir-
cle is
(x-3)2
52 (ADS.)
(c)The coordinates of the
points P and Q can be obtain-
ed by find the solution of the equations of the straight line L and the circle.
-2x+5
(x-3)2+ (x-4)2-52 Substitute (1) into (2) (x-3)2+(-2x+5-4)2 - 52
x2-6x+9+4x2-4x+1 = 25
20x240
12 - (Ans.)
(−1)
2x + (y
3)i
2x 0
5x
10x 15.
x 0 (Ans.)
·3.-
2x
-
(x + 1)(x
3 - 0
3)
y
3
(Ane.)
(a). Gradient of L
x = -1 or x = 3
When x -]
106.5 cm -
104 cm
-2,5 em (Ans.)
(d) 50% of the children lie between the upper quartile
and the lower quartile.
10
+
(Ans.)
Length of 00
12*
Toplog!
+ (6)(12)
(8) (20) (15)
112
130
56
65.
(Ans.)
16(a) F
(ji)聽覺:Q门閱讀:(1)言人
()啞巴S(小學校:(ji)聲音
正如酒时 (i)
(ii) 失明
8.酒徒然行)
P
Ris
T**
9.学校姓(j)
Pli}抬椅
Ri)學生
TUM
10.珴波對 (
P
Rlii設光
Ti戰役
(注)醉酒:何)賭徒 ii沙金錢:
(ii)麻醉S(i)老饕lii)食物
**
正和家庭計
(jj)電視機: Qi)校園,廚房
(ii)兒童 Sii)校工(ii)弟妹
ti)母親
正如撲滅精(订)
tii)天災 QUIRA GE♫ K.
· B Sil兵士(ji)清除 消减
·细期下列一段文字,然後解答所附的問題; 並在所選答案的下面畫一橫線。
有六個小朋友,每人都有一個綽號..在下列 的圖表中,每一個小朋友的名字和他的綽號排列
次序並不相同
Gradient of L
Gradient of L
=
4x2
- 8x-5 -0
ym -2(-1) + 5 = 7
13. (a) When y = 0
0
P is (-1,7)
When x
- 3
(2x
5
y m -2(3) + 5 -
(b) Since the product of
gradient of Lg and gradient
of
L is -1 therefore
7. As shown in the Venn
Viagram below
Qis (3,-1)
Lg + bz (Ana, )
Let
the mid-point M of PQ be (x,y)
at
(22,-
5)(2x + 1)
or x -+
-
the x-axis cuts the graph
When x Q
D) and (-1, 0)
y =
- -5
= 4(0)2 - 8(0) 5
23 = 1
y= 2(-1) 3
*
Mis (1,3) (Ans.)
10(a) Let AD = x
6
the y-axis cuts the graph at (0, -5)
(b)(i) 4x2 - 8x - 5
- 4x- 8x + 4
.GOD
T-30°
In the figure above, Mis
小朋友
小光,大明,小姐
大明,小强,志雄
小李,志雄,奶
#
4. L. €
11.小光的綽號是甚麼?
A
羊、牛、馬
牛兔狗
C+ DG /EB
12.‘「兔」是那一個小朋友的綽號?
A
B志雄
the mid-point of BD, also,
x 30° 4GOM
答案
- 150
GM-
(OG) (sin15°)
C大明 D.小米 E小强
IE 2 D 3)B 4 B 5 E. (6)S 7 P 8 S 9: R 10 Q
I D 12 A
6 x 0.2588
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