頁二第張七第二日六廿月三年午戊
育教僑華
1978
【中學會考試題預習專欄
BORSIEN
歷史科
胡應亮
HISTORY (30)
(三十)
Philip .. Woo
FIMAL REVISION (3)
ALLIANCE SYSTEM IN EUROPE, 1871 - 1914: ..
1. Dreikaiserbund, 1873 (League of the Three Emperors)
A signed by Germany,
Austria, & Russia.
B. Agreement to maintaîn
the existing conditions of Europe; monarchical unity against revolu- tion.
C. designed by Bismarck
to isolate France, to prevent France from taking revenge after defeat by Germany in 1870-1.
2. Dual Alliance (Germany &
Austria), 1879. –
A. Austria & Russia were
bitter rivals in the Balkans. Germany
would sooner or later be forced to choose one as partner only.
B. In 1879, Bismarck chose
Austria as ally, for
the following reasons:
i. German support
given to Austria in the Berlin Conference in 1878;
"Austria's willing- ness to be, domin- ated by Germany; iii. Bismarck's fear
that Austria would become pro-Russian or pro-French; iv. need to gain
support from pro- Austrian Catholice in South Germany; Bismarck's own personal dislike of Russia's foreign minister; vi. Austria was a
German country
C. Both powers would help
each other if either was attacked by Russia and would remain neutral if either was attacked by another power.
Limitations
1 In the long run,
the alliance drove
Russia towards alliance with France.
Austria was encour aged to be more aggressive in the Balkans, which in the end pushed · Germany into World War I.
3. Triple Alliance (Germany, Austria & Italy), 1882 A. Italy suffered from colonial failure in North Africa at the hands of France. B. Germany & Italy pro-
mised military assist- ance if attacked by France. All the 3 powere would militarily help one another if
2 other powers attacked any of them. Reinsurance treaty (Ger- many & Russia), 1887- A. Bismarck still wished, to remain friendly with Russia, Rusala still wished to be on good terms with Ger-
many.
B. Treaty terms - if
either power was at war, the other would remain neutral.
C. Bismarck thus succeed-
ed in allying Germany with both Austria & Russia in separate
treaties -- a kind of
cunning double-dealing.
Highest point of
Bismarckian diplomacy.
WAH KIU YAT PO
報日僑華
5. Dual Entente (Russia &
France), 1893
ww
A. Bismarck fell in 1889- 1890. Williäm II, the ambitious young Kaiser, cbanged German policy:
1. Refusal to renew
the Reinsurance Treaty with Russia.
11. Active promotion
of colonial expansion (where- as Bismarck had refrained from it to avoid dis- putes with other powers).
111. Adoption of a
forward, active foreign policy. iv. Naval armament buildup.
competition with Britain.
v. Eager for interna-
tional prestige.
B. Friendly Franco-
Russian relations in early 1890s; French Loans sent to help Russia with famine relief & building of the Trans-Siberian Railway.
C. Alliance in 1894, both
promised military
support for each other if attacked by Germany-
6. Franco-British Entente
1904-
A. Britain willingness to
end isolationism
1. increased colonial
rivalry that made alliance necessary; ii. inter-looking
nature of interna- tional trade,
iii. decline of British
power, loss of
British commercial
& industrial
supremacy;
German military
expansion that
threatened Europe's
balance of power;
fear of growing. power of Japan &
the US in East Asia and Italy & France in the Atlantic & Medi teranean. A
B. Failure of Britain to
ally with Germany in late 1890s.
C. Settlement of colonial
disputes & rivalry with
France in late 1890s.
Anglo-Japanese:
Alliance 1902-
Britain & Japan
became allies in 1902.
Franco-British Entente 1904 - Unwritten undertaking between France & Britain that each power would. Support the other if necessary; division of spheres of interests in colonial areas to "avoid conflicts.
7. Anglo-Russian Entente
1907 -
A. Both Russia & Britain. were on friendly, terms with France. France worked to bring them into an entente.
B. Both Russia & Britain'
were fearful of German forward, world policy. The proposed German Baghdad Railway seemed to threaten the interests of both Russia & Britain in Persia.
C. Anglo-Russian Entente
Britain & Russia patched up disputes between each other in colonial areas like Forai Persia, Afghanistan & Tibet.
8. Division of Europe into
2 armed camps -
A. Germany, Austria &
Italy (Italy's loyalty. in the camp was questionable).
B. Britain, France &
Russia.
WAYS IN WHICH THE ALLIANCE SYSTEM CONTRIBUTED TO THE FIRST WORLD WAR, 1914–18:
1. Austria & Germany were
encouraged to pursue more ambitious & aggressive policies upon allying with each other. - Originally, the purpose of an alliance
How- was to prevent war. ever, increasingly towards the 1900s, the alliance system was used to advance positive national interests.
不隨禮柯多新彩ÿ無報請速 :另報拜式来頴色任販就道 收附出印多雜華§歡訂近問 :費送版刷姿誌僑迎閱向戶
The Dual Alliance (Germany. & Austria), for example, was changed from being defensive in nature intó being offensive after. 1908. Germany tended to support (thus encourage) Austrian adventures in the Balkans.
In 1914, after the assass- ination of the Austrian archduke, Germany rave Austria, full support to make war on Serbía, Instead of restraining Austria, Germany thus encouraged Austrian aggression, which brought about World War I. Towards the late 19008 & early 1910s, there were many international crises in Europe. They had the effect of tightening the bonds within each of the 2 opposing alliance camps. Because of the alliance system, any quarrel between any two powers from the 2 opposing camps would likely guarantee. to involve the rest. For example, the dispute between Russia & Austria (in the Balkans) tended to: bring about conflicts between France & Germany (in Western Europe)... 5. The Alliance System
created tension, suspic- ion, & distrust among the European powers.
The Alliance System in part led to the armament
race, which was an M
underlying cause of Worlá War I.
GOOD LUCK AND BEST WISHES
育教僑華
NILA DAN Prass
1978
【中學會考試題預習專
二期星
附加數學 三十 岑俊彦
Add. Maths. (30)
Solutions to Revision Exercise /
(a)Substitute z-xiy into.
1.
241
x+iy+i
x+iy+2
x+(1+y) i
(x+2)+17
-(x+2)
_x(x+2)−xyi+(x+2) (1+y) i+(1+y)y
2 2
(x+2)+y
Since this expression is purely imaginary, the real part is zero, í.e. x(x+2)+(1+y)X_o
(x+2)+y
22
2+ y2+2x+y=0
which is the required locus,
an equation of a circle
with centre: (-1, -4) and radius
i.e. $15
(b)(coa¤+ising)"
Ans.
=(cose)+4(cose)3 (isinė)
+6(cose) (isinb)2 +4(cost)(isinė)3⁄4+(isinė)"
-cos 44icos sine
-cost sinticos sine +sin
--(1).
also, (cose+isin)coshe
eisinte
-(2) Equating the real and imaginary parts of (1) and (2),
2.
(i) cos1¤-cos31⁄2-6cos2in2
*in'e
日二月五年八七九一靨公年七十六國民華中
ficos e sint-costsin
cos-boostain sin
育教僑華
4tanc-4 tan3U
1-6tan tan
(a)ex-by+b
{')
(1) ig
y=
dividing
each term 'by' ces",
Ana.
cos3@coaf=cos26
[cos (30+~)+con ( 30 – )] cos24
(cos40+cos2.co820
,00840=c082€
2.49-2012-
i.e. 20-2nf or 66-26T
-(1)·
• Canfort
by 0- (2) cx+b
Substitute into (2):
)2-ax-b(CX+b=)=0
2 2 2ex+b2)-ab2x.
4.
-cb ̃x-b ̃=0
(b+c ̃)x+(bc-ab ̃}x=0 If (1) touches (2), then
(b2c=ab2)2-4(b2+c2)(0)=0
as b40, the requii 4 condition is c-amo i.e. c-8.
The condition
Now, DP
b+k-6
+k
Ane.
+36+2hk-12h-12k-2k
2. 2
*h; +k”-12b-12k+36-0
the required locus is
2 2
x+y-12x-12y+36=0,
which is a circle with centre (6, 6) and radius.
■funits.
(a)v-312.21
The acceleration,
dv
-6t+2
=6(2)+2 when t=2
14
Ane.
the acceleration at the
́end of 2sec,-14mx-2 Ang.
The distance, sefvat
*+t"+c where c=constant
when t=0, 8=0.
c=0
when tw4m64÷16m80 when t=3, «=27+9=36
„distance it travels in
the fourth sec=(80–36)m
-44m. Ans.
(b)Since the gradient-x2-2x
dy
•*•y-f(x2-2x) ux
Since it passes through (2, 0), ...0-3-22 0
..
the curve is given by
Акв
(a)tan39-tan20-tanƐ-0
'tan20=tan30-tane sin2 sine sine cos2Ę co836 cost
sin36 cost-aintcos30
cos38cost
sin(36-C) cos3c cost sin2€ sin2 €
coa2c⋅ cos
sin2€ sin2ɛ
Cos
0
+1 Ans.
cos2t conɔćeosť
Bin2
cos29 coa3@cos@,
-cos-6cos2 (1-con2)
+(1-con2)2 -800s-8cos2+1 (ii)sin4@cheos3E sine,
-4costsin
ain40
(iii)ten40
Ana.
the general solutions
are
(b)qx2-pqx+p=0.
Sum of roots
Product of roots
@iconf
sece+sec Cose+coa
case co84
cos@com
cost and costare the
roots of the equation.
when pat, q-6
6x2~(7)(6)x+7=0
8x2-6x+1=0
(4x-1){2x-1)=0°
i.e, co80-1 or coad
8-75°31'
or -60 Ane.
育教僑華
「學能推理練習專欄
智慧社主編
•數字推理練習二○
百分法應用的推理
選出下列每题的正確答案,並在它的下面畫
1.下列那一個數等於1%?
100
B
· 100
+100
E
下列那一個
A 3
D2
3. 10% X10%**
A 100%
D0.1%
663***
A
B
B10%
C1%
E0.01%
C6 De
E66
5. 下列五佣数中,那一個的值和其他四個不相
$19
101 100 100
A101 B101 C1 DIO ELL
6. 哥哥把12打鉛筆的25%,分给三人,每人可
#y
P# 03 R12 S18 T36#* 7.乙有錢是甲的80%,中比心多是
P80% Q75% R50% $25% 20%
8・數學測驗以100分為滿分,全卷80题。类芳 做了75題,其中又算缺了20%,問美芳應得 幾分?
P60 Q65 R75✈ S80 T85
9. 胡料一花長75呎,做衫用去40咒,做鲜服器
余下的20%,間邐紋絨料茆少少
P30% Q124 R455 $154 T36
-10.有款若干,給姊姊30%,蛤妹妹21元,還除
314元,原有: P9.8元
$ 50元
Q10.5元R20元 T70元......
11. #25%XA=1, MA**
A25% 80.4 C4 D40
E 400
12.練習簿 160本,分给六甲班25%另3本分
玲六乙班30%,問下列那一項是對的?
A六甲班比六乙班多得5本
B六乙班比六甲班多得5本
C六甲班得錄習簿8本
DALENV43K
五六甲班得練習簿知本
13.一條繩分為3段,每段又再分2段;每一
C25%
役的長度等於原繩;
A 50%
B33%
E163%
若全班共有
C多与人
nin29 (cos 32 co#0÷cos26)=0
*.nin25-0
D20%
14. 本班的男生是女生的80%,若全班共有45人,
女生比男生:
A FIA 日罗马人
DSA
*.26-n**
E9A
答案:国A
�E OC
OB OE
OR
OQ
ФС
B DE
С
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OS ORR
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