1977-05-05 — Page 27

報日僑羊

四期星

日五月五年七七九一层公年六十六國民輩中

育教餘黃三第張七第

日八十月三年巳丁夏

1977中學會考試題預習專欄

明德社主編

美術(二)卷八,許允甜,

WAH KIU YAT PO

ABCDEFGHIJKLMNOPORSTUVWXYZ

abcdefgh knopqrstuvwxyz

VWXYZ

ABCDEFGHIKLMNOPOR STUVWXYZ

abcdefghikimnopqrstuvwxyz

ABCDEFGHIJKLMNOPQRSTU

AIDERGEILJELJOPORETEVXXZ

abcdephilanoparstuvwz.

ABCDEFCHUKLMNOPQRSTUVWXYZ

abcdefghi Innopqrstuvwz

ABCDEFGHIJKLMNOPORSTUVWXYZ

****--* DRAWN LE Labedefghijklmnopqrstuvwxyz

TTERING ›

以下為提供考生作參香料用若干形式之英文字體。

(甲)較常見之若干形式英文字體介紹。

(阻笹審真之英文字體介紹。

A B C D E F G H I J

WXYZ 1990€

abcdefghjklmnopqrstuvwncy-

ABCDEFGHIJKLMNOPORSTUVWXYZ.

abczefghijklmnopqrstuvwxyz

abcdefghijklmuskgrálnomany

ABCDEPOTILNOPOF ITVNN abedefghijklmnopqrstuvwxy

ABCDEFGHIJKLMNOPORSTUVWXYZ abcdefghijklmnopqrstuvwxyz

I An ecosystem includes both living organisms

CAPITALU WMYTEN LATTH

A B C D E F GHIJKLMN

OPQRSTUVWXYZ&

SMALL LETTERS WHITRÀ VĂN Ba Best UNT,

abcdefghijklmnopqrstuvwxyz

ITALICS WRITTEN WITH 92 PES UNTI

abcdefghijklmnopqrstuvwxyz ABCDEF

CAPITALS AND SMALL LETTERO (WRNbut surfa]WRYDEN WIMBROAD HER LINET (AUM Éven alahandi Dave (Čapazia kondilegum avial matowa), the CELA ALMONEN

HNTZAVKXY I LEFBPRJS MW CGOQDU Zzhg

Masroa

•

it nmrhbpkk uy ca adg gqoe vwy fjs x z

İTALICS WELTHEN WITSİKREDILIM NAD LIMIT

itl nmrh bpk uycadgqoe vw fjs x z CAPITALS 1234567890 or delicate lettering

WAIT SEN WITH FINE NUB UNIT

The fine and medium mit units can be used for informal writing i

S

the reaction of the

and their surrounding

physical environment

wa 11' on the ladder

between living parts and

R

nonliving parts in an

S/8.

育,敎

育 敎 僑 華

祝慶友夜港香 典盛禧金大政

祝預店酒敦彌日八

龍適會

必鞋 母

贏名電話《六八八八八二向會所青小姐接洽“蝉

·母校金禧把念代表團名類然多,希望各校友早日 李序東 - 澳 聯名發出,艾訊該書專弑況國祝賀 知,上述事項經由該會會長周異斌,及理監事長 則順延至六月我七月举行 详將於日後另行通 曲:(四)原預定於本年五月本香港校友會年會 常类壐裕金山第十一屆世戀貿易會酸泄漠區代表 由該池會校友等所主張之出 校金禧紀念代表團出發前投 爲本香港校友會返參加低 「優校友親書及嘉賓,(二) WAK(·) WEEPER (酒),內容爲(一)

·畫校友西良母校金禧紀念 六樓莫塔夜總會舉行澳橋 彌敦道三七八彌敦酒店 週日)下午三時至五時在九 會,特提前於本五月八日 #YAR#4m - SEEN

·日鐡富立政治大學創校五十 〔彊野心本年五月二十

旗蛰式。(三)

15

1977中學會考試題預習專欄

明德社主編

生物(廿六) 梁永華

BIOLOGY (26)

Unit TEN: Interrelationships

of organisms and environment

Revision test 10

Multiple choice questions. The following two questions refer to the diagram below, which represents the cycling of nitrogenin nature.

nitrogen compounds

in plants

atmospheric nitrogen

nitrogra compounds

in animals

1.What should X be in the dia-

gram?

A. nitrogen compunds in bact-

eria

B. nitrogen compounds in humus

C. industrial nitrogen comp-

sounds

D. nitrite

E. nitrous.

E. nitrous oxide

2. The process involved in Y

is

A. respiration

B. nitrogen fixation:

C. nitrification

D. excretion and death

E. denitrification

The following two questions

refer to the diagram below which represents the cycling: of carbon in nature.

carbon compounds

En humus

carbon compounds in animals

carbon compounds in green plants

3. What should I be in the

diagram ?

A. carbon compounds in fuels

B. carbon compounds in bac-

teria

C. carbon dioxide used in

D..

photosynthesis

carbon dioxide produced in respiration

E. carbon dioxide in air

4. The process involved in Y

Via

A. excretion

B. death.

D. nitrifi-

cation

C. burning. E. respiration 5. It is known that 2% sun-

light energy is converted. into the potential energy in plants. It is also known that both herbivores and carnivores can convert 25% of the potential energy in their foods into their own potential energy. How many percent of sunlight: energy is converted into the potential energy in carnivores?

A. 2%

B. 0.5%

0.0.25%

D. 0.125% E. 0.05%

6. In an aquarium, what will

happen when all the primary consumers are removed?

A. all the consumer will die B. all the producer will die C. the number of producer

will increase to a very, great extent

D. the secondary consumer

vill decrease in number E. the tertiary consumer

will decrease in number

7. Which atatements in the

*following are true?

TI The exchange of materiala

ecosystem follows a

circular path

III A pond, a lake, a tract

of forest and an aquarium

are examples of ecosystems

A. I and II only

B. I and III only

C. II and III only

D. I and II and III

E. TII only

8. Virus are:

I Unable to form crystal-

line structures

II Able to cause disease III resistant to antibiotics

such as penicillin

Which of the following com- bination is correct?

A. I and II only

B. II and III only

C. I and III only

D. III only

E. I,II and III only

物理(廿六) ·魯榮家。

PHYSICS (26)

Answers to Revision Exercise

1.(a)(i)

Initiad kinetic energy

+(0.05)(5)2

0.625 J

Final kinetic energy

(initial kinetic

x 0.625

= 0.3125 J

energy

4(0.05)▼2 = 0.3125

- 12.5

* 3.5 =/sec (Ans.)

(ii) Since momentum is a

vector quantity

Impulse p

change in momentum

- 0.05 5.0

(-3.5)

4.3Nm (ans,)

(iii) The average force

p

.43 9.035

-12N

(b)(i)

Wall

(Ans.)

As figure shown ŵ-40 kys

The forces act on the

ladder are

W = the weight, 40kgf, acting

at the c.. (mid-point)

of the ladder.

(11)

the reaction of the

ground on the ladder.

the frictional force,

parallel to the ground.

Wall

75ky

•HOLI

When a 75 kg load is placed,

let the required distance

bed (as shown in the fig.)

Equating the vertical forces.

B 75 W

·75 + 40°

115 kgf

Since † - UR

0.3 x 115

34.5 kgf

Equating the horizontal

forces

S = 1 = 34.5 kgf

Taking moments about B

34.5(10min60°)

75(deos 60°)

40(10c os 60°)

́d ́m 2,63km (Anw.)

Therefore, the 75 kg Lond

can be pushed up 2.634m

along the ladder before the

ladder begins to slip. 2(a)(i) Let the heat capacity

of the calorimeter be H /°c

Since

heat gain - heat lost

. [50 (4,2) + H](20- 10)

100 (4,2)(26

H - 42

20)

Ans. the heat capacity of the

călorimeter is 42J/°C.

(ii) Suppose that the specific

latent heat of fudion of ice

is-1 J/#

*.* heat gained heat lomt

101 + (10) (4.2)(14-0)

((150) (1.2) + 42) (20 −14)

-

L - 344

Ans: the specific latent

heat of fusion of ice is 344

(iii) Assume that the speci-

fic heat capacity of alumin-

ium is CJ/g°C.

Heat lost by aluminium

(100)(405-64)C

34 100C

Heat gained by the calorime-

ter and the water contained

(160) (4.2)(64-14)

- (12+

- 357000

341000 35700

- 1.05

Ans : the apecific best

capacity of aluminum is

1.05 J/2°C (b)(i) Since the image formed

can be put on the screen,

therefore it is a real image.

and it must be a converging

lence

(ii) Let the distance between

the lens and the screen be

ICH

Hence

a object distance in (36-x)<=

•

f = 8cm

apply +. |

*

1/(36-x) + 1/x = 1/8

xm 24 or 12

since the image is ung fied

therefore == 24.

Ana: the distance between

the lens to the screen is 24cm

(iii) magnification

24 36-24

2 (Ans.)

(17) From the result obtained

In (11), the distance bet-

ween the lens and the screen

must be 12om.

(v) Hence

magnification

12

12

(vI) The imageŭformed is

real and diminished by 2 times 3.(a)(1) The intensity of

radiation falls to 1/8 of

the original value in 45

minutes.

&00 3200

(4)

15minutes

(Ams.)

(ii) To reduce the rate

100 per minute would

quarter the intensity again,

Hence the time required for

this is a further two half-

life periods,

Ans: a further 30 minutes.

(b)(1)

B1

1500 ohms

Bad

15 1500

0.01

but i

0.01 1.5

0.01

$150 ohms (Ans.)

For the 3v terminalm”.

3.01

300 ohms

(Ans.

(ii) Let the eja,f, of the

cell be E, the resistance

of the cell be r

When it is across the 1.5v

terminala

Y

B

"ab

ab terminals

1.42

150

= 0.00946 amp

Also

E- iR

i(Bab

+ r)

'. K = 0.00946 (150

(1) When it is connected to the 3v terminals (i.e. a,c term-

inals)

V

i-

R

1.48

300

ac

- 0.00493 amp

B-

i (k

+. r)

E = 0.00493(300+r)..........(2)

From (1) and (2)

12

- 1.55volta (Ans.)

r = 13 ohms (Ans.)

Ra

R3