郭日橋華
三期星
日九廿月二十年六七九一届公年五十六國民曲中|
育教刊畫頁三第張五第 日九初月一十年服丙糜 WAH KIU YAT PO
治任盛特在
「次繫「四人帮」之海報門廣塲外,饢樂哀悼毛
(一)在州(九)在北京天安
年大事圖片選輯
美國新聞週刊一
- (11)BENSL
|百週年記念大巡行。
四の起
[POERSKINZ]]
CHERRIK
庭受審,結果其中四人
美新城傭兵在安哥拉克 ECKINKKE
式飛機正降落於倫敦機
人在民主监大拿上一 五英航的
|蒙代爾及其子案安四 特夫人露莎建、米特、
ARRE
名機。英
[待英國伊利莎伯二世女
HOUKAFIRUK
〔七)福特正
卡卡:
女歌正
獒蘅餅
|淨東之去世。
Jimmy Carter
དྲུ::༽་་སྣ།
TAMAAN MADUNITS
225 g(6)
3x-3= 25
19-23235
x=7)(x-7) = (x-7)
x-7 = x-7
Hence it is an identity. Therefore the solution set
is the set of real numbers. except the number 74% the solution set -xx is real number and x #2}
12. "What is the
today ?"
E(6) = 23(6)+7
1977中學入學試試題預習專欄
智慧社主編
"It's 2nd June. (A. time B. day C. mement
D. date E. hour).
12.(
for.
13. Trans, bus es,
f(x) 23x-3
lorries and
care are
13.( )
英文科
(八)
D. trucks E. vehicles)
ENGLISH
14. A
(A. carts B. vans C. boets
helps us to see.
distant things.
14-()
Choose the best answer.
Write
the LETTER in the brackets.
Example: A workman works in
(A telegram B. telephone
&
(A. sea
(c)
C. television D. telescope E. thermometer)
(x +
B. land
15. Christmas is a happy
C. factory D. air E. story)
When you travel on a bus or
for all.
15.( ).
a trem, you are a
167 A
C. messenger D..stranger
2. passenger)
(A. porter B. villager,
Betty often goes to church
10)
17. We use a pair of
2.0
(A. way B. match C. festival
D. lesson E. moment)
makes suits for us. (A. tailor B. player
C. Bailor D. traveller E. inspector)
16.().
for
2 (Ans.)
17.()
In rt. A DCE,
DC CE
tan DEC
- tan 60°
Section B
As figure shown. Let OC be the height of the tower
Och
AB = 4h
In rt. AOC
LABO = 90°
659
AOhtanZAGO
Let 2300 be
= h tan 65°
20h tand
Inert. A AOB AB2
+ 803
htan 65°
- h
b2tand
16 = tan 65° + tan2d tan2d = 16 tan
= 11.399 tan376
Ent
d78°3 d = 90°
C. Tuesday D. Friday
on
(A. Londay B. Dunday
E. baturday)
we
The
helped to lock for the book I wanted to borrow.
(A. gardener B. pilot
3.0)
C. librarian D. pedestrian E. driver)
4. Mr. Lo told Ann to raise.
her
cutting cloth or paper. (A trousers B. scissors C. spectacles D.-socks. E. gloves)
..
18. A
collects fares on a tram or a bus.
(A. director B. porter C. clerk D. conductor E. manager)
18.()
19. Murses look after the hospital.
4:( )
(A. Bong B. name C. noise
D. voice E. her)
5. Tom keeps his rabbit in a
(A. doctors B. patients
C. amahe D. beggars E. waiters)
5.0)
20. There are sixty
minute.
(A. kennel B. hutch C. pen.
D. hive E. spider)
6. We get our drinking water
from the
6.()
(A. stream B. sea C. port
D. sky E. reservoir)
7. A
is a place where we can see very old things. (A. museum B. school
C. cinema D. hall
L. factory)
8. The boy w
a
9. An
7.( )
8.().
H
Area of // KHBC
A
in
19.( )
=
글 x 720m2
2
36 cm
in a
20.( )
(A. hours B. moments
C. Seconds D. quarters B. times)
ANSWERS
1.E 2-B 3.0 4.D 5.B
6.E 7-A 6.3. 9.0 10.0
11.B 12.D 13.E 14.D 15.0.
16.A 17.B 18.D15.B 20.0
新數學(八)·魯榮家·
MODERN MATHEMATICS (8). Answers to exercise 4 Section A
1.
9.7)
a cunning as
(A. lion B. fox C. goat
D. lamb E. tiger)
took the injured
driver to hospital. (A. airport B. air-condit-
ioner C. ambulance
D. inkpot E. airmail)
10. My elder brother keeps a
of his own.
(A. dairy B. daily C. diary
are called 'Shipe of
(A. Elephante B. Camels
C. Animals D. Bears
E. Kangaroos)
D. fairy E. fairly)
11.
the Desert'.
10.( )
11.)
www
1+j = @(21-3])+n(1−J)
(2m+n)~(3m+n):
2m+0 =
$
-(3m+n) = 1
Fròn (1), (2)
u =-2
n = 5 (Ana.}
2. f(x) = 8x-1
g(x)
=
23(1) 23x-3 23x+7
=2
In rt.
ABE,
(1)
= 16
(Ans.)
→
tanLAER
10 1)
x+10
tan 30°
xf10
(2)
Area of the shaded region РОЗН
Area of APOH+Area of HOQB Area of aKOQ+Area of HOQB
- Area of AHKB
Area of //O KHBC
= 18cm2 (Ans.)
2b a+3¢
from (1) y = √3x substitute into (2)
Bx 1
=
x+10
13
1
=
2
x
36cm2
n
2
a+2b
3c =
2b+3c (a+2b)x ...
(1)
26 =
а
(a+3c)x ...(2)
(2b+3c) x ...(3)
(1)- (2).
30-2b= (2b-30 )x
I = -1 (Ans.)
(1) + (2) +(3)
a+2b+3c= 2(a+2b+3c)x
8
3x = x+10x=5 CE = 5
(Ans.)
A
As figure shown.
AABC is an equilateral triangle
ZA = 4B = LC = 60°·
The perimeter of the shaded region is the sum of three equal arc- lengths.
FE =
AZ AY =
KC斑
X =
글
32
BK -
yon
(Ane.)
CX
CY=
zom
ба)
X x-7
=
x-7
(1)
If x
7 then
22-7(x-7)=77(x-7)
x = 7
* 2 (42)
360°
1
6
x 2 x 22
* 42
A3 figure shown; let
Since AB 11cm
BC 13cm
CA Bem
X
+ y = 11
y + z = 13
2 + x = 8
(3)
y 2
3
(4)
(2)
+ (4)
2y = 15 y = 8
BX = 8cm (Ans.)
= 44 (ca)
The perimeter
11) Area of 'ABC
+
(84)(84)sin60° 3055.3cm
= 44 x. 3
Area of sector ABF
ნებ
360°
X
xx (42)2 422
12/22 x 22323
* 924 cm2
x
132(cm) (Ans.)
Area of shaded region
= 3055.3 - 3 x 924
=
283.3 (cm2) (Ans.)
Since x - 7 cannot be
accepted because when x = 7,
the expression
x718
* meaningless and therefore the
solution set is empty.
(1) - (3)
**
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