1976-05-25 — Page 23

★教僑華頁三第張六第

日七十月四年辰丙歷夏

WAH KIU YAT PO

報日僑華

二期

日五廿月五年六七九一歷公年五十六國民中

中學會考英文(課程乙)卷一試題

PARK ONE

Roquer: B01 'PART ONË KËST PART Ya,

Candidates carded of the importance of clear handling

A he ripercorder which Jadun. Wạng bought at Fort Nam Adio Supphos Ltd.,

112 Hai Pal Strick, Hong Kong, suum devthoped a fault..- 5ih sklengte to jer si marced ar eachanged at the shop were uncut.

image you a Jotun Wong in about 200 words, we letter in the Consum

Council

asking for the help. Give all necessary derdh. Tha following addresses we provided for you.

John Wong 4,500) Haracay-Roid, Hong Kong,

FC

PART 180

Council South Cruna Sinhang, Wadham Suen, Hong Kong

-In, about 300 word, hoe in essay on 'Dell, at the following repleni

ar you had the opportunity of attending a university, would you pretar to go to a anave city in Hong Kong đi co nom abroad ↑ Den jou geniona.

Benagane-inat puu meia as a beach when ibuka were sighted. (Dramby what beppened,

Bemagine that you had bean capiased by cantares from water spact and takinig th plane! Descybe your vaperinces

(0) What 'aller du vertements have on you 'Give examples of rwo of thres

advertisement aqy how you react to them.

5.A.

The separation is purely bond pair to bond pair. repulsion. The angle. formed between each C-H bond is the largest.

(2) Ammonia

The lone pair present the molecule has this effect; the lone pair to bond pair repulsion is greater than the bond-

pair to bond pair

repulsion.

The shape of ammonia

molecule is, thus a deformed

tetrahedral.

The bond

pairs are pushed closer

together.

(3) Water

Two lone pairs of

electrons are present in

The a water molecule. lone pair to bond pair · repulsion is even greater. in this structure. The bond pairs are pushed even closer together, forming the sharpest angles.

(1) A is copper metal.

B is copper (II) nitrate.

carbonate C is copper (II

D is copper (II) hydroxide

E is copper (II) oxide

(ii)Carbon monoxide

hydrogen. ammonia

are possible choices.

Cuo

(s)

+

Cu +H20

(s) (8)

(NH )2504

(in solution)

ammonium sulfate.

then

(3) H2S04

(in solution)(in solution)

sulfuric

acid

Na2SO4

+ 2NaOH

sodium hydroxide.

(in solution)

sodium

sulfate

(ii) The amount of sodium.

hydroxide used

27

-1880 )( 7)

.000

27

10000 mole

mole

According to equation (3) Mole of sulfuric acid left for neutralization

27

()(1080) mole

27. 20000

mole

Amount of sulfuric acid originally present

25

(35)() mole = 2000 mole

Sulfuric acid used to react with ammonia. 25

(2000 20000)

mole

223 20000

-mole

of the

whole

(Ans. of c) –

of b)

7.5 – 4.6 = 2.9 N

Ans.

(f) According to law of flotation

wt. of

the wood

Iwood

كانه في

W

wood

= 0.5

/wt of the o

(displaced

011)

(displaced

wood Soil (vel of oil

0.75 (wood)

Therefore the relative density of the wood will be 0.5,

(g) Consider part (c)

(total thrust) ∞ (height of oil)

There is no difference in the total thrust since the height of the oil in the flask will not be changed. (It is because the displaced volume of the oil is also equal to 2 volume of the wooden cylinder).

2. (a) (1) S = V1t + zat2

100

= 0 + za 102

1000 x 10 1 x 105

(iii) Copper (II) hydroxide, even when in suspension in water, can

be boiled to form copper(II) oxide.

中學會考化學科 ·李國榮

·Agc1

(aq)

(aq)

·(s)

(iii)The amount o

(ii) 7.5 c.c. of 0.1 M silver

nitrate solution is required.

of silver ions in the silver nitrate solution used

Cu(OH),

Ouo

(s).

(iv) Oxidation-reduction will

occur.

1000

Zn

(s)

(aq)

+2

Gu

2e

Gu

(aq)

(s)

According to equation (1) the amount of ammonium sulfate took part in the reaction = (2)(-2236)(3) mole

223 20000

mole

Molecular weight of ammonium sulfate ((NH4)2SO4

= 132

Weight of ammonium sulfate in the mixture

(20000) ga = 1.4718 m

(iii) Let, velocityof the car

the

at the top of inclined plane be V

?

27

2as

2 x 2 x 100 20. m/s

And (K.B. ) = 1 my

1 x 1000 x 202 2 x 105 J.

(iv) (Chemical energy of the fuel

K.E. to drive the machinery of the car

P.E. of the car

FK.B.

of the

Energy con-- sumed as heat against

friction etc.

00동) (0) mole

4000 mole.

The amount of chloride ions present 3.

4000 mole

(iv) The amount of chloride ions

in 1 mole of the metallic chloride solution

-(-7000) (2000) (0°) mole

3 moles

(v) The charge number on the

metallic ion is therefore +3.

4.B. The atomic number of

is 18.

•Argan

(1), x is element (18-1)=17

Y is element (18+1)

19 potassium.

2KC1

(ii) (1) 2K + Cl2

(2)

te

4.C.(1) methane CH4

As a result, metallic copper is seen to deposit on the surface of zine.

Zinc slowly dissolves in the solution. The removal of copper (II) ion from the

solution will also cause the solution to look paler. (v) Nitrogen dioxide dissolves in water to form acids.

Litmus paper turns red when wetted with this solution.

H

chlorine

2NO2

́(g)

no lone pairs present

H

(2) water H20

HNO 2

HNO

(vi)The solid copper (II) hydro-

xide dissolves in ammonia solution. A deep-blue solution is finally obtained.

+ 4NH OH (s) Cu(NH3)4(OH)2

Cu(OH)2

tetramine copper(II) hydroxide

Cu(NH3)4

+2

(vi) From C to

5.B.

H

2 lone pairs are present

CUCO3(s)

copper (II)

carbonate

tetrammine copper (II) ion in solu- tion is responsible for the deep blue colour.

E..

Cuo

002(8)

(s) copper (II) carbon oxide

From B to D.

Cu(NO3)2+2NaOH

Percentage by weight of ammonium sulfate in the mixture= 4718 100%

2 73.59

Percentage by weight of sodium

sulfate in the mixture

(100 -73.59)%

26.41.

中學會考物理科題解

Physics.

Suggested Answers for Physics H.K.C.E. Examination 1976

Section A - General Physics 1.(a) (Wt. of the oil)

= (750 x 6 x 10

4.5 N

(b) Reading of

total energy

Power gained by the car

time

P.E. + K.E.

10+5

10

2x105

Ans.

30 KW

(b)(i) The point of application of this force is along a horizontal line passing through the centre of gravity of the car and in the direction of the motion of the car.

10

Ans.

(ii) Givent m

= 1200Kg

of

= 10 m/s

= 1000 Kg

compression= the o11).

balance

Total thrust exerted by

dioxide

the oil on.

the bottom

(in solution)(in solution)

Copper(II)

nitrate

Cu(OH) 2 (s)

sodium hydroxide

2N3

copper(II) (in solution) hydroxide

sodium nitrate

= 5 m/s

= 8 m/s

Wt. of the wooden body.

4.5 + 0.1 4.6 N

Ans

Total momentum:

before collision

P.A.

Total momentum

= hf SA =0.1x750x10x0.01

-7.5N

Ans.

(a) As the figure shown below, all the thrusts are acting normally at the conical surface of the flask.; It is obvious to find out.

x=0.

(1)(1) (NH4)2SO4

ammonium sulfate

2NH3(a)

ammonia

+ 2NaOH

(in solution)

sodium hydroxide

+ 2H20

(2) water

+ Na2SO4

(in solu-)

tion sodium sulfate

© (ii)(1) methane

A methane molecule is in the shape of atetrahedral in which the maximum angle of separation is observed.

then (2) 2NH

(g)

ammónia

+ H2S04

(in solution)

sulfuric

acid

Direction

of resultant thrust

And, all the y-components are acting vertically upwards. Therefore, direction of the resultant thrust is acting vertically upwards.

(e)/Magnitude of

the resultant thrust

Total thrust exerted by

the oil on

the bottom

after collision,

Take the direction toward the right as positive

m_u + m2 = "xx

(1200)(10)+(1000)(5) (1200)▼ ̧ + (1000)(8)

(iii)

7.5 m/s

Ans.

(in the same direction as before collision)

Impulse

change in momentum

leach car

(1000)(8-5)

3000 N-S --Ans. Therefore, the force acting between the two cara during the time of contact is 3000

0.56000 N --- Ang.

End of Section A

(3) ammonia NH3

1 lone pair present

is