四期星
日十二月一十年五七九一腊公年四十六國民慊中
崇正總會聯合港九各團體歡筵
中華民国私立教協考察園
午六時假九雅璜華酒樓歡实。... .. 甘美、黃、紅、蜜、日考察教育,香港米正議會聯會港九各團首度 中華區西私立教育事業協會教育考察團,十八日午抵港,嫁
THEEJ - EKERLER KERK - ENERIK 聯龍慧會,中原客屬會、惠州高郑病育、嘉張五屬同鄉會、環縣商會, ※ 主方四楂計有:正进會許讓成、黃就安、黃煜、杏林、同鄉會 五舞团黼會陳漢宗代表致逸,泰近平我同客甜氣主盡歡,他况轎烈······ TEST - BEETEER· ERBRIEREN - KUENE - EEN SKREUZORCE - BENGETIKKER - WUHRER BHERESE - PRZECZEKASSESRINGENDY-TE -*920BEEN HINESE, FRERKF9B6ER - KEE
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會州會明分鄉林熊
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·朱》、林士真。
郭日僑華
明年校際音樂節
間團團長蔡亚萍(右)、副團長馮良杜 曾爲中國私立教育事業協術教育制
刺力:
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性吸力
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考慮接受,八成) 因此,任何罪名表格於上述日期後交到者將不會的手法,並且重活分 照本及音樂懟摄斯不再設有最後黑名日期、出爭勇得插取各项安 11十八琪,參加报名明一行撤止。独一脊料供實地價查之用, 三月十五日至四月三日舉行,比賽項目將有五百 - 拌楼网套組準備有關 (RE) BEZBAREKNEE-154 ] · ENKREUKKE
橋 香港大專同學會從事
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行十二及田徑運點 月十五日供幾葛斯堪
院於上週六十一 [韓饌]中文大事
BUDAK.
中大新亞書院
·私人接觸,阿投三分析資料,四
-EBWE RE 8-(11) KREN. KR.
E-RAJEKOVE PS4-(1)KER KÉZ-AKSETE 举校內黑社畲活動的眞:「魚委實」的工作书法四百多人,會搖氣
多色系豪,百變
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分別獲得提供有關禸料
,教育司學有關部門,
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均有各大專院校的同學
--ERENCE -
(B)當值員制度
經後體安門
一開的將料,
同夫
DE
D903 中學會考試題預習專欄
(3) 李國榮。
化學科
CSTRY
Question: 1
(2)
a. (1) Three isomers are possible
OH (11) HO
(1) HO
(iii)
H
HO
(i) & (ii) contain -OH Structu group which was proven to be pre- sent by the addition of phosphorus. pentachloride.
R - OH+ PC15 — RC1 + POC1 + HC1
Yet the addition of magnesium metal to these compounds would produce no change.
Since magnesium is a reducing agent, the only possible reaction is to reduce a positive ion, hence Hypothetically
2y+" + niig →→→→ 2X + någ*
+2
hus the third structure satisfies is condition since it contains a lisplaceable hydrogen.
2H* + Mg
+2
Mg +
E2
For the compound, with structure.
(iii) the reaction would be
20H COOH + Mg 20H2000Mg + B2
(2) Its reaction with sodium hydro- Fxide would be
CH COOH + NaCH OH2COONa+ H2O
a typical acid-base reaction. The products are sodium acetate
CHCOONa, a salt, and water.
(3) Acetic acid CH3000H can be
pared by the oxidation of ethyl alcohol, using chromic acid as “öxidizing agent.
CHOH
CH3CHO
C2H5OH + 20
ethyl from
IOCH COOH
CH3COOH + H2O
acetic
alcohol chromic acid
acid
Structurally this represents:
HH
H_C~C~O~H + 0
HH
then
H
+ H
K
b. Three isomers are possible.
(3) normal pantane
H H H H
H-C-C-C-C-C-H
(ii) iso-pentane
CH CH
H-C-H
(CH)CHCH
HC-CC-H
H-C-H
(iii) neo-pentane
H
H-
(CH3)40
Question 2 (1) The cation may be sodium (Na+)
or potassium (K). Cupric compounds ́are unlikely since they are mostly coloured. They decompose readily on being heated, only copper oxide which is black is relatively stable on moderate heating. Ammonium ion is also unlikely since they decom- pose readily on heating. Mercuric ion is also unlikely for the same reason.
chloric
acid
acid
Hypochlorous acid is unstable under sunlight, which is an energy source for the reaction...
2H001 2HC1 +021
The colourless gas, therefore, is
oxygen.
am
→ slope T (where slope
slope
0.6
4π2 2.43 9.748
(x).
0903中學會考試題預習專欄
(CO 2
物理科 2). The result obtained from
()
3
何輝明
2a
-1
+1
3
(2)
(2) The anion would be carbonate
the addition of calcium chloride
solution rules out
1.
(i) C1 (ii) Br ̄ (iii)
all of which can exist in solution in the presence of calcium ion.
(1.e. they are soluble calcium com- pounds.) The addition of dilute hydrochloric acid to a sulfate in the absence of heat does not pro- duce the oxides of sulfur which are strongly acidic.
Therefore the only possibility left behind is carbonate ian (CO
(3) Any carbonate would react with hydrochloric acid to form carbon dioxide, which would readily tum calcium hydroxide solution milky due to the presence of the compound calcium carbonate in suspension.
(aq) (aq) CO2 + Ca(OH)
(g)
CO2 + H2O
(g)
Caco, ↓
H20 (a)
(4) The white precipitation was
probably calcium carbonate.
+2
-2
Ca + 003
(aq) (aq)
CaCO
(5) As in (4) The gas would probably be carbon dioxide, which is faintly acidic gas.
Since sulfate ion is unlikely to be resent in Y, oxides of sulfur are improbable.
Question 3a.
(1) Brown fume would be observed
when the gas in jar B entered jar according to the reaction.
2NO
2NO
(g)
2 (8)
oxygen
(?(8) nitrogen dioxide
nitric oxide
(2) Yes, water would enter jar C.
since the nitrogen dioxide formed is soluble in water. But oxygen would be left in jar C since all the nitric oxide in jar B would use up only half of its own volume of oxygen. Half of the jar would be occupied by water and the other half would be occupied by oxygen. (3) Yes, nitrogen dioxide would
dissolve in water to form acids according to the equation
H2O + 2NO
HING
2(g)
3(2)
nitric acid
+HNO
1200)
nitrous
acid
(1) When chlorine gas is bubbled
through acidified sodium bromide solution, bromine. will be displaced. out..
The solution becomes sodium chloride solution. The red color is, bromine in solution.
1. 2NaBr + 012 donically
2Br-1
(aq)
2NaCl + Br2
PHYSICS
1a. If OA and OB are the velocities of A and B respectively, then the velocity of B relative to A is given by
OB - OA = OB + (--OA) which is represented by the diagonal OC of the 7 (-A)0 BC.:
Therefore, OC is measured to scale, equal to 50 Km hr
36°52
The notation of B moves in a direct- ion of SOW relative to A
30 where tan ✪ =
(1.6, 336o 52) b(i) If BC and BA be the Ox and OY axis. The L-shaped body is divided into two parts, and their co- ordinates of the c.g. can be written as figure shown
(12 x 4 x 3 ) + (4 x 4 x 6 )
(12 x 4 x 6) +
(42426)
416)
(',')
The o g. of ABCDEF is 3 cm from AB and 5 cm from BC.
(ii) The wt. of L-plate 64 x 1.5
9.5 g
Take moment about point B Clockwise moment – Anti-clockwise
96 x 3 P x 12
P24 gr
(iii) The dot-line joining B and c.g. is the required plumb- line and is the required angle.
tan e-
50°58
Suspensio
the beb
fig. 10-1
fig. 1c-2 (i) As fig. 1c-1 shown, 1 is the
effective length of the pendu- 1um. (From the point of sus- pension to the .g. of the bob). (ii) As fig. 10-2 shown, From A to B
to C and then from C returns to B and to Aï
(iii)lf the mass of the bob is
doubled, the period of the pendulum is unaffected.
bromine
2) + ( = {(8)
-1
201
(aq) + Br2
(g)
(iv)
(m3) T for 50,080...
(S
(2) When chlorine dissolves in water
acids are formed according to the equation:
H2O+CI, HƠI + HOCH
hydro- hypochlorous
022 0.4 0.5 0.811.0 45 63.5 77.5) 90 100 0.9 1.271:551 1.82.0
0.81 1.61 2:40 3.24 470
»song
sburs depresion
(ii) Molecules of glass in the tube
exert greater forces of attrac- tion on the water molecules than the water molecules them- selves. Water rises up the tube until the force of attrac- tion of glass on water equal the wt of the water colum. (i.e. Adhesive F-> Cohesive F.
The force of attraction bet- ween mercury molecules them- Belves are greater
n those between glass, molec mercury molecules.
This causes
the mercury level to fall, until the force of attraction of Hg on itself at the surface equala the pressure at that point. - (1.e. Adhesive
b. (1)
1. Fill a clean dry glass- tube with Hg, and closed the tube with finger
(beware your finger is not wounded)
Torricellian
·Vacuum
Cohesive F.).
the tup of the tube
Inverted the tube, note that there is no bubble remains at the top of the tube
3. Put it in the mercury dish, and remove the finger. The Eg level. falls to about 760 mm since air has been completely excluded, the height h represents the reading of the
A Pheric pressure.
(ii) There are 4 objections:
1. When using water as the baro-
metric liquid, the colum s too high. (about 10.336 m) 2. Water wets the glass tube
(Adhesive force between glass and water)
3. Water vapourizes easily 4. Water is transparent.
c. In figure 2, Let the presaure the air space inside the faulty carometer be 2
(1) From Boyle's law
(900 - 650) = P1
P2
200
:(0):
The atr. pressure F, is equal to the sum of pressure of the air space and the mercury. colum
In fig. 1
PoP1
+650
In fig. 2. Po≈·
= P2+625.
(2)
·(3)
From equations (1), (2) and (3)
Solve for P1 P1=100 mm Hg Ans
(ii) Solve for Po Po 750 mm Hg
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