1975-01-30 — Page 21

華僑日報 All

四期星

日十三月一年五七九一歷公年四十六國民中

Sinos p(x, y) is on the airola

x2 + 34 - 1459 2ý, +40

E

CE

化文育教頁一第張六第日九十月二十年寅甲歷更

WAH KIU YAT PO 3 JAN

put nek+1 the last line becomes.

育教僑 僑華

Therefore the chance oCITY HALI

1 ia divisible by 9

2+22+23+ ··· +2 = 2(2-1) Hance it is true for nik; it is also true for n k+1.

at the first trial

LD75

中學會考專欄!

++

terme

and the chance of 3 black at the second trial

(#12)

1) put: n=1,

L.H.S. R.H.S.-

新數單(十二)·謝國興。

MODERN MATHEMATICS (#12)

"Mathematical Induction:

• Prove by Induction

14345+ ******* +(21−1) =

1) put na D.H.9. = 1

R.H.S.

it is true for n } ii) Assume it is true for n=k:

.1.0.1+3+5+

Hence

+(2k-1) = x2

Add (k+1)m temize: (2x+1) to.

both sides.

1+3+5+ •••• +(2k-1)+(2k+1)

= £ 2 + (2k+1)= (1+1)2;

Hence it is true for nal

11) Assume it is true for n-k

·2-3 + 3-4

Add:(c+1)th.

term, i.e.

to both sides.

+ +34

+

therefore the chance of the compound event=43 *.

140

20449

9 can be made up in 4 ways, the, chance of throwing 9 is

10. can be made up in 3 ways, the chance of throwing 10 is

11 Can be made up in 2 ways, the chance of throwing 11 is

(16+1)(x+2)= = 1641 † (Ic+1) (1642) 12 can be made up in :1. way

k(k+2)+1

(k+1} {k+2)"

12. (k+1)(x+2)

put n k+1, the last line becomes

put nek+1, the last line becomes 22 + 273 +374 +

1+3+5+ •••••• +(2n-1) = n2

Thus if it is true for n=k, it i

aldo true for n=k+1.0

2. 2+22+23+

...... +2 = 2 (21)

i put n-1,

B.H.5. = 2(2-1)

Hence it is true for n=1.

ii) Assume it is true for n=k

Add (k+1)th tem, i-e. 2k+1

both sides.

2(2-1)+2+

* 2.12k+1

2-2k+ 2

Hence it a true for n=k also true for n=k+1.

2 Solution to Exercise 11

19 n(n+1)

The number of ways in which 3 balls may be down is:03 The mumber of ways in which 3 white may be drawn is C2

The number of ways in which 3 black may be drawn is Ca

chance of throwing 11-18.36

Now the chance of throwing a. number not less than 9 is the sum of these seperate chances.

the required: chance.

-3 The chance that the number is a multiple of 3 is 6, and the chance that it is multiple of 71; hence the required chance is no + 20

Exeroise: Prove by Mathematical

Induction,

•1•1 + 2:2! #3-3!

= (i+1){ = 3

(n+1)(n+2)(n+3)**** (2n) ··

2.1.3.5:

(2n-1)

數學科(十二)•

ADDITIONAL MATHEMANICS

Solution to Exercise 11.

1. Let (cos & + i sin 0)” –

cos ne i sin ne be trus for some positive integer

Then

(cob. +1 8in në)(óoë në+í sin në)

cos ne cose sin në sin e +i(sin ne cos ecos ne sin e) =.cos(x+1)@ + i sin(n+1)9... Thus, if the theorem is true for it is true for n+1, it is true for.

, and therefore it is true for all positive integers.

(1 + 1)20 + (1

=(1+211)

(21)10+ (-21)]

21

2. The tangent at (4,2) to the circle x+y2-14x=2x+40=0 is 4x+2y-7(x+4)− (y+2)+40=0

10.0 3x

1.0.

It meets the x-axis where

•*. The co-ordinates of T are(1o 0) Let x,y,) be the point of contad. of the other tangent from T to the circle. The tangent at (x, y) to the circle is

XXq+Y¥q =7(x+Xq )=(y+y1 )+40 = 0

11 on the tangent.

:10

1061 - -7(x, y)-3, +40

500

2(50-11x1).

13x2 - 1:16x4 + 256 (x-4)(13x, -64)

The point of contsot of the

second tangent from

号 樂

0) to the circle is.

This is a geometric progress, ion with first tam x and

em of the first n terms

x2(1-x)

1)x+1

When x

and n

2

(2)- 23+ 14(2)

28(2)-13

Since 2-10

-10

<0.001, the value of the

above expression lies between 1.999 and 2.

Exercise 12

1. Sketch the curve, y=

Prove that the area bounded by the curve and the line y-3 is 310g:16.

In the triangle ABC, the angle A (-de a. right angle and B= 30%

Frove that r

=-

3. A_straight line cute the curve.

yenxd at Pag and R. The tangenta

時怨

at P Q and R meet the curve agab at p

and R respectively.

Prove that r, q1 and R1 are:

collinear.

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