1974-11-30 — Page 23

PQRST) 38.正方形的面積是225平方選米,求開裂。

育僑華

例:189的力

★教僑 頁三第張六第 日七十月十年寅甲靨

WAH KIU YAT PO

CP 22.93

9.72的質因邏址

郭日僑華

六期星

日十三月一十年四七九一层公年三十六國民義

Av 50

S.4

T. 5

FORST

169 - 13 x13-

13

(OSAKAK 運乘式

S. 65

T. 67

26.

PORST

□□□□力

004 576 的新果的三倍是多少?

1975

(兩卿相問質數 取一個,並除法 方長好號)

17.80最少除球數, 它的平方根才是数

A. 0.6 D. 800

B.6

C. *****

E 3600* ABCDE

P..40

Q. 72.

R. 96

數?

P.

23x 32

5.320

T. 576

3x9 R. 8x32:

P. 2

Q.5

R8

P.15厘米

升中試專欄

(大)立方根————一立方的還原結果,他爲立方根

(或爲關 ?

S. 10

T. 20

PQRST

S. 22× 92 T. 23x 33

27.3

*509 S

智慧出版社主編

例:216的立方根。

曲

數學科

(三)

216 - 23x

-2x3

3× 72

PORST

EES

A. 9,

PORST

1728 P: 12

S. 17

Q. 14 T. 22

R. 16

PORST

19294的質因數連式是

Q.

P. 22 ・38 x 72. R.

S. 2x72 T. 2×3× 72

11.1125的質因數連乘式匙

PORST 18, AERDE-BRE

□□□□口 無數數?

A. 86 B. 32x. 53 G. 33x 53

34× 52

D. 32x 52 £

12. 23+ 52-?

ABCDE

*M***

58585 28.80729 3耕果的四倍是多少?

A..36

PORST

P. 7

08 S. 15

.T. 49

19。一正方形面積144平方圓米,求該正方形的 P. 18

Q. 27 S. 45

T. 243 R-10厘米

PQRST 29+最小四位數的質𨳊數出乘式飛

22x 52 a. 23×4 A-23x 52x7 S. 8x53 T. 23x 53

PORST

30,102的約數中,最大和最小的相燃多少?

Q. 100- T. 104

Q.8厘米 S. 13

T. 24

20一正方嵴,其體積是1000立方厘米,間其一

**21

P. 50* S.. 1000

a. 10* A. 50* T. 300 PQRST

□□□□□

3×2000-7

B. 125 E. 250000

22.160以內,7的最大兩個歉是

C.: 250

P.

P. 99 S. 103

ABCDE 31. 35+. 33mm 7.

□□□□□

R. 101

PORST

C. 15

ABCDE

Q.30匯米日:45淇米 T. 120 * PORST 00000 37.用12,三個數字,可以越成規国2的倍數

?

P. H Q. A: ZR S. FE

PORST

38.一正方體的體積為512立方厘米,餕正方體

每邊多少? P. 8*

Q.16厘米 R.64 T. 256

PQRST

39.正方體的體積是64立方米。求該正方睡一面

的面物。

P. 4* Q. 167ER, 2077FE 15. 324X T. 6477* PORST

40。長方形增長100米,潞49米,與另一正方 形空地的面積相等,該正方形空地银注養多 19

因數、倍戰、香因數、質因數 連乘式、平方根與立方根 (一)因數——乙數如能性除中期,乙(就是甲

類的因數,又叫做約數。因數是有限的, WERKEL (EUETTEN) · R 大的因數是該本身,在1042+2巷10

的因数。

(二)倍數與數能放乙數整除,甲就是乙 「:政的倍數。倍數是無限的,最小的倍數就

漫號緻。在12-312是3的倍數

(三)質因數———咨個如果是質數,同時又是 另一個數的因数,創造們質數就是另一個 假的寬因數。如她的因城有2,3,6,但2 與3都是6的質因數。

(四)智因败逛式——用武除法,我出能够整 除原數的廐職,由小至大大饿除之,最

·後所得的商爲質數止。把簽次的除數和最 後的商用乘號連結起來,能是所求之西 數運乘式。

例,求266的質因數速乘式。

#BUE

1.575的因畝,75是5的聚数7

A.因數 B. X

E-ㄚ力

D.

2.求12所有因數之和。

A. 27

D. 72

3.下列那一组的兩個數是45的倍呶?

A.. 5.9

4.100以内最大7的指数是甚麽7

A. 35

B. 42.

D. 98

C.M

A B C D E

8. 31 E. 144

C. 34

ABCDE COCOO

A. 12

D. 33

3. 16 E. 60

C. 22

A B C D E

21. (0.5)

D. 80.120

B. 3.15 C. 50,100 E- 90.135

12, 43

A. 0.125 D. 3000

P.7**

Q. 17*

R. 49

ABCDE

A. 73

C.49

D. 6

B. 55

Ė.

C. 52

ABCDE

A. 6

D. 27

B. 9 E. 243

S. 70%

T. 100%

POAST

□□□□□

□□□□□

答案

E. 350

ABCDE

32. 24× 52?

(1) D

(2) A.

(3) E

D⚫ 132

5.第11的第二個倍數與館*個倍數之說。

A. 44.

B. 55 E. 1452

C. 88

ABCDE

A.

D. 94-27

A. 5x 112 B. 34x7x11 C.

(4)D(S) A

(6) R

52x7x11

A. 40

B. 60

C. 80

(79 0

(8) S

(9) P

D. 200

E. 400

ABCDE

D. 3x5x7 E. 3x5x7x11

D. 423 E. 3×343x3x3

ABCDE

□□□□□

(10). T

(11) B

(12) D.

ABCDE

24. 53. 12

33. 102 824 33 q

(13) B

(14) A

(15) C

(16) R

(17) a

(18) P

多少

P. 14

S. 17

P. 105

R. 16

A..9

15. 6 2

A. 24

B. 46

49

D. 63

PORST! OOOOOO

B. 13 €. 191

C. 31

(19) S

(20) Ɑ...

(21) G

A.3

D. 56

B. 9. E. 108

D. 50

E. 96.

C. 27

a..126

R. 147

ABCDE 25.441 =?

ABCDE

□□□□日

ABCDE

□□□□□

(22) Č

(23) E

(24) D

(25) C

(26) a

(27)

P

34. 一正方形草地,它的面積是324米,是

(28) R

(29) T

(30)

Ɑ

A. 19

D. 25

B. 20 E. 27

A. 18 D. 42%

B.22* C. 3* E. 72*

(31) B

(32) E

(38)

D

ABCDE

(34) E

(35) C

(38) S

(37) R

P. 0

(40).S

00000 14. 3× 33-7

A. 133,140 B140,147 C.147.154. D. 154.161 E 161,168 ABCDE

23.分解1155盒質因數連夠式。

盤,如此將來自己身入了虎穴?

要是在平常黹况,身入了虎穴,要是說得

歷,要不然

好不舒服。他突然的想到陆開鑿開 ,但因爲那人的存在,教他甏到 偿不翼而飛了。,

·的皮上衣時,他試圖把時間拖延後的步骤,他打算矮,那腕

KE

那老人多得了满自己一 苏,而今想

遠匯好

·遠。他撿起了手提包,開步徼行。 等,他留了在洗澡師事。 正于之後,最好有財經遠,走麼 以及牙,一鬚刨,頭水和香皂

一位英國長科碩士,會經啟 關於這一點,我已路說過, 但仍有脊格煮。」 禁養林局技正的先生,解放後,每年中學畢業生,以萬計 來-無事可爲,只好就算,其中無法升學者,可以做 不過不重要。」「四八二) 「中畢業悌可以教小學 的敦員,雖然未經師範斜, 模的,可以例外。 但我日本 「自然有 - 第十點都有。

起來,事情必定不算常。

那人走在他的前面,替蝕開門

· (+1)

27 286

11) 153

13

2862x11x13

(五)平方根艘一個數皆乘,破平方,如 8x864 TURNERNE BATZE

·成爲期平方。現在只是利弔因數分解 法去求整数的平方根。

5

LD75 --

中學會考專欄|

>堅道書院主編:

生物科(甲)申购關 -

Le Pen Marcos, desaMA

船意

HABET VA. 2-31; 6.21 NS; 24 15. Ja. 4 Adam: Awak 【飽B奶功關心排洩 Are Toge. a) -

6、12與20之間,那一個數是512的因数。

G. 15 T. 18

7. 21:9XMERLAR?

5 216 T. 541

8.44917497270 •

PQRST | 16.12翼乘以那一間精小的數,它的平方根中

是整數?

a. 2

R. 3

冰變形焱的營養方法。 ZA TELMA. 3. 蘇興樊以志從為單細胞 生物西番⻍營養法有何不宜? 4 MERRAÉɱ72MAA 消化

上跑案:

1. A, E, YA; (4)C; (KIC 3

A... 4, 6, 4 mus, & Þoka, 7. #:10.

球:小袼含ㄛ

B. 2. neošek MILIT 不與合成蛋蠻有蘭,支持細:

瑞生物遺傳之主要物質谶你是 tinkAathi #br

分裂(無分

裂(有絲分裂)。

Na vrchuk, h

la

ARTDEK

båløk, nefnd. e. Ab

14 葉酸利用下卵→

Nuevo por debate fa

(感物 A凇心滿

伸縮棍射管,懶我吃速

jah AŽ A f

UDP, B. HORNBERKAC BEHN

...***.

以

#self... a. BAN

7 - $60 fangi 4 kan d

A DEYRARÁN, AJkt dres KOLD ME WAR, ELGRAD - 8.******DIAN, HE JA, TERÉJE, A. Are

kurduk.

9dus A. xbkš, a6.3

祝盆

E.NU.

Andy) ES :

AMING PNUJEME, 8 WIND 4

d. mpira zaurti,» BÉABLA

PAA 18, JAVÍTA BOSHIG

流感:

2. RAWAN

Greek chak.

bok.

Pé d'ézné sídka 109krabrook

NAKE,

Adap plată – AM

Adi Wakoptu Kaube :

A

磯繡D

4. KOJE

- KATA; usi

醤噌醤

醤油

******

kanakkannīkla $itt ferner,

By

++

والنيا

綠费 *

分裂中低植物

We

x R th

Sheer Wor

ÍA ANARCH Měj 海邂缘

TAN DALAS BEL BES PARAUX

结性粉粘性小人

介

胞

+24#+

JUDAY

CA MAPA, duro) skin TETÉBEN. Znam

- SIRA. A

22 vec ply tunes MATAN MERE, 36 hi

qkrožene tok sa kir, ž

Jan 5 PExedy up Faz Dhe kës dink.

生物科(乙)·卓麼喜備,

BIOLOGY B (#3)

ExplanationsI

Exp.4.

We know that air oonsists of approximately 1/5 part of oxygen. Given air, soaked souds will begin to geaminate und in doing so will use up Og and give off (02.

So, in the coures of the day, ligovator was seen to rise in the " shaped tube, ite colour also gradually became milky.

This indicates that part of the sir in the tube was used up, and the 00, which was given off dis- solved in the 11ewater,

When the linewater ceased to rise, the level of the rise appeared to be about 15 of the tube, Gently run a stream of water into the jar, avoiding introduction of bubbles. Placing a thumb over the open and of the "p" tube, lart it un and intoduce a glowing splint. It extinguished. This proves that tho part or the air that is not used up doon nol support combustio (it actually is N2). Se Up in the

air must have been used up,

Exp.5.

(i) Dead needs were used as a control to show that it was the gominating seeds which gave off heat.

(ii) Disinfection prevents bac- terial decay which will confuse the issue as bacteria will carry. out respiration and cause heat to be lost too.

(iii) There should be a ride in temperature in appare buɛ A.

Nutrition

In order to live, we need one or mare substances useful to our body called nutriente,utrition. in- valves the proceseo yubich one is able to obtapi maurishment fo growth and repair. They aro

hatione waye bwhitition is ced opt in ling organism.

Be there are those, like ug ghe tornot make its own food and

in others for their food apple belozoic mutrition; and tre are those who are capable of making their own food from inor- ganic materials le holophytic nutrition. Apart from these are other unusual modes of nutrition:- (1) saprophytic nutrition - mode

of obtaining nourishment from dead organic matter.

e.. moulds grow on bread. (ii) parasitic nutrition a mode

- of obtaining nourishment from

another living host.

e.g. wheat rust on wheat. plent

9.4. a. What are enzyme #7

b. Briefly describe their characteristics with reference to digestion in Namma18.

A.a. Enzymes are mainly protein and

have very large molecular weights They are biological catalysta. Their actiona are apocific, giving specifio by-products, The effectiveness of an enzyme

e affected by, temperature (370

50°C), pH and often the presage of inhibiting agents

the concentration of the

bstances. Some

enzymes a regis irged from certain cells extracellu

enzymes. Some droomed ini!

the cplls in which they hot - intracellular enzymes,

b. In the mouth of man, salivary amylase (ptyalin) changes cooked starch to maltose but has no affect on protein or fat-specific in action, and needs a neutral (slightly acidic) medium -

specific medium.

In the stomach, peppin begins digestion of protein in the prosence of an aoidic modium. Lipase digests a little of the TU

Rennin coagulates caseirogen into insoluble casein.

In the small intestines, panora latio juice is alkaline and

contain the following enzymes. Amylase (diastase) converte oooked and uncooked starch into. maltose.

Lipase converts fat to fatty acids and glycerol. Trypsinogen changes to trypoin on meeting with enterokinase from intestinal juice and auto on protein, converting it into amino acids.

Eropain in the intestinal juice converts peptones to amino acida. Malta se, suorage and lactase' converta maltose, sucrose and lactose inte glucre gerespectively. Thus, every food material is acted upon by their respective enzymes under specific medium and produce specific and producto.

Q.5. Give an account of the

structure of a villus and a root imir. Compare their functions.

NB. As this question concerns With structure, it is advisable to accompany it with two sectional diagrams of villus and root hair. They npod not be too big (approxi- mately 2 inches) but he sure they johow clearly the various parts.

A villus is a finger-like projection from the wall of the

All intestine into the cavity, A rout hair is a tubular pro- jection from the epidermal cella of the roots of higuer plants. The function of both is the absorption of soluble suburbannes from their surroundings. Kaoh ingrease their surface diva of the organ of which, they are part of and therefore increase the degree of absorption,

Pack has a thin wall and the villua to well supplied with blood vennela and İymph vessels which holp to convey the nutrienta #way.

c. 21

ABCDE

□□□□□,35.正力形面積0.36平方米,該正力形的邊長是

Absorption, however, does not occur by simple diffusion.. Some substances may pass into the villus although a smaller concen- tration is present in the in- testines than in the blood of the villus and different suguro ere absorbed "at different rates.

The passage of water into a mot hair is aided in parts by factors such as osmosis and trenspiration pull.

Vijli occur inside an animal while root hairs aro outside the

化學科

OHEMISTRY (#3)

SOLUTIONS FOR CHEMISTRY (#2) Multiple Choice Questions 1. (D) I, III & Y

A characteristic property of all metais (including iron) is the ability to conduct electricity. Some of the electrons surrounding each atom in a metal are relatively free The "flow" of ourrent is the mo vemant of these electrons from one atom to another, Metals are said to coniunt electric current electronically, since only the... slectrons are in motion during conduction. In case of molten ionic salts and electrolytic so- lutions (e.g. ferrous sulphate solution) electricity is conducted

Carbon through movement of ione.

(a.g. charcoal) is a non-metal and hence an insulator. However, the allotropic form (graphite) is a very good conductor because of the mobility of the electron pairs which contribute to the aarbon- carbon double bonds in the structure.

2. (Omitted due to printer's error last week) For the following alemento: 1. Calcium II. Potassium III. Iron IV. Sodium V. Silver, Those that will react with oxygen of air at room temperature are: (A) I & II (B) I & III

(0) I, II & III (D) I, II JV (B) All the above. Angger (D). I,

B. ZOKC Eium

BUTC

4. sote as a proton donor in

reactions.

According to Lowry's concept, ecidity in aqueous solutions is due to the presence of hydrogen ione, formed by a process of re- versible ionization, thus: 101

In actual fact, the naked

proton

I exista only momentarily, and is invariably assoniated with wolvent molecules, •-•

The latter species being known as the hydroxonium ion.

5. (0) Dilate sulphuric acid

Zine but not söpper dissolvee in dilute sulphuric acid with the displacement of hydrogen

Zn + 1,50 Zn30+ Hyt

"A

Conventional Questions Answere to be published next week,

QUESTIONS FOR THIS WREK

The questions in this issue sie related to chemistry of the ple- mente 2,1. (a) Hydrogan; (d)(i) The Halogens. Study your notes ant

[extbook on these suctions hatore

attoupting the questions. Multiple Choice Questions

1. Hydrogen gas may be obtained from (A)Heaction of cold water with aluminium (B)Reaction of load with steam (0)llesction of stess with hot carbon (D)Reaction of hot cone. H,50, with carbon (B)Reaction of hot cone. 11,504

with silver,

2. 2012 - 2NACI + B2 The above equation is an example of a type of suction known as: (A)Combustion (B)Displacement (C)Addition (D)Substitution (E)Double docomposition.

3. Which of the following stute- ments is correct?

(A)A mixture of hydrogen and biomine will explode when exposed to sunlight (B) Iodine dissolves in aqueous potassium 1odide to for a purple solution (C)Lead okloride is soluble in ammonia (D) Corine is released from bleaching powder by the action of carbon dioxide (3)Anhydrous cul- clum chloride cannot be obtained i by heating the dihydrute.

4. Which of the following compoun has itu solubility little affected by tempauture?

AS JAMTONÍUm enɩorius Jean chloride (0) Sodium chloride

(D)Zino chlorido (E) Hydrogen chloride.

5. In the electrolysis of molten lead bromide using carbon elect- rodes, what are the products for ed at the electrodee?

(A)Hydrogen at the cathode, oxygen at the anode (B)Bromine at the anode, lead at the cathode (C) Hy- drogen at the cathode, bromine at the anode (D) Lead at the anode, bromine at the cathode (E) Lead bromide, is stable under the given comitiona.

Conventional Questions

1. Low would you distinguish bès tween aqueous solutions of hydro- ahlorin, hydrobromic and hydriodic acid? Suggest two testa for each ong, I was experimentally deter mired net 2.0517 gm. of potassium precipitated from solution in of allver bromide. What atomic weight of potassium, it be assumed that the element is monovalent?

2. What accesses where

red on a large

hydrogen noale? Wh are purities. likely to badge in such pro- ceƑana? Are the waight of iron that wedla be required to generate by reacting with sulphur de acid, enough hydrogen to fill up a science laboratory 20 meters Long, 10 meters wide and 4 meters: high at atmospheric pressure and a temperature of 20°C.

物理科(

PÉNETOS (3)

·陸永幟、

Solutions to Probleme given last week: 1. (a)

ون

Trolley moves - w tr a relative veloci ty of v with the platform. However, there is no fric

tion between the platform and the floor. The plat -form slides on

freely in

oppositi direction at a relative velocity -of-v with the

flodr...

There is no rèla- 7tive motion be-

tween the trolley and the floor. Helative velocity of trolley to

the platforma v Relative velocity of platform to the floor

Relative velocity of platform to

the trolley

V Relative velocity of trolley, to the floor

0

(F) When the actor atopa Relative velocity of trolley to

the platform = 0

helative velocity of platform to the floor

==

(No friction; Nowton's first law

applies.)

Relative velocity of platform to

the trolley 0

(The trolley raste on the platform and moves together with.at). Relative velocity, of the trolley

to the floor -v (iii) When the trolley runs off the platform with a relativa velo- city of 4 m/s to the floor- Relative velocity of the platform to the floo% -4m/s Relative velocity of the platform

to the trolley-8 m/s Relative velocity of the trolley

Pig. 1

(b)

V2

The two blocks are prosped es

When released, the 12 J potential energy drivau the block apart with velocities of vy and g From the point of Conservation of Energy + x2 = 12

joules Am,v,2+ m2 = 12

2.

24

v12+2v2 = 24 ....(1) From the point of Conservation of momentum:-

+

-22(2)

Solving equation (1)

and (2),

2

42

+242

#24

2

62

2

= .24

- 2 m/s

By substitution, V1-4 10/3

The negative sign indicates that the blocks alid in opposite dir ection at velocities of 4 and 2 n/a (b) As the bars are cut from the same piece of wood, their masued are in direct proportion to their lengthe, that is, lengt

Ma: Mp

by - 112

The tension of the stretched rubber band exerts equal but opposite for ces on the two bare of wood when the thread is burnt. By Newton'e second law of motion, F.- pa, the acceleration, a, of the block is directly proportional to the applied force and inversely pro- portional to its ma88;- a F/m Therefore,

: شیر

ก

BA

B

៥.

日

=

1 10

2:1

b) Let x-on mark be the spot where they collide, and t sscconds be the time taken.

A

Distance moved by A before, the collision, S

taja, 12 Distance moved by B before the collision S

Sa :

**A

→ HA

and

+ Sb = 72

velocity (mp-

to the platform 8 m/s

201A

10

~20

time

Since -10 m/s/3, the graph slopce down at the rate of 10 in 1 The bull reaches its maximum heit at t 2 seconds, point B, where iba velocity is zero, before it retume to the grund with positive 6 of 10 //.

Up-flight is marked by the area of AOB (positive)

Down-flight in marked by the area of 800 (negative)

t18

(ii) Displacement of the ball. at

Area of the shaded portion

(2010). 715 mi

Displacement of the ball at t = 4 3 Area of ACD + Area of DỌC

20+ (-20);=,0

It returns to the ground,

til/ Change of wununtun between

m(v - u) = 0,2(10 − −20) = 5.2(30)=-6 Na

iv/ The rate of change of momentum

E

हैं

Problems for this week

نيكنيك

(1) a. A rubber band of longth 12

cm will become 18 cm when loaded with 9 R. If it is cut into 2 halves and be connected in paralls) to a load of & N, what is the elongation of each of them?

b. A arene with a jib of n

long (AB), centre of gravi by 30 from A is attached to the wall by a stretchel opring as shown.

Tha jil is 20 N and the loud is 60 N. The criginal length of the

Ing 183 m. What additional load is required to stretch the spring to 6 m long?

Discuss the difference bet- utable, unstable, and neu- trul aquilikaku, zaing so an exam- plc a rigid body fixed at one point only Determine the position of the pentre of gravi by cf. the solid uni- form prism aloss principal cross- section is shown below.

2

WETA

24 1

S= x 72 = 24 cm o-lii) Just before they collide,

their velocity ratio:

Vivut: at (v=urat). -4102:1

u=0

2(a) When the motor starts, the

AB 6 cm cb= 18 en AU BO

[ADJ -[BCD=45"

Could the prior raat with the Tang

BO in contact with a horizontal plane?

KD-KES-BASEDRA

「他,」中年渙說:「你是鬼謀

?我與你們無仇無怨 -

本

› KER-STRIKKJKC