1972-12-18 — Page 17

育教僑華頁一第張五第

REFERENCE LIBRARY

18DEC1972

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樹仁書院大同學

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聖誕不忘小朋友

-

WEST 1-1/2-29CHEDIE

PERSISTEREN 屆時將標,徐現,魚

被一個熱的,多一向上述各谍術、蛋仔民

PERFE

SIKRERA 156+

NAH KHAND

·招待坊衆一千五百名

聖若望書院祝聖誕

·明日在麥花臣球場舉行 羅明

CERY EXPETHE ***

換,體色實稅擠,越花實演出

TEA..

ARRISK

名腿

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1978€

中文中斷會考試題預習專欄

數學科(八) 張正邦 •

第一次預習題解處

析下列話式之困式,

93 (4-3)+3x(3 −x) + xy (x-4). | 2x-4117 82 19 43 (1-3) + 34(3-4)+ y2(4-4) = 0 JMB * 定理知メー触除霊原式即カーリ 式汐田子同理可得リーなるーメ皆 原式之周子

*} 43(4-3)+3x(3 −x) + x4(x-4)

- 1(x-4) (4-3) (3 −x)

営X=04=18=2代入り得 2(1-2)+0+0=1(-D)(1)(2)

43 (4-3)+8 × (8-x)+xy(x-4)

(x-4)(4-8) (8 -x)"

x2(4-8) + y2 (3-x)2+ 8" (x-4)3

BE EX X Y Z NBA X 12 X-Y HE 整除此多數亦即為多數之因式。同理 得一子及子一人亦為多數之因式 2x2(4-3)2+4213-x)2 + 32 (x-4)2

=(x-4)(y-3)(3 − x ) [ l (x2 + 4 + z2)

1+k(x4 +48-481)]

xX X=Q, Y=1, 3=24X9>1?

(0+ 2 + 2 (-1) = (-1)(−1)(2)( | (0+1+4

t* (0 +2 +0)],

52+26=2

<X X=0 Y=1 3=3. <£^^ (1) 15.

0 + 32+32 (−1)3 =(−1)(−2)(3){£ (0+)+9

+ K (0+3+0)]

*(-) (3) P}} l=0, k=r

- X2(4-3)2 + y2 (z - x)2 + z = (x - you

= (X-4)(1-3)(2− ×)(x4 +18+2x

y=z

3. (X+4+3)-x-y3-3° 解設=

此函數為零坟X+y HE PK & WE 3 BX Y X + 4 **** 2 拿因式,同理子及第十七亦為此函數之

~2(x + y + 7 = x2ys _ z = l (X + Y)

× (4 +3)(8+X) -

X=0, 4=1, z=| A^ W

12) (3) (AX 13) 2×80-k=160 k=0"

• (x+Y+7)= (4+3-x) = (8+X-4js

-(X+4-8)=80X43(x2 + y2+3

(5)化簡x+a

(a-b) (a-3) (b-c)(b-a) -

原式x+a

CHEVRCPSENYAME* HERMOSKY TEXT SEE

●期星:

6日八十月二十年二七九一暦公年一十六國民華中

油!!

EM-CHEIERT¥-2404RATON SENEKI, 宁出路問題云上倪生十八人,二百七十名進候曾陪

香港學生赴英國求學 去年七百二十八人

前往英國留学年有,質,畢業出之源萊梅亨 六人在大學,工業院校 SEER EK KÖTART KIRANHAANME-111

當地就業之機會較前下降 較七零年增百分廿八 畢業後在

241IKAKA

浸會及中大工商管理學會合辦

;在香港經濟發展中所担任之角色」歡迎

·本月卅日至下月7日舉行 主題爲「政府

香港經濟發展研討會

SEBKE•ZREN ENE (0) HORN BEKTREZ-ZERK *ZKIZ-STIV MENTER EZEK • U KISELO ESKIE RIKK

·各界參加

GAHELEBER

SKENDUELEK

-FI SEK =

BRUNETT

BRINUS)

SEE LIST

RICKY HE

K

者四

者注意

頁六息有

在背

In the middle

part

教

CC-OAO(C-)1913英文中學會考試題預習專欄

of the leaf

which is divided again into two

x+b (a−b)((-a) (b-c)(a-b))

(c-a)(b-c) (a+b)(b-C)(C- @ <[(x+a) (b−c)+(x+b) (c-a)+(x+D{a-b)]

3 a=b 12 (x+a) (b−() + (x+b) x((~a)+(x+()(a_b) ☆ ☆ by Q-b

#6 | X+a)(b+c)+(X+b)(( a ) + (x+c) *(a-b) = [ *\\ 1668 (b−c) / (C-Q) J). 為此函数之团式

Ex (x+a) (b+c)+(x+b) (c-a)+CHO xca-b) = √(a - b) (b-c)((-a) --- $a =2b=1 c = 19 l=0.

X+6

X+C

(a-b)(a-c)! (6-()(b-a) ((-a) ((-b)

6.化簡

6.12% (b+c)2

(a-6) (ame) a+b)?

(6-c)(b-a)

((-a)((-b).

(b+c)

(a-b) (c-a)

•(a+b)=*

((-a) (b-c)

(b-c)(a+b)

(b+ ()=(b−c) + ((+a) (C−c)+ (a+b) (a+b)(b−c)(C− a)

#6)2(b=0)+(c+a) (C=α)}

*+ (a+b)" (a-6) #4 V) (a+b)(6-c) (CA) Rebeca_b)(6-0)(c-a

Q=0, b=1; C= 2 q§ 1 =1

(b+c)2 - (C+a)2 (a+b)?

(^_b) (Q-c) (b-cX6-a) + ((-a) ((-b).

151 #21 x2+342=31

(3)

(3)~(2) ; 12342=207 y=±3

7x (1) '7x2+214^=2)

11-13 代入り得

(0+1+1)2 -0-1-1-((1))(HD) (1) 1

2=3

3(=3)2=31

~~~(x+y+3) 3 =x3- y3 - 33 — 3 (x + y).

((4+3)(3+x).

4=-314-3

八次領習題)

4(x+y+3)=(Y+z− × ) = ( 3+ X-W

(X+43)

nauk zen, Trg YGE

(x+y+3)-(4+8-x) = (3+x-4)

- (X + Y -3)= X Y Z (±(x2+y2+8?)+k(x;

+28+8x)]

x=1, y=4 8=14&U_

| (1 ~ \ + 1 ) = ( - 1 + 1 -1)2 - (1 + 1 + 1)2

231-k =240

总X=-lq=-1,8=2 代入

-(2)

10-(-1+2+1)2 - (2~1+1)2 - (~1-1-2)2

(-2[(1+1+4)+(1-2-2)]

Jalka160

解下列各联立方程。)

2x2-x4-34=0

P

2x + 4xy + 2y 2+3x+34-2=0

-324245

6x2-x4-242=56

5x2-xy-y==49

2x2+4x4-2X-4+2=0

3x2+6x4-x+3470

5- 1 x2 + 2x4 +243 +3x=0

1 X4+ y2+34 +1=0 xy+y2+34+1= (6 / 10x2+542-278-48 +5=0)

-1 x2+4=-3x-4=0!

生物科(八)

Biology (3)

Answers to the

Week

Ans.

Distinction of a root from stem is tabulated as follows:

Stem

Root

last

(1) grows ascend- grows descend

ingly.

-ingly.

(11) Negatively

phototropic.

(114)

ever green in appearance

iv)Bears no 7

leaves and *bad's but

lateral roots. (v) Branches are

positively phototropic. Green in、." Tappearance

part. Bears leaves and buds.

Branches are

endogenous in exogenous in origin.

origin.

((vi) The root tip

is protected by a root cap

(vii) possesses

unicellular. hairs (root Mairs).

The stem tip

is protected f by scale. leaves of the terminal bud. possesses multicellular

hairs (stem ** vahairs).

viii)Has no nodes Has nodes and

and internod Fes,

(iz) Is for anchor

age of the plant body,

intemodes.

Is to support the plant's. organs such as leaves, flowers and fruits.

Six functions of the root are: (1) for anchorage of the plant body in the soil in an up- right position.

(ii) for the absorption or water

and mineral salts.

(iii) for the transportation or

manufactured food and water ap the shoot.

(iv) for the storage or rood."

(v) for nitrogen fixation from

free nitrogen to soluble nitrates. (vi) for vegetative propagation

e.g. root-tuber.

Six functions of the stem are stated as the following:-

+() forms a framework or the

plant body on which leaves, flowers and fruits are supported.

(ii) Acts as a passage 1or the

conduction of manufactured

food from the green leaves to the various parts of the body of a plant.

(iii) Acts as a food-storage argan

of the plant.

(iv) is for vegetative propagat-

ion e.g. sten-tuber, rhizome (v) is for conduction of water

and mineral salts from root to the leaves. (vi) is for bearing flowers and

buds.

2 Aris.

(a) In section, a dicotyledonous leaf shows that, its upper and Lower surfaces are protected by a single layer of epidermal cells.. The cells of the epidermis are irregular shaped and densely pack

ed. They are in turn covered with a thin cuticle. "Among the epidermal cells there is a number of minute pores, the stomata, guarded by a pair of bean-like grard cells. Most of the stomata are arranged in the lower epider- mis.

layers of tissues, the palisade and spongy tissues.

The palisade tissue is the

upper region consisting three or four layers of cylindrical cells with numerous chloroplasts. A number of small intercellular spaces may occur between these cells.

The spongy tissue consists of large and irregular spongy cells. which contain a few chloroplasts. Among the cells, large intercell- ular spaces occur to store wateri vapour and gases from air...

Veins of the leaf are embedded: in the mesophyll tissue. They are the vascular bundles of xylem and phloem tissues. The cells of the xylem are large, less dense and with less protoplasm, while those of the phloem tissue are small densely packed and are numerous in number.

dermis

dermis

Sloma

Cuticle

Upper epi-

palisade

Chloroplasts

frssue

Lower epi-

-Spongy tissue

(Intercellular space)

A transverse section of the leaf

Chyma

Xylem

Phloem

Scleren

(b) The function of a green dicoty -ledonous leaf is 1-

(i) for photosynthesis

the leaf possesses chlorophy -11 and makes carbohydrates from carbon dioxide and water, with the help of, radiant energy.

(ii) for exchange of gases ---

the leaf possesses stomata which serve as the passages for the exchange of gases during respiration and

photosynthesis.

(iii) for elimination of excess,

water------ the excess amount of water in the plant is given off in the form of water vapour through the stomata during transpirat ion.

(iv) for vegetative propagation

certain plants may be propagated vegetat ively by means of their leaves e.g. Begonia and Bryophyllum.

Questions for this week!

What is meant by vegetative propagation in the flowering plants? Explain briefly, four advantages of vegetative propagation

2. Describe, with the aid of

diagrams, the external featured of (a) a bulb, (b) a rhizome, (c) a comm, and show how these structures may bring about vegetative reproduction.