頁四第張六第二日六廿月九年子壬屏夏
1973英文中學會考試題預習專欄
* AA **R+9
物理科
PHYSICS
Suggested Answers:
Solution
()
The rectangular components: of individual forces are tabulated as follows:-
Forces X-component Y-comporent
Resu? t-
ant
Ans
2001bf
+300cos600 +300 sin60 -100c68 459 +100 sin47
0
-200
+279-1bf +180.51
(279)2 + (130.5)~
R = 308 lbf
tan
1130.5
308
250
The resultant is 308 1bf. at an angle.
above
the x-axis.
Solution
Procedure
1. Diagram.
2. Isolate the
body...
3. Indicate forces
on the body.
4. Tabulate the
componenta of forces.
Equate ZP
y
Solve the simult-
aneous equations.
Forces x-components y-components
If
-T cos 60°
+ T sin 60°
Where F is the force,
T is the tension of the
cord, and
W is the weight, 5k gf
system is in equilibrium, IF O
Therefore,
cos 60° Tsin 600
From 1 From
0.50
csc 60°
:77
2.89
ins
The tension of the cord is 7.77 kgt.
the force 18 2.09 kgt.
FORCE IN
EQUILIBRIUM
Resultant A resultant force is
a single force having the same? effect as two or more forces act- ang on a body.
Graphical Representation of a force
Any one force may be represented by a straight arrow drawn with its length in proportion to the nagnitude, the sense of ite ar row head for the direction; and the origin of the line for the point of application of the fore Concurrent forces
If forces act on the same point, or their lines of action when produced cut at a point, they are concurrent forces.
The resultant force of the sys- tem determines the motion of a body.
It may cause the body to
韩日僑羊
WAH KIU YAT PO
move laterally, or rotate the body. It may also experience no notion at all. That 19, there is no resultant and the system is said to be in equilibrium.
First Condition of Equilibrium The resultant force of the sys- tem must be zero.
ZF = 0. This also means that the sum of the x-components must be zero and the sum of the y-components must be zero for the body to be at rest or moving at a constant rates
IF
-0 and X
Problem proc
1. Diagram:
Summar
Read the question care- fully and draw a clear but simple diagram to visualize all the expli cit and inplicit factors.
Isolate the body
This is done for the pur- pose of a detailed consi- deration made on the for- ces acting on a portion. All forces should be clearly indicated on the diagram
Evaluate and tabulate the x- and y-components of all forces acting on the isolated body.
Equate Σ x
Solve the simultaneous equations.
three forces, non-parallel, are equilibrium, they must:
1. be on the same plane, 2. meet a point, or be con-
current when produced, satisfy the Triangle of Forces shich states that "If three forces acting: at a point are in equili- brium, they are represent ed in magnitude and direc- tion by the three sides of a triangle taken in order" Any one of them must be an equilibriant of the
ther tw
Lamis ineorem
The forces that satisiy the Tri angle of Forces can be calculated as follows: –
A
Non-concurrent Forces
If the forces acting on a body are not concurrent, the first condition of equilibrium becomes a necessary but not sufficient. condition of equilíbrium. It must satisfies another condition. The Second Condition of Eau111- brium
If a body is in equilibrium, not only must the forces acting on it when added up be zero,
but also the torques exerted by these forces with respect to any one axis when added up be zero. This is known as the second condition of equilibrium. ΣΕ
Problem Procedure:
Daigram.
Isolate the body, Indicate forces on it. Tabulate all forces com- ponents and brques. Equate
ΣΕ
0
0.
Solve the three simult- aneous equations.
Moments Equilibrium of Parallel Forces
The Moment of a Force or a tor- que, about any axis or a point is the turning effect of the force. on a body about that axis or point.
It is measured by the product of the force and the perpendicular distance from the tuming point to the line of action of the force.
三期星
(接第六張第一頁)
日一月一十年二七九一歴公年一十六圆民希中育教儷華
1913英文中學會考試題預習專欄
堅道楽書院主編
化學科
hus the weights of lead which
combine with a fixed weight (gm)
of oxygen are in the ratio
4 3:2, which is a simple ratio, Exercise
Part I: Multiple Choice questions
Which of the following substances would you expect to stay the same weight when heated in air?
A. Silver oxide
B. Ammonium nitrate
C. Magnesium
D. Gold
Copper
When a compound is formed two elements, the chemical properties
of the compound,
are an average between the properties. the two elements
not resemule those. of the elements: depend on the element which weighs the most depend on the states of the elements
depend on the element which is there is the greater volume
Which of following changes belong to physical change?
A. The evolution of gas fr
health salts placed in water
Solid iourue 19 heated gently in a test tube
C. Sodium nitrate and
ammonium chloride solutior are warmed together
Iron filings and powder sulphur are heated togethe E. The Solution of magnesium
in dilute sulphuric acid
4. The atmosphere is a mixture
of gases because
A. air contains nitrogen and
oxygen.
B. different gases in aıı can be separate by diffusion method
it is soluble in water" its composition does not vary
E the pressure of the
atmosphere varies from place to place
The Law of multiple proport ions is illustrated by
Principle of Moments.
If a body is in equilibrium, the sum of the anti-clockwise moments of forces about any point is eq tal to the sum of the clockwise- moments of forces about the same point.
Conditions of Equilibrium for Parallel Forces
The algebraic sum of the ces acting on the body in any given direction must be zero There will be no linear dist placement as there is no un- balanced force.
The algebraic sum of the mom- ents about any point or axis is zero. There will be no ro tation.
Couple
A couple consists of two equal but opposite forces at a distance apart. A couple produces rotation on a body.
The moment of a couple is equal
to the product of force and the distance between the two forces
F
Moment of the couple Centre of
ravi
Centre of gravity of a body is. the point of application of the resultant weight of that body.
The weights of the cons tituent particles of any body are parallel forces directed towards the cen-
A. Sodium chloride and sodium
Iodide
B. Nitrous Oxide and Nitric
oxide
Sulphuric acid and sulphrous acid
D. potassium chloride and
potassium chlorate
E. Oxygen and ozone Consider the
Statement If two different compound of copper and oxygen are formed it can be shown that the weights of copper combining with a fixed weight of oxygen are in the ratio 2:1 This an illustration of the law of
P. constant composition Q. Conservation of mass R. compound proportions combining weight's multiple proportions
In the atomic theory, Dolton stated that all atoms of the same element were alike.. Which of the following. statements would he rejected its
P. An element can form
allotropes
An element can form isomers
R An element can fore
isotopes
5. An element can have mora
than one valency
·T.
An element can have more than one equivalent. weight
Metal alloy one generally
P. A chemical compounds.
Q. A mixture.
R. Metallic ones
S. An element:
1. Can be found in nature
Give definitions of the law
of multiple proportions. Show how the following i analysis of three compounas of nitrogen illustrate the law of multiple proportions:⇒
A per cent per Nitrogen 63.65 Охудел
36.35
B
Per cent percent 46.68- 25.94 53.32 74.06 2. 5.85 gm. of sodium chloride is found 15 contain 2.30 gm. of sodium. 3 gm. of sodium, reacts with water to form sodium hydroxide, which is further added to hydrochloric acid, after neutrisation, and heaty, the weight of the residue(sodium chloride) is 7.63 gm, use these figures. to illustrate the law of constant composition.
tre one earth. Their resultant, the weight of the body, acts through a definite point which is independent of how the body is placed.
Exercise for this week
The above figure shows a square A and a triangle B. attach together. A of mass 300 g, and B of mass 100g. Given the dimensions as in figure. Find the position of the centre of
At what angle gravity of mass.
to the vertical will the side 00' be when the, figure is freely pivoted at
A train starts from rest from a station A and travels with uniform acceleration 50 cm/ sec/sec tro k 20 seconds. It is then travelling at uni- form velocity for another
seconds, and brakes are then applied so that a unifom betardation obtained and the train comes to rest in a fur- ther 10 seconds. Draw a vel City-time graph of the motion, Use the graph to calculate (a) the maximum velocity reached, (b) the retarda-. tion, and (c) the total dis tance travelled.
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