1972-10-26 — Page 27

REFERENCE LIBRARY

2.7 OCT://

CITY

下係華真三七第日十二月九年子壬軀夏 WAH KIU YAT PO

報日橋華

and ear).

1973英文中學會考試題預習專欄:

Reproductive system Endocrine system

生物科

Biology (1)

This weekly series serves as a revision course in Biology for the H.K. Certificate of Education Examination (English), 1973. The Biology paper of the examination comprises two main sections:- (1) Multiple choice questions; (2) long questions of the conventional type.

For the section of multiple choice questions, you are required to identify the correct or best answer to a question or a state- ment from a group of alternatives Generally there are four to five. questions appearing in the conven- tional section, which you should take a longer time to answer each of the question you select.

In order to obtain maximum marks you must read through the instructions given at the head o the examination papers or on the cover of the question book very carefully. Make sure that you follow them before you start to attempt any question. Each questic

You

arries a maximum number of marks which cannot be exceeded however good your answer may be, so if you! spend too much time on one questic you are jeopardizing your chances of gaining marks on others. aust read the question with suffic ient attention and grasp what you are asked to do, then make a sum nary of your answer before you start to write out the answer in Full; if the question is set in several parts, you have to answer the various parts in the order in which they occur in the question” which you are fully familiar, you then proceed to give a detailed lescription but keep strictly to the question.

To sit the examination of this subject, you should go throug the whole syllabus in preparation for the examination. A note on the 31ology syllabus of the H.K.Certi- Ficate of Education Examination (English), 1973, is made as the following headings:-

General

(1) Characteristics of living Organisms.

(2) Protoplasm, plant and animal cells.

(3) Differences between plants and animals.

(4) Cells, tissues, organs and. systems.

(5) Conditions necessary for life

II. The Variety of Life

(1) Plants and animals:-

green alga)

Amoeba (a simple protozoan Apirogyra (a filamentous.

fungus)..

Dryopteris.

and Honey bee.

--Hydra (a coelenterate)

Mucor (a saprophytic

tems e.g. Cyclosorus or

Insects e.g. Cockroach

Fish (a local bony fish) Frog (an amphibian). Rabbit (a small mammal) Two local plants (a herb and a dicotyledonous tree

2) Morphology of flowering

plant:

(3)

Root

Stem

Leaf

Flowers

Fruits

Seeds

Anatomy of mammal:-

General arrangement of

the internal organs.

function

Muscles (structure and

- Skin (structure and

function). Es

Skeletal system

Digestive system

Circulatory system

Respiratory system

Excretory system

Nervous system.

Sense organs (tongue,

III. The Basic Characteristics of

Living. Organisms

1) Importance of water:-

Cells and water.

Osmosis and diffusion.

importance of turgidity water and land plant

transpiration).

- water and mammal blooa

and lymph systems)

(2) Nutrition:-

food and life.

plant nutrition (photo-

synthesis, and mineral requirements

- animal nutrition (ingest-

ion, aigestion, absorption, assim-

Good stuffs and diet

ilation and egestion).

calorific value and balanced liet).

Good tests.

(3) Respiration:-

mammal.

plants.

external respiration in

exchange of gases in

internal (tissue)

piration.

Cermentation, or glucose solution by yeast.

(4) Excretion :-

elimination of waste. products of metabolism in mamma

-excretion through the

lungs and kidneys.

-working of the kidneys.

(5) Homeostasis (régulation of

the internal environment; of the body):-

-regulation of water and

mineral salts by the kidneys. - regulation of body temperature by the skin.

hormonal control.

(6) Support and Movement :-

Skeleton (general funct-

Muscles and Movement of

lou, bony joints).

the body.

7) Plant and animal benaviou

(detecting changes in the

environment:):-

Sensitivity of mammals (to chemicals, light, sound. gravity,

and contact). Irritability of plants (response to light, gravity, wat and physical contact).

- Nervous co-ordination (Nervous responses to stimuli).

Chemical co-ordination. (hormones, in mammal; auxing in

flowering plant

(8) Reproduction and Development:

(1) cell reproduction

(mitosis and meïvsis (11) Organi su reproductior

Asexual reproduction. (binary fission bulding, sporulat -ion, and vegetative propagation

Sexual rerroductiof (pollination and fertilization in flowering plant; fertilization. and embryonic development of mammel

(9) Inheritance:-

basic ccrcepta inheritance of a single, pair of contrasting characters.

heredity and environmen

IV Tife and Environment

(1) Relationship of plants and animals to their environments

(physical and biotic environments

(2) Cycling of Materials:-

interdependence of plants

nd animals.

good cycle and good craan. -carbon cycle.

nitrogen cycle.

(3) Parasitism as a mode

life:-

Dodder (a plant parasitej Tapewarm or Liver fluke:

(an animal parasite),

中文大學學生會

下天

年

日六廿月十年二七九一曆公年一十六國民華中

四期星

浩化八週學

「VR期录十一月八日,投入場。 Ord·SERFE# E-FEKETO./RPE1E-33 一磴院,曹明無價由四元一各界入士加,欲何支持,由十一月份起 賞及首映蓉片「大國民,地點是陸俗常,系 純,轉動育司拼 94KSER284 KESED-S EXTUREKEKE? XECTO ESKESTESER

JESKARASUS, REMENI HERKKE• C FEKZEKA SERI CHE

·術的無越,故以「於營胱出。

年,在提高一般人到女化」十八日隨上七時三十分 率越高媺摄研習, 七化娇],潋得幽香麥那」「就」——中预音 斑無節會百名爾濶各科 浩姓小月香助人。樂及舞靜中效,音英比同門會龚决定商們所使 八日至十八日行「文』,對在關佧定舉行。 王娟剪商務的 「文化節」之目的变,優著將於十一月 光表特漢文師孤同源 四年船高,特於十一月,有攝影擾,語話劇 第二訪出四 「學生和做誕視成立六十一校發育館外行,此外股感。今首屆中椐带饭 特码) 香褫大學」露天綜合性節目,在本,既恐不足,按自不

份節目歡迎各界人士參加 以「視、聽、思」爲主題 大部

港大學生會慶祝六十週年紀念

下月初舉辦文化節

編中大學生歌集 電捲类,

BORANEKER

ONTENESS21 S

想生图術部*尔進蘇一盘有笑她者,可逃向中「認知 (EIS)XXS BE÷4DLCE%

有興趣者可向該會接洽

公司矧钱

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·公教大學校友

「色是金屬非文歌曲、附

ZEE-RIDE-

定下月開課

2093(EXC 八日下午六時,假九 【敦大西校友協會,索状

13= ESSAIR İNKARIKE FEISKPASAE · 百七十百,全部附以被連斯只得子狀,而每日有號碼助興,做迎修員 【紊,翎饉歌曲等共三流蒩爲幽情調處,舉行自助脆愛小米 D. WHEREOF SKENEZERES

本維國陰,山河特 育

ARAK KE KERKCETÉN

1978

上

1 F

期六日下午老林至发

−(12+||2)+7(x2+11X)−18 + 30

中文中間會考試題預習專欄 (x+x)+7(X2+11x)+12

數學科

張正邦

在中學數學課程裏面分有高級數 學和普通數學前者有大代數三角与 及解析幾何,後者有算術代數、幾何及三 商等依我本人的意見認為代數一科最 為重要,其中的運算方法,可應用於解三角 幾何等問題,且有些算術應用題,若用代 數的運算方法:會覺得易於列式及求其 解答而代數科東面因子分解佔很重要 为一部份,不論解方程式,化商分式繁分式 求最高公因式或最低公倍式等等都少不 吃了因子分解的步驟,所以我在本欄先討

渝因子分解

1 OF 10X - 17x4 +642207

10x2=2x-5x6y=24:34

x 101 672 y 6y.

2 x

5x

-67

· -12xy - 5xy = -1724

X 10x = 17x4 +64 = (2x-4) (5X-64).

151 = 334 yr + y + 1 Z El 7. (38) 4++42+1=y2+242 + 1-y2

=(y2 + 1 2 y2 = (y2 + 1+4)(y23⁄4i−y)

(y2+ y + 1)(y2= y + 1)

= 8 x4 -3x y2+ y2 ≥ 0+ }4) x=-3x2y2+ y2=x=2x2y =+ y2x2y

= (x2=y2) = (xy) == (x2y2+xy) (x2y2xy) = (x2+XY-Y2)(x2-xy-y2)

alw >4 m2=3m2+3m-28217. {1}) m3-3m2 + 3m −28

m2-3m2+3m-1-27 —(M-1) —33 = {(m-1)−3][(m −1)2+3(m−1)+32 = (M− 1 − 3)(m2=2m+I+3m−3+9)

(m −4)(M2+m+7)

{]ź » }}} m2+4m2 + 10m +12m+y 18) M2 + 4m2 + 10 m2 + 12m +9 ={m2+4m23+4m2)+(6 m2+12m) +9

- (m2 + 2m)2+6(m2‍+2m) +3= (m2+2m)2 + 2 (m2+2m) 3 + 3°

•(m2+2m+3)?

1517. />§q x4 +4 20+. HF) X -x2+4x2+4 −4x2

2-(2x)?

(x2 + 2 + 2 x ) ( x2+2−2x) (x2+2x+2)(x2-2x+2)

15ft » pf X" +X2y=+Y+ 2 F3.

$B) X4+x2y2+y4=x++2x=y2+y4_x}

(x2+Y2)2 -(XY)=(x2

BB + Rx = x) {ch + RX+2X)=(hx-zht zX)*

15] A 384 (X + [[X−2)(x2+!!X+9+3

201.

|0}})(x2+10x-2)(x2+1|X +9) +30

(x2+ ||X+3)(x2+1}X+4)

[b]2 3 Bf 4x+4x8+Y+4X+24-3

之因子、

4x44X+4+4X+24-3 (解)

=(4x2+4xy + y2)+(4x+2y)-3 (2x+y)2+2(2x+y) −3

=(2x+y+3)(2x+y−1)

11+ 25 m2+nt-xt-y4+2min +2xd ($4) m4+n4_x+_y4+2m23n2+2x2y2

-(m^+2m2n2+1o)—(X4−2x2y2+y4)

n2+x2y2)(m2+n2=x+y2)

1+ m2 + n2)(-x2+ y2+m2+N2)

15111 2294 X-9x2+8x=722 Bà

(PP) X5-9X3+8x2-72

= (x5—9×3) +(8X - 72)

X3(x2 -9)+8(x2-9)

(x2=9)(X3+8)=(X=3°)(X2+2,

(2+3)(X−3)(x+2)(x2-2X+4)

例12.分解:x33X2+10%+24

(解)用綜合除注。

13-10 +24 2

-1-12 + 0

+4 +12

1 +3 +0

24

$7 x3-3x2-10x+24

14

2)(X−4)(x+3)

151 13. X-39X+7028+ 解)用綜合除法

1 +0 -39 +70 ₤2

+2 +4

70

+2 -35 +0 |5

+5 +35

+7 +0

6X x3-39X+70=(x−2)(X−5)(x+7)

151 14. 537 X++ 4x2Y2-24 +3 214

+4x=42_24+3

(x*+4x2+4)-(y2+24 +1)

x2+2)2 = (4+1)2

· 2 + y + 1)(x2+2-y-1

= (x2+y+3)(x2 - Y+1).

第一次預習題

分解下列各式

1. 12x2-11X-5

2 15x2 + 22x

३.

x2+4x2-

4 **+647

5. 4x2-12x2+29% −30x+25

6__ (x2+3x+9)(X+3X−2) +30

7 abx2+(a2+b2)x+ab

8 x2+2xy-842+2x+144-3

4x3-3 x − 1 X-4x+3