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̇育教儒 ® 第三第張四第日五初月二十年多辛歷夏 WöH KIU YAT PO
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四期星 日十二月一年二七九一冠公年一十六國民望书
HALL
1972
中文中學會考試題預習專欄 數學科(十二)
·張正邦
+(a2-b2) coc
~ (62 (3) (62+(2= a2)+(ca)()
第十一次預習題解答!
1912英文中學會考試題預習專欄
Við AXEME
生物科 (十二)
BIOLOGY NO.
Study the following Biological TermS carefully and try to understand them:-
and try to
1.RADICLE The root of an embryo plant
within the seed..
2.HECEPTACLE The base of a flower, ta which all other parts of the flower are attached.
3.RECEPTOR A structure specialized for
the reception of sone parti- cular kind of stimulus Bigr eye, ear.
-
4.RECTUM The terminal portion (or end
región) of the alimentary can-
(gut or enteron.)
15.REFLEX ARO Aseries of neurons tranex atting excitation for ner vous impulses) successively. from a receptor through, the central nervous system to an effectory comprising one. sensory and one motor neu- ron with or without one or more intermediate neuronse (concerning the involuntary actions, e.g. the knee jerk.)
6.REPICLUCZION. The production of organ-
isms from those already living
7.HERMAPHRODITE A monoecious animal,
bearing both testes and ovaries, e.g. Hydra, Ear tirworm and snail,
OPHY IG King of nutrition found
in green plants, which utie lize light energy for syn- thesis of organic matter. (i.. able to carry out - photosynthesis.
9.HOLOZOIC kind o
10.HORMOTE
of nutrition found in typical animals, which ing➡ ent orgaia food.
An internal secretion, having) some specific effect on met- abolismy development, OF TеB- pense of the organism or some particular part of it. secretion of an endocrine gland that affects vital.p body reactions in higher animals.) Hormones are secrations passed into the blood..
11.HYDROLYSIS Chemical decomposition or breaking down of a subeta noe by combination with water.
12.OVARY The female gonad of animals,
in which the egg cells are.. formed. Ovary of a flower contains or unfertilized seeds, 137ÖVINICAZ the duct which carries the
14.OVIPAROUS Laying 078%; either before
or shortly after they are førtilized, (Compare
yiviparous.}.
15.0YULE A small structure (e.g. inside)
the ovary of the flower) that. develops, into the seed after fertilization.
10.HYPOCOTYL. The part of an embryoniq
seed plant, below the point: f attachment of the cotyle done. (Cf. picotyl)..
17.INGESTION Process of taking food
into the digestive cavity of an organiza.
18.INSULIN An Internal secretion of the
pancreas essential for the normal netabolism of carbohy (internal secretion
draten.
hormone.)
19.HAEMOPHILIA A disease characterizea
24.ORDER
Internal, tissue or cell respir ation, is the chemical reation from which an organism 'dervies energy. The energy is used for the activities of the body, •£* transportation, absorption, del1 division, activity of muscles, many chemical reactions inside. the organism. Food is consuet.. or broken down during the process.
If oxygen is required for the process, it is called AEROBIJ RESPIRATION. If gluOOBB, for instance, is being used as busin
for aerobic respiration, it is oxidized to carbon dioxide and water.
Energy can be liberatau by the break down of substances withe out molecular oxygen being con cerned in the reaction' this is known as ANAEROBIC RESPIRATION, e.g. breaking down of glycogen to lactic acid in vertebrate muscles or glucose to ethyl alcohol and carbondioxide by yeast. Many organisms respira anaerobically for sexs time
when their supply of oxygan is. insufficient for aerobic respir- ation. A few bacteria are stri- ctly anaerobic, žve, they do not aced free oxygen at all.”
A taxonomic group, between clans and family.
(Kingdom-Phylur-Class - Order-Fami
Specia.)
Genus
25.ORGAN A localized part of an organ-
Len, specialized for some part icular function, and usually composed of several types of tissues e.g, eye, ear, stomach. (Compare tingue & system.) 26.ORGANISM An individual living thing.
27.OSMOSIS:
↑ SOLVENT or water between two solutions- separa¬ ted by a semipermeable nombr-
Puestion I
ane.
True (+) or False (0) statements.) (Answers at the end).
5. C
10.
In a tree transpiration occura only in the leaven.
Animals take in oxygen but Pla- nts do not..
Fungi and Bacteria are non- green plants which, as a rule, cannot perform photosynthesis, Anaerobic respiration does not involve the liberation of heat All the calls in a green plant
of photosynthesis.
The direction of growth of the
hoot is not affected by the force of gravity.
Any curvature in both the young shoot and young root takes pla os in the ragion of maximum growth
The direction of the growth of the stem is, in general, indir ferent to the difference in con- centration of moisture in its "envirorment,isNE KARA
The direction or groven or the root is unaffected by the light under
circumstances
Only the water molecules pass through a semipermeable membrane and the solute or dîn- molecules cannot. solved
Camosir only occurs in the pre- sence of a semipermeable membr ane but diffusion can take placi in the presence or absence of such a membrane.
12. () Only the root-ha
by poor clotting of the blood; results in uncont→ rolled bleeding after injury.
15% C
20.HEPATIC Fertaining to the river.
21.HERBACEOUS
12. HISTOLOGY
Plante without woods (usually killed to the
ground by front,)
A phase of biology dealing? with microscopic structure, a subdivision of morphology. 13.RESPIRATION This may be divided into
two parts, the external and external respiratione,
(1) External respiration: This inol- udes BREATHING, .5. pumping air in and out of lungs, or water Lover gills; and taking oxygen
from the environment and giving (off carbondior:
can absorb water and dissolved minerals from the soll,
The phloem tissue is user to conduct water and mineral salts. up the stem.
whzon
The root also a 12
is later transported upwards to the leaves for photosynthesis. The plant cell will become tur. gid or firm when water diffuse into the cell.:
The plasma membrane of a cell is, a semipermeable membrane Question I Aneversi—
(5)
(6)
[(2) 4) (3).
((7)
(49
(9)
(10)
(13) 0- (14)
__(15) (+)____ (16)
Question II:
Pick out the app the brackets.
words
at
誠証下列各等式。
(!) tan A= a sing
C-αGB a
証、右端一(0)
zac
(-a ( a2 + c2-b2)
ab
a2+c2 b2 2c2a=c+b
206
== abc (62 c2)(b2+c2=a2) + abc (c2ay
*(c+a=b) tabe (a=b)(a+b=c>
=abc [b2=c=a2b2+c2a2+c2_a_b2c2
a2b2+at_bt_c2a2+b2(2)
abc 0=0=$ (10):1-) b) 2 JAY? #4 Jxy
20
SMA Cos A
·Tank ME
266
左端
(2) tamB
tan C
a2-b2+c2
SMB
証、左端
= 右端
SMB COC
SMC COB
(3) (b+c) CoA+ (C+a) CoB] (a+b) (r.C
a+b+c.
tacotta các
(clop+b6c)+(cCon+aCc)
+(acob+b CoA)=a+b+C
三右端
Cont
Bx+ £x = b2=c2 b2+c2_a2
c2a2 c2+α= b2 a=b2 a+b=c2
aca
2ab
=2abc [ ( c = a*) (C2 + a2= b2) + (q=b*)
*(a2+b2-c^)+(b-c2)(b+c=a2)} >aic[ c = a = b2°c + a2b2 + a=b-ca" tbc +b-c-ab+c2a"]
0=石端
Zabc
(5) a2+b2+c2=2(ab GoC+bCC@A
+ CaCOB)
Git= £35=2abcoc+2bC CoA
+ 2 ca cos +(2-a2) + (C2+a= b2)
= a2+b2 + c2 =
±
)+(63
(6) (b2 C2) Cat A+ (c2 a2) CotB
+(a2= b2) Cot C
b.
-(62-c2) Col + (c=a) (
The skin of the frog is (Tendryby
SMB
2. wet which (3. can 4. cannot)
be used for breathing.
2. In the from the hand of the fore-limb bears (1 three, 2, four, 3. five) fingers (or digita), while the foot, contains (4. three, 5. four, 6. five) toes (or digite).
The elements, sodium, chlorine and silicon, (1, do not play any, 2. play) an important part in the vital fun tions of the plant.
In general the (1.hydrotropic, 2. geotropic) stimulus has a stronger effect on the growth movement of a plant root. (Can you demonstrate this with an experiment??
The (1. auxanometer, 2. potometer, 3. klinostat) is an instrument used to nullify or eliminate the effect of light and the force of gravity. the growth movement of a plant.. In the experiment using different culture solution to determine the Ossential elements required by a ./ normal growing plant the following precautions should be taken.
The jars used should be blackened to sxolude light, {1.preventing
12 3/8272 × 4/x3 =2 770).
(122√ =) 12 2/17 17 6√x7. 14. 6√x7 = 22/77 - 3/72 解
3/3/
3xy
(11 =) (2√3-√TO ) ( 3 √6 + 2√3) BE (2√3 −√70) (3/6+2/E)
-6√18+4√15-3/60-2/50)
1872
8/3-2/15
6/15-1015
(15:√ @) 22 $$ 15/16, 16 53 0921.
2LCM=30
30/256
30
(all 2) 129 +/ab = √ab + √26
# Jab Jab Jab
x afb2 +(ab afbox atb
− q* +F-‡ × b*+t-§
a = b
= ab
第十二次預習題
·孔箱下列各根式
232√35 × √65 391 3 a3 3 ab
man
= √(a+b2c-Ja2c-√6c
(√a+Na+D (Ja-Ya+1) 7.用正指数而不用根表 8.不用分母以可能之最商武表
~(6+0=1). a2(b+c)
growth of Algae on the glass walls, 2. to prevent photosynthesis in roots.)
1. To renew bulture solution (1.daily, 2. weekly, 3. monthly), an some
minerals are used
a.up.
dii. The solution should be aerated once every 1. day, 2. week; 3. month), to replenish the oxygen used up by the root. iv. The jars, should be placed in
(1. normal daylight, 2. the
dark).
The individual plants used (1, must be of similar, 2. can be or different) size and, kind.
(1. Distillea, 2, tap) waTNI should be used in making the culture solutions.
Wash jar should be (1. completely 2. 2/3) filled with the culture Boution.
Question II Answers:→ (1) 2, 3,
(5) 1,7
(iv) 1
(2) 2, 6, (3)
[(6) (4) 1
(11) 2) (111) (vi), 1, (vii)
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