1971-05-30 — Page 10

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頁二第張三第日七初月五年辛夏 WAH KIU YAT PO

英中會考數學A(三)試題

CHONG KONG

CERTIFICATE OF EDUCATION EXAMINATION ERILISH›

Candides

cenù sảy, CHRIE quietions I Secto

manse di Centre

The, given diagrami sic hại necessary stáwn to acum

SECTION (40)

For questions para “the box opponteto in portaci andai ana or questions - par zie Answer if the spaces provided on the question papei Thị question papima muso de canded in any working chày th suonering the Jaar bew pages of the unjwer Booster wil dor de cucina Quartum mið)' uiouta be dona a The beginning of your shower boor

47 markar

490) is any triangle, it's point X ta equidumuri trompa una Cana meno equatiini trom Al-qadi

To'ché intersection of

the check ventre Bad NO THE DUNCIÓT DELACA

The-crete în 10 is drumeter and the bouctos of LAGA:

use perpendicular duectors of AC, una DC-

the perpendicular "busctor of AC. and the bisector of LACE.

the Diaectors of LBCAMS LBAC

(7 marks]

gure 1.

which one of the following statements mGAT

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1971英文中學會考試題預習專欄

日期星 日卅月五年一七九一三公年十六國民雄中,有致僑犟

(11) When ammonia is passed over hooted copper oud,

Colourless liquid and a colourless gas, drops of a

±& SUNLIGHT PRESS

化學科 (十九)

CHEMISTRY

LESSON TWENTY-NINE

A reducing agent is a substance which brings about an increase in the proportion of the electropositive component of the substance, for instance by adding hydrogen or by removing oxygen or any other electrone~ gative element or radical such as chlorine or sulphate

(b) (1) A slow stream of dry hydrogen is passed through a horizontal test tube containing a layer of black. copper oxide, and is lit at a small hole at the end of the tube after the air has been displaced. When the tube is heated gently, the oxide glows red hot and changes colour rapidly to the red colour typical of actallic copper. Steam escapes from the hole and extinguishes the hydrogen flame.

+ CuO » Cu + H

Since hydrogen has removed the oxygen from copp

oxide and thus acted as a reducing

英中會考數學A(二)答案

MA PREMA FICS SYLLABUS

PATULL) {Cóntinued)

reddish-brown residue are produced; The pit can be identified as nitrogen by burning magnem um in it

and adding water co the residue, when aponta will be evolved. The liquid, which turns anhgirout copper- sulphate blue, is water, and the residue must be

* NA. 2013

Ammonia has acted as a reducing agent because it hab removed oxygen: from copper oxide.

Hydrogen chloride acts as a reducing agent, when si the form of hot concentrated hydrochlorideid:it removes half the oxygen from manganese diorite in the preparation of chlorine. The manganese monoxide foratu fs immediately neutralised by excess hydrochloric acid

2HC1 • MÃO MD + 1,0 + €1.

20140 MIC

(iv) When hydrogen sulphide is passed through yellow..

ferric chloride solution, the solution becomes clouay due to the formation" of finely divided sulphur, on heating, the sulphur coagulates, and a pale green solution of ferrous chloride is obtained:

28C1

+

In this reaction hydrogen Gulphide acts as a reducing agent because in the ferrous chloride which as formed. the proportion of the electropositive component iron is higher than in the original ferric chloride.

SABC

Mora

an the centre of cache ÄBEL

Penguins, "bantajon

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mi rigure 5.100's the d'ameter of a circle and

48 "la #chon parallel to DC W Cosicolate CB(D

marker

figure o de circles whose centrem an "B" and

couch each ninay and placi vouch carer santr *.internally (AZADƏN GVAČ •Nim, and

mour to the

'ATAWIŁ, LEAD •

48 a partiler to CD OF WOD = 14 an. Gable am and CD • •'an: Caieutia cha

SABU

A dienen perpendacular uni

izioni Of · produced ni, é Cascurate, LAEI,

́ooing

SECTION

160 கூ

TURSKAS, ALOpe in, the, segumeni munde gran.

presentation' av materjal

Scharwan stat

stasis will "ba: sequcted for poor

in Figure was squad Sticles altérsaçlar in so

w's stringere une austing "ZLE GAME AN

Địcha thelatheist € ..

- polár

е

ngureni vransversal: yo "zuti sa paraber

sincer (ste, drawn in sauch each sluse chrea tubes as shown the diagram – Prova PORS

(1) ke

and

comparing:

i) the required

Let

and C be the roots of the equatio

then the roots of the new equation will be

pne g

-

applying the Sine FormALLS SALIB

Sán ADB

0.3711

ADB

-23:47

BDE

LABD

BE

70 Ain BOE

Area of the

130

801:

0.6186 sq. em.

The

rise of wate

(3850

Figure 10-PX acu·LOPR and PY bisects RPS. Ma the mud-point of XY

figure

Haric

Pues on the circle diameter XY Fatherwe prove that

(a) In CABO,

Bor

listine

din 30°

(11) for only one triangle,

His right-angled [1110 o triangle will

(b) By using the Cosine Formu

for MABEY

Cos BAC

BAC

Cog CAD

/CAD r

Therefore

Zsınë - ♬ sin 8.

2sin e

sinetz •/3)

1.2se

¿sin

Sin

The required

Cat 37°

AB

0.8660

Figure

rectangles.

LAPR

1500 Cor 679;

1500 col ?

bmarks!

KBCD 15 « trapezium with parallel to DC. Share the mid-points of BC AC

BD and AD respectway Prove that PQ =

shai PORS 18 e injoki lina

412 marks)

Pin, figure à 178C EF and De ara parallel

8. LDA

If the was of GALE la i squar unit' calculati

(i) the arts of ABEC

(the stop of GEAF

(9 márks)

to figure 12. ARB is avare of a circis radius

QA OB PO·ure cangonta a 48 wid

пересечнит ¿POO

00 cm

(i) Fund PQ us resma në

190°: PO

Hence otherwise and the raise of

fal 14 marks)

DOCF, é mediana-

“prove (hai, SABC, a moscales-

19 marks)

APR

ing

spot.

#point Inside the circ

the circle and, Prove that

tre on the same site of

CARR

mangle inscribed in

nice the angle bisectos al angles 46 and

kerter

and niest the oppoute aris WT

19 markat

DE CONTINUED)

figurë

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