1970-06-12 — Page 25

ERENCE

育教僑華莫三第張六第日九初月五年戌庚屬要 WAH Khi VAT 報日僑筆 英中會考現代數學(二)答案 ·高鑽獎。

HALL T-PO

五期星日二十月六年〇七九一曆公年九十五民警中

中中會考高級數學(一)試

本科因不在本報會考補習專攔範霋之內,故並無出答案,現豪亞洲 文化學売高鏡葵先生義務代答,雍惠選考該科之間學匪样,謹此致。

(兩小時光

FICAT

PICUTE

3x+4+5=50p

吳中會考現代数()答案

К к ко

Stup Key. .

若p為任意實數,求,

『之最小借

HK CERTIFICATE OF EDUCATION EXAMINATION

I REAA??2+as+1=02#Ro· 8; 5 IK 2+1

02 #

只邁英文書院電訊工程溉管馬嘉荣报:上有一校監林與銅紙園。《上左,校長陸永炮報告赘

1970

MATHEMATICS SYLLABUS B PAPER I

Find the 2x2 Matrix A such that

A ( 2 2 ) [ ( ? ? ) + ( 6 =))] = (! ;)

(b) Find x, y and z such that

(89)-(649)

lution

(4) A (5)-(!?)

A- (45) - (++) 2.HS=( 108 day boy)

Find the locus in the I-y plane so that the

tistance of each point of the locus from (2,5)

is equal to its distance from the line Ly

{(x, y) y+2=0; x, y ER}.

z Ziÿ

Find the intersection of the line 60=1127, y}

X,YER} and the locus.

What is the geometrical meaning of your resuel

Find also the line passing through the

and perpendicular to the given lin

Solution

Let p (x, y) be a point

on the locus

1 = √(x-2)2 + (y-3)*

dad

(given)

d (2-2)2 + (y-3)2 = y + z

(2,3)

pexy)

⇒ 22-4x+100+9=0 ( lowes)

{ 2 == 24 107 +9=0

5.5. { x=7;y=3} (point of intersection)

(Da2 +2+2 +8 21

(1):分解30~31至+101-x您光

5 21

30-31 10! —r

爲部份分式,並は、之!課題問之以求。

之係數。並派出此問式和之允許值之界限

某幾何殺數之公比圈,其慈項焉首痕的C倍

Blog

3.000.000

log C

(j)某城市人口每年依幾何級數培加。該城入口在1965年時屨

,在1970年時推至3600,000,求精嬷间級數之公

816371975 THARLAD

已知{}

+8

(f) 證明f(x)恒小於岁,

(ii)求,集之界阻便!)<2

(六)(g):x ] 解方程式:

V3x-3+ log; √x-1=2

(5)利用數學歸納法證明當n為正整數時,

1月篱13之倍數。

{5},同學9人旅行,分乘大小汽車各一端,大車最多可載个人,

矗多可載4人。求分親之辦法有顯示

J - £OZAHMABCD EF GHAE BF

HD各7cm,其他各邊均4cm。今使長方鐵之對角線AGA地面 垂邐而A在地上,

il E · F · G · H&RROZA.

1. THAB PLERIMIZZA »

(九)證明tan(一年)

KB tan (~+ * } – tam t

(十) 瓦輸出下列兩方程式之圖線

cos

~2810 (+3)

並利用該兩圖線解方程式

cos 3 sifs -com a

AM-1-(1)2-12 in

-ABC-

中中會考化學科答案(練 ) 林錫衡·

X203

XH3.

HXO3

XH3是還原田×所表現的氧化數在各 種化合物中最小當進行氧化還原作用時 其氧化數只可能增高無可減低即本身氧 化故為還原劑。

HXO是氧化形因×所表現的氧化数在谷 種化合物中最大當進行氧化原作用時 其氧化數只可能降低無可增高即本身還 原故為氧化劑。

還原作用例

亞硫酸溶液

5 H 2 SO 3 + 2 KMnO4 » K2SO4 + 2 MASOR

+ & H2 5 Q x + 3 HO

(i)氣化亞鐵溶液

求在0與2元關之債

1 mid-pl. theorem

AM-AN-22 ‚MN-₫

refer to A ABC

C-ICH-Z

uper to A OAH

2 FeCl + Ck → z Fecla

(ii)亞硝酸鉀溶液

5 KNO2+ ZKMnO4 + 3H2SOK

SKNO2+ K SQ2+2M#501+3H:0

A是硝酸鉛

B是硫酸鋅

C是硫酸鉛

D是二氧化

G. 是硫酸鋇

E是氧化鉛

F是硫化鉾

Pb(NO3)2 + ZnSO4 →→ Zn(NO3); + PbSOù &

2 P60+ANO2↑t QT

(2)Z Pb(NO3)2

(3) P6O+ZHND, Pb(NO3)[557%) + H2O (4) PbO+ H2SO2 →→→ Pb SOL (**) + HC (5) H25 + £n SO4 H2SO+ ZAS

(6) Zn50, + Ba(NO3) → Zn (NO3), + BaSON!

the locu

parabola and cuts y=x-4 at

one point.

slope of yox-4 10/

x+y=5 (neguired)

ABC is an equilateral

A. AO is I to the plane

Cano-714

Its angle between the planes ABC

(1) Evaluate Si. Sz and S. from the following glow

chart (START)

Read not

[ Tn == Ta-1 }

陰極

(6)

陽極

(鉑)

ABC M, N are mid-points.

of OC, OB respectively

If M (AB)= M (AO) - 1 inch, then

(8) Calculate the measure of the sides of DAMN,

(b) Calculate the measure of the angle in degrees

between the planes ABC and OBC.

Solution

(a) refer to A OAC

Increasi

n by ans

Record Sa

→STOP

The sum of the digits of in two digit number

of base 8 is 108. The number formed by

reversing the digits

by 168 Find the number.

7, - 2 % -2 2-1. 5-

the number

解

富童為 1,008

稀硫酸

一克當量 在 NTP 時枯

2.8升合法克當量=克當量

在硫酸亞鐵槽中魔得鐵

•克當量=x雙克 =2克

在硫酸鐵槽中應得鐵

56

43

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