1970-04-09 — Page 23

REFERENCE LIDRART

94PR 1970

育教僑頁三第張六第日四初月三年戌庚歷夏 WAH KIU YAT PO

報日橋

HALL

四期星 日九月四年〇七九一曆公年九十五國民華中

#

僑

#*%$#$@@$#$%$#$%$#$%$#5%5# 5%$#$%$# 5%$# 5+£# 5%£## $ %$#8%%£*****

170英文中學會考試題預習專欄

経道英文書院主編

生物科

(廿三)

BIOLOGY (23)

Answers to une questions or last wee

中文中學會考試題預習專欄

數學科 (廿三)

喬仲强。

1. (a) Nanos or the parts from 1 to 98

écapula

2. stern-VAN

patella

famer

5. fibula

8. radius

6. tibia húmer

第廿二次預習題解答

1) a, b, c, d my H.P. (1938), *EK

3(a−b)(c-d)=(f-c) (a-d).

E) ♬ a, b, c, d &XH.P # a I Ċ à A AP

誤其公差為x,則女一

=**

三式相加,

#(1)

ad

2-3x=-4---(4)

(5) *(2),

b(3) cdx--(7)

(5)х(7)х3.

·(6)x(4),

3(a-b), (c-4)=3x2----8)

ab

(b-c) (a=d) — 3x2-----(9)

bead

**(8),(9), 3(a−b) (c-d) ___ (t−c) (and)

abcd

abcd

• 3(a-b)(c-d)=(b-c)(a-d) 2)設A為两不等正數ayf的等差中项,

•»7, H1⁄2 384« qz, E A>G>H®®

G 為等比

*A DE of (ab+cd) (ac+fd)=40&cd

Ŕ (b+c) (c+a) (a+b)=8abc

SE) & a, A, b✯ AP.

RA=a+b,

XQ a,G, BAGp. th

JG a, H. P & H.P. t

・

(1)~(2),

& ño 4 lat (2) a π IMAP

H

A-G---Jab a+b-2ṛab (a-B

@ a, b 7 #8 # (fa~17) HE & EXC, the A-G>v

(1)x(3),

A>G (不等量定義)

AH = athx da

每二年(>1,因上证 A>G/

(±) G>H T&Q,(3)**** 1 *ZZLAZ

BA A>G, B

The

ulna

type of joint present at

(1) X Ball and socket joint

(11) Y Hinge joint

(0) The six functions of the skeleton or a mannas

are 1

(i) to form a framework to support the body

and supply regions for muscular attachment. (ii) to protect certain underlying delicate

organs such as the brain in the cranium. (iii) to give shape to the body.

(iv) to form a system of levers by means or

which the body can move from place to place.de

(v) to manufacture erythrocytes (zun vLUDI

corpuscles)

(vi) to reserve calcium and phosphorus in the

bones of the body.

The five types of vertebrae making up tha vertebral column of a mammal are:

(1) servical vertebra

(ii) thoracic vertebra Lid

lumbar vertabra (iv) saoral vertebra.

(v) caudal (coccygeal

State four external features in (a) a fish, (b) a bird, (c) a rabbit, which you consider are adaptations of the animal to its environment,

Anawe..

(a) Azian --

姊 A>G>H

afted fatcd.

actfd

-210gr. Rb+ca >&fabed.

將此两式相乘

A bird

(ak+ed) (ac+&d) >4abcd

The starea att > Sat,

(f+c)(c+a)

=***, (f+c) (c+a) (a+b) > √a^8"C",

•(f+c) (c+a) (a+b)>8abc.

(3) = a, u, v, f & MP. X a. x, y, & & AP.

(a) $x a,

(AF) □ a u, v, bm H.P., tk

設公差為4, 則

-=d,

三式相加 3d=+

X(2) *

Saf

yu- ab.

(BE) A

Jat

求証

A-P.,設其公差),則

-(5),

-(7)

・代入(5),得

ཨོཨནིཡཏིསྶ

Ha(7) 18 y=

-= Зав

yu ate

4) = a, b, c #

atat

caf

Q.E.L

AP

18 Scales ara vony plates in the skin, overlapping each other and give a protective covering the bodj (ii) The lateral ----

sense organ to detent ways move- ments in the water.

lii) Fina give stabilisation and control

the direction of movement during awimming.

The operculus is a bony structure covering and proteating the respiratory organs, gills, and playa an important part in the breathing mechanism.

(1) hings are nositide fore-vings with

a large surface ares provided by feathers for flight.

(ii) Feathers protect the skin of the

bird and form as a fan to uphold tho

body with air underneath so as to support the bird in the air as well as to repel water,

(答)其逆定理亦為確,因為可由上述說明步驟 即可。 註>等差級數各項加同款,或秉以同數仍成等差級數 ( 5 ) 2 # 1 a b Q *+, £*} & 3 H−a, H-bz #ffufið (正)因H為a六調和中項,故H=2(此羊公式)

-(4)

Hof

2(H-a) (1, b)

A.P. EASE OF HP 91 a(b+c) r(c+a), c(a+f).

(2) 1 a, b. c.* H.P. HAP

*y-abc,

又其逆亦真否?

-bc-c

ca, ab #A.P..

the fc+sa+ab, 7 catab abte, fe+ca #A.P. `\a(b+c), &(eta), c(a+b) ✡ A·P. (È££)

(H=a)+(H−f)

a(-a)

Mazh

BG29***

at B

H. # H3 H-a, H= &<=**«*»«. (SES)

́6) T£ A= 2(E2+R)X+(!IRTARIA TIETOR/KTOR

B=2(B+k)x2+(11k−2)x+4,

按A,B两式有公因式式求

值

(解)依輾轉相除法,求AB之H.C.F先以B除A.得商式

£x, ** C=A-8xkx=(k+k)x+(5k−1).

因A,B有公因式,且C為一次式,故C為A,B之公因式再油 因子定理,以x=(5-1)/(龙)代入B式,其值為零 B=2(k+k)(~3~==4)+(111-2) (-5-1)

hem, 2(SR-1)-(1}}−2)(5£−1)+4(★+k)−0

2(25k-10k+1)-(55%−21E+2)+(4k*+4k)=-6

-₤+52=0, -R(R-5)=0

∴厄一口或在一5,但因龙一口時,则A式马绝对項不合, 题意,葉之

答:在一点:

7) #k (a+b+c+d)(bc+ca+ab)=abc+abd+acd+bed,

*** (f+c) (c+a) (a+b)=o

(E)

(a+b+c)(be+ca+ab)+d(*c+ca+ab}

-abc+abd+acd+bed.

(a+b+c)(berca+ab)-abcmo

(a+b)(be+ca+af)+c(be+ca+af)-abc

(etc) (Berca+ab)+c2(b+a)=0

(iii) The bones of a bird are mostly

hollow, and make the whole body isgar.

(1) The shape of the body of a bird is. stream-lined for facilitating flight-

jo) A rábbás — (1) Fur keeps ita body warm" as it forme a layer to insulate the cold air from reaching the body skin of the rabbit.

121)

ear flaps catch #lightest sound.

(iii) Large prominent eyan set at the]

side of the head so that they have a wide range of vision.

Cav) Long hind-logs and short forE-

legs increase its speed by running in a nezies of leaps accompanied by the help of strong and muscular feet

Questions for this weak

I. Study clearly the diagram shown below.

What system of the mammalian body does the above diagram represent?

What is the purpose of this system?

Name the parts indicated by the letters A to H

B

Stato excotly what occurs in D.

In what cavity of the mammalian body are thene organs found?

(a) What do you understand by the worm

"Respiration"?

Describe now air passes into the lunge of a mammal and how the oxygen is distributed to

the living tissues of the body for cambustion.)

(a+b) | (bc+c2)+(ca+af)]=0

(a+b) [c(b+c)+a(c+f)}= 0

(a+f)(b+c)(c+a) = 0.

8) #2 +, 8, r, S ALKAJ, XIE (8−2) + (k−4)2 + (5-2) =(+-5)2

(TE)

=pr, r2=gs, ps=82

·O.E.D.

25−(82¬28r+r2)+(r=2pr+p3)+(5=2qs+gy

+ (12 = 282 + p3) + (s = 2 r2+8 *

{5+52=(-b-5)2 [/b]

第廿三次預習題

(1)0爲两平行线息,m間一定点遇 0作任意直线48各典Lm相交 於A及B. 求证:AO:OB典2選之 直线果团,又能0莫在总,m之 外,其结果若何?

RED

(2)P為∠BAC内一定桌,求遇P作直线 XY與 AB. AC ***XBY M1R XP:PY=3:2.

(3)P為介於0园興£直线間一定点 求遇P作直线峡0园及毛线各交、

A,BI AP=27B.

(4)A,马相離两已知园,作两 平行 (方向相反)之任意半径 AC, BD 試證:CD典AB之交矣恒為一定 只着两平行半徑方向相同時,其 结果仍相同否?

5)A笃介於两外相離之0园,P园間一定奌,求遇

A作一直线各奖 O) P园交於B,C而使 BA=2AC,

6)区知△ABC,求作正三角形PQR各丁百至分别在

BC,CA, ABE. AS ROI! BC