育教儒堂 買三第張六第 日六十月四年四巴座夏 WAH KIU YAT PO
報日僑華
英中會考數學科答案(續) 歐陽絡女
F(x) 2x
a factor of F(x). 15x2 + 34x 24
Remainder thewen
2.-15
-44|2·
H.K,C.E.E. (English) 1969
Algebra
Section B
Suggested Answers
(a) The length of the journey 18 x miles (x> 1)
onarges on: che journey.
The
=
- [+ d(x = 1)]
•
Amount of petrol used for the journey
- дже
The cost on pétrol
-
$1201025) 3
Sum of x and twice y = x + 23 - 5k
i2y Sk
(1)
Sum of sq. of y and the product of x and y
+ xy
(2)
(1) from Eq. (1) 1 x · Subet. Eq. (3) into Eq.(2),
2y
(3)
2
+3(5k. ży).
- Sky
2
4k
Hence, the amount the taxi-driver earne
$ [+ 2(x + 1)] - $ 203-8 [+ C(x + 1)]
+ =
(b) Let x be the no. or studente.
25
y be the cost of running a summer camp
for students in dollars.
max + bz whare a, o are cona tan te
(y) (y 4k)
k = 0 Or y 4K
**
*k or 41
When yk, by Eq. (3), x...• ɔk When y 4k, by Eq. (3), * - 5k
3k
Ana.
of
. 4K
(ii) If x, y, k are all positive,
Then x 3k, y
- K
2x = 38
2(4x).
3K
2.(.)
321 when x = 30
321 - 50a + b
(1)
471 waen x - 75
471-
75a +
(2)
Eq. (2) - Eq. (1), 25a
Subat. a6 into Eq. (1),
150
321 50 x 6, + b
Hence y 6x + 21
21
If x 120, then y□ x 120 + 21 - 741′
Ans. The daily ooet for 120 students is $741,
*2px + 5x • 6p - 2 = 0
(2p+5)x
2 - 6p
2 - 6p
5 + 2D
(1)
30
-2-0
3)x - 2 - 3g 2 За * =
·3 2
(2)
both equations are satisfied by value of x.
équating Eq. (1) and Eq.(2)1
the заде
2-61
5 + 2p
or (2
&
-
·
6p)(3 18p
4 + 220
or 179 -
3 + 4
+ q)
+ 2ą
-
2- 39
(2
• 2p)
- EU + 4p
-
150 -бра
...0
22p
(b)
2
+
x - y = 4
六期星日一卅月五年九六九一圈公年八十五園民鋼中
消僑
英中會考中史科答案
呂思齊、孔頤
(續)
民生困敞,不以賦稅、勞從不均,在三賣,操縱物質,供土地,以至就會不 貫之,宋室當時訒處於內優外惠:國民寒之情况下,座漒圖強與屬有其必要者在。
新之原因
*介出生性强,捐款少容,故未能與辦人合作,於政見不合者,崛辦排斥,滿懷 加白酒香一個:力加反對,因而新解業之間,初由政具之榮,新雨變成團位之
。
乙、政見相左:
·宋代之邊,因循保守,已積習,故守洲大臣以無新法之執行,更宗祖之法 隆,因·俗翁力反對。
王安石設計之新,不然以新於求功,推行過案,又不得其人,以致利 民之政,反成憲民,尤以出,市易,均、保怎諸法,最鶴然攻擊之口實。 TAEMOPAN:
王宏安不能飞的※合作,记得把落入,惟中用多訂之輩,以迎合王安石面
PEREZWUE › EMAILWA».
王安石以政未有成效,欲善狀功以接入心,惟是對、四用兵,均警 失敗,而漈兵又無機檯於東北,吳維數百里。面時連習準,哀鴻遍地。為 借此力加干,以您皆行新政之過,致王安石自動下腳。(未完)
(接第六張第二頁)
英中會考地理(一)答案(續) 劉玉
3k - k .4
K
5. (a) This problem is, equivalent to the compound
interest relation
A P(1
RZ)"
When A the height after the ath rebound.
P.
the original height
R% - the rate ()
Now Am 16.2 (ft.) when n
-
Let h (ft) be the height of the tower,
16.2 - (1 - 4 b()4 - 16.2
h
16.2 x 54
24
632.8 (ft.)
corr. to 4 fig.)
The height or the tower is 632.8 ft.
(b) The man starts with a salary of $450 per monta
and is promised an increased of $20 per month (at the end of each year)
(c)
Which 15 séigon 128ad zor communication.
winter the river is frozen. In summer, ice in
ite apper course thawe first while the lower course is still frozen. Water which flows down finds no outlet, and therefore flooding:. frequently occurs, In addition, the area is not suitable for farming because of ita poor soll and its cold winter and there is only scanty population here. Thus there. 18 a neither a large demand for communication nor importani products which need to be transported to other places. Therefore the river has little value as a. Commi'cation means,
South-West Asis is a dry area where the lang is not productive agriculturally. Previously people who lived there were mainly nomads moving from place to place or else small patches of population were found in places where conditions were more favourable for growing crops, Now, after oil has been discovered, it can be sold to foreign countries and the money thus obtained is used to develop the country in projects such as building roads, railways, and airport to improve ite communi ostion, or to build dams for irrigation purpose so as to improve the productivity of the land, or to establish more public facilities such as schools, hospitals. Through these measures, the livelihood of the people there may be improved to a certain extent.
his salary in the lat year
2
*
5450 x 12 $5400
his salary in the 2nd year -. $(5400+20x12)
= $(5400 + 240)
$5640
•
bis salary in the 3rd year- (5400+240x2
= $(5400 + 480)
$5880.
Vinos 5 & † are tam roote or the equation,
* - (5) (3) »
L2R
• (−11) = 2 and C
& - 5 t 2
+
b_1_0 = 2; (−1) .;_5
The smallest possible values for e
» 2, b. -11, c'- 5 Are
his salary in the nth year *[5400 + 240(n − 1)]
(1) Hence, the total amount earned in n years
101
=
+
b and c
$5400 + $[5400 +
240]
+
$[5400+240x2]+...
++ I (5400 + 240 x (n − 1)]
$[5400n + 240 + 240 x 2 + ...
+ 240 x (n
-
1)]
Check
2x
- 11x +
5 (2x
1)(x-5) - 0
X
- 5 or 3
3. (a) Let x be the given positive number.
Whan 1 is subtracted from 1, the result - x-}
·which 18 4 times 1 (1.8. #)
X.-
3
2
-
JJ - 4 - 0
(x
4) (x + 1)
4 = 0 or x +1- J
X - 4 OF -1
Since the given no.
✦'ve, the answer x
-
should be rejected,
- $5400 + $240×
+ 2 + 3 +.....
+(n
In which, 1 + 2 + 3 + A.P.
the first term = 1
the last term - n
.*. 1+ 2+ 3+
11 - 1
(n - 1)
==== + n(n-1) [1 + (n−1)]= n(n = 1)
+(n-1)] 1) is an
Let A be the total amount earned in n years.
1).
then A 5400n+ 240 x
n(n = 1
2
=
5400n+ 120n' (n
2
1)
120n + 52Bon
120n(n + 44)
1st year's salary
35400
2nd
11
14
=
3rd
5400 =.5640
240.
35640
+ 240
35880
4th
10
5880: + 240
$6120
5th
14
6120 +240
$6360
6th
6360 + 240 -
$6600
Putal amount earned in 6 years
F
836000
X
за
--55
1 2 3 4 5 6 7 8 9 .10.
43 58 59 58 5550
34 23 10
Check When 3 as subtracted from 4, the result
16 1. 4 times
Ans.
the result is also 1.
the requirad given posivave numer 19 4.
(b) Let F(x) = 2x3 - 15x2
H
34x + k
•. P(x) is divisible by x- 2
F(2) = 2(2)3 – 15(2)2 + 34(2) + x = v
k = -24
Hence F(x)= 2x3
152 14x-24
When F(x) is divided by x - 4.
the remainder = F(4)
2(4)3
- 128
(ii) Suppose that the man will earn $36000
in t years. Then,
or
120t (t 44) ***36000
+(+44). 300
(t + 50)(+
300-0
+ 6 or -50
Since the time here is non-negative, the result, t = -50 should be rejected. Ang. The man will earn $36000 in 6 years'
time
15(4)2 - 34(4)
24
Cheok
- 240 136 - 24
- 264 - 264
The curve is drawn in the attacked. figure.
(1) For 20 y $45, from the graph, we find
9.4 x 6.7
(ii) If y = 70 - Sx is drawn, a st. line should
be added.
I
2.
4
6
y = 70-5I 60 50 40
From the graphs, the possible values for x are 2.3. 8.7 approximately.
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