* = TAT [92 (dz + d22 +α32}]
真四第六第
BADAEĦDREI WAH KNJ YAT
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四期星一日四廿月四年九六九一层公年八十五圈民藝中有教體舉
1969FUNZ
Sal
現代數學科(廿五)
1. Evaluates
MODERN HATHEMATICS (25)
the exercises: 89signed last week:
"21 031)
022 432
423 da
131
33
(20.48,
6.2.
35 21
Solutions
35 21
0 3 9
48
x (2
-121
(2 rows are identical)
+b+c+d a+b+c
i+c a+b+
(a+brord)
LIT
a-b b-o ord}
(arbrord) [b-o ord d-a
lo-d d-s a-bi
ord d-
[(a-b)
(arbrora] [(2-0) f(0-1) {3×3) – (dua)2} - {b=0} {{b-o)(a-b) - (0-8)(d-a)}+ (q-d) {(b-o)(a−a) - (c-d)2]]- ? Complate it yourselves,
Solvet
2+k
Solution:
3.
Prove that
Proofs
(2+k)
(2+k) |
(2+k)(k-1) | |
(2+k)(k-1)(x-1)=0
1,-2.
#31
#21
No13 923 33.
1112131
21
#31 32
11
*12.121313 022 912 + 043 213
13
**12022 + *13 423
82222
21832922
*12032 + 293 033
2333
3122
#32 32
(
(店)
0 1
1. Hence A.A Similarl
833 23
(property 6 and property 7)
(property or a matrix multizlied
by a Boolar)
021 31 d12 022 432
323
33
I is proved.
I can be proved as below.
11 12 13
21 22 23
32 33
- ✩ (§ ~ :) - # ( ¦
Remarks: (1) Although only square matrices have multiplicative inverses, but not all square matrices have multiplicative inverses. If the determinant of a given square matrix A, or ja 1a zero, then the multiplicative inverse of A is not defined. In such case matrix á is called a singular matriz, otherwise A is called a non-singular matrix. Hence only non- singular matrices have inverses. (2) Although multiplication of matrices is not commutative, the multiplication of a square matrix and its inverse is commutative.
5. Application
The inversion of matrices can be employed as means to solve a system of linear equations in two, three, or more variables, The procedure, is illustrated as follows,
Let the system of linear equation. be
2
#132
esented by a matrix
* = [*3 (α 13 **32*33)
4. Worked examples +-
(1) Solve the system
₤3x+4y- 15-J
Solution i
G 1)(3)-(6)
Inverse of (3
(34) 1 (3) 1
(4)
B41
*(3)8-90) + ( -4) (2)
(62) (3) • → (3)-G)
()-G
(2) Solve the systèm
2x +
3
Olutions
()()(22)
+(3-2)(3)() + ( )(2)
~_~) (1)
(금) (주)(3)
(3)-(3).
(3) Solver
2x
Solutions
(1)
0400-0 AGT90100-2 6390.
(-1)
C50-A (0-6)
The above can be
equation as below,
/11 212
21 22 23
31 32 32
00
The inverse of the matrix, which is made up of the coefficients of the equations is
1011 £21 231
(4) Solver
7. Work for this week
(1) Solve:
(4x-38 7 15x+y= 23,
Katrices (continued)
4. Inversion of matricas
The objective of this section is to Learn how find the inverse of a matrix with respect to multiplication, That is, given a aquare natriz we are to obtain the inverse of A, denoted by A such that
-A = 1, where A same order as that of A.
and I are of the
The procedure of finding the multiplicative inverse of a square matrix is illustrated as
follows:
Assume
12131
12 22 32
TA 13 23 33/
Kultiplying both sides of the members in the equation above by the inverse of A, we have
where{A}is the determinant
the coefficients matrix.
(2) Solver
2x 5y
3
13 8.
(3) Salve
+22
2x
2z 1
02?
11 21
12 13
22 32 2333
31 32
£11 £21 31
21 22 23 #32 33
Then there is a matrix galled adjoint of ▲. denoted by adj A, which is defined as below.
Adj ▲ is the matrix which is obtained by repacing each element in the transpose of a given, square matrix A by its fofactor. That 18,
11 *21 #31)
12 22 32
13 23 33/
Then the inverse of
கர்
011 21 31
12 22 32 2.13 23 33/1
(12: 22 32
13 23 33.
Simplifying, we have
chat
(2)
M
21 31
TAT 212 A22032 213 223
R11 21 311 112 222 232 18013: 123 33.
(4) Test whether each or the following satřices
singular or non-singular
(a)
(b)
( (} }) ( ( ) _ " ( 1 )
y+22
3x + y -
23
+22 -4.
The matrix of coefficients is
12
+22
But
-2
Therefore the matrix of the coefficients 18 singular and there is no solution for the system;
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