1968-12-24 — Page 22

真二第張六第

日五初月一十年申戊歷室

WAH KIU YAT PO 日橋

二期星 日四廿月二十年八六九一腊公年七十五国民塞中

育教備器

工業前途有賴於生產力之改進

工業教育亟待擴-

·馬香港工業培藝更多人才 政府、工業界、教育界 鎮通力合作一百三十八人,接升級者 七月加考試學生在

我只使

要有工間鄰肤

·術品及教轉接納與生炸

·品有水準,並發展輯的一期求。 高生痛力+對?格的,就往不符隆商的實際 | 甜对新里斯與被巧。泰濶,文長,梁志仁

·在悌望君,醫谂遠沒有,吳啓,張

·甲班李志成,號

第十九屆离小畢業

[努力,香油工業必須提」戶的關練,訓於無論 【來發表中,作應大的。茶過,這些年來人所一區名 保持其地位,必須在來甚,並不十分有般引力解,殊不知實際上工業,位。 楊齢烈之刻,古灣財,很低;對他們而| 於小學之辦理,不大;,就貼私立學校之學 整日

安成倫良好的工區人質 含小學安育,做須不徊十九人,其中有四十四 出日仝菜 (他心香省經濟|:丁X中學畢業生以培教育咕質綁死,做就以,加升中國之六年級生A 斜百分之八十八,艾

一,使工業入寸終會缺乏一般身體酸服務的靈體行,及榮總發表,但難,,長達 本所面的問題一法用减工業與工業界之上的機體,选,變,改 有嫌要大歌的人力支持,散緒,大低增加客觀,一般埠把合學校,上午第一英语,而交後,老然 【方巒。所有這些工作,,除了鄭術完工業離總一般外疉鉅建設動,陳淑兒,陳兆為,道 十年間工業的非凡交服务廣爲你第一代爾一些商出席散京,在北角健倫糊,德然查,学 ,總別是經受訓練的披菜更多發生有積克接受, 官立以校,下午則其供好想如,香柱殺,共 ,上述过種情况顯示,在一九四九年段,九龍溪嫩,周惠善,若致良

** 如壼週知,香港近開養,同時,東風

,只有迅攒此方類 。

•但本號被褥狹育與,以為大明有熱

「葛前及未來之需要,,,,他何投身工業部門服務 何發展,各悲太伯特會

一,對於所要工業人材,

「梁中季,在造無設施下

【家門學院及*開庭立工一努力方向。

效

·改亮黑幽,和國

|瓦門感院炸然暑本沿 才有效可言,透著,把可仲兒意了薄奔油,梁國源,每

紅磡街坊公立校

• 工朔界人士常推出,

【當得五官對。至於所謂同努力,以供求對本港 校,但新生物料、工業界及論育界的典

·外,其餘爽文迭小琴桀育,培豢鹩偉工峦人材 工業中學,除两鎖無際|青年遷開麻大的工藝

致育子女,無暇及,,和烧泳,就一年,鄭 ,終日次奔立大,對於「志剛,其他交,張笑嫻

出外,我國在外奇 恐以爲小京除在就誊本 因此加重灣之負担。

所活動,例如是,一何湖文,許永寧,地让

忠

麻麻 藥

第十九屆畢業禮

「於兒童多見骨湯,了解 一,湖山發水等,皆有助

唸倫伉儷致詞及授憑頒獎

及後,本人所被發

·校叫“融之努力工作,

與度,於陸其假國前大,这,依借他偷尖人想發利,以橡將來在社鳥之 公立巫校第十九屆羸梁底利快等,逐一簡路部|校之優依統及超卓动

-具煙開始,首開來代表意甜,告破一中校如下:

長實踐基隆女士致悯及一座。

那生人數,全年上

隐徐氏致詞

人數、考試成毅、王第一 今長本人驚的小

小糊

者注意

論現代大專教育

伯险阻,不計利查褐;而有二种天下限亡,捨

「分离的。

無功用:

· 大華必須盡力培豢一珍佛色的半没有由体

的啊斯婚力,此之粱「蔥術良姊」。這雄學筱間可缺的一部份。 一间传舫,才能培癸们大塞生明然思對的家立列已,還鄉無外送,故逃生邁向是理想的大总数不 務,從存在奉隋自由的空照下,才能有點何的水,如已忘我的古诗的!織化的要建及姿感,為學生,

【此无本的必須條件外,俭湖加上一個做低的良,她年管不傲买,把魔心酸,也氣方剛,估不免感 格,才算四頣與肉骱就飽,精神與物質两全。但,他用娶,易無野心的就多所利用,經驗為資本, 這個獨特的優庖風格,其非一蹴而成,是需要和“此就有心,固然出自愛雙岢年之熱性,聽起來 「體塊。一所低代的大學,种非祂以只有宏代的養生被乖乖地位起門來喜心還應,不照過到救 的一部份,而且小某一所良好大型所必不可能的,動畫超優的保留以强烈的反對,他們配第1 「知,不僅是毎一個珽好大學生所必不可缺的人格:蓄今有不少人一到「無生運動」證個名詞 以我行 踮碴‐ 跲習學業,自染前途,大

過歷史的考驗,經過就灣的地貌,極培啖而來

张成大的 亦似乎會之成,但有架大一分析,則其實爲

不好

·如果段症性的梭舍,完整-

分而現代作的設

(六)學生運勳與學生指導、童之獨家相背道。

格的大傑生。二臂是相她而成,互相影响,不可大智大開,夯娶叫大奉生奖過問國家社會大再, 一書,實有關門造車之商,與大學救育之太旨及民主社 似是而非,與宿疾忌醫無異,因今日文明進步,

假如大學生只知蚍緣,與現實脫節,從來

「流行,著守一般大樓店必不可缺的 河之社角?何筑起領導強任。

大买的召煦的船,那麼學生覺他便是大好的人格,他們又何來劉志能力,以適應此複雜篇區啟化

「他是一間大耏的枳壳,傲,的師資與他洗标絡社 民心社會大礙,沒有軟際經殿和茶本知識,試問

興趣和增加其淼任感。

,因迅學生班就具有四

為此人

(B)繁生区新可以培养大學生的社會意織,此不做爲神似的,無可惶綾的查任,而且亦得一 (A)學生遺跡可以激癸大器型的衬覺。. 人均殿負責來管患該就會內與全體有阿之茲項, 作爲民主社會一份子的基本掂利,一鐵不容否

!!有」「民事」,故凡一個社會內之評成貧,人

·何况民主政治之间諦,不外「民治」、「民

零食的,

(C)&生運商可以提高大學生關心脏會的 韶的機制,此爲民主政治必不可缺之詞成要件。

HD生運動可以粗大學生獨立自主

任制

免治的推此間

自動,和自本的能力。

雙任,治宮律,獨立不傈的精神,和明辦素

虚錢,不吹牛拍馬,不投機取巧,不畏强濕,不 子 純潔、天真,宮正義感,易衝助,不做作,不,人架廠利用的危险了。 大學生之所以可設,是實手他們深感应青年:那,公正客觀的判斷能力,那麼便自然不高有被 (KB)

蛋谢 真六息有

育

1969

數學科

來

文中學會考

MATHEMATICS (8)

試題預習:1

̇歐陽絡文:

LESSON. B: SASY PROBLENS SOLOBIS HY

ANALYSIS INTO RIGHT-ANGLEDA,

every triangia nas six parts, namely three sides. and three angles (interior). We knew from Geometry that it ie always possible to construct a triangle when any 3. parts are given, except for the cases AAA and SSA. (AAA gives a group of similar triangles and SSA is an ambig- uous case.) Similarly, if the values of suitable parts of a triangle be riven, wo man fång ku telpanemetry the rensining parts,

Fred Geometry, we have the Pythagoras relatien, bac, for "a"right-angled triangle. Nhance if any two of the 3 sides are given, the third side may also be determined, Again, the tre acute angles are complementary. Se that if end is given, the other de alɛs known. Hence, in the solution of right-angled triangle, there are really only TWO cases to be considered

(a) when any two sides are given;

(b): when any one side: and anehcute angle are gaven. Let us consider the following: examples:

在育

EXEMPLE 33 The angular elevation or a tower Dat

place A due South of it la 45%, and at a place

B due West of A at the elevation of 30′′. 11 A8- show that the height of the tener La 51 SULUIIUN: Let CDs h

Frem rtin BCD B⇒CD cat 30 – 43 h From The AGO: AC-CD cat 45-h

2 BAG fart.cat A

Zh

The height of the tower 18

EXAMPLE 4: A persen walking along a straight road observés

that at two consecutive milestones, the angles of elevation of a hill in front of him are 30′′ and 75%, find, in feet, the height of the hill

SULULION: Let A, be the twe positions

-of tws consecutive milestones,

et. AB1 mi.

and let Cum the height of the hill,

Iron rt Gunù) Ge Ch.cat:30

From rtzA DBU: Bum CD est 75% Substracting,

CD:

Cel 30 ~ cat 76*~016830mi ~36061,

秦補有

之

各

學校四八參败者五本

once by the recip to cat relation, COS HE COMES from the

is found by the

for all the

(a) Proof!

162 Proof:

formula, and fur

It is better.

in turn < by the

Sec

Sin

EZAVIMAS 2: A boat sailing against the wind frea I tea

a place to Y due East of a takes a counes. sither: N64 E er 564 5 alternately. What is the distance as Y from X. if the boat has travel 5000yd,

SOLUTION:

A,B,C be the 3 turing pointains

1,No be the pt. the shim masts with the XX line. Then, as AX, B and CNY are iss.

Hence, fren A,B,U, drop,reso,, AP, 83,CR, perp, to 11, And Jet XPanayd., MQ=b yd.jinmc ydv

Then, Ca + b + čim XI (VAS ARM, BMN, CNY are 1998/ And MXP = 4BQ= 4UNK --- 90° - 64 From rt. AAP KAw a sed 26 yd.

Mb Gec 26: yd.

rt. UNR: Nu o sea 26′′ ya.

Adding,

JAUDING=(a+btc/sec 26.yd.

XA+MB † NO ➡half the length of the journes-2500rd

btcm 2500 cas 26(d):

茗= 212500:ces 26.jyd

3 4494-ya

ac:4490Bydki(cerr, te 3 fig.)

NOTE: This problem can also be solved by drawing ́a rt

Preduce A ten

sit. Xh= à of 5000ya=2500yd."

fran Hydrop HA iXY,

then XY

fres rt...e HXY+ _XX=zHcən 26′′

XI=2»XN*004 26 — 5000 c»8 267d.

EXAMPLE 24 A man observes the elevation of the top of a

mountain to be 50°, he walks 1000 feet nearer and finds the elevation to be 60. Find the height of the mountain to the neatest feet, SOLUTION: Let AD h

Prom" rta ACD:

ABD

tun ACD

AD BD than 30.

cot so- cofin !

-0.8392-

the height or the mountain is 382

s

BXAMPLE 5: A mhip sailing dus. & abserves that a lighthouse

known to be 12 miles distant bears N34 B at 3p.m. and N56°N as 4:10pm, now many miles a day is the snip making ?.

SULUTIONS Let A's be the 1o & 2" positions of the ship,

be the lighthouse, From the figs, as shem „

* LAB #90° - 3456

2- ALUS = 56′′ 4.34 —90":

AL 12 MAN

PEJA ALM, AÐAL 800.

12. aec 56 (mt,

in 12 hr) (4:10m - 3pa), the ship sails 12 amc 56 må,

in 24 hr., the ship calls:

7.07.2

DECREASI

BXAMPLE 6.1 me given figure represents a section of a

rectangular bax with its lid us; a sphere of diameter 16” is placed in the box. "hat is the least angle US makes with B.

E Jein AD, then AU= DE = 20′′.

Draw·ONEAD.

Where. ON =AD = ?= 13# ND=AD H=20"

5+1213

Let M be the pt. the lia DB touches the sphere. Join O, then OMIDE

DE 18 tangent ta: the sphere)

OM

Bin ODM = AD-43

A ODM

AADE

B111. 0,61543759!) 4 OFM - Z ODN 37-59-22 37*.

03.makea with BC

HINTS & ANS. TO EX. Z

In torching down the choose the smalest

nost natural.

As

ANS

(27) == (jzz) + (5) 8

Adding

Vechst 3)

3 (rejected)

is impossible

"2 003 02-1

tan A

tan B

EXERCISE B

sphere of radius 8 cm rests inside a conical funnet whose àxia is vertical, the highest point of the sphe- re 1a, 22çin, above the vertex of the cone. Find the angleaf the cone.

A, B are two billiard balls at distances.

20", 30

from a perfectly elastic cushion CD. The ball A is struck along AP and hits B full on the rebound after travelling xitogether 70", neglecting the size of the, balls, and assuming that AP, PS make equal angles with CD, calculate APB,

At noon & ship which la sailing a straight course due ". at 10 moh observes a lighthouse 32′′W of N. At 1:30m

the lighthouse bears 58′′ E of N; find the distance of the lighthouse from the first position of the ship, Two towers, A and B, en a level plane subtend an angle of 90° at an abserver's eye; he walks directly tewards B a distance of 630 metres and then finds the distance of. A. from each position of the observer, Find without any measurement the angles 'ef "an ises. each of whose equal sides is three times the base,