IBRARY
育教傑華
第三張如筆
12 DEC 1968 AX82
CITY HALL
文中學會考試題預習
生物科
BIOLOGY (6):
Answer to the questions of last week
Ana
廖古琴:
(a) Define the epigeal and hypogeal germination
and to each type of germination give one examela,
(b) from your personal observation of seed
germination, draw a series of labelled
diagrams showing epigeal germination of a
ramed seed. (from the splitting of the testa to the seedling stage).
(a) During the germination of the seed the
cotyledons come above the ground surface and form the first green leaves. It is known 83 epigeal germination, e.g. the seed of caste oil plant. In the hypogeal germination the cotyledons remain under the ground surface and gradually give up their stored food to develop the plumile and radicle, sig. the ̈ssed of broad bean.
(b) Epigeal germination of castor oil seed :-
(A)
•Cotyledon's stalk
Secondary Loots
Ans
Radicle
Tegmen
Split testa
Soil level
Hope catyl
J
-Radiele
Root hairs
Root cap.
(B)
ladon
spocotyl
(E) Liberatagor
Secondary
Roots
plumule
•cotyledon
Hypocotyl
Stages of germination
(A) Emergence of the
Radicte
6) Elongation of the
hypocotyl
c) further alongation of the hypocotyl
of the plumure and (D) Liberation and the formation of the Seddling
withdrawal of the cotyledons
On germination radicle which first emerges downwards, and then hypocotyle straightens and lifts seed out of soil surface. Testa drops off and endospero can be seen on outside of the two cotyledons Enzymes from the cotyledons digest the endosperm into soluble substances which are passed to the growing shoot and root. When the endosperm is all used the cotyledons open out and form the first pair of green leaves
What is meant by the term "osmosis with the newt of labelled diagrams, describe an experiment to show osmosis in living tissues,
Usmosis Lá a physical process in which the molecules of a solvent pass from either a diluta solution ér a pure solvent to a more concentrated solution through a semi-permeable membrane.
In plants the absorption of water by root naars is the result of osmosis. The plasma membrane of ✨ sach root-hair epidermal cell is a semi-permeable membrane which separates à dilute solution; the soil-water, from a more concentrated solution, the cell-sap, a difference of osmotic pressure is developed and water is drawn into the root-hair
WAH KIU YAT PO 11 8 15
報日僑筆
四期星 日二十月二十年八六九一曆公年七十五國民華中
伍
-EM-TENE
CHERY TENNES PROF
CRS) PRESMIESITION -
今舉行下學期新書展覽 【中小學教材研究社公司
VARE
HEYJUNTANEK •
EU-SWISSTYREK -*-*
遇紅
聯合公報 (續)
中大教學法研討會
少年支百醤謝副總監;k潘劣人持“以 光靠平赍贈紅十字百年紀念一坐,費 YANNA-ASEETSTEE 年問答比賽決賽,决賽就准因幫方斯 日下午,庭中,宾客港紅十字会被沉,定必行過
· CEE.WER÷tEJE-CHI ?定十四日假該會禮堂舉行
一週年問答比賽決賽一
|紅十字會靑少年部
(UD) XERA · ·
「長遠的計劃,
二、黑硯小海激平,希望有一個比般完整及、
•T•BB÷YXNSKNAKKE.
墨素碘生發展花兒,導師不宜有
四、對丟年級應智謀其治學方法,到高年级
三,與學生接觸,了解學生之径建及反
CERE
SEME <BSNEW-
ILARTE POKALERTER.
一、同是對小組或學豳有一個比較海彩
#HE-BE
VENEKKFZes
SEDNIKA
·消運行爲,如有至月,唐啟
TEOKSENECEK?
TRANSES.
微取學生對中大致學法之意見以做插花自於施 ENTER-EISHIHELKKU-Z JANZA-BHK-ANAK
,到合乎期望之錢想,並與三深之讲程有
·紫了诸各院前各五對各開運,大學四年中厚
CACHZUNORTEXXO#ES - $50. ,且各经各实党庞之方出不做,我上流裁,故我
方法,但中大當爲於推行上缺乏一段经越之計的
1969
現代數學科 (六)
MODERN MATHEMATICS (6)
Solutions
Simplify (AMBJUCANBİÇM
CAMBUCA ABACHD))
= (ANB)U{(AMB)/C®}
ANP
Associative law -Absorption law
Simplify: (XUY)ŃCZ!UT ® )}U (X/T£}
{{XUY)/][XAY) JU(XAT) ...De Morgan's law
Commutative law".
= {(x/x]U<X/Y}'}n{(XAY}}}¢XUY
un (XIY)U(XUY
· (X/Y )UXXUY)
•(XDY)UCKAY).
(XUYUX )/(XUYUY
XUT
Distributive law Complement law Identity law Commutative law Distributive law ..Idempotent law
Idempotent lau
(3) Prove that (AUB JN(AUB)N(AUB) =A AB
Proof:
L.E.S. AU (BB)N(AUB)
= (AU){}(AVE)
AA(AUB)
# CAMİA) U(AMB)
BAMB)
AR
Distributive law ..Complement law ...Identity law ...Distributive law.
...Complement law Identity law
Prove that (ANBŃC) UCA 'NC)U(B*NC) = ©
Proofi
L_HS = CN{(ANB)VA 'UB"} Distributive
CA((ANB)UAB)}...DeMorgan's law
#COF
...Complement law- ...Identity lav
(5) Prove that if AB. then B'CA"
Proof:
Assume bEB
Then DIB
DEA bЄA!
Therefore BIGA'
Assumption
¿Definition of the compl-
ement of a set
ACE
Def. or the complement
of a given se’ ..Def of subset
Difference of 2 sets and symmetrical.
difference of 2 Betsy
Definition: The difference of two sets, denoted by A-B. is defined as the set all elementa of A. which are not elements of By
That is, A-B = A/B",
We shall consider some
A-B as follows:
(b) U-Ø = U
perties of
(a) U~A = A Because 0-A UNA'S A
Because U-Ø=UNG®±ÙNU=U implies ACE
(c) A-B =
Proof:
If A-B-0, then A/B-0. But AB is the necessary and sufficien condition for ACB. Conversely, if AGB then AB, which means A-B=
(A+B)UB Proof:
(A-BJUB
لله
(ANBDUB
·CAUBIN(B'UB!
CAUBINU
AUB
Der. of difference Distributive law Complement law. Identity Law
Intersection is distributive over difference. That is AN(B-C) =(A/B)=(M/C)
Fresh potat
Sugary Solution Boiled potato
At the beginning of the experiment
No Change
Solution over flown
At the end of the experiment
vo akin peeled potatoes A and B were taken, In potato A concentrated sugary solution was introduced up to about half way of the scoopea cavity. Potato B was first cooked to kill the living tissues, then an equal amount of sugary
Proof
R.H.S.
(ANB)-(ANC)
(A/B)/[(AFC) •
„Def of differenci
(A/B)/KATUCA) ..De Morgan's law (AMENA · JUCARBÆK Y
Distributive law
(ANA 'NIB)U(ANBNC))·
Commutative law.
law.
CAMBOO Come law
AA(BAC)
AN(B-C)
Identity law. Associative law .Def of difference
DerTinition: The symmetrical difference of A and B, denoted by A+B, is the union of the difference between A and B, and the difference between B and A.
That is, A+B = {A=B)}}{【B=A}.
There are various ways to express +8. Notice the examples in the following a) A+B = (AUB){}(AUB").
Proof:
R_B_S,= (AUB)KA'UB!):
[(AUB)/IA ^] V[(AUB MB'
„Distributive lav [(ANA)U(BNA⋅ )]U[(ANB® )UBAB |_) Distributive law
..Complement lav
Identity law.
Commutative law.
= [ØUCB4A TULA NB! )UØ
Proof:
(AMB!)U(BIA)
BU(B-A)
Right hand member
A+B
(ABULB'_A!)
Der.or difference? Def of symmetrical. difference
..Definition of symmetrical
difference
(AA(BI) DAKBYZIA®}}
...Definition of differe
(A'B)U (BA)
..Complement law.
(BM®) V(ANB!):
.Commutative law
(B-A)U(A-B)
Definition of di
(A–E) U{ B-A) -
Commutative law
rence
A+B ...Def.or symmetrical differ
·A+B (AUB)(AMB)
Prodfa
Right hand member
(AUB)-(ANB)
· (AUB)/(A/B)!
(AUB) A (AUB)
A+B
...Def of difference
Exercise for the week
(A) Prove that A(B+C) =
De Morgan's law „proved in Example
(MMB); (MC)
(b) Prove that A-(BAC) = (A=B}U{A (c) Prove that (A-B)ĄC = (ANC)¬E
(d) Prove that A-(B-A)
(e) Prove that (AUB)U(B-A)
(f) Prove that (A-B}/{C-D} = (AAC)-(BUD) (g) Prove that A-[B-(C_D)] = (A_B)U[(ANC)=D] (h) Simplify each of the following,
·A+UA+A•1⁄2
the
solution was added to the cavity. These two potatoes were placed in a trough of water for a time
By observation it was found that the sugary solution in the cavity of the potato ▲ had overfloWES after a time. This indicated that the tissues of potato A had been acting as a semi-permeable membrare which allowed water to diffuse into the sugary solution as a result of osmosis, No cha ngo was shown in potato B because the living tissues of B were killed by pre-cooking and the tlasuma were no longer semi-permeable, thus the process of osmosis failed to take place.
Questions for this week :
£, 187 What do you understand by aerobic and
“anaerobje: respiration? Compare as far as you san, the differences between respiration and photosynthesia.
10) By what experiment would you show that neat i
given off quring the process of respiration? 2. (a) How would you distinguish between pollination
and fertilization in a flower? Describe in a table form, the changes occur in a flower after the the process of fertilization.
(b) What are the characteristics of an insect
pollirated flower? Name UNE flower which is normally pollinated by insects and carefully describe the mechanism of its nollination.
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