育僑墜
0968
四
日十二月一十年未丁屋言
英文中學會考試題預習專欄
生物科
(八)
徐錫褸 T
Biology (8)
Answers to exercises for last week:
naad through the following statements carefully.
ement
If the statement is true mark. "7a or the statement
is false mark "F" in the blank of the statement: provided:
An example is given below.
1. A bird. 13 anamua 1.
2. Afish 15 MARA),
All mammals are animals but all an imma la
are not mammala.
Carbohydrates are any compounds which contain only the elementa carbon,
hydrogen and oxygen.
Bile is made in the kidneys and st in the gall-bladder.
The smallest blood vessels are called arteries.
7. All veins carry deoxygenated blood in the
blood circulation of the heart.
No digestion takes place in large intestine.
Pancreatic juice digests the food as passes through pancreas.
10. Yeast is a one-celled plant that converts sugar into alcohol.
11, Fungi have no chlorophyll.
12. Moulds, yeast and bacteria depend on
other living or dead organisms.
13. Parasites ootain food from other 11t
things.
1. Saprophytes, live on dead organic matter. 15. Fungi perform no usatul function în
nature.
16. All infectious diseases are caused by
bacteria.
17. Most bacteria are either harmless to man
or useful to man..
18. Sterilization means the killing of
bacteria by heat.
19. The gall-bladder is in the liver.
20. The greater part of the human body is
made up of water.
H|| | || | || H | H + + + H |
11. Give a full description of the methods of dispersa) of fruits and seeds with one example for each."
To prevent the competition for water, food and sunlight from the parent plant fruits and seady kr descified many devices of dispersal to Baquira theli wide distribution so as to survive their same species. Generally dispersal 19 brought about four methods:
1. By wind
2. By anima 19
3. By water
hot 4. And by special explosive mechanisms
- Disperszi by vinc:
Fruits and seads, because of their spesifie
shape, size and structure, can be carried awdy from their parent plante by wind
The seeds of some plante (e.g. orchid) are light and small to be blown as dust particles b windi
Other plants te-g. poppy) have a censer mechanism the dry seeds are free in the fruita, from which they are shaken through the pores when the long-stalked fruit is agitated by the wind.
Some other seeds, because of their increasing surface area, can be carried by wind. The sailed fruits of sycamore, the winged seeds of pine, and the parachute mechanism of the fruits of dandelion ire all adaptations of this principle,
Vispersal by anamı”.
There are internal and external methods of dispersal of fruits and seeds by animals.
The
fruits such as strawberry guava mas grapes are eaten by birds and are carried for some distance by them. The undigested seada in the animal body are then dischanged with the fecas. (1.8. internal method of dispersal by animal)
By external" method); Many forms are held such as the adhesion of sticky seeds of mistletos to the bills of thrushes, nuts being transported by rodents and then forgotten or fruits and seeds being carried in the mud on the feet of animal or the clothing of human beings. Other fruits and seeds are provided with
barbs, spines and stiff hairs by means of which they adhere to the body of woolen animals and the clothing or human beings, By this way they are dispersed.
Diaperssi Dy water.
The fruita and seeds dispersed by water must have a large bulk body of decreasing density. They have fibrous and spongy fruite as well as small and light seeds so as to suit for floating, such as, mesocarp of coconut is fibrous and drift over long distance.
Vispersal by explosive mechanism.
Only the dehiscent fruita have such explosive
sechanisms to scatter their seeds to some distance
by sudden bursting of their dry pericarp caused
by differential drying tensions of the fruits, elky sweet pea or violet.
Exercise for this weak:
a) Make a list of Eight named multicellular organiem (plants and animals) that you have found in any one named nabitat (or in a balanced aquarium) you nave studied.
Give a brief illustrated account or LNG LATG history and habits of one plant and one animal from your list.
What is oil? And describe the chemical and physical structure of it. Why do the activities or plants and animals. affect them?
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明年度中大入學考試
聯合書院規定
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接田經鴣南迹地區: NEKO.S
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第七次預習題解答
(1)在任意角形中,证明
c = b A cot B+ amß ut A
(E)設 A,B 均笃銳角時,如右图
好示,邊C作 CDL AB,則
CADTDB
rt
CD=ksin A,
A ACD RABCD
M AD = wc A
wt 8,
CD
a sin B.
Au= CDent A == a sim.B cot A.
DB—CD cot 8—4 sinĄ cotB.|
代入得
c— a sin Bast A+ & sinA cat B.
岩A,B角中有一為鈍角蟻測
CD = f sing
B. CD-a (180 – B)
M AD=CPLA
- ang cot A.
BD = CD cot (180°-B) == bain A (~cot B)=.
-AD-BD a sin Boot A- •(~bain A cot€)
asing cot A+ & sin A cot B
(2)証恒等式:
(証)左が
•(tan A+ tan B) x.
(b) (Iano-caco)
= tan A tenb.
ton At Xan 8
cot A + cot B
tan A+ ZenB
Zamo
(18) kj — tans + Cac 8-27
tans+ TanĀ
= tano + me 82 csco ( tang+1)
tam 0+11+ cot 6) – 21.
-(tan 0+1)+ cot 8 – 2×
tam A tam B (to 3)
0 – sec0)2 = 2 DECO.
COS D
-(sec8-cote – 2 ucoast 0) — 2 sec 0 = ( cot 6- seco) — 2 seco (**)
(3)△ABC中) AD薦 BAC六平谷銭
BC at B123
AD
(解)由正
定律
分角質
依合比定理,
「由正弦定禅
sim &
668.
9 sint == log. 768 6:4 + log sin 42° = log(68)
** 24729+T. 8a55
-7.8802
8=49°22" 60 180*38" (3442)
A = 180° _ (B+D) = 180°-(49°22′+ 42) 3 R
=88°38
因AD方向為正比,故AB方向為比偏88*38
X 31 40 12 668 OR. BRA# A#$* *88*58′
(5)(4)証明 ABC的面積
Cor (B-C) + CedĄ) ►
(1) A CHA = CAS [180° - (B+C)) === cos(B+C)} Cos ( B-C)-+ Das A === cos (8-C)-cos (B+C)
sing (B-C+B+C) sing ( 8°C-B-C), 1-2 sim 8 sin (-C)
î pin 8 sinc
Tak simb cin {{CH (B-C)+ ON A}} 又由正弦定律
設
sinA
b
4 sinA
AL
•253 001 (B-C)
E D
No. .LOG.
Zain A+ != {001 (B-C) + cos A}
• cos (B-C) + 603 /
=850), BC=504, <BAC=57° #<B <CH A B
a=5, A=53° sa ex
cas (B-C)+ cos 57°}
1570:
sim 570
<+ sot 570}
Coo (B-C) = sin 57° ( 8×===cot 579)
=sins7° (7:28-0-1u94)
0.6306 ain 57°"
B-C 584"
- 123
(1) (2) # *** **
8= 90° 32′
1306 77997 sin 57° 1.92366
7.7233
= 90°32′ cm 32°38'
·C=32:28!
PBRARIES.
0.8387
3587
0.1-200 +0.4387
sim B
Alm 123°
sin 57°
BD+QC 8 D
0.5.200
-13587 .O. SA
1768
v! BC= 3.4 4λ
6D= 3.4x0.52
1.3587
ZABADY A*****
• BAD — — ( 180° - 123-
AD
sin23°
#Dain 123°.
AD=4910t
AD
1.30X0.8387
0.222)
*20
(4)白200呎高之崖頂測得 A,B两船的俯角各為15°皮
130談A船本達之江南 船在菌人あ42 え距離、文B船在A船え方住?
(解)設如右图C為崖項因由C測A之俯角15
ACZA 15 m <CPA="90"
同理
AD=CD cot CAD
200 tot 15
200137321
-7464 (32)
BD=CD cot 11:30.
200X49:5
·983.0 (02)
*A ABD AB — AD+ 8D*— 2AD* ED GOS 42"
No | Log
0.30/0 746428729 983 299261
!]
— 746·4 +7.83 - 2x 746-u× 983x còs (2 =557100+ 966300-1,091,000
432.400
Cart 42° 7.-87114, AB== [432400 = 648 (OR)
09,000 0376
船
(6) #| A+B+C-T $£•Ą
(修瓜方式=2
Are cos AB.
A+8
At B
AFE)
2π-A-B
B
#1+2 sin A+ (-2_sin, A-8+ (27-A-B), un 8-8-(27-A-8)
#1+2 sim 472 (~2 sin The sin AT
2 sin I
7-8
44 sem IA sin the sin IC (to*), QED
第八次預習起
(1) st. s ABC4, LCSIA, & CD LAB & ABT D. (a)指出图中有那载对“相似三角形”?
(f)那些线段為其他线段的比例中工具
{C)作一正三角形使典已知正方形等材
(d) 作一正方形使興己知正三角形等積.
(2) † 18=HĦj ABC & AB-ACDEF&B A3, 80, CALLE
ZA, ILLDEB=FEC, 91 ABEFACED
(3) PA, PB ZOR ZWW Q2 A8±14ZE Z PRIMO1CA
ZIWARTKiɛ on‡* 30Q; OR 2 441144
(A,日為定直线xy同侧两定
桌,求遇 A, 8作一且在xy上p
CDMR CD=££a.
(5) $180-2£ § P IS –Ħ ABMAL-
AP=318*
又器使AP:PB為定比時,其作法若何?
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