1967-11-11 — Page 21

頁一第張六第

日十初月十年未丁歷宴

1968

中學會考試題預習書調

化學科

林錫衡•

複習題

複習項目 普通氣體(二)

工以簡單化學方法鑑別下列各組氣體並

附有關方程式

(1)氧氧化亞氮

(2)數二氧化碳

(3)氫一氧化碳

(4)硫化氫二氧化硫

(5)氬氯化氫

(6)氨氯化氫

1.(1)實驗室以二氧化錳與酸作用製氯 而製氧時亦用二氧化錳其作用有何

不同?

(2)以何法使製得之氯純淨乾燥又以T

法收集,並加解釋.

(3) 寫出氣之主要物理性質化學性質各

三鼎

(4)氯何以能漂白,

複習題一解答

工(1)極易溶於水氣體:氨氯化氢

氧化硫 (2)可溶於水氣體:氯、硫化氫

二氧化碳、氧化亞氮二氧化氮 氨氮

(3)微溶或難溶於水氣體:

一氧化碳、一氧化氮

(4)是還原劑的氣體: 氨 二氧化硫 氯化氢、硫化氫、一氧化碳

(5)是氧化劑的氣體,氧、氯

盒子量少於29的氣體輕於空氯女 氧、氢、氨、一氧化碳是

Z氣體製法方程及收集法

H

3ht Hiso→ 2ns9+ HM1(向下排氣)

2RC1+3Q(排水)

→ MACh2+2H2O+CH

MnO2+4HCl

(向上排氣)

(向上排

HCl:72NaCl + H2SOy → NasSOG+ 2HCl

N2

NaNO2+ NH2 Cl → NaCl + NHÚNO, NHQNO → 2H2O + Na↑(排水) _2NHuCl+ Ca(OH)2 → CaCl + 2H2O

+2NYT(向下排氣)

N2O NHNO3 NO3Cu+ 8HNO3(稀)

12H2O+MO↑

NO2

→3Cu(NO3)+4H2O+2NO1(排水) Cu + 4 HNO3(濃)

向

→ a(NO3)+ 2H2O+2NO.↑ 排氣

CO:HCOONa + H2SO4(濃)

⇒ NaHSO4 + H2O + CO7(排水)

CO2: CaCO2+ZHCI → CaCl + H2O + COT (#K)

SQ丶Cu+2H2SOu(E)→ CuSO+ 2H2O+ S& 1

WAH KIU YAT PO

D48英文中學會考試題預習專欄

地理科 (二)

劉玉領

GEOGRAPHY (2)

1.(a) Construct a linear scale for a 1:25,000 map on

which all distarioss up to a limit of 2000 metres

may be measured.

Map Scale = 1:25,000

-1 cm, to 250 metres;

To represent 2000 metres, the line should be; 8 cm. long.

300- 250 。

500

(0,00

-1500 Metres (b) Construct a grid to represent hundred metre squares!

and calculate the approximate area of the water deeper than 3 fathoms.

600)

400

Map Scale = 1 : 25,000

- 3 cm. to 250 metres

4 cm. to 1000 metres -0.4 cm to 100 matras

The side of a grid/Square, to represent an area of

(100 x 100) sq. metres should reagure 0.4 cm.

Number of complete quares

• Sh

Number of incomplete squares

Area represented by one small squaED

0.1) sg-Km. 0.01 3d Ran

Theran he approximate 'area of the Water deane

tha 3 fathoms - (54 17/2) x 0.01 so. Km. -0.625 sq.km.

t Name the features showri by the conventional Be

at each of the following grid references.

168809 Trigonometrical Station

162803

-

Quarry

142812

-

power line:

145821 - pier

160802

139805

132813

village

cultivated land- isolated boulder

d) What is the distance of the oad shown on the map"

Calculate its average gradient S

By: measurement, len tollche

Length of the road on actual ground

13cm divided by 1/25000

13 cm x 25,000 3.25 Km.

the map

The road begins right at the coast (at sea-level) and Leade up to a height of 300 metres.

Rise in height + 300 metres Horizontal distance

3:25 Kai 3250 metres

Therefore, average gradient of the road

Rise in height/Horizontal distance 300 metres/3250 metres.

in 10.8

日一十月一十年七六九一満公年六十五國民中

In the ero99-section,

Vertical Exaggeration 1.5

Horizontal scale

map adale = 1:25000

Vertical Scale Horizontal scale x V.E.

-1:25,000 x 15.

- 0,6 cm, : 100 metres

The man standing at the peak cannot see the pier because there is a spur between him and the pier.

(f) what name is given to the type of drainage patteri

that can be seen on the eastern half of the map?

The eastern half of the man exhibits a radial arsinage pattern.

a) What do you regard as the two chief occupations of

the aree?

They are farming and mining.

(b) Tell how the material which is obtained at the

ouarry is taken out of the area .

The material is taken out off the quarry ground by carts onto the road whence it is carried down to the piers by lorries and then shipped overseas by ship.

(1) Describe the physical characteristics of the coast.

The area shown on the map extract has a smooth coastline characterised by depositional feature -- sand and· mud, the largest sandy bay being located at the mouth of river in the south- western corner, Noticeable indentations of head?ands: and bays are absent, Drying reefs occur only at once place. Immediately off the coast, water is shallow, less than 1 fathom.deep, indicating a fairly gentle slope of the land into water.

(3) Write a reasoned account of the settlements in the

area.

Settlement in the area is of two types: mining and farming. The greatest concentrations appear in the quarry area or at the coast which serves as a shopping centre catering for the needs of workers at the ouarry. Farmers settle in the well-drained and westward-facing valleys near the cultivated fields. The rest off the region remaine. unoccupied on account of the hilly nature of the land and steep gradients.

Questions for next week

2. (a) uraw a map of Asia and mark on it.

(i) the following mountain ranges: Hdma Lai ya sy

Karakoram, Kunlun, Altyn Tagh, Tien Shan, Hindu Kush, Elburz, Sulaiman, Caucasus. Fontic, Taurus, Great Khingan, Urai.

(41) the following rivers: Euphrates, Tigris, Indus, Ganges, Brahmaputra, Irrawaddy, Salween, Menam, Mekong, Yantze, Hwang do, Amur,Lena, Yenesad, Ob. (iii) the following latitude lines: Artic Circle,

Tropic of Cancer, Equator.

(iv) the following longitude lines: 60°, 90°,

12008

*(v) the Worthern Lowlande and the Inland Drainage

Corament on the usefulness of rivera in Aala. fo) What significance does the Himalayas bear on the

climate of Asia?

d. The table below provides information on climatic

conditions existing in four different cities in Asiá which are typical of the climatic regions that they are in que

BRA

eman standing at the peak at 168809 gee der at 1468207 Illustrate your answert ith a cross- ser ton using a vertical exaggeration of 1.3

PUBLIS

fine of vis

(a)

Locate each of these regions on a map of Asia. (b) Name eath climatic type and write an account on the

climate and natural vegetation found therein.

(c) What generalisations on changes in climatic

conditions can you draw if you compare these rour types of climates?

City

A

©

。

Temperature (OF)

Rainfall (inches).

Jan.

July

Patte

81

95.1

8.

60

82:

38

85.1

4.9

72

()能使瀑石蕊試纸聘红色因其興水」

作用成亞硫酸

FeS +2HCl (稀) → FeCl + H2S57

(向上排氣)

(向上排氣)

化學性質

氣体 迅

顏色

刺鼻臭 厕所臭

黃綠

無色

一氧化二氮有甜味

無色

硫化

臭蛋味

氯化氢

氧化氮

二氧化硫

刺鼻臭 腐蝕性臭味 燒碗味

無色 無色 紅棕

無色

正製二氧化硫

(1) Cu + 2HLSO-

(3) 1949 thot sto

銅是還原劑,使硫酸還原為二氧化硫

硫酸是氧化劑使銅氧化成硫酸銅。

氧化硫物理性質,

(a)無色有特硫味

(b)種易溶於水

(C)重於空氣

SO2 + H2O → HG50g

(b)是一種還原劑,例如

ü令高錳酸鉀運原為硫酸錳(退色)

5SO • 2KMnO4 + 2H2O

→ K2SO4+ 2 MASO, + 2 H2SOu

(Ji) 令重鉻酸鉀運原為硫酸鉻(自橙

黄色轉綠色)

3SO+ K.CnQ + H2SO4

K:50, + (r2 (504) + HO

與濃硝酸作用生成 = 氧化氢

SO. + HNO → H2 SOu + 2 NO2 1

【必使高鉄還原為亞鉄

SQ+ Fe (504), + H2O→FPSGG+2H.TOQ

(9)製造硫酸 (6)漂白絲羊毛

(C)作消毒劑防腐劑

(d)用作致冷劑

)實驗室製二氧化硫的装置,

燒瓶

鉄架

交環

(C)興硫化氫作用生成硫此時二氧化

碳作氧化劑

(註

MSO+2H S → 2H2O

(5) 二氧化硫之主要用途

長頸漏斗

●硬纸板

棉納

.集氣瓶

凡氣體之分子量大於29, 便是重於 空氣若能溶於水则多用瓶口向上 的排氣收集法製氯氯化氢硫化氫 皆有類似装置但製碲化區時不必 加熱)