買-第張五第
日二初月四年宋丁屉室
WAH KIU YAIT POCIED
中文中學會考試題預習專欄
數學科
(廿八) 單廿七次預習試題解答 (1)K罵运内接四边形ABCD对角线
喬仲强•
奌試話-A8-AD
AK
*S
姓名
(誤詆如題)
REFER
別級
ARY F
AC1 BD AER CF, Bl.
1 MAY 1967
E)
A AEK ACFK (BLAKE=LCKF)
2. AK:CK=AE: CF (‡84×#j » żż)
3. 4BAD + 2B C D = 180° (2##{N}}
A ABD AB AD
CBD cxen.
(两三角形有一角相補:
・其面積比等相積之】
ΔΑΒΡ
ACBD
AB 一装(同底三角形面積比,等於其高之比,代换
བབ་
ABX AD AK FNX t }
CK CENCO
Q.E. Dr
(2)口笃△ABC六中线AM上任一直BOCO之延线各交AL, AB
【
DE THE EDIBC.
註如題)
AABM
(SEO) SACM
2.
ABOM
ACUM.
(同高三角形面積比.等於其底边文比
"ÜM SABM-A80M AADB
BACM--A COM
酸
MC
4400
(加比茂理,全量等於分量和)
3. Aigar ABDC
M
(132)
BM
路
MCS
EB
AABB ABOC ACOA (***).
BAAD
(等童心理)
E. D
BM=MC (740)
CD AE ==-1
DA
7. EDBC (=QL*EM#21=**)
¿Uug¢ (4) ×± 352&R* (bera's Theorem) (3)两团外切,求遇切要作一直线被两园截线段之差為定最
(己知)OP两国外切
KEDA GRE
[★44) LE A T— 1 §
交OP两园各栏 B. *%£013 AB-AC= 2
(作法)联OP則必
遇A桌(两鼠相切
联心待遇切兵)
2. A & AD=AP
一遇口作-適當直线 OK.
並在其上截 OE
4. AI DE LIS AM‡ ‡411⁄2 & OK ZE
6 TBA (BA) TEZ PEX C(XC)
7 BC BC +3 30
証明)縦略讀者可用似可証明
(4)(a) 求作已知扇形的內接正方形
(已知)扇形 OAB(求作)扇形 OAB的內接正方形
(24)114 AB # u/ AB LZ G&#!/k++*l
ABCD
2 af OC OD & ǎ AB3LYP Z QË
425 P Q 14 PQ bb & à OB OA
5 AK RS AJ PORS 341,
(en of
E. F
01 ABCD A RSTQ 2 12 1x4c
(6) A, B為定值线xy同侧两定点求在
xgħk-d€ IR < ACx=2&BC4,
(已知求作如題的云)
延長元至8雄B = BD
2.以8為心 染洋作团
13. A作B园的切线
ADXC
uC互為河求
QEF
(証明)讀者可聯及的自行
(立)過A奌之地-切機不適合本題條件
(5)在4ABC証明
(2)证由餘弦定律
(0)=(2)
移項化簡
cla
校一祖別 地址
糖
日十月五年七六九一年六十五國民華
A
華僑日報
四
年二
報慶
有關上項微文發磋之祥饰如下, 微文初中及高初小學生微文,卻強比賽,歡迎本港大、中、小學生踴颦參加、 八衿部)本年六月五日爲華僑日報創刊四十二週年紀念,特舉行大孚、高中學生
舉辦大中小學生徵文徵畫比賽
定五月十五日截稿請踴躍參加
大專生微文宀限三千字),
題目:我的老師,校際音樂節見聞
初中生徵文(中三 3以下,限一千字
·高中生智文(中四科以上,限二千字)
期:香竭地方政制之商館,如何帶用海塢空地
「題目,中文應與英文井列爲官式語文,改善柰港市容秩序與清潔
自由強、粥九新界社會百態新增項目)
高小八五六年)學生緻文(限八百宇)
・題目:學校風光(新項目)
自由 ·花九新界的發展
初小八四年以下,學生自由短;我所愛的人,我所愛的寵物,我所愛的任何受物
****
·A大專組:冠平一百元,既七十元,季軍五千元。
CB79-RAPIR-PEKTR-BABYR·
初小組:冠三十元,丽軍二十元,季軍十元, 就自由,冠軍三十元,兹軍二十元,64元。 高小→冠軍三十元,二十元,季單元易 自由:冠軍三千元,龍二十元,季十元, C初中組:冠軍三十元,二十元,季軍十元+
·各祖薇文及香師日開始收卷,截止期爲五月十五日,郵爲溉,逾期不收。.
·寒戰者桀在文雅內附向身份證或學生證規研,所高學校袖級(自由智务
。
EK-1ERS - KOKEATENEDISLES-WAELEK?
初中及初級小数生日由變比賽,再過優勝潑若干十名致浍蹲酬,
以下表格各麽徼同摩可剪出发安,貼在作品後面,如無我格,只要照寫,亦可投
桃英文中學會考試題預習專欄
化學科 (廿八)
·王錦釗· 王先生;大作如須填寫,請用黑色墨水筆或深黑色原子筆蕊荷。!
CHEMISTRY (28)
Q.1(a)When potassium nitrate is strongly heated, it first)
melts to a colourless liquid. When heating is! continued, the colour of the liquid changes to pale yellow, and a colourless gas, which reignites. á feebly glowing splint, is given off. The gas evolved is oxygen. The residue, on cooling, solidified to a pale yellow solid, potassium nitrite. Equation for the reaction.
nitrate
02
(b)when green ferrous sulphate crysta
heated im 2test-cube, clouds of vapour are given off, which condense to a colourless, liquid in the cool par
the tube. The liquid can be showi to be water for it will turn anhydrous copper sulphate The residue is grey in colour, and it has crystalline shape.
The crystals decompose on heating, water of crystallisation is given off leaving the anhydrous salt, ferrous, en phate, Equation:
(c) When met
HONG KO
-abccos A Rca cosa zaaan B-abc nos
b)
cla cose & con A)
QED)
餘弦定律
coa Com
Rac
QUE D.
(**)
(解)因
rekindles silvery liqu
to the test-
tube, The gas mercury Equation-
mercuric
Y SOL anhydrou:
ferrous
Sulphate
개20
water of Crystallisa-
tion
white fumes of sulphur
tionen invisible
angana te A
sulphur trioxide
Bly in a hard- changes colour sible gas which ht 15 given off. A
rror-like appearance. the cool parts of the ygen and the liquid 13.
24g
mercury.
02
LIBR
JB
oxygen
then crystals of copper nitrate are neated it first mella to a blue liquid and clouds of vapour which condense to a colourless liquid in the cool parts. of the tube are given of The colourless liquid is. water for it will turn anhydrous copper sulphate blue. The residue 13 a green amorphous solid, copper nitrate.
Cu(NO3)2 3H 20
copper. nitrate,
rystals
520 anhydrous water of copper pitrate crystallisation) On further heating, the green solio gredually zurns black in colour. In addition brown fumes are gaven off, and an invisible gas which reignites à faintly glowing splint, is also evolved. The black,
residue is cupric oxide the brown fumes are
itrogen dioxide, and the colourless gas, is oxygen.
2Cu(NO3)2
NO
nitrogen oxygen dioxide
cupri
oxide
To an aqueous solution of the Substance add dilute hydrochloric acid, effervescence will occur and carbon dioxide is evolved when will turn 1 une water dulky.mThis shows that the substance as carbonate orla bicarbonate,
To afresh portion of the solution 300, à solution of magnesium sulphate. If the substance is
bicarbonate, there will be no apparent chemical change, 10 both products formec are soluble in water.
Tan O+ seco -
tan lit à tano seco
a tano
10 sec 0-1 tame]
QE DY
(解の程式
一口【答案小於360°之正角)
分解
(2 sino+5)
次預習試題
B
3(因绝对值大拾!不合理)
0 = 30° * 15.0° (%)
又由正弦定律
(6)(a) =[ of lan 18+ seat
tan 8 acc@+
tano seco +
(tame + 1) = (secé)
(Zan 0 + xec9-1) ( Lan O+ see 8+1
(tan 8-seco+1) (tands Decor
tai
seco + sec 8
tan 0 + 2 land +1: acet
(la) Z a+b+c=0 õht
if xyz=13k xy+R+T
(2)(a) je (b-a)x+(c-a)x+(a===ate u
Peel tano + dec 8.
之值
9# +5
Hil
ZNA HOD
Naci
Na
育
Mg (HGC3)2 Apply the flame test to a solution of the supstance. If it is a sodium compound, an intense yellow flame will be obtained which: is insoluble in blue glass.
(b)To an aqueous solution of common sait, G 31ver
nitrate solution. If the substance is a Chloride, a heavy white. precipitate will be formed, which is soluble in ammonia solution, but insoluble in nitrie acid.
AgC1*
C1-
Ag
To test for the Sodium ion (Na"), repeat mngj flame test as described in part (a)
(c)Add dilute hydrochloric acid to chalk, effervescence
occurs, and the gas evolved will tum lime water, Bilky.
The
2H
+ 002
Digest the solid with water, is insoluble, the substance is a carbonate,
Apply the flame test to the solid, an oranges red flame will indicate that it is a calcium, compound
Shake up the powdered zinc wiʊn copper surpnace Red metallic copper will be displaced, which indianwe that the substance is a metal which is higher than
goer in the activity: series,
Add nitric acid to the metal until it just completely dissolves. Heat the solution until no further action takes place. If the metal is zinc, the residue will be a solid zinc arina which 19. yellow when sot, white when cold,
Cuo
1x2+16)
18
ater that can be formed from 79-5 gms?
Cupric oxide
18 gm
weight of water fomed
weight of cupric oxide in sample =
wb, of impure copper,
10 g.
79.5
of cupric oxide in sample)
-100%
18 -44.2% 55.8%
Herce % of copper in sample
QUESTIONS FOR NEXT WEEK (29)1
„Describe how to distinguish between the following parIS
of substances, giving one test for each compound: (a) lead dioxide and copper oxide; (b) sodium sulphate solution and sodium nitrate solution; (c) sulphur dioxide and hydrogen chloride; (d) carbon monoxide and hydrogen sulphide.
2. (a) What liquid would you select in each case to remove
(1) rusty iron filings from a glass tube; (ii) wax spots. from cloth, (til) sulphur from a crucible. (iv) iodine stains from cloth?
(b) State the name and colour of the cold residue ler. after heating each of the following: lead carbonate, sodium nitrate. aluminium hydroxide. zinc nitrate.
(c) What colour changes will you observe when (1) hydroge sulphide is passed into a solution of lead nitrate, and the mixture formed is afterwards boiled; (iii) dilute nitric acid is added to red lead oxide?
3.Given Supplies of sodium nitrate, ammonium sulphate and slaked lime outline how you could obtain four different gases. Water may be used, where needed, but no other reagents. Give equations.
Describe two reactions or properties for each of the gases so prepared such that each could be distinguished from the others.
at BE a b c A.P. (KD)
(b) Ez a (b−c) x + b{c=a}x+c{a−b}=o?☎#81F A#
ab ca HP (3440 (22)
(3) ALB (a) X+X-2ax+i-a
4b; x2+3ax2 + (3a-f}x+ a(a f')
(4)解方程式:‘a}
(6)
X-3x4-69+2x+3=0
2x2+xy+ay-4=0
(5)(a)有一GP(等比級數)其無窮項之和马,其各项之立字符
成级数买窮嗄之和茑192 求此级数
(陽) 設為正數且x=試求 x+ 2
(as ́8(1-x) * 8(1+x)
)(a-c) (b-c)(&
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