1967-03-22 — Page 15

真三張四站:

日二十月二年宋丁度文

育教僑華

珊英文中學會考試題預習專欄

化學科

(十一) 王錦釗

WALI KILI YAT PO

●上她小華道之入此取九雅區及新界 (國際)

「協美州招待,產期向會洽訂餐 一於世,世迎會員問表,阻躍位親友參加 一時不候。若發夢無位玉元,額時被米,换乘 在西營衽深水埗小橋議,集中出說,透 【地爲南丫島榕公灣。是日上午十時於分

風文娛康樂活瑚,茲為促進聯誼,定 碟激消儉第六人十二樓安敞新址淡,師大

·船啞券每位五元歡迎參加

週日遊榕樹灣

育才警社同學會

驗。至於臺瀕方面、發育、美術、及 之九雅及斯养越小想“墨原運、心理學、營 【時四分致學院、社會、音樂、手工 ,六時四十五分至七有中文、英文、其 一文,你息-正分鐘後兩年不變,科目包括 办咄至六時宇先宠的等現處。學創仍樂持 開四十號分止; 錄取九龍戚學校教師

社區楧敦。丙、柏

尚云

11期

22 MAR 1967

级

*

CITY BRIA

日二十月三年七六九一层公年六十五中

往派將生範師

學教習實校各

作合予惠長校校各盼署教

絞校:保邈世事

保

ñ.. 但之鬣-希各校校長允于合作,是所盼禱。 甲·伬,惟各前鰡專科醮校校長當與各校校長盼格,以求鑾減少不 作鱚梭羅斯神校實際,或略不甓倫教授昨日

1 大神助,是以,配症生之派出實醫工作,被視爲一件激烈批施。安全電子及電器工程 計.閲師鰌專科照校,其學生,通常是每年要派出售敎學 1. : 按太把基崗導師費的學校,現有經驗,汪洪及柏立基 两式,此後實傷,財陔生將班畢業以後,正式担任敦職時,有其舍菲灣大學工學院院 系主任實倫熱痰,昨

訪問聯合書院

HL 無師範敦育之最主要港段: 人口與否,在密切關係,而致越實習時期又准入學。(成) 二、犁校之效淨水蒸吳鈽寫訓細計劃之成功在今年九月中旬被批 骸校實證,並於宁適當之協助,發本港口試亦及格,則可望 滋請各校校長崔放技納師範生莉件 在復活節後辦理,如 口試方面聞將突

永 校學生,在當熱灣內,均須到本港各擊 ,麥作致感實習,此一撞施,包實行多年合格,尚須參加IK

·樂敦靑司蠆意籍-政府師範專科

邁與師懟訓導之成功否,當有熱切之關證營,將獲警定爲资 實可署强闊,此導與本费崽校之教學达员持有东刻式之二缴 實習,希于以法當之協助安排致,她推思。

·紀將合作,盼能壺北接納布署學生到校 在第二年大選亦及格 其賞安裝载-侩此-大灣對 学没近向各校 許升上第二年條裙, (特糸)郷町换生作溯期間,須槎第一年大考及格,方 「格師。

C)

港九及新界區師訓班

道後報明

明日舉行入學試

格後須再參加面試 試期將在 報考人數將近二千名 試合

掉士蘇接待鬆戲。

,物理系主任樂痧 |趟由方院長等陪闩A

|海學院代院湯馬

億,代開院專場方 「由絏院代院長方心 中文大學聯合醫院, (十一)日訪 香粥.

廿三)下午分离地點。 一座加盟商科。今一般有:城、羅盆會添下午及晚上。學員在 教授主舞 上到械包括有中文·凯勒理小組,仍分時,一種時間分有在學術演講會,由佛 [湘两地行炉 本年度在按教師而整定在還上旗六小 交大昂件将塔然公開 成人學绣試:將於四分到達各考」。畢寊敦義實習,將,就中文大學之君子 安西,九龍及新界盛間,大亦相若。投。各項麒程除英語教。實倫教授此次來港 我知度導所小學 考之學員必須在四時配外,全閈好接,保飕中文大亭之影 有邀師 導。 學科,失蹤,中

英國P菲爾大學工學院院長殮,

作品若這在職教師完本校斯———鏜取香

小選手法,红法師能高校班—,代院奨方心重鑑與實人予以歡迎招待

CHEMISTRY (21)

1.Contact process for the Manufacture of Sulphuric Acids

In this process sulphur dioxide and sir are passed

together over finely divided platinum or vanadium pen-

toxide, and the sulphur trioxide so formed is convert-:: led into sulphuric acid.

2 502 + 02, − 2 303 + HEAT

The reaction is an exothermic reaction.

In the manufacturing process, the gases must! (first of all be purified, all dust, arsenic, chlorine] d water vapour present in either the air or sulphur] dioxide being carefully removed, as they 'poison/ che. Iaatalyst, which then becomes ineffective..

The purified gases are then passed into the

'contact converter where the eulphur dioxide is oxide

ised to sulphur trioxide. There are a number of differ ent converters in common use, the main difference bein in the catalyst which is used in the converter.,

中文中學會考試題預習專欄

數學科 (北一)

喬帅强

第二十次預管試題解答

。

*Sulphuric acid is not made by absonbing the sulw

phuric acid directly in water. The sulphur trioxide is dissolved first in concentrated sulphuric acid (98% concentration), water being added at the same time to keep the acid at a constant strength of 98%..

903 + H2O = K2 30

4.2(a)To Prepare Crystals of the Normal Salt sodium Bul

phate..

Na2SO4 + 2H2O,

H2 SOL 98 49

2 NaOH -

2 x 407 40

1 litre N – H2504 € 1 litre N - Naoh

Prepare normal solutions of sulphuric acid and caus tie sode. Mix exactly 200 ml, of each solution in a large beaker. The solution is evaporated gown and allowed to cool. Crystals of sodium sulphate are, formed which are filtered off and dried.

Ta Prepare

hydrogen e

H2

+98

49:

e Crystals of the acid salt, sodium

1 litre N-H2504

NaOH.

40 20

NaHSO + H2O

11tre N-N&Dн

Mix 200 ml, of normal. sulphuric acid solution wit挥 100 ml. of normal caustic soda solution in a large beaker. The acid is in excess and as a result, the acid salt is obtained in solution. Again the solu tion is evaporated down and allowed to cool. Crystal ef sodium hydrogen sulphate are formed which are then filtered off and dried..

(b) BaC12 2H2O + Na2CO3 = 2NaC1

137+71+2x18_46+12+48

240 (122)

106 (53)

The equiv.wt. of Na2003 =.53

# BaG12-21207

BaCO3 = 98.5

BaCO31 + 2H20

(137+12+48)

197

(98.5)

=122)

Since the sodium carbonate is in excess, all the

barium chloride is precipitated as barium carbonate:

Wt. of BaCO3 obtained from 122 gms. BaCl2+2H2O

-98.5 gm

Wt of BaCDs obtained from 4.88 gas BaCl2+2H20

98.5 gma

(2)- (3) ·

代入根出公

滷味味

則

(y-1)+ 2y (4 1) - y2+3(y- 化簡

或

得

y= ±(1±123 i)

y=2

(2)設a.c為AP. XY3為GP 試証

(b-c) log x + (c-a) log y + ( a−b) log}=

x E x y z # Q T

两论死对数

3)(2)相樂

ab

(2)

29.(37

z(X]+1)=0

+

3

logx logy = log y - log} (b_c) ( log x - log y) = (a−b) ( log y = log })

S[S~B)(S-C) + $(S-C) (5 · Q) + S ( S − q)(s~b)− (s-a)

(s-b)

(s=()

= a(s-b) (s-c)+b(s-c) ( s − a) + C(s~a) (8+ b]+2 (s~a) (s− b ){ $C)

-afc

FLE) S (S-b) (S-C) + S { s−c) { 5 − a)+ S (5− a)(s- b)~(s+Q) (6-k) (8−c).

* $ { $ · C) [ ( 5 - 8 ) + ( s − a)] + ( s − a) { s −8) [s-is-c}}

-

s(5-c) (25-a-b) + (s- a) [ 6 - b) ¿

< { $(S-C) + (6·2}(sb)}

* ¢ [stcs+s2-as-bst ab]

=c[ zs-(a+b+c)stab]

adc

{@ a+b+c=25)

2_a(s-£}{s~C}+&{s-c}{s-a)+c (8-a) (S-4)+2(s-a)($_k}{s-c)

− (s−c){a (s-b]+ $(s-a}] + (8-a)(5-6) { c+215 c}}

-(s−c) [ (a+b)8 - 2a6}+(5-0)(5- b) { 25-c) =(a+ d) $ (5-0) - Za} (<-C)+ { $−a}(S-1) (arf. =(a+b)[ 5(5−c)+( §- a) ; (-b)} - 20b (s−c)

(a+b) (s=cs+5"-as- fs+ab}~ 2a8 (5.0) ((a+b) [ 252(a+b+c)s+a8]- 2«b(6-C)/ =(a+b) ab-zab(s-c)

al{ a+b - asia abc

10 abromas)

QED

16) k ( b c d + c da+dab+alc) a b c d (a+b+c+d)==0 $i]

a

od可任意排到西成比例

(£a}= 2đ2+ 2ɛab

(bcdts dat dab+abcf

(2)

ardalrake+2(abcd

cbd adfc

+ bea bc+ 2abcd($al)

•af

*#$ (b-c)logx - (b−c) log y == (a - b) logaj ~(a+b) log z

□移順化簡: ( b_c) lox x +(c-a) log y + (a-b) logz=0 QEE (3)分解 (b+c)+ {*ce@et(a+b)=a-bic aabc勇式: (解)令a=b+c代入

M * = ( b + c) + b2 ( 2 c + b) + C ( 28 + c ) − ( b+c) -f=c___ abc (b+c)=0 ∵故式有a-8-c之因子又因原式為開於alcz輪换对辑 (Cyclic function) that ħ ib-c-a) £ ( ¢ a b ) z ✡] F 再因原式爲

*勇 abcz主次齋次式(Homryonerous)故除 述之三個 - 次因子外 尚餘之因子必為常额龙(即不含adc等

(字)故假設原式=

( = k(a-buc) (b-ca a) (c-a-b)

因止式為恒等式(Identity) 畝abc可為任意*数值。

★*➡ 2+2+2-1-1-1-2 —

一

(主)求花值亦可用比較保數法得一

設比較a*<佛數右方=小右方一绝

R=-1

(4) %% 6x* 1174-1042-194+ k 365) 41 £au - × 8★#E)

最值並水分解肝得之因式,

(B) = 2x2-11x9-104® =(3x+ay)(2x-54)

着原成能分解必為w.y之一次因式(3x+2y+2)(2x5y+b) 其中口暴禹常数项

• 6x-11xy-104*-19y+R=(3x+2y+a)(2x−54+b).

3694" gue m

1.of N-Na2CO3 that reacts with 122 gme BaC12.2420

2.1isre

0 y2+ ( 2a+3b)x−(50-26)yeab

比较两边偾數得

2a+38 ====0 50-24 14

(2)

(3

Vol.of N-We⊃COg that reécts with 4.88 gm Bé¢12•2H20

Vol.of N-Na2CO, originally used

4.88

×1,000ml,

122

40° min

2001

♦ 200 ml of Capent" Na2CO3 solution

160 ml.N-Na2CD

320 2003

解:(1)、(2)得 =3f_-_ 代入(3) 得=6

龙一6. 原式分解為(3x+ay+3) (2x-54-2

(5)設 2S= a+b+c, 試证

x abcd(a+b+c+d) == abed [a+b+c+d", &$qb]

kądrida+datratc-abcd(a+b‍+c+q}

ched(m-abyr a'od{cd-Ab)+ d'ab(al-cd}+c'ab(ab-cd)

(cd-ab)(fcd-dab+acd-cab)

cd-ab) | bd(bc-ad) + ac(ad-bcl

ca-ab)(bd-ac) (bc-ad)=(

cd-abo

dr ab=0 (ut ba-ac=0 bc-ad=0

ba-acac bc-ad

则a:c=a:名(艹莉衍变為8個比例)

鲠absd可任意排列而感比例

第一次預習試題

1)M為樟) ABCD=腰 BC 的中戛遢

Q.4.D

MENADA DO HE

EXES EFI B C & A B * F #31 OADM=ADEF-ABCD

(2) AABC中两友角日及C三分角绑书两腰十五及5EMAEF中奖

3.正方形

200x)

試從右图tam 之值!明根威表示)

BAC之分角转各& BD BC於X

刁

稽之二倍☆两銳角≠度數 (5)两船同時離-海港 ul 24/08 10 th l » 62 15 BL

一人20哩/時 南偏西:18 15駛行則2小时後二船相距着 7?

(6)設△ABC中,R爲其外接园半拉,s翼半周 4面積 試 (a) 5 = 48 cost cos Con

晶) (8–c)= 4 s tant

Hence Volume of N/2-HCl that would be required to) react with the excess of sodium carbonate

9.3. (1)Cold concentrated aulphuric acid rendera Lron. But hot concentrated sulphuric hold

fects with iron forming a mixture of ferrous and

ferric sulphate, and giving. off.

Fe + 2H2904 * Fes0, + 5021*

2H 2504

ddad de

2120...

Dilute sulphuric acid will react with iron án the cold with the evolution of hydrogen..

Fe + H2SO

H2

OWhen concentrated sulphuric acid and sodium nitrate) crystals are heated in a retort, the liquid that is distilled off is nitric acid.

H2 SOL + N&NOy * NaHSOL + HNO3

At temperatures higher than those normally used

in a chemistry laboratory, the reaction will proceed further.

NaHSOy + NaNO

NG250 + HNO3

At this high temperature, however much of the nitric acid formed is decomposed. į

t)when cold concentrated sulphuric acid is added drop

by drop to hydrated copper sulphate, the acid will acid will act as a dehydrating agent removing the water of crystallisation from the hydrated salt, unt 11 the white anhydrous salt is obtained

THEO L CuSO

5H20

removed by..

conc.h2804)

QUESTION FOR NEXT WEEK (22)

(Li Describe one method for the preparation and collection

of a reasonably pure sample of sulphur dioxide in the laboratory.

State the conditions under which sulphur dioxide reacts with (1) magnesium, (ii) litmus, (111) chlorine, (iv) lead dioxide, and describe and explain the reactions which occur,

Explain carefully how you would distinguish between the following pairs of compounde:-

sodium sulphite and sodium sulphate; (b) ferrous sulphate and ferric sulphate; zinc sulphate and aluminium sulphate. Compare and contrast the bleaching actions ddoxide, and chlorine,

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