1966-05-28 — Page 15

日八十月五年六六九一层公年五十五南民套中

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交

一、二、三年級學生,現任系主任爲羅會激授。宀幣】 踏大中文系現有學生健數二百一十四名,其中当十四名爲研究生,一百八十名爲 Jke-ok-te - ĮNE-FORMERÍ

六 在教授及學生,將燈加一倍。上述消息來都可靠方面之透露。 HKEKESKENKOA E -BUSERASER-BERKRETE-ZKRIDERICKAX 西文化的交流,因此,擬定計劃,在一九六七年時,就中文系學生鞍現险增加一倍

· 據悉,花大估為在今年就早時間,已計劃中文系的大發展,校寫該系主任策劃

·爲促進中國文化發展及加强中西文化交流 六 、特餅、香港大學中文系將得到加强發展,在港一九六七年秋季開始,系無論 教授及學生將增加一倍 課程亦增數項 目的

香港大學中文系

六七年秋大擴展

長沙灣警察小學

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謖賞不絕 六一 警察小學,於二愛人士指之旅演,對於該校合化界,新業界及校長 七日行游放日,潔。基日泰出科目有一生之努力,無不稱許,激師等数百人, LETTROKKK-4K-EE-VERTNES JE()) (REBAR CHF-KOCIN KE-OVERE.TALE. 來賓数百人、對各項展出,琳瑯滿目,突不生之爭,收迎恋者。 勝收,參與者皆散打賞品評。日鹨校 梁,木工及外活食品飲料,皆出自報 - ERKJE • V

GERIATREKEN-

買三然鵜四第

3九红月四年年丙鹰宴

英中會考數學答案

歐陽籃文

SUGGESTED ANSWER TO: RKESCE 1966)

MATHEMATICS PAPER I [son to

SECTION B (cont)

17, (as The wholesaler pays $1800 for the motor cycle?

retailer sells $2574

#

Let the price the retailer bought the cycle? Then, the wholesalers profit = $( 2-1800),

retailers

X-1800 x100%

profit=1804

مر

·rofit = $(574 −2) profit = -257-241007

Retailer's Profit 7% = 3 × wholesaler's profit

1

2574 - X, 100% = 3 ×

X-1800 x 100%.

1800

600 (1574 - D) = X(X− 1809)

CALO X* = 1800X

X" - /2002-15 444220

Не

for investment on Mars

vested $10:800 on $5 shares at $25 per share

The annual dividend = 25% of $5 = $14 per share,

By investing $25, he received $ yearly

X

$ 500°

The dividend 3xr = $500 x 3 = $1500.

share! sated his shares at $27 pers And the mo After the selling, be received a $27 £10000

$108001

Hence, his total receipt after 3 yr

270800 + $1500 m $12 300

- $10.000

The profit on this half = $12300

ta

= $2300 can to the nervest $7)

From tia & clls, we find that, the half on shaves gave a better post it, and by

$3800 – $2250 - £50 (Con to the nearest $16

必無

鹽

糖

(−1780}{ x + 780) = 0

\either 1-1980 = 0

ir I+780 = o`

or - 780 (rejected)

X=1780

"ANS The retailer bought the moler Cycle for $1980

**

for

finding the factors (2-1980) (24780) you may make use of the formula >--

6-490 = 144 œD + 617 7600 = 76/7600 = (2780)

answer a fellows?.

We can check the

The Wholesaler's profit to

retailer!

I

1980-1800-180 = 10%

1300

4574 - 19RO 1450

1980

Suppose that their starting speed X mph.

The time taken for I scent to cover the journey

the other scout

scant finished the jonger 24 carli former scout, hence,

The tatal length = AB+8C+ CD =(33x2+64)yda/32 yd, If we placad

post on A then the total no. of posts

from A-B

Be 20 q = 122 13+

Helded

Supporting

IMPOSSIBLE

CASES

from the above 6 wases, we find that, the positions

P

Q

are arbitrary: your may given mece stang

Conditions

fond

this from the

AP × AB=18-4 88, AB =000

The results AP = -20.94". AQ = 3.06", nuis APE3.06 AQ=2194 are both correct, you can interchange the pounds of

P 9 d.

Consquently the lengths of AP A2 are 20.72

(20(4)

13

Coi # à dre

solve the above

asked to b

an equation from

eed can be cal-

which the scouts startin

culated. In the above egu. x represents then

Starting speed

1818) The ratio of commis

The LCM of 1 54

the least

Value = lac=50¢ +$/=.

least possible combination of coins

vod-coins 2504 - Coins

least total no of coins w 10421

represents the actual no of coin, in the bag,

"must be

and, TC, is dXpetly divisible

Since

13 =208

C You may find these by Rohini dihala)

between

Love 07-13)

can solve this by ALGEBRI

com

2/0343230)

first equation

(The total area to be sain

776

fog

14150

15772

07971

Hum:33,4803.

1966) Given

33574 ~3363211

§ apart « both lie on the same it.

the same st

(Solution

AR

The lengths of

<A> Consider

AB 23

∙and

on & Corto 0/20)

OM AB

Let AP=2

Hence

then PB = 8′′ 2′′-

(*))(8) - (8-8)

We find the following

check the

> + 3 2 = ? &- colff of 2 tiom

th's Product of par

passes through the fowist 4 then the lowest pt.

Heasured from

−72 ± 8.944

0 3.056

Cause If Plies on HB produced.

Let Ar=2" then "BP=2"-8" Hence, (X)[8] < (2-8)*

which is mathematically.

If P lies on BA produced.

then, Ape 8+2

8X = X +16x+64

equation

From the graphs we

9=1.3

لے کا ہم نے

Travet Graph

integral solution

Hana,

702

-J = = =

tal no of cous #1704 34 *17 #

The man deposited $20000 equally in a bank 4 in $5 shares

„ds The half in a bank for compound interest

Principal = of $20000 = $10000

Rate of compound interest

Time takave for

7% pa.

3.

.700.00 78

$10700:00

7:49:00 78

$11449.00

201-43 75

$ 12250 43 } 4.

"the amount, after 3 yr = $/2250.42 The profit on this half = $1/2250, 43

cor, to the neart.

no solution for the

negative no, hence

mo solution for this case;

possible values AP are: 1223.944

ces Consider the pc Q

16 of Q lies on AB!

Let AQ X then QBE P^x! Hence

which is Case la

Caweb of ofres on AB.

B produced LET AQ = X" then QB = "-**

Hence!

which is case 30 (Le identical with CASE

Cast 36. & lets on 84

84 produced. Let AQ X then BQ - 2 -

hence

DISTANCE

Time (PM) - 2:00 2:05 210 2:15 Miter from glo A3 0.6

Ang. They meet at 3 mi away from A

Nabsum, after of tom..

2:25 2130 2135LITO LIN5... 1.7 2-6 3.8

5272

100

Duph

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