1966-03-15 — Page 14

日四十月二年午丙磨签

WAH KIU YAT PO

英中題試題預習專欄

Example 6

Solve 52-17+ 21-7 - 31-14+ 51 14

數學科 (十一) ·歐陽路文 ·

Solution Divide first all numerators resp; by the ir denomination

=(3+x/5)+(5+x'

Mathematics (11)

LESSON GA PERCENTAGE( [rofit & Loss Ta).

SOLUTION of EQUATIONS

§ A, Percentage: Profit & Loss por cent,

Example 1. A is 15% heavier than 6, and C is 15% lighter than B; by how much A heavier than € 3

per

cent is

Solution Lot 83 waight be 100 units of wt.

Then A weighs (1+ 15% 30f 100=115 unike.

Examples:

Saluthèn:

.

(1-15%) of 1oom 25 units.

-A is heavier than C by ·

J15-85

85

30-35,77

: A tradesman maiks on article at 40% above price, but give a discount of 15. in the £ on the marked price. What is his gain per cent? He also offers *i of the articles for the price of 20, allow. ing the same discount. Find his gain per cent in each case.

Suppose that the C.P. of the article in £100 (i). Then, the marked price =li+40%)fx100=(140

the selling price =()

He gains £133 - £100 =£33

His gain %

--33%

2100

sir If the c. P. per article is £100

Then the S. P

1133

The C.P. of 21 articles =£100×21=13100 ~~~£133×20=£2660

S. P. ... 20

•

He gains 1266 0 - 1 2 100 –£56a ̧

His gain %=

=26号2

Example 3. On a journey across New York a tan averages 20mph. for 70% of the distance, 35 mph for 10% of it, and 8 mph for the

"

(x-4)+(x = 8)

(x-8)(x-4)

*** 12x + 32

4

(x-7)+(x+5)

€2.50 - 7) į

24-12

2-12 +35

1. (2x-12)[15 123 + 35 ) - ( x2 - 12×+33)} 0,

HINTS IF ANS To Ex. 58

P

F19 1

A

Draw EN II PQ

2 x -

X=

M

Fig 2

Fig 3

then PN= QC (15sos a) and

PN = PB ( intercept theczem} Hence AB=AP..

Q C

12, In fig 2

}

NM. ND

AB+ AC = AP+(QC+ AC)=2AP.

let N. be the mid-pt of AC Join

Since N is the mid-pt of the hypotenuse

of it a ADC, then ND-LAC

And

M. N are mid-pts of CB, CA resp.

MNI/AB

< NMB= 48, but NDC = _C = «NMD+AMIND

«NMD = _MND

3, draw KH/BC ( to cut AY AT H).

HK-ŹCY (intercept thetrem), <XAB=44

< XKH=支H..

remainder · Find the average speed for the 5, By drawing a

whole journey.

Solution Suppose that the length of distance a roo má

Then, the distance at 20mph —70% of 1000-70M.

To m

The time taken at 20mph = 20 mph.

Bin X, and __Cosa,

<KHX=)He=d.

KX=KH=支 cr..

By Pythagoras. = √¢p"-g's Kepqs**

ANS

ANS,

日丑十月三年六六九一层公年五十五國民革中

盘和向並會人士保證- 該項計到並沒有發

得到良好效果。神父SE,現時可以六六6

【 雜問必須加以研究,否則不會變,鑑話:八三

於通过計圖得這裡風異套误,對屈一項複灌—黃大仙花織學 在交通失事案件中

默,且快將完成。

——元朗區泰安

兒童傷亡率甚高

交通安全會主席靳神甫透露·

心如就。 悠然剄廻具良好禮貌,無拦學生將應到器,C四六。 ,且有-

足傘架,不用久候之苦,可及學校,電話→0 均有吼位,其內不在站立,上落十分安 食坑口濃滑水灣中心 服務之優點,毌服務運到, 一證號,张戈ll进 此外,靳神父又再次表示:學魔巴士 校(錦田局信箱中 紅磡區:中

對應

- 六四一九. ]]]; 電話 誤——耶酒拿實樣 月初至发去年十二月 從各狱活動及乘都雅 因之獍系数而引致之 檮赏 |寳在一年級時,可工作,以微帶年學生

學童巴士計劃

路段由

短期内可實現

且財

百開

五備

條階

|在本港設立學寬巴士服務,乃爲一項急,

,亦係市民大衆所期望之大事。(南)

(#5) DEX(ES) •

四二九

此担承更大責任 在幼童時代卽開始,學校對 交通安全常識之灌輸

䒑. FE角寜I活 |蹬話 - 六四二九二三。 直落三樓二二一案,兒童佔一百八十七名航爾對此方面之注塞 家長教師會 ,黃傑——馬頭酒菜島,計七百九十名,通安全至斯,以引超躉猜第一小學

|激及青年學生之道路

。此外:學校又何在

合法巴士。 贤一千五百萬港元開發「學生亦服務 公司」,並於去年四月將項※ 路綫 先在九龍區展開服務 續謀推廣至港島方面 由某財團投資一千五百萬元開辦 現已進入最後準備階 ,一項使家長拳生高興的消息艾少少活。某勘湖蟧開鸯图茦巴士服诎稃有睨糍-鄀 风粥與無施,亦非六瓷棄他瞭版倒入十月1日下午七時,假一察。 《特泵 ) 指入六五臣六六年下限期中胡、神父当年九月旺洲而著之流器,「原燃借予宏李的挑杭潞法,其他有門外雨 Be勦街,特定于四——星村牡丹樓九 本版昨晚 星當精神問 段. 且快將完成 計用二百輛以上巴士 約分十五條有司署夜學部在發器,B親水埗區,內戰,南與地是胃中,總還在小學低年級六七點,還可令他晚區還該國遊熱點聽 周覺識(MIR 六八五五二 。 張

【九龍夜師同學宴賀 同學,近以陔班主任 二一〇蜜,話:八七四。〔》 新颗鐡珤九髂置至授时————灤屋村閂林根學,青觀:七六〇一內發授兒童以基本产們參加各棋社會學驗,因為甜的,當由各 周覺識氏榮獲動銜 星, r -c Oil - 恩心為陸總計,加入交通題材,以便聯集行,像長教師 一路上交通意外事件之以提高他們之發亮。 C桩港 -李雅安全教育于以上地和远夕到會來長 通安全法,對減少讓之交通安全活勳, 級任教

由於兒童在交通 各机酶物寫信,韩青树獠)香剂

,將可望在短期得以實現 「爲大衆所想盼之在本牌設立學院巴士服務

後準儂階段,相信在短期內斯可成爲事實 千五百萬元的學生巴士計劃,經已 示,媞安年所透露之第一集團準餅投资 據交通安奈會主席新寧漢神斐昨日

一

推上

E周

但塔斯悠演神父去年此一脫後,禸賀,鑿位十五示 成[!太子辮四四四

到

稿昨

件晚

時

、因此,在意,安全對記 視大陸醫者活動。從以往成龍體

徵詢交通安全會 當聽的强調,主人會 開始,武將絕再推廣至岛方面,靳神新源息。 斯離心昨日表示;上頂點帆並棄

满;八二一四六四,,化學(一)、雙 型巴士,大約分十五條路潑,先在九龍方,根戰巴士計劇已沙灣,否則然何遲遲中,各小外,並推它 謖 府審核。該等人士計價用二百懋以上之新,關上说消幾一古沉動下弋,有人林希丽娜,推夠突然嘴除照號九龍五女中學,說中中醫電 的意見,該會橫能支持該項熱啊之娩現,一,就且正中右關人爵加緊進行研究中。由組級八關同學神,八一{二〇一五,拳拳 升中專檞;英文一項極有將物之事 A第一、二 中山學校,電話-爪,志中開,化學科之道路常識,為一 寬年幼時,致班以 安全

下列佈人賣安: 許眞——林染治理,

有因

銀碼養校 交級,開光約

揹洽妫絡與答由意,螢家

施谷,學各恩席榮長師七

"

25 mph.

**

8 mph.

10% of 100m to mi, 20% of 100 m

方士作 進泚绝安亦

Gicas 1.5. leo + shp) ( sin & + Co≤ 0) =

(Sin 8+ Cos.0)

南屯用 交安全保障。燕辦他較深

Sin 8 cos σ

SM & CD38

25mph =

Bmph.-

-

-

sing)

Sino- !

The total time taken to cover 100 mi. is

(31 + 3 + 22 ) hr. — 6 // he

Sinb

−1)( 1+Sin®)

Six B)CH secos,

The average speedm6.

-15 mph..

(14 seco

§. B, Solution of Equations (1)

Example 4. Solve 3h+ķi hk IT-

2h-3k=-qhk povlastneg (3)

Eqcia + hk + + +-11-

Let A=4 and 8-%, then we have

imilarly,,ag (2)

3A+ 48

21-36== becomes 944 128–33 BA-

(62

A=1

Subet. A=1

A-U

(B=-2

3 (1) +48= ||

3x

Example 5 Solve x+3 2(X-2)

Solution: ro (x-2)=3x(x+3)

102

- 20

- 30 -30

-

。

3X-X-10

x = 2 or -1/

We should reject the case

the-denominator.

15

1=z which makes

豆素

=0jwR.S.

Sintex Cos of

Cos-oc

+☆ Sind cos x)

Sik”ot + Colfax + 2 SİKO GOSTI

Sinol cas ot{

(sln*od + Costex )&

Sinox Cor of

= seca_cocα=R.$;

(d) ́£.§. = Sin3d (1-sinf) – six f( 1 − sin3d)"

sina sin's - sinpß + sind sinß

Sinto-

a= laß

fan a cotß

Two partners invest £2000 and £1200 resp, ie

a business and agree that 20% of the annuar

...

profit is to be divided equally between them, and the remainder in proportion to the capital | invested. The profit for the first year £260; 1

how

will this be shared between them】

4, B ̄is 20% heavier than A, and C is 25% heavier than B; by how much per cent is C heavier, than 113

[Exercise GA

In the course of a year of my capital increases by 3% $ of it decreases by 4%, and the rest, increases by 69%, What is the percentage increase on the whole &

A sold a

B Sold it to

to B'at a profit of 40%.

"a protit of-60%-C-so loss of 25%. If D paid £137 more than it cost A, find the profit, A

made

·5,- My insurance premium is 8 guineas a year

for my car which is valued at £350, what' percentage is premium of the value.

Solve the following simultaneous equationer aly +6x=3xy

& Solve (a) -2 2-9

ofax.

Jx+m

(b) 2x-3 - 2-3=23