1964-03-20 — Page 14

十五國民中

《鹊轼》一九六五伴英文中學會考,有關中國史一科袒範爾,敬尙司發色荸

+ - 中國經典一科,以前訴與國文,一併作一科,但在明年開始,此兩科各一 林」之蘇浙小學」

明年英中會考中國歷史及低級中文科

科 明年起兩科各爲一獨立科目 中國歷史科以前與國文科一併算作一

課程範圍礙定

日十二月三年四六九一曆公年三十五國民華中

地潤

發光

崇宁小妹,表現得

【立科,餓文科總採創獻,已首誌進日志歡。明軒陸鐵一棚之園甜甜,特衛強冰十分還車 模其大賞活燊,聲鐵 不相上下,不然師資 可樂阄控残示 谢耳勋題,蝤語變音 本港之水適與英國者 陈清楚,篤後筴要

試題內容,以中國之通知 命題,分爲下四點+

相關用地點:發 優良,學生天才横溢 搡奏冠軍賀任沱同學

九僑第一萬,易女 附際代商館榮科

林

上上中

二樓事貫 省

阿臣緻又 ,竟有單登少究而母,在彈從一開馬地卡

幻懑力, 樱君乃

舞曲時,-

份鹚示出

大會堂之鄉鑑委員會 被過人之音坐天才及

保嶽兴女校小學學生

年 (四)(萬),(五)阿正R(書社),(六)(留鈞),比微者,散步態宿時十二,現年近百十一 年始能賨現,此音樂 源傳「首辦選館」 遴城(沈從文),(十)將勞ć

煜心

「二第四

日七初月二年展甲磨腳

WAH KIL YAT PO

雜 日

儷

五期星

持主儷伉員議臣屈

會獎頒次二第節樂音

面方樂音在生學港本揚讚 詞致氏屈

猶大目節項各之出演晚昨 就成之

掌鼓賓來

此意白珠光威局發:經沙監沓考首雄典 演出和內的東西式晚 音樂節,覺陶德税發市是弱致佛司由“夜問須多的項設應羞,

在第八的演说

市

市

√

大臣

之

沙先生領導下,香

王 彼浩:大不 音樂之發展亦朗文化 持其水準,博得下 開啓之一象徵,在傅 跌置。其绘荳有基愛

良之音响設備,足以上架造戰鋼 能令人璜極越音樂,競賽之時,但仍能保

姫至世界上每一音樂 英冠軍,保渴男女 學校之合唱,黃

炎音樂之延誤。以前

賀各人。 活動。最後,彼料稅 惜,香島中學之中

「湍急难南北之音 秘买无表演, 談談如何,音樂節乃 唱,英鑫佐治五珓之 發掘婚戒天才之風糁 T侯后女両音说 中心。結無論將來之 铋之初滅毋画言分 一所習樂學院,使缮,鼎雅各下午七之 會寫人批眾在港設立 受業於文之

並無附帶測者手中。

人「安•高壽推述」

好處,經無缺少,亦

不過粉,超來說运 今午授

傑出,雙被感動 羅冨師

文校進黨策之英詩 演出,台下一片

| 烈惓> 籍 篠之公開社术管器 男女校吳園。萃 瞷等,各洪均精彩 九龍馬利語文楧茜乃 魯及音在化工学 新,和灰者鷥坐保 餮之再被祖剪邱大合

鋼協獅曲演奏一 ̊中做試合唱,拔萃女 ,在座觀衆均報以紧 閟阁,按拲爲授徐永 最受讚賞,一曲嘅移 校之中被近英證戴證 出国引精彩,但何以,聖保祿中學之女鑿 昨號之十八式演 沐術硏之手風呠獨奏 「集體,中學

新制(簡)

拎授。 分,而之長,整治「華僑司 |表達出巴哈之『小 育乃心谈

我逃欣汽廂之 之説現一年勝于辘年 犟G繊岵一台講,衛乃傑兴人主

靜思,互相推出,時,在沙互道

【英县印紙之口琴大樂 國師種專科學校,定

歡的陈術良,今(十)日下午五

【演,騙這些丧子,闻言灣

升中指南」英文科教材

今日在麗的呼聲播出

上午十時常

時間:

下午九時正

ENGLISH LESSON 38

SOME USEFUL WORDS

女,

馬經

」,當然基大門了,老馬不能飽

· Colours:

ted

yellow

blue

white"

black

green

orangd.

purple

pink

brown

Things to wear:

coat

belt

tie

'boots

waistcoat ? butron

slippers

collar

cap

blouse,

dresa

hit

trock

comb

handkerchief

overcoat

jacket

jacket

gioves

skirt

Meeves

РуЇаа

shorts

shizt

pa ket 40:ks

TO BET

早昨

|

(仲筋)教育司磐主辦之英文

蘅浙小學生于案 獲獎事裔日報杯後習影〔本報記者)

順

一:京仁院禮堂,

,今年三月廿一晚無行,地點在

主治传別

上湖南名,都市 團贊鹊,紛紛邀請,亦儒蘇浩,相信居

相

全港佛教徒協力

14) •

仍落

Food and drinks

con

salt

cheese

butter,

milk

wine

beek

ginger

· serater-water.

Pork

honey

chocolate)

coffee

華僑日報英中會考試題研究委員會主編

ham

flour

salad,

beer

fian

broad

biszait

台

lemonade

化

學

(十)

九六四年度

文中學會考試題預習專欄

gen atom

from an oxidising agent to form sulphuric acid, a very stable, molecule.

S02 + H2O

H2SOJ

:

H2SO3 (sulphurous acid)、

(from an oxidising agent) = 150

Thus sulphur dioxide reduces concentrated nitrio

acid to nitrogen peroxide,

Fugger

pie pudding

Question 17.

The family

buber

parents

'aunt

father-in-law

mother Brother

grandson

grandfather cousia grandmother nephew

njace

mother-in-law)

son-in-law

draghter

granddaughter trusband

uncle

wifm

bathroom

'attic

kitchen

garaga

Javarory

andy

celiar

Rooms in the house

sitting roog

bedroom

dining-room

In the school:

Papil

寸瓷梅觀念。

以上者,財院內小素。

院內攒十11寸安留

(examination

desk

playground

chalk

dustes

婚

blazkboard

plation]

pen

mark

pencil

Deport

e of traffin

lanw

motor-cyde

rickshaw

boar

fecry

finer

HOT DOIN

Junk

#mpe

「EXERCISE: 38

the corract spelling in the blank

We play football in the pl.....ə. "My

We

M

daughter-in-law

can see different kindg of animals at the zouy

The son of my uncle is my iC......................

A small dog is called a pu..........

The people who live in England are called Eng. and the people who live in Frans are called Fru

ose the best word to go in where there is an X. Write the number of the

this in the space.

This book is very X' because it contains many victuner. F

1. ingreased

2. interesting

3. instructed

4. interosted

Please X to my words.]

1. hear

2. zsk

3,believe

4. Listas

We'łuve music Lesson X Monday.

1. at

2. ju

3. oo

about

X some money and give it to the poor,

continued from the ninth issue)

Explain the terms: "oxidising agent" And "reducing agent". Select from the following substances examples of each, and write an account of the ው እ -- periments you would perform with them to illustrati your answer: hydrogen, carbon monoxide, chlorine, sulphur dioxide, nitric acid, potassium permangan-. ate.

Answer.

A substance is said to be oxidised when

(1) it adds on oxygen, chlorine, sulphur or other

atoms

or groups capable of forming electro- negative radicals or anions

(2) it loses hydrogen, metal, or electropositive)

radicals or cations,

(3) it loses electrons,

A substance is said to be reduced when

(1) it loses oxygeny chlorine, sulphur, or other

atoms or groups capable of forming electro- negative radicals or anions,

(2lit gains hydrogen, metal_or_elecvropositive/

radicals or cations,

(3) it gains electrons.

Therefore an oxidising agent is one which is capable of causing substances to be oxidised and is then able to impact to them oxygen, chlorine, sulphur, electronegative radicals, etc.for to remove hydro- gen, metal or electrons from them. Similarly, a reducing agent is one which is capable or causing substances to be reduced by removing from them oxygen, chlorine, sulphur, electronegative radi- cals, etc., or by imparting hydrogen, metal or elec- trons.to. them.

First example of an oxidising agent chlorine.

Chlorine oxidises by adding oxygen to other subs- tances. Thus if to a solution of sodium sulphite chlorine gas is passed, the sulphite is converted to a sulphate, which can be identified by the form- ation of a white precipitate insoluble in dilute hydrochloric acid when barium chloride is added..

H20 Na2S0y

2HC1

Na2SO4

+ 2HCJ

ji Na2SO.g + H2O + Cl2 = Na2504 Oxidation is carried out by imparting chlorine toʻ another, substance. Thus to a solution of ferrous chloride chlorine gas is passed, The iron is changed from the ferrous to the ferric state, which can be proved by the formation of a reddish-brown preci-. pitate when sodium hydroxide is added.

2FeCl2 * Cl2 2FeCl3 Second example of an oxidising agent nitric acid,

Following are the basic equations for the decom- position of nitric acid;

J2HNO3 ( dilute )

2HNO, (concentrated)

H2O + 30m Sulphur is oxidised by concentrated nitric acid to) sulphuric acid..

2NO2

1

6HNOG

6N02

+

30.

S

So.

* 30

H2O

S.

H2SO4

6N02

H250 4

BHNO+ In the "brown ring" test, the ferrous sulphate in oxidised by dilute nitric acid to the ferrio sult, phate with the liberation of nitrić ožide.

correct.

2. brings :

3. together

4. collect

the plural of' the following_nouns]

676504

ç. handkerchief intymi d. knife

ZHNOG

+ 3H2SO4

-

2NO 30

6FeS0

2HNO

baraboo

ó, continued

Ambed

suceed |

Exercise. 36 Answers.

- í,, dressed

b. bresk b. Lovely

exkatast

c. much

R. xlived

re. camel

LC, bravery

aptain

fd. wiece

d.

ceiling

é bengert

d. enable

*. lengthy

20

ōi 3F®2 (50%) + 3H20

....

+ 3H2SO4 +

3F02 (SO4)2 + 4 H2O +2NO First example of a reducing agent sulphur dioxide,

Sulphur dioxide in the presence of water forms sulphurous acid, a very unstable acid. As a rulo, an unstable compound has a strong tendency v byte come stable. This is achieved by removing an oxy-

2HNO

2N0Z

+

H2O

*

*

*

H2SO4

2HNO3

+

50%

H2SOL

2NO 2

́Sulphur dioxide also reduces acidified potassium permanganate solution from purple to colourless.

Fllowings the equation showing the oxidising action of potassium permanganate in acid solution

2KMnO + JH250% 5S02 + 3H20

+

*

→

*

50

K2SO4 2MnSO4

5H2S0

→

3H20 +50

2H2

0 =

carbon monoxide

5502 2KMnO4

K2SO4 + 2MnSO4 + 2H2SO4 Sevond example of a reducing agent

Carbon monoxide burns to carbon dioxide by remov- ing oxygen from ferric oxide, which is réuces to

the metal.

Fe203 + 300 - 2Fe + 3002

Question 18.

(*) 4.5. g. of a metal M produce 5.3 gm of the oxide

of the metal. Calculate the equivalent of M.

(b) What volume of hydrogen (at N.T.P.) would you

expect 7.5 gm of the metal to displace from an cess of a diluts neid?

(a) What would be the volume of this hydrogen at

17°c. and 740mm、pressure?,

(d) Define atomic weightr

OXF

(e) How is the atomic weighs related to the equiva

lent weight of an element?

(f) Assuming the valency of M to be 2, calculate the

atomic weight of the metal.

(g) Write the formulae for the bromide, sulphide,

hydroxide. nitrate, and sulphate of M.

Anewer.

(a) The equivalent weight of a metal is the number of grams of the metal that will combine with 8 強 of oxygen.

6.3 - 4.5 = 1.0 gm of oxygen combine with 4.3 gm

of the metal M.

Therefore 8 gm of oxygen combine with 4e218

1.8 =.20 gm of M.

The equivalent of the metal M is 20, (b) The equivalent of a metal is the number of grana

of the metal that will displace 1 gm of hydro- gen, 1.0., at N.T.P. 11,200 ml. of hydrogen.

The gram-molecular volume of any gas is the vol. ume occupied at N.T.P. by one molecular weight.

of any gas, which is equal to 22.4 litres.) 20 gm of M will displace 11,200 ml of hydrogen at N.T.P.

Therefore 7.5 gm of M will dispiace

11:200 * 7.5

= 560 x 7.5 - 4,200 ml. 20 7,5 gm of M`will displace 4,200 ml hydrogen

at N.T.P. (c). 4,200 ml of a gas at N.T.P. are at 17 ́0 and

740

mm pressure, occupying

42.00

290 273

篇

760 740

m1 = 4381 ml

The volume of hydrogen at 17°C and 740 mm would

be 4581 ml

(d) The atomic weight of an element is the ratio of

the weight of one atom of the element to one- sixteenth of the weight of one atom of oxygen. Examplest hydrogen 1.008; oxygen 16; chlorine.

35.5.

(e) The ratio of the atomic weight of an element to the equivalent weight of the same element is always a whole number. The number is called the valency of the element. In different series of compounds an element may have different equi- valent weights and different valencies, but the product of equivalent weight and valency is for all series the game, viz, the atomic weight of the element.

! Example: the equivalent weight of carbon is 3, the valency 4, the atomic weight = 3 x 4 = 12. (f) For the metal M the equivalent weight. was found ta be. 20。 The valency is 2. The atomic weight is therefore 20

40.

(g)

•

x 2

MBг2, MS, M(OH)2, M(NO3)2, MSO4*