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MILLE DALE PRESS

English Language (13)

PHRASAL VERBS (IV)

Choose the best answer from the choices. given.

1. You'd better act

B. If you go on shoplifting, you wil)

end

C. at

B. off

D. out

my advice

before it is too late.

A. at

9. He was very depressed when all his

plans, fell

B. on

D. off

A. out

B. through

C. off

2. You are my friend. I hope you will

10. John fell

D. over.

Mary over

some

trifles.

A. In with

c. off

A. nut with D. for

D. Rout

C. out

.n. in

A. on

B. for

Di-by.

The volcano suddenly blew

15. The principal Tet. the naughty.

1993年中學會考預習專機:

LAST SEAR

the whole city perished.

BA. out

student

·with a warning.

23. Be always ready to stand

30. The shoplifter fan

before we

could catch him..

A over

B. Into

C. off

D. out

in

A. down

Coff

C. out

B. off

D. in

own principles.

A up at

B. on at.

31. The thier was still at large.

16. Having been sick for months, John!

father passed

C up for

D. out for

police were beating,

for him,

last night.

24. He has thrown

very good job

A. out

C. by

B. down

D. away

17. As soon as I get my salary, I will:

25. The assassination has triggered

and gone off somewhere. A. Up.

Cover

A. about. C. 15

B. down

D. out

-0. on D. off

32. It was very hot and John took

shower to cool himself:

郭日僑華

一期星日四廿月二十(〇九九一)年九十七國民中(26)

A down

B. up

pay

my debts,

∙A, in

C. out

B. on

D. off

*C, over

D. off

war between

the

two

18. I don't know why she picks

nations.

A. up

33. These

experts

are capable

him all the time.

She seems to

C. over

B. on D.-off

ironing arise.

any problems that

hate him.

A. into

26. Would you lend me your pen?

Mine

A. .up

C. on

B. off

D. at

C. away

B. cat

D. off

has run

A. up to

C. in

B. down on

D. out

police had successfully crack

the triad societies.

11. It's no use hanging

Nothing is going to happen. A. round

12. John finds it hard to live

his father's expectations,

A. cn

20. Be patient, the train will pul

A.. Over

here,

B. into

19. have picked

Some Italian

C. off

D. out of

34. We expected him to dre months ago

but he lingered- in pain.

8. over

Dup

during my visit there.

A. around

A. up

C. on

B. off

D. at

t. up in

B. down

D. up to

-soon.

27. This theory has been fully tested and there is practical

confirmation. A. On C. down

C. on

D. sway

·D. aff

35. The new TV. station manages to sign

most of the best performers:

8. out

D. into

A-in

Cup

B: out

De off

A. up

∙C..in

8. on D. down

5. That heartless husband did his. wife by poisoning her. A. away with

13. have put on much weight.

td. let my dresses

I need

a bit.

C. over

6. down with D. out

A. down

C. out

B. aff.

D. in

A. up

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1 will stand 21. You can rely on me.

you whenever you need ma.

B. by 0. at

28. John has followed the plan

the end.

A, through

to

Answer's

1,0

2. D.

3. C

4. 8

5. A

C. up..

B. on 0..off

6. C

7.0

A. A.

9. 8 ··10. 8

11. A

12.0

13. C

14. A

15. B

29. That gambler ciced his fortune

16.0

17. 0

18. C

19. A

20. C

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The lawyer, is still drawing the contract for the sale.:

A on

B. off

14. We are counting on you. Don't let

at the casino

21. B

22. B

23. C

. 24. A

us

down

22. This symbol stands

love and

B. off

Tiberty.

A. through

C. off

B. away

D. out

26.0

27. B

28. A

29. B

30.

31. A 32. D

33. B

34. C

35, C

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7號金滿樓3A

#$111

1991 中學會考預習專欄。

明德出版社

MILL & DALE PRESS

Physics

Exercise 13 Momentum

(where necessary, take g = 10 ms):

Мак

1. As shown in fighendab a block of mass 4 kg travelling with speed

-1

15 ms collides with another block

of mass 6 kg travel in opposite "direction with speeds"

Figure 2(6)

the trolleys stuck together after collision, find

(a) their common velocity:

(b), the energy, lost in the impact.

3. A gun of mass 3x10 kg which can move freely on a horizontal ground,

fires a shell of mass

shel

103 kg with al If the muzzle speed of 1800 hs. system (the gun and the shell) is at rest before firing, Find

(a) the momentum of the system

before firing.

5

If

(b) the momentum of the system after

firing. (c) the recall velocity of the

just after firing.

cun

after impact, the 4 kg block returns with speed: 3 ms shour to figure

(b), find

Before Impact

5 my

4kg.

6 kg

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- smooth þorizontal floor

台灣學生機票一年效期 R

Figure 1(a)

After. Impact

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smooth-hat|zontal floor

Figure 1(5)

(a) the speed of the 6 kg block.

after Impact.

(b) calculate the energy lost during

the impact.

(c) in what form will the lost

energy be dissipated?

2. As shown in figura 21a) and 2(b). the trolleys are travelling on smooth horizontal table before and after impact.

Before Impact

$3.

4. A ball of mass. 2 kg is projected horizontally with speed 12 ms"!" towards a vertical wall and is rebounced back horizontally with speed 10 ms 16 the time of stentact during the collision, is

0.1as, find

chote a momentum of the ball Before and after collision.

(b) the form acting on the wall

during collision.

Figure 4

(a) What is the velocity (magnitude and direction of A after the collision?

(b) Calculate the average forcé (magnitude and direction) on A during the collision.

(c) Calculate the average force (magnitude and direction) on B during the collision Compare the result with that of (b), 4 (d) Calculate the fraction of energy lost during the impact. In what form will the lost energy be dissipated?

Solutions

1. (a) Taking the direction

right as positive Momentum before impa (4)(15)+(6)(-6).

24 koms-12

Momentum after impact.

"(4)(-3)+{5}{v}

6v-12

conservations

_momentum.

PUBLIC

5. A ball of mass 0.4 kg is released from a height of 18m onto à horizontal floor. It rebounds to a height of 0.8 m,

(a) Calculate the velocity of the ball just before and after impact?

(b) If the ball is in contact with the floor for 0:02:$. what is the magnitude of the average force exerted by the floor on the sphere during impact?

8 ms "1

6. Two trolleys A and B move towards

1

and each other with velocity 4 ms"

respectively. The mass of tralley A is 12 kg and that of B is 3 kg.

The two trolleys remain in contact for 0.5 seconds during the collision. After the head-on

rebounds collision, B

with a +1 velocity of 4 ms 85 shown in figure 4.

before collision

Figure 2(a)

Figure 3

ans

Since the system is at rest before

(b) By Conne

momentu

momentume firing

total

Tinear

after

(c) Let the velocity of the gun be

after firing.

-{2x105)v + (103][1806) = 19

(Ans.)

The negative sig indicates the gun will recoi

(a) Momentum

the

impact

•{2}(12)

the 6kg-block will nove with 6ms to the right.

(b) K.E. before collision.

· |-|(4) (15)3 + 2(6)(6) 1

558 J

*

K.E. after collision

|||(4)(3)2 + {{6}(6) ►

126 0

Loss in energy 558 126

432.0 (Ans. 1 (c) Mainly converted into heat and

Sound energy.

2. (a) Taking the direction to the

right as positive Momentum before collision

(4)(33)+(6)(~8)

84 kgms**

Momentum after collision

(4+6) V

10 v

·10v

84:

8.4 15

(Ans.)

The trolleys will move to the

・24日

Change In momentum

(-20)-24

-44 kgms

before

(Ads)

(The negativa sige indicates in opposite direction).

Magnitude of Change in momentum is 44, kgms

(b) Magnitude of average force

- Magnitude of Rate of change of

momentum

440N

5. (a) Velocity before impact

21104128)

6 ms (downwards) Velocity just after impact

EXTOJ (OB)

4 ms (upwards)

(Ans.)

(Ans.)

(Ans,)

(b) Magnitude of Rate of change of

momentum

·(0.4)(4) - (0.4)(-6)

=200N

The average force required.

5. (a) Take the direction towards the

right as positive.

Let the velocity: of A after the collision be Vas

Initial momentum of the system

= (12){4) + (3)(-8)

24 kg

Final momentum of the system

(12)(V) + (3) (4)

12y + 12

By conservation of mome

24 = 32v + 12

the velocity of

towards the right.

(b) The average force on A

= rate of change of momentum of

A

(12)(1) - (12)(4))

-72N

0.5

Ans: The average force an

72N towards the left.

(c) The average force on B

rate of change of momentu

#72N

0.5

(318)

the average force on 8 is 72 towards the right.

we see

Compared with the result of (b), that the average force exerted on A by B is equal in magnitude with the average force exerted on @hy A but opposite in direction. Thus, it satisfies Newton's 3rd Law of Motion

(d) Since there is no change in potential energy before and after the impact, therefore the energy loss in this collision 1s equal to the kinetic energy. loss.

Initial kinetic energy

•12}{4}+3)(64

#192 J

Final kinetic energy

• †(12)(1)2 + }{3}{4}?

307

The fraction of anergy lost

Ans.)

200N+ weight of the ball

200+ (0,4)(10)

204N

(And.)

The lost energy converts mainly into heat energy and sound energy.

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3312 1188

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