二七十七國民蕈中

育 開港 日九初月十年辰戊饜夏

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二十四:秋如向經理 挑戰

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四期星 日七十月一十(八八九一)年七十七國民華中20)

爲認通孝費 能不永藏西

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1989 中學會考預習專欄

明遶出版社

MILL & DALE PRESS

Chemistry (8)

mass

of

the

2

1.7 The

of one mole constituent particles of substance is often known as LS

molar mass (M). Its unit is g mol e.g. M(Mg) = 24 g molt

MCH250)

= (1x2+32x1+16x4)

-1 28 g mel M{MnO) = (55x1-16x4) 119 goli

e.g. (KC) in 25 cm3 of 0.4M KC1

solution

25 1000

- 0.4 X

0.01 mel

1.13 A Molar solution of a substance is one that contains one mole of the substance dissolved in idm the solution.

of

Calculations on Chemical Formulae 2.1 The empirical (simplest formula of J compound show its constituent atoms and their simplest integral ratio.

R. Chu

Unit 5: Revision notes On calculations

chemical

1.8 Thus, for a substance x.

Mass of X in grams

M(X) in g mol

2.

1.

Basic concepts

8.g. M{tact2)

11 g mol

n(CAC!

2.22

=

1.1 The relative atomic mass (4.) of an element is defined as the mass of an "average" atom of the element relative to the mass of an atom of carbon-12, taken as 12 exactly.

- 0.02 mol

tr 2.22 g of CaCl2

1.9 The molar volume of a substance is the volume occupied by one mole of its constituent particles particular temperature

e.g. Ethane has an empirical

formula of CH, indicating

that it is composed of C and H !

Lums in the ratio 1:3.

2

2.2 The molecular formula of

substance shows the actual number of each kind of atons in its molecules.

e.g. Sthane has the molecular

formula of Gels

Thus, for a covalent substance

Molecular Formula of X

nx Empirical Formula of X where n is an integer.

A, of an

element

Mass of an "average" atom of the element

- x 12 Mass of an atom of

carbon-12

at

and

pressure.

it is a units.

ratio and hence has no.

Molar volume

of X

Molar mass of X Density of X

Rolar 1.10 All gases have the same

volume at the same terature and pressure.

Q.1 Calcate the

ro

The molar volume of

22.4 tm at s.t.p.

aturi Kuleric Beessure.

15

20

gas X,

The mass of an "average" atom of an clement is the weighted mean of the masses of all its isotopes, i.e., taking both the isotopic masses and proportions into account.

e.g. chlorine exists d5 two

37, isotopes, 171 and 350), in

the ratio 3:1,

17

Thus, 4, (C1)

=

35x3+37x1 3+1

35.5

1.2 The relative molecular mass (M) of

a substance is just the sum of the

relative atomic masses cl

atoms contained in its

formula.

8.g. (HS04)

= 1x2+32x1+16X4

= 98

xx

1.3 The formula mass (Fμ) of an ionic compound is just the sum of the relative atomic masses of all the atoms contained in its empirical (simplest) formula.

e.g. F, (CuSO4.5H20)

=63.5x1+32x1+16x4+(2x1 +

=249.5

c.9. n(02)

Tue of X at s.b.p. Molar volume of gas

at s.t.p.

in 72 cm3 of oxygen gas

at s-t.p.

m3

72 cm

24000 cm

= 0.003 mol

1.1 The concentration of a solution is commonly expressed in terms of the number of moles of the solute in

on

cubic decimetre of the solution. It has the unit

-3 mol dm This is also known as its molarity and denoted as M. Thus, for a solute X,

HONG

,2-)=52x2+16x7

Eμ (Cr202-

=216

1.4 The mole is defined as the amou

of a substance which contains

many elementary entities of the substances аз there are atoms in exactly 0.012 kg (12.00 g)

of carbon-12,

carbon

The elementary entities refer to

any type of particles that may

represent the chemical constitution

the investigation,

of

under

atoms,

etc.

the amount

of

substance

e.g. molecules, ions. electrons,

denotes

n(x) substance

X in moles. 2.9.

n{H20)=0.2 no?.

1.5 It has been found that 12.00 g of

carbon-12 contains 6.02x1012 carbon atoms. This number, 6.02x1023 is called the Avogadro number densted

as L. Thus, a mole often refers to the Arogadru number of particles of any particular kind, e.g. atoms, tons, molecules, cars, etc.

1.6 One mole of a substance is just its relative atomic mass (foratons), relative molecular mass I for molecules) or formula mass (For tonic compounds or ions), expressed in grammes,

1989 中學會考預習專欄

流出版社

MILL & DALE PRESS

Economics (8) ·

is

Alain Li

INTEGRATION Integration. the combination of existing firms to form a larger one. This is a convenient way of expansion since it can save time in setting up new plants and recruiting professional

staff.

TYPES OF INTEGRATION

There are 4 types of integration:

A. Horizontal integration

When two or the same product combine to form a

more firms producing

Concentration of X

Amol dm3 (or

Molarity)

Amount of solute

in moles

Volume of the solution in dm3

9. 21.2 g of anhydrous sodium

is

dissolved

to give 400 cm3 of

pepcs comotion by mass эт

the

Q.2 Aydrate has

percentage compositi 20.25% iren, 11.5% sulphur, oxygen and 45.30% water. Find its empirical formula.

0.3 Hydrated magnesium sulphate (MgSO, xh26) consists of 48.9 % by mass of the anhydrous salt, what is the value of x?

3. Calculations on Chemical Equations Q.4 3.425 y of lead(II, III, IV) oxide (Pb204) is reduced to lead using hydrogen gas. Calculate

(a) the mass of lead obtained, (b) the volume of H2 ças reacted,

measured at s.t.p.

Q.5 Metal D is in Group II of the Periodic Table. 1,5 g of it is added to some dilute hydrochloric acid, 448 cm3 of hydrogen gas is collected at s.t.p. and 0.2 g of the metal is left behind. What is its relative atomic mass of B.

4. Calculations on Volumes in Gaseous

Reactions

of Combining Volumes states that "when gases react, they do so in volumes which bear a simple ratio to one another, and to the volumes of the products provided that all

at,

4,1 Gay-Lussac's Law

KONG PUBLIC

Now, M(Na2CO3)=106

21.2

0.2 Nol

*.* Vol of solution=0.4 dm3

.. concentration:

0.2

Daz

-3

=0.5 mol dm

(cr. 0.5M)

1.12 The amount of a solute contained

in a known volume of its solution with à known concentration 13 readily found by using the- relationship below.

Amount of solute Molarity x vol, of

in moles

single

solution in ɗm3

firm, it is called horizontal integration. There are 2 causes for horizontal. integration:

1. Lo enjoy economies of scule; ii. to eliminate competitors.

B. Vertical Integration

When firms operating in different. stages of production combine to form a single firm it is called vertical integration.

When a firm combines with another in 3 preceding stage in the production process,

called it is backward integration.

When a firm combines with another in a latter stage of production, it is called-forward integration.

There are 3 causes for a vertical integration:

1. to enjoy economies of scale; ii. to ensure a steady supply of

raw materials;

iii. to ensure a steady market for

products.

corrected to the same tempereure and pressure."

of

nitroge acts with 750 cm3 hydrogen to produce 100 cm3 of ammonia.

Thus, vol. of No:val. of H2ival, of

4.2 The

= 50:150:100

MP3

= 1:3:2 (simple whole-number

ratio)

Avogadros Law states that equal volumes of all gases, at the same temperature and pressure, contain an equal number of molecules.

The reverse 15 also true, i.e. equal number of molecules will have equal volume, measured at the sane temperature and pressure.

C. Lateral Integration

When Firmas producing related but not competitive products combine to form a single firm, it is called lateral integration.

There are 5 causes for a lateral integration:

i. to enjoy economies of scale, especially in marketing:

ii. to reduce business risk through the diversification of products; iii. to herefit from its existing popularity by extending its brand names to other products:

iv. to offer extra services to attract customers from competitors;

v. to enable a greater flexibility in the use of resources.

D. Conglomerate Integration

When Firms in totally different lines of production combine together to form a single firm, it is called conglomerate integration.

There are 5 causes conglomerate integration:

Avogadro's

Law

volume of gas number of molecules

4.3 The Avogadro's Law also explains why gases have the same molar volume at the same temperature and pressure. This is because one mole of a gas must contain the same nurber (the Avogadro number) of molecules.

Q.6 What is the volume of oxygen required to burn completely a gaseous mixture consisting of 40 cm3 of methane (C4) and 45 cm3

of carbon monoxide (CO)?

Q-7 50 cm2 of a mixture of methane (CF) and ethane (C2H6) required exactly 115 cm3 of oxygen for complete combustion. What is composition by volume of the original mixture?

the

Q.8 12 cm3 of a gaseous hydrocarbon requires 36 cm3 of oxygen for complete combustion, giving off 24 cm3 of carbon dioxide. Calculate its molecular formula.

Solutions to the Problems

Q.1 Formula mass of Na2003 10H0 - 206

.". Z of Na

0.2 Now

*.* 1 mol

i.e.

X - H250 → X504 + H2

New

i.39

x: 1.3 22400:448 x = 65

1 mol

22400cm3

at s.t.p. 448cm) at

5.1.D.

Q.6 N.B. Write a separate equation for

the combustion of each component.

202(9)002(9) + 2920(2)

2. mol

C(9)

+

1 mol

1. vol

40 m3

* cm2

2 vols (by Avogadro's

Law)

Vol of O2 required

200(9) + 2(9)

'.' 2 mot

i.e.2 vols

by CH1 = 2x40

= 80 cm3

+2002(s)

1 tol

1 vol (by Avogadro's

Law;

.*. 45 cm3

7 cm3

Vol. of 0, required by CO =

x 45

23x2

"286 × 100 = 16.1

% OF C

12x1

=

286

* 100 - 4.2

16x3

Hence, total volume of

30+22.5

- 22.5 cm3

required

% OF O

=

* 100 = 16.8

-% of H20-

286 18x10

x 100 =

62.9

286

:S: 0 H2C .239.45.3

006: 0.36: 1.44: 2,52 0.36.0.36 1.44” “P 0.36 0.36

1:1:4:

. its empiri

(N.B. In the case of hydrates, the

vator of crystallization is treated

0-3 M(H20)

= 18 g mol-1

= 120 g mol-1 M(MgSO4) M(MgSO4**H20)

=

(120+1)

.. by mass of the.

12

salt

= 102.5 cm3

Q.7 N.B. Write a separate equation. of

the combustion of each yas.

Let the volume of CH2 be x cm3. Then, the volume of Cylle is

(50-x) cm3.

202002 + 210

B

RARIES

120+18x

48.9 (given)

120

120+16x

X =

be a whole

685 g mol

207 g mol

1

Let the mass of Pb obtained be x g and the val. of H2 used be y dm3.

→→→→3Ph + 4H20 Ph204+ 4H2 *.* 1 mol 4 mol

3 mol

i.e.685g (4x22.4)dm3 (3x207) g

Now 3.425g ydm3

X9

(a) x:3.425 = (3x207):685

3x207 X =

685

2x 3.425 = 3.105

(b) y:3.425 (4x22.4):585

CHA

1 mo!

2 mol

i.e.

1 vol

2 vois

x cm3

[By Avogadro's Law! ? CT?

Vol. of reacted with CH * 2x cm3

202H 2 mo!

+

702

+4002+ 6420.

7 mol

7 vols

i.e. 2 vols

(By Avogadro's Law)

(50-x) cm3 ? cm3

vol. of 02 reacted with Call

*(50-x) cm3

.*. total volume of 2 reacted

=-2x + 2(50-x)

:= 115

(given)

1.e. 2x + (50-x)

= 115

Q.8 Let its molecular formula be Cully.

CHу + (x+4) 02→→→XCO2 + $120

** 1 mol (x+2) mol

1.e.1 vol (x+) vois

x mol

x vol

(By Avogadro's

Law)

12x cm3

.*. 12 cm3 12(x+) cm3

vol, of 102 formed = 12x

= 24 (given)

.* ́Vol. of O2 reacted = 12(x + )

y =

4x22.4

x 3.425 685

= 0.448 Cm1 (or 448 cm3)

= 36 (given)

1.8.12(2 +

= 36 (as x=2}

y = 4

Q.5 Let A of B be x.

Mass of 8 reacted = 1.5-0.2 1.3 g

ii. to reduce the business risk through the diversification cf products;

iii. to break Chrough Lae difficulties in expanding with its existing products;

iv. to re-organize the existing

for resources

profitable production;

more

margerial

v. to re-organize the firms in order to improve efficiency.

METHODS OF INTEGRATION

There are 5 methods of integration: A. Merger occurs when two or more firms combine into a single firm. Their separate ownerships are combined into a new single entity as more or less equal partners.

B. Consolidation is a kind of merger when the firms involved are public companies or corporations.

for

3

C.

i. to enjoy economies of scale;

Take-over occurs when one firm buys up the ownership of another firm.

D.

E.

Hence, its molecular formula is

24-

Trust is the term for a large firm formed by the combination of independent firms. A trust 35 responsible for exercising the common policies agreed upon by the individual firms.

Cartel is the term for まして association of firms which acts as the representative of the industry. The ownerships remain separate, All that 15 shared is some COMMOTI policies.

can

THE EFFECTS OF INTEGRATION Continuous integration may finally result in some large firms dominating the market. These large firms occupy a major share of the market and are able to control the price and the output. This is called 'industrial concentration'.

If the industrial concentration becomes serious, the consumers' benifit may be threatened. So in some countries there are anti-trust laws to forbid those combinations

at aiming

reducing competition and controlling the market..

程不住的情

·朱秀娟、

假女明星比得過紫鬱的。」 我的发居都喜歡紫書,氓脱上還沒有那 「媽,我倒不反對。」瑞芳說:「

的好。」

!像故在那裡似的,被子也不用燈, 漼去睡黹呀!現代的人也太不做視毡眼 子罴:「都到哪裡去啦,大白天的,張 「王嫂,王嫂。」婆婆風然有一

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-

Tur 5.

J

B

●氣生

功活

視坦一方盡見臟腑

〔三〕望恐的創立

尚宗 的望診方法,在中醫是積累了帶富的經 行觀察,以推開內在的病態。這種人 范、予以及分祺物、排洩物的質,色通 中髗望診,是運用祝就如病人种、

生成篇 A云:「色味常五臟:白萃肺、车,赤常心、苦 、韓菡、舛,皆亦其經脈之行也。」『素殿、籃 均有記葳。刘一素問·經絡』:「心赤、肺、肝靑 色白「腎色黑。jq稹五臟色, * 内經一中許多篇章 望而知之者,望見其五,以知其病。」「三十四難 引述古醫經『擞』云:一肝色裤,心色赤-神色黄,號

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塞車

就塞巾,地鐵人山人海。 微雨路得,上下班時

一片质比良比時

選擇男友應及經濟力

保留性接觸待婚最佳

“的三個男友之中,其

婚事,對於信中提及

胡讀友: 從妳的括中語

,我了解到已心於

的菜冬有長處,各有送過之處, DUODALIDAS - I 一但,妳維開找意見,地已可少見妳對照

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