WAH KIU YAT PO
育教聞港頁三第張二第日二初月二十年発夏
1一篇有未月輸加在監
或時行步上
火
以一般商界人士的對法,已屬厚利。在經濟不現的情况下,中巴獨得摩利而仍獲准加價,可見現行 」的十二一,不足許可利潤,故可中請加價。但導實上,中巴去年盈利爲「股東基金」的廿二%,
· 編毅先生:由一月一日起,中巴提高學假。就現行監管法例而言,中巴去年盈利爲「固定資峦
中巴加價後各綫巴士能否改善服務
一學時,雖然很攝柏也要在行人潞上通過,希有關部門造訪歷生往來不便,可否將娜大水喉荫移開一 此行落大坑道 - 眞光小學生放學時,千多人亦同時由此恩去乘車,如以福難道來往本多,故學生放
·大步而走,超去乘校車,但因大水喉正行人路中心,小童往往碰應受傷。公理古洗的學生,多 老工烬伯上。
銅鑼灣福羣道棪工代表一羣學生有此要求
滅火喉可否移近路邊方便學生往來
調例大投,署價所 香,百入運及 改 每二服 交 中心苗 當日十務 普通巴的话
爸一的
污旁五之的投帶,存洞,
晚輛單訴來是法 其均已輛 路組巨中例
份有一段共額巴的
行,發接 利加方
走但:獲潤個案
有的股的聯
亜投 東金委
-有六百二十五輛巴士行走,相距要求達一百三十四儒。巴士數量不足,造成乘客人。就以八一M
前,應作-
份的考慮並將有關資料公佈。一 椎。我們希望巴士公司及政府贫局了解到公共事業加假是直接影珽民生,故在作出任何加價决定之 原走廊自然減少中途上客人数,但由於班次增多,總乘客數量應可獲緩和,加價是否合理實有待商 政府批准部份巴士行走該走廊。可是有消息却体出郭行走該走廊之巴士路綫準佛提商票價,行走染 -.柴灣關注民生聯委會上。
我們不是「蓮加必反」,我們要求的是一個合理的交待。東區走昭於明年開始啟用,我們歡迎一
·五輛巴士方能應付需求,究竟中巴是次加價會否對此有所改善?...... 巴指出現有巴士一千零五十五部,但揀一路發展計劃」,中巴於八三年十二月應有一千一百九十 一盤,究竟我們多付的票價會否用作改善服務質素?抑或只成爲股東們的私利?中一
移生多
開放出便在
of the lens; it:wi星
retrace its path after reflection.
低年
是們
中国一間M能或九運次現
橫問
寫題
報日僑華
三期星 ®
日四月一年四八九
·曆公年三十七國民 華中
關
本
一九八四年元月三日。
香港四邑商工總會二千 四邑生熱心社會公獄,偽善不甘後入,昨捐五百元。
新
聞
1984
中學會考試題預習專欄
物理(十六)
•Image
明德出版社盧雄國 提供資料
object
PEYSICS (16)
LO
MFI & WALE TUESS
/B&C+b=90°
={BAC=30°
Let the refractive
index of the glass
prism ben
2sin500
0.766
0.5 =1.532
From vart (a) when
the angle of incidence.
is 500, the angle of
refraction is 300
X=300
y+60°-180°
Y=1200
x+Y+Z=180°
2=300
By using the fact that
light path
the angle deviation,
ennstand, the
frequency of the note emitted by the wire
is proportional to the square root of
the tension in the wire
150 18
the
牌
18
#150(12)
the focal length can be determined hy measuring the object. distance..
(b)The focal length
20cm.
250 17
15018 200°
Consider tire
leus only. real-is-pos
1 11 50+9 20
v=60 cm
=60 Fem
=00er-10cm: =550cm
Consider the
refraction due
the
concave lens
Since v' is negative), there. Ta is virtual
and in 35 cm in front
of the concave lens. Magnification produced
60. 50
by I
T 58118
T=32:
the tens
be 32 Y,
should
(h) Lottlie length of A be 1, the tension o A be T, and the diameter of Aic Then,
The length of B is.
7), the tension of iam and the diameter of B is Ed, Consider the
21/u
where,
f=fundamental
frequency
formula
1-vibration length" TЯtensionTM
u=muss jer unit
Tength.
HP is the density
of the vine
then.
wherer is the radius
of the stretched wire.
wered is the diameter of the
1
21.
Magnification oduced
requency emitted
ency, emitted
tal ma nification
Therefore the final image is virtual and magnified. Size of the final image
=2cmxㄨㄛˇ
(a)
focus
wire is kept
B
B
(Ans.)
ii)rf A is shorten by.
10 Cow, then
equntium (1)
becomes
As shown in the figure, if the
Juminous obj ject
placed at the
不隨禮柯多新彩g無報請遠 另報拜式采穎色任販就道 收附出印多雜華§ 近
費送版刷姿誌僑 迎向戶 訂閱電話:5-491181
禮拜出版
柯式印刷
d(1-10)
导
生
L-30
物
(十六)
明德出版社梁偉宏 提供資料
BIOLOGY = (16)
W.V. LEUNG
MILL & DALE PRESS LTD.
Thit
Change in size nud increase.
complexity:
The following diagram. shows the life history of: mosquito and the: graph shows the growth pattern of wriggler (larva of mosquito).
Bodyl length
adult
breathing
tube
Tarva
(wriggler)
・Time:
(1)Name tie type of
life history that the mosquito
undergoes.
(2)What is the
advantage of this type of life history?
Describe the feeding habits of the male and female mosquitoes, Account for their difference.
(1)Where does the
mosquito lay the
number of eggs is produced.
The graph shows the growth pattern.of.the larva. Explain why
(1)growth,does not
take place at X.
(2)a rapid growth.
takes place at Y.
with reference to the diagram only, suggest two efficient ways to elliminate mosquitoes.
or your
Give reasons suggestions,
The following graph shows the change in dry weight of potato. stems, Leaves. and tuhers for 8 weeka after the tuber. sprouted.
Dry weight (g)
14
∙12
10.
TUBERS
6
STEMS.
LEAVES
a) What is the advantage
of using dry weight
as
a measure of plant growth?
Describe and explain the change in dry weight of the old tubers during this period.
c) From the graph
determine
(1)the loss of dry
weight of the old tuber
(2)the total gain in
dry weight of both the stems.and. leaves from 4-8 weeks.
Explain the difference between (c)(1) and (c)(2).
Answers:
(a)(1)Complete
metamorphosis.
(2)Since the young
and the adult in this type of life history are different from each other in from and feeding habit,
the competition
for food and space
(2)Explain why
large
報日僑華閱訂期長請
between them can be avoided.
(b) The female mosquitoes
such-blood from mammals while the male wosquitoes suck juice from plants. The female has to suck the nutritive. blood since more food materials are needed
for the production of eggs..
(c) (1)In stagnant water.
(2)A large number of
eggs is produced to increase the chance of survival
(d) (1)At x, the body is
enclosed by the hard skeleton and therefore no :growth takes
placevi
(2)At Y, the:
exoskeleton has been shed away: so the body can expand to allow growth
(e) 1. A layer of
paraffin or oil can be sprayed. onto the water surface. This kills the larvae and pupae by preventing them. from taking in atmospheric oxygen.
Draining the
pends. swamps and vessels can
destroy the ground for the mosquitoes to eggs.
a) Dry weight shows the netual changes in plant materials,
The dry weight of the
old tubers "decrease8 during this period. The tubers lose their weight as they respir arid as some of their stored food are converted into th
the materials of the new plants.
c') (1) 3,2 g
(2) (11.2+12,8) g
24.0
Some of the mass, 3.8g. Jost by the
tubers may go to the leaves and stems. However the total mass gained by the stems and the leaves is 24,0 g in the same period. The difference can be explained by the fact that stems
and leaves is
carrying out
photosynthesis during
this period.
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