育教僑頁三第張二第日九十月五年癸夏
WAH KIU YAT PO
報日僑華
I.
"X+z = t
R
初中成績評核預習
17
x+y=180°-z
y=tz
c. -16,
三期星
30%
日九廿月六年三八九一展公年二十七國民蕺中
D. 11100
E. 11011
number
THORN
雄風出版社
I only
E.
9. Find the value of y
in the given figure.
D. -4, -16, 30%,
30% -16
12. Find the correct
relation anong a, b
+
some
中一數學
MATHEMATICS-
Revision Test (F.1)
Simplify:
(-5)+(-6) --( -5) - (+21)
A. 17
CA7
E. -37
2(3x
)-5x(2-3x)*
A. 6x2-23x-4
B. 6x2 +7x-4
E.
B." If only.
C. TB. only
D. and I only
E. I and III only
5. Which of the
following ordered
pairs do not belong to the line 2x+y=52.
A. (0,5) B. (-2,1) C. (1,3) D. (2,4). E. None of them
6. The cost of a piano
is increased from Sm to $. Find the increase percent.
A.
100m
100
LIE
100 (n-m
n
190 (n-m)
100(m-n)
E
18
24
20 36
E. 60
B. b-c-d+a C. b-c-a-d
10. The sides of the
given parallelogram are 6 cm "and 9 cm. If its heights are
cm and h cm.
Bind the value of
вст
8cm
D. bec+a+d Eb-d-c-a.
When the equation x-y-5 is sketched. graphically, will look like
it
+
The
+
outside surface. of an open box is painted red. If i costs $0.7 per cm how much does it cost for the box?
A. $113.4.
B. $126
C. 136.2
D. $148.4
E. $155.4
15. If u=4; f=3, find the lue of V in
R-5 Q
R
are
F4line
integers on the number line. Find the false statement. in the following descriptions.
A. P is a positive
number
B. Qisa negative
number
Pis less than Ris greater tuou-5
E. Q+7 Ls posi tive
19. In which of the
following numerals does have the
place-value
"hundred thousand
A. 431896
B. 1283156
C. 35162
D. 72300815 F523189057
20. Angles x, y, z are
in the ratio of 25 3. Then y
6x-21
21x+12
21-8x-4
If a is an odd
number, which of the followings is alvey s odd 2
A. 4a
a+2
E. 2a+4
Which of the
a-1
7. Approximate 1.44.5
metres to the
Dearest
A. 144 cm
(a+1)
B 145 cm:
C. 1440 cm
D. 1444 cm
following is/are not
found in 4XYZ?
1.983
中學會考試題預習專爛
附加數 <試卷二)
明德出版社提供資料
SUGGESTED SOLUTIONS"
ADDITIONAL MATHEMATICS
Paper II 1983
E. 1445 cm
Twice the sum of certain number and 3, the product will
be the same as
dividing the numbe
by 2, Find the number.
Equation required
y+3+2(x-1)
2x-y-5-0
Arrange the
followings from the
smallest to the greatest value;
30%.
-4, -16
· — 30% -16,
B. -76,
- * - (1)2+(2) −3(1)+2(2)
−2+ X{( 1 )2 + ( 2 )2 + (1)+ 3(2)-101-0
4+\(2)-0
1--2
the required circle
x2+y2-3x+2y-2
2
+(~2)(x2+y_+x+3y=10)
+y= +5x+4y-18-0.
(a) In 4 CFB,
BF=2RF
-2acose
In ANMF, B
MF-xcose, NM-xsing
BH=2&cos0-XC080
In ZAMB AM=√a-(2aco99
(Aug.)
(Ans.) The centre of this circle is
(b) IndAFB
AB
16. If 2x+1
then
18
E90
(base 2)
10011
B. 10101 11001
Answers: 1. A 2.E
D 11D 16 C 7. B 12 A 17. C 3. C 8 A 13E 18. D 4. E 9. C 14. A 19. D 5. B 10. B 15. E 20 E
10.
(Ane.)
dx
B
FR (13)
area required **} (1x11+7(−1)+3k -
-7x3-11k-1(-1)-20. -11-7+3k-21-11k+i±40
k--7 or
du=2xdı →→
-8k-16=40 (ing.)
I-fxsin2(x2)dx
2
2
-feinu.
2
du
sin ndu
=2]}(1–cos2u)du
-zu-Zain2u+c
u1+3x
dumóxdı
when xo, nei
when x1,
114
(Ans.)
Area of region ONP
-fo(x2-4x)dx-
(2x-5)dx
-15-27-622-5]
-(3-2)-(1-5)-3
Area of region PMQP* -(2x-5)dx-(x2-41)dz ~(x2 -5x ] ] - [3 - - 2x2 15 -(044)-(125-50-42)
32
the required area
-732-13
5. Let the line
parallel to 3x-2y=0
be
3x-2y+c=0. .(1) This line meets the
curve where
4x2+(3x+a)2=16
16x2+9x2+6cz+c2=64m0
2
25x
x2+6©x+c2¬64~0 Since (1) is a tangent,
(6c)2=4(25) (c2 -64)=0
9c2-25c2+1600-0
the required
tangents are -3x-2y+10=0
and 3x-2y-10=0
(Ans.)
R(-2)
Slope of Po-2-(-2)
1-(3)
87
Slope of tangent-
the tangent at (1,2) is given by y-2-(-7)(x-1)
1.6. 7x+89-23-0 (Ans.)
2 2
Bin no-gin mos
(1–cos200) (1‐cos2m4)
➡(cos2me-ros2ne) ➡+(-2sin(2+2)e.
sin(20–20)e)
■-sin(m+n)0.sin(u-n =sin(m+n)4.sin(n=m)0
(Ans.)
sin 30-sin^20-sine×0,
(Here m=2, n=3)
ma +(2acose)
In 4 AFN,
ANAFNF
(c) In AMN,
2
-NM 2
cos. A-
(Ane.)
@ +48 cos 0-x
dx
A (12)
·R(-1, 0)
pt (-1,-1
slopem
The line through R, A and B 18
y=mx+(x-1),. (1)
2
(2)
(1) meets (2) where
~ +[ mx + (m− 1 ) ]2 =
2
+1 242+1+2m
Slope of L
Slope of 12-2
.*. 1, :y+2-(1)(x-1)
x-y-3. ... ... ... ... (1) 1 ̧:y=4=(-2)(x-4) 2x+y=12..........(2) Solving (1) and (2): x=5, y-2
Co-ordinates of
N (5,2)
Slope of \ON=
(b) Let co-ordinates of
P be (x,y) where
4-2k
+k
1=0
1+m +2m(n-1)x+
-2m=0
Sum of roo ~2m(x-1)
1,4m
where A={Xq,Ÿ1) and B=( 12. Ya)
Let co-ordinates of
p be (x,y)
wat I
-(-1) .. (3)
1+m
2
sin 6+a
2
2
cos -4axco
cose
sin 9+cos" 4axcos 0-2 -чехсоя 20
x(x-2acos 0).
ཧྥ་
(Ans.
Slope of OP=
4-2k
4+k
sin(3+2)0. sin(3-2)0– (d) It
sing-0
sin50.sine-sine=0
sinė(sin50-1)=0
sine-0
or sin50-1
50-24
2 10.
or
(Ans.)
NM-☎sin60°
2
NM
- (4)
when PON is acute,
4-2k 2
tan /PON=
4+k
-
1+m
(Ans.)
(b) (3) -
(3).....(5)
Substitute (5) into (4);
7
[.20–10k-8-2k 20+5k48-4k
12-12k
28+k
(Ans)
When PON is obtuse
tan (PON--|(12-12k) |
(Ans.)
12-12k
(c) [PON=45°, 28+k
12-12k+ 28+k
16 13
or
40
1-1
2.
+x+y=0 which is of C and circle.
a
(Ans.)
6.
申請(号(25)号 (5)
22
-0.4296
x+y=3x+y=2+
22
Xx+y=+x+3y-10)=0 Since this circle passes through (1,2),
the inclination of AN to the
horizontal is 19
(aun.)
But from diagram,
k is positive,
40:
11
[PON=180o,
12-12k
28+k
(Ans.)
(Ans.)
Locus of
(-1,-1) | (0, -1)