四日七月一年二八九一層公年一十七國民華中育教儒
Saw dist
與二第張六第日三十月二十年酉辛腾夏
WAH KIU YAT PO
place, the sides of the hollow
1982
中學會考試題預習專欄
地
理
(十四)
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GEOGRAPHY (14)
YAY Lee
MILL & DALE PRESS LTD.
Questions for Revisions;
Study the lakes A and B shown
on the
following maps.
Name the type of lake in each case. Briefly state the features which aided your
identification. For each, explain its formation.
-850-
-750
650.
550
Ice
forming
are steepened and the base deepened.
ii. The hollow is enlarged into an armchair feature known as corrie.
Warner condi-
tions cause ice to waste away,
and moraine to
be pushed.
forward and left
on the lip. After the ice melts, a lake occupies the corrie or cirque.
It is called a corrie, lake or tarn.
Freeze thew action at the base (plucking)
報日僑華
期星
and
BIOLOGY (14)
Leung
be carved out by the actions of plucking abrasion of the glaciers, water will occupy these hollows and convert them into lakes termed ribbon Jakes. Sometimes, these long and narrow lake s may be a result of the deposition of moraines on the floor of the U-shaped valley. They. dam up rivers to form lakes.
area
28. The figure below
shows a lowland covered with ice. Name and briefly account for the features that would. be found at X and Y after the ice has melted;
Mile
& Dale Press Ltd.
Unit 10: Integration and
behaviour.
1. The following diagram
shows a section of the human eye
up using the apparatus as shown in the diagrams.
porous pot
Empty
ANS:
B
VI 50M
650
0 km.
1. Names of the features:
A Corrie lake
B. Ribbon lake.
Characteristic
features of
identification:
A-1. steep-walled
basin.
ii. arm-chair, like
iii.
on high
s
mountains ope about 700-750 m.
source of a river
which flows down to a wide U-
shaped valley
with
alpine
benches below
long narrow shape.
(oblong, shape)
ii. located at the
floor of al steep-side
U-shaped valley
iii. has alpines
iv
benched above with truncated spurs and hang-
ing valleys. perched above
Formation:
In mountainous areas, snow often collects in the hollows of rocks.
Plucking, a process by which craks and joints
are enlarged by:
freeze and thaw.
takes
action.
1982
Broken
Causes
abrasion
or grinding
Crevass
Bergschrund
materials
Plucking
Bergschrund
Margine
Grindin
Moraine deposited
on the lip
stream
Moraine
dam
Plucking
•Vertical
backwall
Lake
FORMATION OF A CONRIE LAKE (TARN.
B-
On the floor of U- shaped valleys
elongated hollows may
3441
a+bi.
中學會考試題預習專欄
3+420
2+1
3+hi
3441)(2-
電新數學
(十四)
(2+1)) ((2-i
6+81-7144.
明德出版社盧國雄 提供資料
MATHEMATICS (Syll.1) (14).
H.K. Lo
¡MILL & DALE PRESS LTD,
Suggested Answer
centures found at X and
Y after the ice has melted
Feature X
A kettle hole would be found at X after the ice has melted.
Formation
The presence of such ice blocks broken off from the main sheet in the area will probably result in the develop- ment of circular hollow. The formation of such hollow is due to the deposition around“. individual ice block, With higher temperatures,
the piece of ice melts. The melt-water will fill up the hollow and convert it into small lake called kettle lake,
Feature Y
Terminal noraines would be found at Y Formation
Terminal moraines are debris which accumulated at the edge of a glacier As the glacier moves along, pieces of rocks will be broken off from
the valley floor and carried downslope. With the retreation or melting of ice, the debris will be left behind forming a ridge termed the terminal moraine
生物
(十四)
明德出版社梁永華 提供資料
2x + (e+f) = 180
[180°-(e+1))]
(a)(1) Name the three
layers A, B and C (2) Describe and
(b) (1)
explain the structural adaptations found in each layer,
Name E and E. Explain how E and F differ in their | ability to detect the form and. colour of an object.
(c)(1) Which two types of
light-sensitive
cells are found in layer C
(2) How do these two
types of cells differ in their functions?
(d)Give the functions of
the liquids in D. (e)(1) Besides of the
liquids in D, give the names of two other structures. of the human eye that are
transparent,
(2) Give the functions
of each of these. two structures.
(f)(1) What is Go
(2) Give its function. (g)If rays of light from a distant object come into focus at
a point in front of C, (1) What would be the
defect of the eye? (2) What type of lens would be suitable for correcting such a defect?
(b)(1) Name the vitamin
which is essential
for vision.
(2) Why is it
important?.
Seedling A: radical
untreated. Seedling B: tip of
radical removed.
Seedling C: radical
untreated.
(n)With respect to growth
and curvature of the radicals of seedling A, B and C, what changes, if any, would be observed after a few days?
(b)What conclusions cen be drawn from the
obervation în (1) for seedling A and B. (2) seedling A and C. (c)Briefly describe the
advantage which growing plants gai from the response. shown by seedling A.
Ansvers:
(a)(1) A: sclerotic coat B: choroid C: retina
(2) A: It is tough and
thereford can. protect and maintain the shape of the eye..
(b)(1)
2. An experiment is set.
2x+3(2x)+4 = 0
Since, e-40° f=36
X
(180
·(40°.
52
ZBCF:
2x
2(1)
the coordinates of
It is rich in blood capillaries which supply oxygen and nutrients: to. the eye. It is also black in colours and therefore can prevent the reflection of light insi do. the eye. It contains the light sensitive cells which can detect the form and colour of the object, E: blind spot F: yellow spot
(2) E cannot detect
form and colour of the object because there are no ligh sensitive cells.
F can detect form - and colour of object clearly because there is the highest concentration of light-sensitive
cells.
(c)(1) Cones and rods
are
(2)ible for.
vision in bright light and BAPANES for colour vision Rods are
responsible for vision in dim light.
(d)(1) To maintain the
Key shape of the eye.
To supply.
nutrients to the
Tens and cornea,
(e) (1) Cornea and lens.
(2) Cornea protects the eye and
refract the light Lens focuses the inage on the retina,
Eye muscle,
(f) (1) It moves the eve
(8) (1)
in the socket.
Short sight. Concave lens.
Vitamin A.
It is responsible for the formation of visual purple, A lack of it would
cause night blindness.
(a)Seedling A. the
radical- continues. to grow and bends towards the pot.
Seedling B: the
Seedling C
radical
as 10 further growth anŸ” bending. the
radical continues to grow. downward without.
bending.
(b)(1) The tip of radical.
is responsible for the growth and curvature.
(2) The radical grows towards water (hydrotropisa). The effect of the stimulus of water is stronger than that of gravity.. (c)This makes the root
obtain more water.
Ans.
(sing-cost
Ans
1
=
4cm
FG
FD
AB
AD
.. FQ *
AB
EG BG
CM
E-16 - AF-3
EG
BD
CD
* бет
4cm
1+2cos@sinə.
2cosesinữ »
sin@cos✪
Therefore,
(sine+cose) -4gin@cost
EF EG-FG-
7. The value of the car at the end of the
first year is
$10,000(0,85)
The value of the car at the end of the 2nd year is.
$10,000(1—–15)*
· 100
$10,000(0,85)
The value of the car at the end of the nth year is
$10,000(0.85)"
If the value of the car first falls below $6,000 at the end of
then
the nth yea
10,000(0,85)*<6,000
(0.85)" <0.6
nlog0,85 < 10g0,6 n(T.9294) <(1.7783); h(−0.0706) < -0.2218 (0.0706)n > 0.2218
20.2218
n>
0.0706 3.1416
the value of the car first falls below $6,000 at the end of the 4th year.
Suggested solutions to Test 5
Section A
1
(i) Since - is one of the
roots of the equation
2
6x+13x+k=0
~6(3)2+13(3)+k-0
k-5
(ii) Therefore, the
equation is
6x+13x-5 = 0
(3x-1)(2x+5) *
#
the other root
i's
Ans.
Ans
As shown in the figure, ZEAB - X
(ext of cyclic
quad)
LEBA = x+f (ext of 4)
ZEAB+LABE+ZAER=180°
(sum of A
‚. x+(x+f}+e=180′
(1) The slope of the
(ii
P is (1,2)
straight line 3x-y÷0 is.5.
5.
(sint-cost)2
The slope of the required straight
line is -
consider the equation 2x-3y+4+k(2x-y)=0
2(k+1)x−(k+3)y+4=0
slope 12(k+1} The slope is
2(k
k.
(k+3)
And
The equation 2x-3y+4+k(2x−y)=0 represents a family of straight lines passing through the intersection of the straight lines (2x-3y+4=0.
2x-y=0
From (2),
(1)
2x
sin 8+cos 8-Csinecose
21
sin 8+coa 642sinécoge
-4sin@cos✪
(sind+cose)
-Sşinecoa✪
Since, sine.c
c༠༠8 * (sing+cose)-().
sin
0+2cos@sine
dada