WAH KIU YAT PO
日三廿月九年酉辛夏
頁二第張六第
行全國出口搭調查後 傷,韓國工業聯會在珤 甲鱼業務。 蝦美國與日本這兩個市,在美國的迅速發展,為客戶提供更完善的進出口 出口市場,不再大過琦於本月十九日正式開幕,它的業務正標誌著該行
一分二十六·三,而且林京華銀行三藩市分行 的產品,佔總出口的全面性銀行服務,同時,以美元存歎的客戶將更
廠家促當局資金通融
發垝去华南韓輸往美國 門後經營港美進出口貿易,將透過該行便可發動
[卷南韓廣(特)香港京華銀行美國三藩市分行
·如所週知,美國是港食最大的出口市場,客
市場則佔百分之十七
四,他在一九七拉著, 昨舉行開幕典禮
而日本佔百分十五
·英國佔百分十二月
,在過去十年,南韓
為便利。"
一四個一九七五年一 個,一九七〇年 一O 一九六二年僅有三十三一作一张列安排。 產品的國家與地區,達一特爾深典禮。较早時,京舉行助總經理黃玉 到一百六十五個,而在」赴美國考茶葉務,亦參與三藩市分行阳海事宜,
的貿易頍化國數目,急自爾與遗經運屈你堅,日前已飛赴美國,並由B
恊行開懷式,京華銀行董事主席
首腦蘇白爾屈偉堅主持
「百二十三個。
·分让九·七,這也反映
戶的百分五十,降至百
,不過,該住北美國家
百分之二與百分
與大洋洲的出口,分別
在一九八〇年轎往非洲
·增至百分匹·四與言分,雖
·九;而十年前見到这
西以地風來說,南韓脾
漢申受接雖照牌新
吃⌋依|牌]銀
然照行
本
└、 韓讓假値估計出逾五千萬
不然已經嬴接受申银行, 照仍異常吃香,一位行 牌照,但目前本港銀行牌
: 特訊 港府自前骓
請吃香 說,絕少有藏雄棄牌照。
“銀行牌照價值,包括银行
,以目前银行營業狀况來。
牌照在市場需求更爲股 一定的似值,但持牌銀行 搜受在欲公司牌照亦有
拨銀行家指出·注册
南韓減少對北美市場的,就史及其萬翳,而業務作風後母一般客戶信报,耐 亦對牌照轉讓價值有一定的支持。
過分倚賴,
韓國工業聯會敦促
帶出台市場。 一,特牌银行共一百1|十間。. 將進行合委聯營,豆摊 富不易,因此促致現有銀行牌照有價。截至目前 加出口,以及與外國公一至二十張路元,還有其他基本條件,宗融牌照相 付方式,協助工商業堖,可本額爲一百億美元!本地財務檢 亦須存資 有關當局,透過推娅女」,但顺件要求十分高,包括海外銀行牌照其母公
·據稱·台前雖然港府重新接受银行牌照
,
定
1982
中學會考試題預習專欄
物理
明德出版社 盧雄國提供資料
PHYSICS (4)
H.K.Lo
MILL & DALE PRESS LTD.
Answers to Exercise 1. (a)
115 Kyl
As shown in the figure above,
Let Tetension in the
string,
a=acceleration of
the system.
Apply Newton's 2nd Law.
to the blocks
separately,
15(10)-T=15a.
T-10(10) -10a.
(1)+(2);
50-25a
Ans.
(b) substitute a=2 into
(2)
T-10(10)-10(2)
T-120 N Ans.
(c) Apply the formula
2 22
v➡u +2as N
Let v
the
velocity of the
15. kg block when it strikes the floor. The initial:
velocity is 0ms
2.2(a)(2) -2(2)(2)
8
-2.8284 s
the
(d) Let the time required for 15kg block to reach the floor be t (seconds). Apply the formula
initial velocity
0 ma
-1
Substitute s=2
(2)
1.4142
down
2(g)(h)
8
2(10)
** 0.4 m
The maximum
height reached
by the 10 kg
block is
0.4+2 = 2.4 m
above the floor,
2(a) Let the velocity: of
the pile driver as
it strikes the pile be v ma
By conservation of
energy,
mgh =
where m
and h
(b) Let the
velocity
be v us
mass of the.pile- driver 10 kg height fallen 12m
2gh 2(10)(12) (240
15.492 ms.
common
required
Initial momentum of the system:
» (10)(v.) kgma
Final momentum of
the system.
(10+12)v kgms
By conservation of linear momentum
10v:(10+12)v
·10°
10
-22(15.492)
=7.042 ma
(c) Let the average
retarding force exerted by the ground on the pile be F newtons. Rence,
Work done against F loss in kinetic energy + loss in potential energy work done against F = F(0.5)
Loss in kinetic
energy
(10+12)v
- 2(22)(7.042)2
-545.5 J
Loss in potential
energy:
= (10+12)(10)(0.5)
110 J F(0.5)-(545.5+110)
F-1311
Ans:
̈600
華
| 點九美恼,非成四百一十九手,無法達到今年的出口日 月份一五美仙,排成一百一十八等,十月份一五一趨安持續至今年底,將 一手,七月份、三塾七六美仙,共成三十一,九類和實際出口额的下鲜 | 心戒十六手,五月份 三點五六美仙,此成二十 果收到的出口信用狀数 點七五美仙,形成八子,三月份一二點六美仙商工部宣員說,如
報日僑
積極找尋新市場
南韓不再偏重美市場
·朗俄反投靠排,市場無大发現的汊河消息。明係一個月被少了百分之一 市協上,懿傳學西,向輝夜茲低微人了,但始豹口用狀共爲三億六千 一百三十二乎,現價下跌二十點,報3美仙,五千一百萬美元,較前
星
持支息消乏缺
價造糖期
穩靠覆反
交,黙十二跌價現
百六成共日全,爽暢投
日十二月十年一八九一曆公年十七國民華中 少減已雖米寄候 凉未凉應氣天 慢仍銷實米食
日爲止,基本存會 . 又據工商醬統計,截至本月十三
米二百六元 五元,世龍蝦新米二百一十元,紅菊花慈香米二百一十五元,苦酒昔 庄金冠絲苗二百卅四元,澳洲米隆二百八十一元。秦國金鳳新香米二百卅 「十三元,大運新油點一百八十九元,日字彩油粘一百九十川R·澳洲版袋 一七元,金組紫有二百廿一世,金繼新油紗|百〇三元,江西商苗一百九 九十三元及一百九十四元,新粮粥粘一百九十三元,惜字餘苗一百九十 CHE
成盤紀錄:中國大陸整学新秣苗每批一百九十七元,继字新繃苗一百
分率〔百分六之五. )。 | 存倉运,佔八千七百八十五噸,即佔百分之十三,五,比較規定入口的百
[ ][ 噸,澳洲米佔四千七百卅四噸,其他地區米佔五百七十三綱,又米 存會的調中,蔡國米佔三萬〇九十九成,中國大陸米佔二萬九千五百九 ,另有特別額一千〇七十啊,在基本 光子啊,包括候寄米五千九百卅大順、
-
補盆三二,到未米新造晚
旺非交成市米,緩從給
月一份月的
全日共成
交易所原
香港商品
每月九首韓南
台二去感品機無趨 額 果 少 這十年七出,法勢和收T
賀但: 百谊 至今系主任的她也共 金品姿 年念日只售,咬份工美元美億十四 之佔了 美爲 月的年額 信德 八三收 百元運走 八百 元 出底的 用說 月儅到分,到下品在一部國心淡 ,二十年分,十枋口下狀。 份六的 之較三 城出到示歡迎
·定
綠目將降如 一压之較大
(10+20+30) a
-2
Ans
- 10 ms
Substitute:e=10 into (1) and (2), We have
-600-10(10)
500 N
30(10)
Ans.
300 N Ans.
As shown in the fig. above, fi, fg and.
are,the' frictional forces on the 10 kg, 20 kg and 30 kg blocks. respectively。
f.=0.2(10)(10)=20 N fo=0.2(20)(10)=10 N *fy=0.2(30)(10)=60N.
Let the acceleration of the system be a,. the. tensions in the strings be
be Ti and 1:2
Apply Newton's 2nd law.
to the blocks
acparately,
600-T-20 = 10s..(1)
9-40 = 2081..(2) 30a..(3)
2-60
(1)+(2)+(3).
600.120 - cửa
a= 8 ms.
(ii) Substitute a
into (1),
=500 N
Substitute a
into (5)
S300N
Ang
(b)
x 100% =40%
MA。 x 100%
4.0%
Ans
1,6 (c) Let the minimum
effort required be F.
1.6
Load 50g
50.0N
500
1.6
E312.5-N Ang
(d) Let the tension in
the string.
connected to the
50 kg block bé T newtong.
T effort
1.6
when effort = 600 N
on
the cube
- weight of the
cube
900(0.1) 900(0.1)(10)
9 N
(ii). Let the volume of the.cuhe immersed in water be V
Upthrust on the cube
(1000)(g)(V*) 1000(10)V = 9
V-9x10m Since the volum of the cube.
1x10-3
fraction of the cube immersed
1x107
Ans
(u) As shown in.the.
figure below
h depth of oil
The 1
st
term and the common ratio of a G.P. are a and r respective- ly. Find the produat of the first n terms of the progression. In the figure, Mis the mid-point of nC and N is a point on AC, such that AN=2NC
area of 4ABC 18 90.sq.cm.. find.the area of SMNC. (Geometry theorem
need not be quoted when used
包另一百三十大包。 晚造新米未有連來,二、三盤商補給一 仍然變慢,因爲天氣應凉凉,且因 商快寄米雖然比旬日前減少,但 整 據米棻人士指出:現時二、三盤
米佔一千四百二十中包,澳洲米佔八 紙,其中十五欸有成盤的,中國大陸 入口米商士三家出盤,提沽食米四十 多,中國大陸米及泰國米成交仍少。 别品襁成交互有增減,澳洲米成交蛟 十
(C) 中包另四千小包,泰國米佔八(C)(D)
[特)昨(十九)日米市,
育教濟經
and (5,-2). Find
(b) the value of
and b
(c) the co-ordinates
of the points where the graph cuts the x-axis. (d) what additional
Tinear graph. would be' [« necessary to solve graphically.
one equation-
12
watër (ookgm)
16%
If one of the roots of
+px+32-0 is -8, whilst x +px+q=0 has equal roots, find the value of q
In the figure, ABCD is a parellelogram DE-EC. Find the ratio of
OF:FC(Geometry theorem need not be quoted when used)
(2,-5)
11. An agent purchases
250 bicycles for $18750. and fixes the selling price at 30% above cost, He sells. 180 at this price and a further 50 when this price is reduced. by one-fifth. The rest are sold at a loss of $10 each, Find his gain per cent on the whole transaction. 12. In the figure
<BAC=90o
Prove tha
BEBC=2AE”
aud: AB AE,
A cross-sectional
area of
cube
(=0.01 sq. m.)
Upthrust due to oil
on the cube
(720)(g)(HA)
7200hA009 Upthrust due to water:on the cube 1000(g)(0.1–h)A 10,000(0.1-h)A Total upthrust.. exerted on the cube:
72092200(0,1
1000A-2800kA (1000-2800h)A
Weight of the cube
≈ 900(0.1)(a)(g).
900AM
Total upthrust weight of the cube.
-(1000–2800h)A=900A h = 0.0357 m the cube rises :0.0357m-1cm
0.0357 m-0.01 m 0.0257 m
學
(四)
| 明德出版社 交長波提供資料
7. Find the value of
the form a<x< that 3+2x
such
8.Find the values of P
aud:q if (x+2) and (x-1) are factors of
· +px +qx-18.
Section B
9. The figure shows a
regular Gexacon ABCDEF inscribed in a circle
of radius 10 cmand. another regular hexagon PQRSTU circumscribes the same.
circle.
13.
In the fig., ACB is a semicircle centre 0, its area is bisected: by a line XY parullel to the diameter AB, if 4A0X-0 <- prove that
(a) 1-20
- sin200
then
In the fig., PR is the the diameter of the circle and NRM is the tangent. Prove that (a) PQ•PN =
PR2
(b) A POs and PMN are
similar
(c) QSMN ia cyclic.
amst
1.6.
1 - 960 N
心
Mathematics (Syll 2) 4
C&P. Man
神
2m
30kg
18m 110kgl
As shown in the fig. above. let the
velocity of the 10 kg. block be va
when it reaches the level at
A.
2.
8
Hence, the string slackens, assume the block moves h meters farther before dropa
3 20kg 10g 60mm Smooth horizontal plane.
As shown in the fig. above, let the tensions in the strings. be Tand T the acceleration of?. the system be a. Apply Newton's 2nd law to the blocks
separately,
LGOO-T
置
=-10-2
T1-2 =.20a
2
~30a
(1)+(2)+(3):
Hence, the net force MILL & DALE PRESS LTD. acting on the 50 kg block
960-50g
960-500
460 N
Apply Newton's 2nd
460 = 50(a)
- 9.2
Ans Ans. The block wil
move upwards with accelera- tion 9.2 ms
(a)
(i) Upthrust of water.
Exercise 2 Answer All questions in Section A and any Five. questions in Section B.
Section A
1. If sinxy sinox. 1 are.
10x360
V
find x wher
The cost of fuel increases by 20%, driver decreases the consumption by 15%" What is the chalige in
the expenditure the fuel?
on
(a) Find (1) the area
of ABCDEF. (ii)
the area of PQRSTU (b) If the average of
the areas of these two hexagon is taken to be the
area of the circle, 15. (a) Find the sum of what is the error percentage?.
10. The curve of the
equation y=ax+bx40 (where a, b and c are. real numbers) is sketched in the fig.... It passed through the points (0,3), (2,-5).
the aeries 9+99.999+..
to n terms
(h) From the
of(a)or: wise find the value of
5+55+55~4
ton terms.
だ