Solution (a) Area of
真四第張六第
日一十月一十年申庚
WAH KIU YAT PO
報日僑業
三期星
1981
1.e. loga, logob and in A.P. 10c are
= 77(4)2×360
2,150 T
sq.cm
中學會考試題預習專欄
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Mathematics (11)
C. P. Man
MILL & DALE PRESS LTD.
Solutio
Solution to exercise
Section A
1. Solution: Let x kg be the
Weight of zine
added.
Weight of zinc in 400kg of
the alloy 400kg 35%
140+x:
40048-4
140+x
400+x
140kg
420+3x= 800+2x
="380
380kg of zinc is added.
Solution: - psinA+qcos A
sin A+2pqsinacosa,
2
b
peosA-qsina
cos A-2pqsinAcO §Â +
qsin
Solution:AB is the
diameter of the circle.
180°-90°-28
ZAQB
LQAB
= 62°
AO/PO
LAOP=ZQAB=62
ZAQP ILAOP
3x62
)+(2) p2 (=
2 (si
Solution:
A+cos A
A)
AP
AQ
AB AC
LPAQ BAC
As ABC, APO are similar
PO 10
AQ ÷
BC AC
PO/BC
ZKP). ZKCB; ZKQP = KBC
As PKO, CKB are similar
10.
-20.94 sq.cm
(b) Length of AB
150 360 10.47 cm.
Base radius of the cone
10.47 2.7 1.667 cm.
CM
(c) Height of the cone
√42-1.667 cm
3.636 cm.
(d) Volume of the cone (1.667) 3.636 cu.
10.58 cu. em
16èm
A
5cm.
Solution: (a) Let AC=X¢m
In AAEC
2 2
+4-2x5x4 coaB
= 41-40cosB
In AADC
6^+7−−2x6x7cosD
85-84cosD
ABCD is a cyclic quad.
LB+LD = 180
41-40cosB-85-84cos(180o
85+84cosB
124сов=-44.
B-110
4784
(b) s = (5+4+6+7) = 11
Area of ABCD
√(11-5)(11-4-)(11–6)(11-7)
=28.98 sq.cm
1981
中學會考試題預習專欄
日七十月二十年〇八九一鼹公年九十六國民塞中目播育教
of the system.
(ii) the mass of ice at
0°c required to
obtain a final temperature of 20°c.
2. iure 1 shows a
constant pressure air thermometer. It consists of a uniform thin glass tube containing dry air
with a mercury index, and fixed to a half-
meter rule.
Figure 1
The length of the column of trapped air is meas- ured at different
temperatures
Temperature
Length L
ice point
280mm
steam point
385mm
unknown
345mm
temperature
(1) What is the value of
of absolute zero
temperature as
indicated by these.
experimental results?
for reading. It is found that the area
of the image of a square printed on book is 9 times that of the square. Find
the distance between the lens and the
book.
A tuning fork of freq-. uency 255Hz vibrates unison with a stretched metal wire vibrating. with its fundamental frequency. If some wax is now attached to prongs of the tur fork so as to lower frequency, 5 beats second can be heard. what fraction must be the length of the wire. be altered in order that it may again emit a note in unison with the tuning fork? Is the alteration in the leng of the wire an increase. or decrease?
A wire of length 1m supports a weight w
enitts a note of frequency f Hz (See figure 3)
Solution: Let AR h ̈
PO
BC
KC
ΔΡΟΚ
30
AQKC
ДРОС
i
AOKC
AAPO
APOC
·AAPQ
ДОКС
are in
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ratio of area of AAPQ to W..LC. AOKC is 2:3
8. Solution: Let $x and $y be
their combined income and expenditure respectively.
75
7x-10-27-201
10
12 11.
x:y = 40:33
ratio of their combined
income to combined expenditure is 40:33.
1500
FLYSİCS (11)
(MILL & DALE FRESS LTD.)
1.0.5ks of ice at 0°C is
thrown into a vessel containing 0.5kg 01 steam 100°C. The specif- ic heat capacity of water is 4200Jkg71c-1 the specific latent fusion of ice is
336,000JEL-1 and the specific latent of vaporization or steam is
Calcul 2,268,000 JK
(ii) What is the unknown:
temperature?
0.02
DEL
(금)
Figure 2 shows a graph of the reciprocal of object distance plotted against the reciprocal of image distance. (+) for al
converging lens.
0.02
COS
Figure 2 (a) From the graph,
Figure 3.
If the weight. W is immersed in water, the Length of the wire should be adjusted to 0.9 meters such that the frequency of the
noted emitted rem.
unchanged. (duc figure
ate
calculate the focal length of the lens. (b) The lens is now
(i) the final temperature
as a magnifying
used glass
Figure 4
Calculate density of
the relative
the weight.
In AABC, BC-h
tank 50
In AABD, BD=h,
tan30
BD-BC CD
√√3h-h=
100.
100
hm
136,6m
The height of the tower
18 136.6mm
Solution:
(3x+1)(x−2)
(x-2)2
4(3x+1} {x−2) >3(x-2) (x−2.) [4(3x+1)-3(x-2)]
(x-2)(9x+10)≥
>
10
Solution:
logob
10a.
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