日六廿月九年未已愿复 WAH KIU YAT PO 報日僑
四期星
賬電如亦之
買二第張九第
《六》九龍紅磡船塢街一百二十五號地下-戴話|健」補貼一元五的「亦認爲賴合理,因爲少
方才没合懸起八號風球時,以今日之幣值及物價,
|,已上班的工友孫由最
一場爲千二元亦給非過級
號地下一話——一六六五一.88 反
· 號新界屯門德政圍三十一號地下,種話:千不同,有些亦已調戲於由衆方安排其实護工发 第匮四樓 電話:——二〇一五四;(十二廠工制度與高低各有,天文台懸起八號風球時 一九一九〇〇(十三) 新界大埔麗正道五十元,故來仍在數字上提安全獄話一點,亦德育
CTR (+1)新界荃灣沙咀道碴打銀行大 龍深水埗元洲街狹曷大度二樓,電話:七,該會並未提出增加工资,無問驅。 3. 上述第一要求,,故相信該行起來,實 幅度的原因,是由於各 談到工友上班後
號地下,但话:“九王六一七五八十)九離厰。 (九龍區角花園街一百八十五 方派專車安排工友安全島各敗著會工发一間
金 何記?
七小麵
3. 柴濡*男性,十八黄以上,有經維優先。月一時工作摄小時應作向小時計)。
工廠總務一名、
柴費。男性,檻不拘,年二十至六十歲,
遇待善改求要人工織紡區
接|會|雙
觸有方
案方出提會商向已會工
鐵
調器
日來猪牛鮮魚漲價
出人世界
受漲
影價
響
.非播范十二元以上不可。 致各個工友家換對日常鞑茶的開銷大失預寡,雖不致「食無肉」,但雖然使到大家百上加斤。 亦随之措高,價书说無一定,尤以工友住宅區之公共發嘔爲然,加價幅度多遠百分之十五或以上者
·趉工友们指出:日來不詆肉價貴,并做,籍聰亦同時被升,那麽,平日每猱從來銈原是十元的 肉價格,由於市政事務署衛生督些探取工業行動,致居煤級半裙午銳華,各內槍因供求關係,
·香港工人生活,在通貨膨脹急盪,物價動蹲之今日,所遭受的生活壓力已签沉重,而日來豬牛
直接對政府無大威脅間接使市民受苦 衛生督察採取工業行動肉食供應減少
日五十月一十年九七九一瑟公年八十六國民華中 育教人工
你
作
想 嗎
?
,
善人
“以致工友吃既不饱,又得「恭食」,同爍著開銷. 二元三角,更有祧至三者;明邀愛由五元張至六元,另加一服務費。也有不再加似而把質及減少 一另方面,由於最近各酒樓市中的心服務,不少又改新爾·感心由元一角到二元成
部份工友又說:煎熬最近至質蟻罕,不吃菇牛肉,改吃多些英研成群魚好了
學能推理練習專欄 智慧社提供資料
數字推理
數字推理練習:
綜合練習
選出下列每割的正確答案,並在它的下面叠
下列那一款式的值不等於100?
A 1-+-99
B 10X 10
C10X9+10
D25X4
0.21
13775
E 20X6
B2X2 X3
D3>
3X3X3
E-§×(7+7)
下面那一個排列是對的?
前特簽向早点
−300kgma
Initiul momentum of.
bullet
(0.01)(600)
:-1
6. kgms
Assume n bullets are required to stop the motion of the target the momentum of n bullet
Gn, kgms
1
Since the target stops finally, therefore, the
Ans
finni momentum of the system is zero
On÷300: CON 50
(b) The energy lost during
the impact
(100)(3)
+ 2(0,01)(600)2 (50).
450 90000
2(a)
3 +-4
學生:780人到郊外旅行,他們乘坐旅游車出 問他們共乘 發,若旅避車每輛可坐5/
P17 Q17.3 R17
S17.4T18:
上體育課時,老師命該班學生排成一列,然
·夜拔1.2、3、4、5報數,若最钱一人 所截的數目是2,開該班共有學生贬义急
P.20大Q34人 R 37 S 40A T45A 弟弟交学费用去50元的10 買書綁用去餘下 的蛋,問下列那一项是不對的?
P弟弟還餘21元
R當牌費14元
0學費15元
T買當得所用的软项较多
弟弟共用去29元
6人合谳可在18天内完成的工程,若工作瑰率
年不變。4人合做情形怎髅2
P所需時間就少
R仍需18天
Q所需時間較多
SX39 A
904503
Ans
Let f= density of copper. Weight of the copper cone
(xr2n) (f) (8)
hemisphere
Weight of the copper
(号ar2)()()
Since the centre of mass
of the combined body is at
therefore, moments of
the weights of the "cone
and the hemisphere about 0
are equal in magnitude.
(Har2n)(5)(#)(h)
(xr)(1)(e)(x)
案
As shown in the figure,
and T. are the tensions ih the string,
Let a he the acceleration of the 18kg-block, then the
acceleration of the 8kg-block is 2a,
8(2a)
16a
g-T2 18a
Substitute (2) into (3),
18g-2T 18a
9.5-12. 9a
9g-1.6a
Substitute (1) into (4),
25(10)
3.6 ms
acceleration of the
18kg-block is 7.6ms
Upthrust on the block due to oil
(0.5)(d)(g){8A)
where A is the cross-sectional area of cube
Upthrust on the block due
to water
(d)(g)(2A)
Weight of the wooden block
(F)(a)(g) (10A)
(S)(d)(g)(10A):
- (0.5)(d)(g)(8A)
+ (d)(g)(2A)
10ƒ » 4 42
(4)
Ans:
the 8kgu
block is 7.2ms
and that
(b) T.
16(3.6) 57.6N
(c) Ta
115.2N
Ans:
Ans
let N - the reaction from
the smooth wall of the cylinder. weight of the ball reaction between the halls.
數學
Ans
14
(六)
明德出版社交長波提供資料
Mathematics (6)
C.P. Man
(Mill & Dale Press Ltd.)
Solution to Exercise 2
11. Solution:
12
(a) Let t=0,
The velocity with which the particle P leaves the point O
1s 5m/s.
(b) Let v=50.
50=36
3t -6t-45-0
t -2t-15-0
(t-5)(t+3)-0
t-5 or −3 (rejected). The time taken for the velocity of F t虹 reach 50m/s is 5 sec,
v=jt-6t+5
=3(t −2+)+5
=3(t −2t+1−1)+5
-3(t-1)+2.
The minimum velocity:
of P is 2m/s.
Solution::
(a) (x+y)c(x-y)
x+y=k(x−y) (where k
circumference / }
/AOD=/APB(/s in the
same segment)
- [AQB=2/APB ( subst.
(b) /APB=[PQB+/PBQ (ext /
of A)
/PBQ=/PUB/APH PQ=PB (sides opp
(c)/ARB-/AOB
equal (s)
(/s in the aame: segment)
[ARB=/PDQ (subst.)
AU//BQ (alt /s equal
Given: AD is a tangent to
circle ABC and.
AC is a tangent to circle ABD
To prove:(n) AABC und ADBAL
are similar
AB =HC•BD
TTC TD are
tangents and /CTD=120 Tind /CADT
Proof:(a) (CAB=/BDA F/ACB2/BAD
( in alt segment) (ABC=/ABD (3rd /
of A)
A ABC and ADBA are
similar (equangular As)
(6)
AS RCT
DB BA
(corr sides,
similar As)
ABBC BD
(c)/ACB+/ADB-/CAB+/BAD
= /CAD
[BCT=/CAB
(a) The direction of the
reaction from the smooth wall of the cylinder on the upper ball is normal to the wall and towards the centre of the ball. (b) As shown in the diagram,
BA # 2x (radius of the
ball)
BP
0.2m-
(diameter of the
cylinder)-2x(radius
of the ball) 2x0.15 - 2x0.1 0.1m
BP
AP AB
Since the balls are in
equilibrium,
Reind =
R(4)
17.321N
is constant)
y+ky=kx-x
)=(k-1)x
tazi
re già
constant)
$2
一起+1
__+g+1 . (x2-xy+y")
ka: countant
y)x(x2-xy+)
13. Given: 0 is the centre
ofei rcle ABQ
To Brave: (a) [AQB=3/APB
(b) FQ=PB. (c) AR//BQ:
Let
water
density of water relative density of the wooden block
Proof:(a) Join OA, OB
LAUBAOB (centre
double the
[BDT=/BAD } (_ in alt
segment)
/BCT+/BDT=/CAB+/BAD
/CAD
/CTD+3/CAD=360o
sum of quad) 120°+3/CAN=360°
5. Solution:
[CAD=80°
Volume of the closed.
cylindrical tube
(0.1)x35 cu.
Weight; of mercury -1.1x13.6 gm.
=15.0 gn (correct
Solution: 1/10gm)
Let $x and By be income and expenditure respectively,
then.
1yncome (a)
|Expanditure(3)
Saving (0)
60%x=7.5%y
x-1.25y
70%
s saving-0,6x-0.7y
=0.6x1.25y-0.7y
-0.05y
Bia saving-x-y
=1.25y-y -20,25y
The ratio of As saving to B's saving =0.05y:0.25y.
15
T需要36天
10.下判五個數目中,有四個在某方面是類似的,
就退出不類似的一個來。
P11
Q22 R 23 S 44 T.55
11、在下圖中,若M的高度是30cm,每塊碍的高
12.
度是多少
-A 5 cm
B 6 Cu
61000
D 15cm
E無法計算
PQ是大圓的直徑,長48m2,是小圓的圓 你心。恰大里的半程是小圓半程的2倍,PO 的長度是多少?
AD
B.8 cm
C 12cm
.D 18cm
E24cm.
OA OT
OR 6T0Q do P
OA OC OF
1980
中學會考試題預習專欄
物理
(六)
明德出版社魯榮家提供資料 Physics (6)
WK.o
As shown in the figure,
the centre of mass of the combined body is G and is X cm from Gg
Hence, moments of the
weights of the cone and
hedisphere about G
qual in magnitude
({xr2u) (J)(g) (4h+gr-x)
(xx3)(S)(g)(x)
h(3h+gr-x) 2rx
(3r+zx-x) -
(ii) The system is in
atable equilibriu府 because the c. below.
(Mill & Dale Preas Ltd.)
Answers to Exercise 3.
1(a) Take the direction to
the right as positive Initial momentum of the target
(100)(-3)
akg.
18 kg:
← #圓