$18(1+54%)

8.12

Selling price of the

日四十月三年九七九一层公年八十六國民奉中育教僑華

Cost price of the article

(a) Volume of water

in the pool

ŝx(15+6)x20x12.

900 cu.m.

article at a

of 40%

(b) XR =

(6–1%)m

$12x(1+40%)

tand

$17

Salution:

買四第張十第日六十月二年未己鹰复

WAH KIU YAT PO (i) the resistance of B

報日僑華

三期星

1979

中學會考試題預習專欄

(ii) the current through B (b) The resistance of Bis

now measured. by using

of

specific heat capacity

opper - 420 J kg.

數學

(十三):

明德出版社文長波提供資料

Wheatstone bridge circuit

物理

(廿三)

as shown in figure 4.

明德出版社碁榮家提供資料

PHYSICS (23).

Mathematics (23)

Solution to Exercise 10

Section A.

Exercise 12

Magnetism

Solution

Electricit and Atomie. Physics

1. Two resistance coils X

and Y are connected to a

slide-wi

Wheatstone brid-

ge in the usual way and a balance is obtained when the

eliding contact is 0.3m from

the left-hand end of the wire (see figure 1).

(Wheatstone Bridge

Figure 1

The resistances X and are now interchanged and balance is obtained with the slider 1.2m from the left- hand end of the wire (see figure 2)

Figure

Determine

A.

the length of the wire (b) the ratio of X and Y

In figure 3, the driver cell E has an e.E.f. of 2.OV and negligible inter- nal resistance. The slide. wire is im long and

resistance of 20

Figure 4

The standard resistance S

is 120 and PQ is a uniform

resistance vire of length 1 m.

Cell & has an e.m.f. of 3y

and a negligible resistance

The bridge is balanced when

PX is 40cm. Using these data,

calculate

(1) the resistance of B (ii) the current passing

through B when the brid-

ge is balanced. (iii) the power dissipated

by B when the bridge is

balanced:

(c) Explain why the values

for the resistance of B obtained in (a) and (b)

are different.

A copper voltameter of

resistance 20 ohms and a

heating coil of reaistance

10 ohms are connected în

parallel across a battery. The coil was completely

immcrsed in 0.5kg of water

in a lagged copper vessel

of mass 0.5 kg. It is found that 8.91 x 10 kg

of copper is deposited in one hour.

·Coil

لتا

Solution:

20 cm

k-d'

(AOB – 2(5)-4

1080

[AON=/NOB=

AN NB

1089

Radius of the

Solution:

em 10 cm

The floor is inclined

at an angle 12a

the horizontal

Let radius of the

cross-section

(7.5-r)m

3m

AC=

LOCA - 90°

SN = √202+(41)2

20.5 m.

Area of the floor and

the four vertical

20.5x12+1x12+2

(1346)x20+6x12 sq.m.

486 sq,4,

Cost of the

480x704

$340 (correct to

nearest $

56.25-151

65.25

4.35

The radius

cross-section

Solution

(1_tanx) + (1+tanx) (1+cotx)" + (1-cotx)2

35 m.

work

10. Solution: Let xcm and ycm

be the lengths of the other two sides of the triangle (a) x+y= 19

—2tanx+tan x+1+2tanx+tan

from (2) x=

(3)

2cotx+cot x

Put (3) into (1)

10

17.01 cm

2+2tanx

CD is the tangent

of the circle åt [CAB= [BCH "[ACR= 90°

[CAB+/BCD+36° = 90°

2/CAB+30°

CAB = 27"

Solution x

(1)

(2)

The lengths of the

remaining two sides

from (1) x= 1+2

(3)

of the

Put (5) into (2)

(1+2y) y-y =

cm and 9

riangle ar

9 cm.

When y=2;

When

(b) x+

(2)

Figure 3

With K open, the balance

length x is 0.8m

(a-) What is the

of the

cell Eg

(b) What will the balance

length be when K is closed ?

An electric bulb B consumes

200J of energy per second when connected to a 200v

supply at its operation

temperature, Find

Calculate

(1) the current taken from

battery.

the

(ii) the heat energy given

out by the coil in the

same time,

(iii) the rise in temperature

of the copper vessel and

its content

(e.c.c. of copper -3.3x107.

-1

kgC specific heat capas

city of water - 4200 J kg

Solution:

Let $x be the sum

of money of the man.

His five daughters received $(1-2)(1) ►

or $

5 16

The fraction of the

each

money that

laughter received

5. Solution

攤提防假容

Section

Solution

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10 10

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19 (rejected)

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