有教消耗頁三第張五第日五廿月十年卯乙展
WAH KIU YAT PO
報日僑莘
·四期星
日七廿月一十年五七九一腊公年四十六國民业中
̇元位單 日六廿月一十
計統合綜優市栗股所易交券證間四港香
謝備 景高伫,最低價
收市價
*
假 最低價
汐市價,收環量 收楷體
)銀行業
(四)地查建築類
MERIT
「我辦 新高 最低 收市创收市價收市價
香港
名
15.60
2.275
16.60 16.50 16.60 16.50
2.275 2.35
16.60
·創購骨炎(除惠)0.69 0.69 0.69
4.10
0.56 0.56 0.56- 2.80 2.80 2.80
0.56
2.95
2.95
2.80
開市做·漫高倎 最低收市價收市價 收市價
3.95
一
2.95
0.69
2.275
2.35
0.75
3.90
3.90 3.90
3.90
4:10 4.075 0.75 0.75 0.65 0.66 .0.64
4.075
1.20 1.20
1.20
0.75
1.20
* 1.29.
3.95
3.95
3.95
0.66 0.64
2.95
2.925 2.975
2.95 2.95
2.976
公用類.
0.42
.0.42
0.42
0.42
2.175 2.175 2.125 2.15 2.175
9.00
3.00
2.95
3.00
15.70 15.70.
15.60
15.70
15.70 15.70
3.45 3.50
3.45
3.475 3.50
3.475
预地公司 MIGA
0.35 0.35
-0.35
6.15
6.15
6.10
6.15.
6.10
(九)投資類
1.96
1.96 1.95
1.96
15.70 15.80
15.70
15.80
1.54
1.54
1.50
1.51
1.51
4.30
4,30 4.30
0.72
0.72
14.70
14.70
14.50
14.60
11.60
14.60
新昌集團
14.30
14.30
14.20
14.20
廣泰股份
11.00 11.00 11.00
11.00
4.675
4.675
4.65.
4.65
4.65
4.65
ER FAKAN BA
0.50 0.50
太平徊
0.50
0.86
0.86
0.86
6.90 6.95
6.85
(三)工商企業類:
̇銀灘
3.00
3.00
2.975.
2.975
2.125
2.175 2.125
2.15
-6.25
6.25
6.75 6.25
6.90 5.95
PRACT
1.65 1.66
1.63
1.63
新隱基館肪
1.49
1.43 1.42
وس
(五)倉瑞類
13.80
13.90 6.50 6.50
19.80 13.90 6.50 6.50
13.80
13.90
̇新鴻基地霪
3.275
5.30
3.275
3.275
3.50
6.75 6.80
6.75
0.24
0.25 0.24
0.25
九龍食
11.80 11.80
11.60
聚合祿學
1.23
1.23
0.82.
.0.82
·0.12
0.81
安全貨倉
•橡膠信托
14.70 14.70
14.70
2.50
2.50
1.40
1.40
2.45 1.35
2.275 2:30 2.25- 1+68
(除各項) 22:00 5.50 (B) 9.10
9.10
14.70 14.70
2:50
2.475 2:55 1.40 1.35 2.275 2.90 1.69
1.68 1.69
1.69 1.69 22.00 21.70 21.70 21.70 21.70
5.50 5.455.50
5.50 9-10-
6.00 6.05.
)其他
1.15
1.15
1.14
1.15
1.15
(六)酒店類
奶敬酒店:
1.06
RE
1.06
0.90 0.90
0.90
0.90
城市酒店
0.70
0.71
0.70
0.71
0.70
海港公司
10.80
2.175
2.25
2.15
2.175
2.175
大酒店
8.15
8.15
永安人壽
5.40 5,40 5.40
1.18 1.18
9.10
確保
0.29.
.0.436
0.44.
0.435
0.44
0.44
7.75
7.75
.:
涂层健康
(除廳)3.70
3.70
3.70
9.70
3.70
3.70*
*
0.91
0.92 0.90
0.91
0.91
沸機工程
0.91
百樂:
بیت
1.94 1.94
1.94
1:94
.0.33 0.33 0.39
0.39
3.325 0.85
3.325
3.30
3.30
3.30
3.925
0.74
0.74
0.70
0.74 0.70
(七)防機製衣類
0.85
0.84
0.84 0.84
榮漢(除息)
0.60
0.60 0.60
0.60
南豐砂爽!!
4.30 4.10
4.10
·4.10 4.10
九體交易所上市股
名
開市價
最高價
黢仳
救市
肇光地菌-
0.52 0.52
0.51
0.51
0.51
保温
6.10 6.15 6.10 6.10 6.10
6.10
中筆船商
正國際
0.45 0.45
0.45
越
15.80 15.30 15.00
15.00
FIR (KA)
兆安
*會機登砂廠
依養表
0.30
0.30
1:74
0.99 0.99 0.99
0.99
1.74 1.74
1.74
永達科
0.25
0.25
0.25
0.72 0.72 0.72
0,72
WHER
1.40
1.41 1.38
1.30
1.39
0.59 0.59 0.59 2.65 2.675
長江製衣 ·
0.59
3.325 3.325 3.325
9.325
65
2.675
2.676 $2.675
暱㞊藥
3.85 9.85 9.85 3.85
The equation with magnesium should-
成交徽:香港周三百六十八萬元.
金氣篇三百七十五萬元
遠東錯大百
1976中學會考試題預習專欄
堅道書院主編
物理科(三)
何耀明
EHYSICS
(3)
Attempt all the questions.
Where: necessary take acceleration due to gravity 1g' to be 10
be 10 mg 2
la) State Archimedes' Principle.
b) there is an ice cube floating in
a beaker full of water. As the ice belts, will the water overflow or act? Give your reason. c) A balloon contains 800 litres of
hydrogen having density 0,1 gm litre 1
The density of air is 1.25 g litre and the balloon fabric weighs 0.8 kgf.
(i) Find the total weight of the
balloon, in gf.
(ii) Find the force in the rope
preventing
rising.
a balloon from
(iii) If the balloon is released and
rises at a steady speed of
8 me, calculate the resistan ce force due to the air.
(iv) Calculate the rate at which it
does work against the air re- sistance.
2a) A metal ball dropped, from a
helicopter flying horizontally at 100 S hits the target, after 20 seconds. Take g as 10 ms ignore air resistance.
and
(1) What is the ball's horizontal speed just before it hits
the target?
(ii) What is its vertical speed
then?
(iii) At what height was the plane
en the ball was drop-
flying. ped?
(iv) How far did the ball travel
horizontally between release. and impact?
(v) At what angle of sight, 0,
should the ball be released to strike the target.
b) A man pushes a 40 kg box, origi- nally at rest, along a horizontal. floor by exerting 113 N horizont- ally. The frictional force seting Is 50 F
(1) Find the unbalanced force. (ii) Find the acceleration of the
box.
(iii) Find the displacement of the
box after moving for two seconds from rest.
(iv) Find its speed after two
seconda from rest.
(v) Find the energy supplied by
the man in two seconda.
(vi) Fird the energy gained by the
Box.
(vii) Find the energy lost as heat
at the surface
c) In an elevator accelerating up- warde at a certain rate, a spring balance reads a body to have a weight of 20 kgf. When the ele- vator is accelerated downwards at twice the rate, the body, appeara to be 14 kgf.
(1) Find the upward acceleration. (15) Find the mass of the body. (iii) Find the reading of the spring
balance when the elevator at constant motion.
(iv) Find the reading of the spring
balance when the cable of the elevator is broken.
Suggested — answer of Question No.1 1a) Archimedes' Principle states
that when a body is wholly or partially immsraed in a fluid, it expériences an upthrust equal to the fluid diplaced..
Note that: the word 'FLUID emphas–
ised here. It is a common mistake
to replace it by WATER or LIQUID. This principle applies to both liquid and gaa.
b) Let the weight of ice cube by W. Volume of ice immersed be U.
Volume of the melted ice. (wholly volume) be V.
Before nexting:
(± upt. = Vol
After melting:
the weight of that of part, water obtained from the melting. ice is still we ghing the same as before. W
W÷ya. HO
From (1) & (2)
U:d,
U V
-(2)
Volume uccupied by the ice cube before melting is equal to the volume of that part of water con- verted from the melted ice... Therefore, water will not overflow As the ice melts, the immersed vol ume displaced by the volume of water which converted from the melted ice exactly.
C) Wt.
of
(density) (volume)
bmôn gf.
Total wt. of balloon
= (wt of H2)+(wt. of fabric)
=80+ 800 =880 gf-
(11)Upt. oz balloon
-Ana
(Vol. of H) (density of air) (800)(1.251 - 1000 ef.
Force preventing it from rising
Upt. Te tal
Lawt.
-1000 - 880
120 f
have been
Mg + 2CH COOH
Question 5
(5), should have read.
(CH2C00) Mg + H2
"If excess 0.05 Molar solution of Bilver nitrate solution"
Question
A1. The function of sulfuric acid
here is to retard the rate of the following reaction.
H2O +0
But
H2O2 Traditionally sulfuric acid is termed a "negative catalyst" it does not mean that sulfuric acid slows down the reaction by providing a higher energy barrier. 2. Here sulfuric acid acts as a
catalyst and dehydrating agent. It removes the meter formed in the reaction and increases the yield. of ester by affecting the relative concentrations of the equilibriun mixture Equilibrium can then be shifted to the right, favoring the formation of produces,
3. If water is used instead of
sulfuric acid, efficiency of coll- ection of the gas will be affected A fine mist of sulfuric acid wil
he formed in the air. For all practical purposes sulfuric acid ia used to dissolve the gas, a fuming oily liquid will finally be formed
+ SO
This is called oleum. It can be converted to sulfuric acid by cal-
culated addition of water.
2H 50
4
4. He re sulfuric acid acts as a
catalyst. The structure of formic acid is so affected that water and carbon monoxide are formed
HSO4
TOOH
structurally
H-C.
Ans.
(iii)If the balloon rises at steady
apeed, the agebraic sum of the vertical forces must be equal to
Upt
W-RO 1000 - 880 - R = 0
(17) p =
(R is the
resistance due to the air)
-Ans. R. 120gf . ---
(where 120gf = 1.20).
= 1,2 x 8 = 9.6 watt.
1976 中學會考試題預習專欄
堅道書院主編一
化學科
(三) 李國榮·
CHETSTRY (3)
Corrections in question paper Question 1
(1) One more isomeric structure
H
K
HO
H
H
is also possible but it does not explain all our observations.
+00
H2SO
H2O + CO
Sulfuric acid has a great affin- ity for water. If accurate amount of the acid is required, the sin- plest way would be by means of volumetric measurements. Weighing out such strong and hygroscopic acia would not only be dangerous but also inaccurate. 81. Glucose can react with concen- trated sulfuric acid to form a relatively pure form of carbon by the following reaction.. The clear. crystals of glucose would then be turned into a black powder form..
0
C612 6
60 + 6,0
godium chloride would give no such reaction. But on the edition of silver nitrate solution to a sol- ution of sodium chloride, a white ppt which can be dissolved in ammonium hydroxide will be formed. NaC1 + AgNO 2 AgCl + KaNO3
In effect
01-1
(aq)
+ Ag* (aq).
2. Ethane is a saturated, hydrogen.
carbon which will react with. gaseous bromine slowly, showing a gradual discharge of the red color of bromine.
C2H6+ B*2
C2H5Br
C2H3Br3
tc.
DLA BUDS Titution products are
possible. Yet what we are inter-
ested here is only the rate at- which such substitutions can take place
Ethene, on the other hand, reacte rapidly with bromine gas, thus removing its red color much more rapidly. The reaction is additive which is typical of ethene.
Br Br H-C-C-H
Br Br
ethene
bromine
1-2- dibromo- ethane
Question 5
From the equation
H1+ NaOH ~
NaCl
we know that 1 gm mole of hydro chloric acid FC1 reacts with 1 gm mole of sodium hydroxide. NaOH, Thus if the gm mole of sodium hy droxide used.
10001 gm mole Then the amount of hydrochloric acid used 100%
1000gm mole
2. From the equation
Mg + 2HCl, MgO), Ho
m mole
we known that 1 gm mole of magnesium metal reacts with 2 gm moles of hydrochloric acid.
Thus if the gm mole of magnesium metal used [12.20
=
zygm mole = zgm mole "hen the amount of hydrochloric acid used 1
x 2gumole = 1gm mole
The amount of hydrochloric acid in the original acid soution
+ 1) gm mole
- (to +
Togm mole
The volume of the acid solution
500
dogliter
****
liter
The molarity of the acid solut ion.
(70 )Molar
2.2 Molar
The amount of sodium chloride formed in the reaction equals the amount of sodium hydroxide used i.e.
TO 80
10
go mole
The final volume of the reacting mixture = (500 + 100)m1 = 600 ml
.::600
liter
=
1000liter Thus the molarity of sodium
chloride solution
(T0 = 18)Molar
0.167 Holar
Molar
According to the equation
As(aq) + Cl(aq) AgCl (sh
In terms of moles the amount of silver chloride obtained will be 'equal to the amount of scluble chloride ion in solution. Thus the amount of silver chloride obtained will be 1.1gm mol. since all the chloride ion in the acid remain in solution. Molecular weight of silver chloride = 108 + 35.5 143.5 The weight of silver chloride
143.5m x 13/157.85 gm