日八十月二年五七九一靨公年四十六國民牶中
芳名如下:......“
元港
1,中
新業
名
如日
下
報
會基
:
按某人」數字撻朵 各界捐铁救重两季如用支骐祈付,請寫「觀瘸日報救重助學」,在左上角,及劃去「
合計共四千式拾元 。 #K-KEUR#+R - MEI FUNG CO. LTD.K+R- 千元,新會荷葉同郷會叁百元,香港華人足球員聯誼會百元,錦華洋行 香港中華基督教青年會(慈善舞會)式千伍百元,推新英文中學全體員生 華僑日報第十八届請者軟童助運動,昨廿七日收到各界熱心捐欸响,
本港新聞
助學捐欸源源而來
方善長慷慨解囊
28 FEB 1975
CITY HALI,
五期星
新英文中學校長說一九七五年二月廿五
負生捐千元助學
斯•荷塘同鄉
·
橋日報救童助學運動,讓得社會人士支持
|事 - P醋面本上本校已生掛助之猪幣一千元皮恩英,黎基,監事長李長順。 模員坐,急公好義,至令人感佩。茲錄來面如下。托國際新聞就算上應鯤鐦行三百元或祭一 ,任何推獄,無滄大小都是用得特別有意,該,成緩卓著。此種熱心社會黨帶精神,至含鈥 啓者,爲响貴報讀者救食助平點] 僑日報岑糖休先生+新會蔔同鄉會理事長李世 迅啟者:貴報所辦救育助學運動,並有多年 ,但救 助學之用。予查收盼望爲荷,此
·新會荷塘商絡會熱心捐助三百元,育來而
-EKKER I KRK - TEKKIDEKEK- ,世幣一千共支某乙張,在此經濟不景氣情况下
英
無真姓名住址者不登
讀者論壇破他人名譽者不營
一紙雨面寓字者不登
津貼校文員飽受種種不合理待遇
一同情者
.學校之文員,因爲完全没有病骰,如果生病- 不論羲重與否,仍須帶病返學,否則學校當局交警 「之有辨病醌,使其安心無病,而在政府任職員工及所有教師們,每年均有有薪病假,然而在津貼
·編輯先生:大刀在谁禇學校工作之文員,向社會人七訴說一二點不平等的待遇。 一、病载......在任何帶牌中,均有含共職員身烩微康着想、如遇職員有病,當會給予一個時期
WAH KIU YAT PO
郭日僑華
保有包居
纖轉屬年外外
不貼題作也的所
有教聞港頁三第張五第日八十月正年卯乙
上受
1. •
理,其他的事情更無論矣。
I
貼汤,此教作 亦長旣萍 婆的已貼
校侵校病不生日,
2於薪否師齏上
學而位障員
次衆 理爆作
工
注助校
蛋蛋理九然
滷仍不
做學校以外的工作,更有對本編主任成教師們工作亦要文員代勞,是更不平等的了。 得不到順外薪酬也是意料中事,至有些學校在教養之公衆假期中相定文至日校工作,有些文員規京
保留年許的,何獷空毀鹘外?:
平苻貼上
學
退變政
H:
我的不平等待遇:長爲各力所忽視的問題。 不人個格過而提出意見,要求當局改曾了希望社會賢達,各界人士,正視一樣存在本港津貼學校 一個選貼學校委員會之類,討論學校文員之大小事情,未知有沒有寫有關津貼學校文盈之不平等, 受公積金制度。以本人而具,並非讚而歷年在眨體中之公積金,但在瓶口的文員薪金中,加 一,以上数黇·道路羨的其嘅賽,據聞教育司彩英聘語一部份就會知名人士及學校校長,組織 五、退休及公積金——在政府工作之月,可享受退休金洲;在洪貼學校之教師,可本 一同带者上。
2
初裤驮當处穖會計,所有坩些都說明政府助理文員的域和壓迫···· 「軍機,難明知違例,但生香港人,奈何于此外有些在工餘酒樓食肆做樓面,收錢,被小型公 南世工夫,我們大部份已婚同食部分娩兩職,有些在工餘些繁,小巴,的士司機,甚至當前牌 ,見女的教育費,交通費,食等每一項都是極大的支出。在入不激安的情况下,只有一世人 由於吾等爲低辦公務員,微的米金在通貨膨脹日銓重下,豈能持沉爹的生活
· 編輯先生,君等爲政府助交揖,現俄政府助和文员的薪級制度及升級制度及會向处叙司進 一助理文員
籲請當局改善助理員的升級制度
『未的不郁,
一業助理文員敬上一九七五年11月十六日。 交員的升級制度,及他們入不敷交的生活值得政府當局候想的。 」助文發一個升職機會,否則才州的一些助交易 ㄝ五千遙無期的退休期,無 的工作熱拊,自然會冷却凝固了。是故如何對待工作日低落的助理交員,及有效地改善助理 西女員」 - 頂薪點不妨校現存的助理文员頂薪高三個薪級點,從而提供不能轉職爲二文角的「老
·機會和服務年既有很密切的關係,助理文員的和服務年資著無相干,是故助理文員的升級染 選委員會考店助理文員的服務年資,使服務年安較長的助理交員獲得優先機會。此外盡早公佈升 二,在第二年已可獲得遞增的複點,而有接地很快影响政府的支出。談照其他等級公務員升毅 「唯一不同的是頂薪增加了,可惜那是毗年養的水了。已頂薪點的「老」助廂变造如獲升爲二級女 親由来千所有鬼天谷武者爆拓也法必須的,在別一方面~音等宗議政府開放的XXC 一以上而未洺頂薪的助文獲升爲二級文貴,但薪金林毫未獲調整,和未獲升級前的薪金一樣, 考筆試部份是極之不合理的。由於二級文員和助理空之間有幾個實亞的薪級點,是該工作|||年 一米的問題包纈萬有,口試則毫無搖出可口,此外即使筆試合格而凡試不合格,翌年的考試亦 「老」助理交貞的敢大離開易一年一度的升級試◎升級試分試試兩部份,珠試部份中普通常 此外,助理文盈的升級機會是非常之渺茫的。個人的工作行爲謝告固然要良好,但對於大部份
七不固否
only
brief
B
K075:
橋
中醫運用專欄
化學科(十六) 陳湛杰
CHEMISTRY
(#16)
Solutions for Chemistry (#15) Conventional Questions
The chemical fom which a metal is found in nature depends on the. reactivity. This is indicated by the ome
in the electrochemical series: L,
es, Ca, Na, Mg, Al, 2n, Fe, Pl, Cu, lg. Ag, Aus Thus the alkali met
metals and some alkaline earths are so reactive that they never occurred as free element or
but are found a
the stable nitr
down.
heart
themic reaction occurring further
The iron fo med is tapped a helt furnace. The limestone decomposes.: into quicklime and removes the earthy impurities aš a silicate slag that float on top the dron, preventing the latter for being oxidised, it is also withdrawn at interval
cao + Si - 64520, Meat of the
iron from the Blast furnace is refined to renove
caat
all impurities. When almost all th carbon is removed, the product is wrought iron. The various steels: have a
a carbon content varying from 3.1 to 1.5%. Different refining processes giving steels of differen composition are in use. These
include the Ressener process, the Siemens-Martin Open Hearth Broc838 and the electric furnace. The manufacture of steel demands not only a reduction in the amount of carbon and the removal of most of the silicon in cast iron, but al00. a very thorough purification from sulphur and phosphorus. Sulphur addition to molten imn of can be removed by a preliminary
manganese, foming a high melting insoluble sulphide lins; but phosphorus has to be eliminated by the basic lining used in the various privéesses.
even as the oxide, AB A1 2. Methyl alohoi ás manufactured
Zn
Fe;
nitrate,
Pb, may
eulphate or carbon the oxide of the sulphide in addition to the carbonate.
For Gu, Hg, Ag, Au, du to their stability they even occur as free element although usually the oxide and sulphide ores are, important
positivel
During extraction, the posi charged Metallic ions in the-ores
are supplied with electrone to be
07 of the reducing agent.
the
converted to the corresponding. neutral atoms, Such a process of
reduction. The electr
ctron gain ia a reduc
is dependent
upon stability of the metallic ions... Thus to
for reductions up to compound of Al, the dratic presss
of electrolysis is necessary.
For the less stable metallic ions (Zn++ onwards) the most economical reductants available are coke or carbon monoxide
from incomplete
nation of coke).
often, the
"the richer oras di sa obtained by separation from the
stream
This is. usually inpuri attajned by washing sitli a of water when the lighter earthy particles are removed. In certain Cages, A magnetic separator can be
Such processed are employed. cent processes.
com
sulphide and carbonate o res are often given a preliminary roasting in air, for removal of sulphur dioxide or carbon dioxide. The oxides so obtained are easier. to deal with.
22n+302. 22n0 +250,
znco, - Zac + CO2
The roasted ores can now be reduced with coke. Sometimes, by a suitable adjustment, it is possible to reduce some of the sulphide by the oxide.
As the product of the reduction: process
ess is seldom a pure specimen, purification has to be carried out. Electrolysis gives very pure metal but more often the impure metal is heated in an open hèarth, when ippuilties oxidise and rise to the surface as a soun and can be removed.
Irun occurs ohlefly as oxidès in different forms: haematite Pe¿0,, magnetite Fe3 4*
Extinction 'consists of two processes, firstly melting to the crude metal, secondly the refined process. A
Smelting is carried qut in the Blast fumade. Iron
Για τα ore,
coke and limestone are powered, mixed and pre-heated and then fed into
A blast of the furnace at the top.
hot air is blown in at the bottom through water-cooled copper pipes.
200
The Blase
500'c
€30°%
800'
[47 Le gasca (amoj
Rik blast (post.
At the hottest part, combustion
đi ooke to carbon monoxide occurs,
iris carbon monoxide is the
It reach essential reducing agent. With ferric oxide in two ways. Fe0, 300 = 2Fe
+ 300 LB
exothermic and reversible, and according to Le Chateliere. principle more iron. will be produced higher up, where it ia cobler..
F®203 + CO = 2Fe0 + 002 is not reversible, the ferrous oxide formed is reduced by coke in the endo-
on a very large scale by passing
mixture of garbor monoxide and. hydrogen temer u pressure of 200- 300 aungspheres, over a catalyst heated to about 350°0
·CO + 2HCH2OH + 34Kcal.
The catalyst consists of zinc oxide and, another oxide such as vhromic oxiút. As the reaction proceeds from left to righk; with Hi મા lution in volume, it follow from De Chatelier's principle that the yield of methanol is i
and becsua in the pressure; the reaction 13 exothermic, mising the temperature will drive thu eqail-brium to the laft and the yield of methanol.
Now east malasively high temporaluzes of about 150°C a re
re employed, heceuse the Et of the reaction is atliervise too low.
monoxide is obtained mainly, by he action of staan on red het coke.
CICCO + H2
Additional hydrogen iz obudnal by tran king some of the water g with move steam at 500°C in the preserve of an irch cxide Patalynt:
the carion dioxide heány- coaoved by tate ? under presure.
Methylcohol may be identif u by its endineas to be oxidised to formic ani of a tharacteristic
Thus when methyl alcohol e 3] 31 *** heated with a solucion of a mixtare of acum dichranate ahi dute sulphuris acid under a reflux pordenser, formic acid ja forned and the ong colour dachte is anget to the green colour chɛemio .Bilt
CH2OH + 2(0) = H.COOH + H2O.
Ethyl alenhol can be distinguish-. ad fe ethyl alcohol by olafo M
This is carried at by brating the alcom) in a tout tube with a
little iodine and sedim carbon teaolution. Ethyl alcohol fonas-yellow-coloured crystals of iodafore which
leanturistic
Bae Ly if its pure methyl alcohol induffin curut be chthined. the actual sourve of the rections can be interpretad Col3ows:
No or
CRI3 + H.C0982
3. The canetion of A with hot consent:oted sulplaric acid yiel4- ing as that apporte combustion indicates that it must be an oxidizing agent. An oxidizing agent that # rot really soluble in water or acida predicte thit it. orimo he those that are walts or
· Pirthanen re. ecoily its wielding salto.
Mack clout, coupled with the eho beristic reaction with cor- centrated hydrochloric acid confirm
that it must be
be manganese dioxide.
sulphuric acid on heating
B
The
Sime on admixture withự canganese dioxide and concentrated
ing yielded a greenish yellow gas which is
B must be a chloride. chlorine 19 a white deliquescent soll. solution of Buron passag hydrogen sulphide in acid medium yaelde no precipitate, but a white Sale precipitate is formed if the medium is elkaline. Thus the sulphide quot be acid soluble, and since it
is white, can only be zinc sulphide
Hance' Big zinc chloride.
The reaction of A, B, and conc. 2504 is as follows:
MnQ + JZn011⁄2 + 4μ*
Mn012 + €12. 210222
+
the reaction of A with conc. H2504
10:
200 + 2110 231504+0 +211
The reaction of A with hot conc. HOI io like the first reaction. is deliquescent, and on heating readily yields a basic chloride: EnC140=Zn(OH) C1, HOI
A solution of B firstly reacts with ammonium hydroxido to give. ̈zdno hydroxide, which is readily
soluble in excess ammonium hydroxið by complex fomation to the tetraammine
+ 20H Zn(OH)2+201
2x (0)+ ANH TH
(Zn.4NH) (011) 2 + 40°
Zn 2+
The Zn ion in solution can be precipitated by hydrogen sulphide in alkaline- medium:
+18= ZnS
+ 2H+
QUESTIONS FOR NEXT-WERK
1.() What is the bowim Usat hoja Uy wanted (1) when a meden nomzinga viti be puningatal, (23) when two Zale tuline... Th) Par the trema decom el si ant of potassiefariate, to potassium
horkie and clysen (i) given Wyrm for the electronic phoetry of the products, (15),
to the optica the products world hyann due, type of ominj.
las
Before reaching the point o
After reaching point Q.
(c): When waves generated from S, and S are in phase or reaching the point P, a Construtive inter- ference occira.
However, if they are out of. phate when arriving P, destruc- tive interferece padure,
parentar
2. (a) Infm-red
We
BIO WE 2. Wen da med den last, tuha
១៥ : powder of lead dioxide who t and
ed, a
a ya how residue was During the heating a glowing splint plwerd as the routh
192. cubre tunt tube was rimit When Fart of the rusidue w treated with dilute auguric sold, e-whiite insoluble butane, Was obtained. The c'the part of the renidue is reach with dilata acift and filtered.
Dazed
Eed to a sulphuric acid was Brick of the filtete. The othe
(6) Braleingli the that tonic
(b) flow.
emile for further
se pure dry lervi prepares fru tilga
Say I thighsonita
thanol,
ration of uoatic
What uan sulphurie neid are used. are the purposes of Each of these
Uraler at conditions Wagents. #ill tat eximum yield of acetic acid be reached.
(b), mat type of rangli codurs
helin acts with (1) Satur.ted hydrscarón, (11) an unsaturated Hydrocarben (c) Tao moles of ethane, on
complete comntion, price a Litres of carbon dioxide at NurLP. ositions and grans i water. Find a un b
075
物理科(十六)
Solution
PHYSICS: (16)
陛承造
(a) E. and H aute in phase.
Its wavelength is 9/3-3 om Its frequency is 6 ha, then.
= 6 x 3 18 ite apead f (b) True. iine; approaching wave-fronts Dotted line: the reflected
Wave-fronts
wavelength: 3x10"
7.7x10
requerer: 1612 10z
...).
speed: same as visible light
3x16 ms transmitting: ct essential; medis
can trazonit. through
origin: very not body; solar heat;
(love enrgy change in
electron structure of atoms)
penetrition very weak
power!
detection: themometer, thermopile Visible light
wavelength: 7+7x107: 42107? frequency: 4x114 7.5x104 @peed:
tremitting hot asentiel
medium?. cen trust through
origin:
vacum
White hot bodies, the sud
(Energy change in election
struotura of atoms) penetration weak; ezen tamugh
POWET: transparent objecta detection: photocell; photographic
film; humer eye (visi^n.
-{3.tru-violet
wavelength: 4x1377- 6x10 frequency: 7.5x1014
Light Breed: Rame us
5x10
3x10 trendmitting car as through:
raud itam
vaciun origins solar heat, fluorescent
emp (Pairly high enargy changes in electren" atructure of atoms) penetration weak
Fowera
2ctection: photographic fils;
<-my
fluorescent scre
wavelength: 10-8
Frequency:
10-12
3x1016 3x22
speed: 3x10° /s
melium: not essential
origin x-ray tube (high energy
Changes in electro structure of atoms)
penetration powert strong; can
penetrate 5-15 cm of lead sheet
détection: photographic film;
ionization; fluorescent-
(b)
acrean
In deep water-
Its wavelength-3 cm
It spead 22-8 = 21 cm/3 Its frequency = 24 = 7 Hz
In shallow water;-
*
Ito Apard x 21 = 14 cm/e Prequency of vibrator 7 K Its wavelength = = 2.co The fractive index'
velocity in deep water velocity in shallow water
=
3
.
The angle = sin(x 0.707)
28°6'
Questions for this week' 1.(8) Compare sound waves and
electro-magnetic waves.
(b) what conditions are required to produce
(1) echoes
(ii) resonance of sound?
(a) The questions below require
descriptions, shortene your answerg by using diagrema. (i) How can it be shown that sound will not pass through a vacuum?
shown that
(11) How bán ít
sound obeys the same laws of reflection as light? (iii) What conditions are
nccessary for two sound waves, travelling in the same. directions, to cancel csak either and give silence?
2. (a) Explain why the same musical
note played on two different instruments sounds different ever
when they have the same amplitude
eape
(b)
Of
pressure intensity effect the
velocity
(c). Two peo
people A am B-sland 200m
apart along à line parallel to a
When A fires a pistol Long wall. B. Hear's
irs two reports with an
interval of 0.25 8 between them.
What is the perpendicular.
distance between the wall and the line AB?
新數學(十六)・謝國興
MODERN MATHEMATICS (#16).
Coordinate Geometry. IV Conice.
1. Paraboles Def: A point moves so that its distances from a fixed. line and a fixed point are equal. The locus of this moving point ia called parabola
Let xp be the fixed line and (0) be the fixed point whore p i'a constant then y = 2px 10 the standard equation of parabola. The fixed line is called the directrix.
rix. The fixed point is called the focus. Here x is the axis of parabola since it is also. the axis of symmetry. The point midway between focus and directri is called the verter.
2. Ellipse: Def: A point movea so
that the gun of its distances from two fixed pointa. remain constant. The locus of this moving point is called Ellipae
Let (-0. C) and (0, 0) be two fixed points and 2a be. the con- stant
So √(x+c)2+y+ √(x=0)2+y2 = 2ạ After transposing, squaring and reducing, we get
Let a-c2= b2. Then
2
(-0,
0)
On the ellipse, zajdr axis – 2a, minor axig = 2b. Focus be and (0, 0), The chord drawn through either focus perpendicular to the major axis is called the latus rectum. The length of latun rectum
The ratio of .15. called the eccentricity of the ellipse.
264
3. Hyperbola: Def: A point moves so
that the difference between its. distances from two fixed points remina constant. Thus the lacus of this moving point is called Hyperbola.
Let (0,0) and (0,0) he two fixed points and 2a be the constant.
=2a After transposing, squaring and reducing, we get
Let
Then, b2x2
On the hyperbols, tænaverso axis =2a and conjugate axis 2b Focus be (-c,0) and (0,0). The latus rectum is also equal to
Are the eccentricity e
རྒྱུུ་
=
If the, fodi are on y axis, the equation of hyperbola becomes
EXERCISE:
=-1
1. Find the equation of the locus of a point which moves so that it's distance from (3,-4):18 units less than its distance from the 1in x+5=0
2.
Pind the locus of the vertex of e triangle with (0,6) and (0,-6). ar the enda of one side if the product of the slopes of the other two side
19
3. If two vertices of a triangle
are fixed at (0,5) and (0,-5) find. the locus of the thin vertex if the product of the slopes of the variable side is 7..
1975
中學會考專機
數學科(十六•文長
ADDITIONAL MATHEMATICS (#16)
Solution to exercise 15
1. By De Moivre's Theorem
and
(cos +1 ein e)"
* con 6+ i sin n e
(cos 0 + i sin 8) D
(cos (-n 9) + Dein (a 4)
ens n 6 – 1 sin ne
(20+524
=2, cos ʼn ☺ and
sin D
+15Z
81(008 60 + 6 cos 48
15 cos
Similarly,
2. The number of ways of forming the groua da thể rubor af ways of aknosing 5 children in arter for the firit group divided by the lat mauer of ways of ordering those". children and the number of ways of ordering the gmupa
10!
ར
- 126
The group coulaining the ta youngest children can be formed by selecting 3 more children out of the remaining 8 (and the other group follows) Thiu pan be los Lu Cah = 56 myn
b) In the remaining (126-56) groupings the two gungeot Children are not in the some grup 1. mugher of ways - 70
3. The diele which has for a Siamutur the connector af, (1,2), ((-1, -1),13
The ouatlon of the diameter of this cirle Which passed through the points (1,2), (-1,--4) tapi
2 4
4 or 3x - y − 1 4 0
So any cirole through (1,2), (-1,-4) 18
+ 3 + 2y -9 + This phases through (3, -5)
925-10 -9
0
y=10
(9.5. 1)·
Plan carcinon rele of the triangle is
x"
+ y + by - 5 - +(3x - y − 1)
-
Jr x2 + y2 - ffx + fly - 103 -
The co-cidinstep of alreumaentje
110.
Exorcise 16
1. Find the first three terma and the pom in of the expansion of
- 5
(x+3)(2x-1) to escenting powers of x and state the range of values of.
for which the corresponding expansion sa en infinite series 18 e valid one.
2. Find the equation of the tangent 'drawn from the origin to the ellipt
x2+752+16x~1 12y+448=0.
3. Find the equation of the cirole through (3,4) which is orthogonal to each of the oiicles x+4x+1=0 2x2+y2+6x+1=0 4. If sin( +X)~ coa{@ +0)
consin express tan e in terms of adi eniculata the value of tau 0 if tanz