日六月六年三七九一醫公年二十六國民華中 育教僑華
真四第張七第 日六初月五年丑癸歷夏
香僑
WAH KIU
YAT PO
報日橋華
(田PO在BC之同側,故取員蹄) LABC之平分線為
三期星 M BP (56) By_b = m (x+5).
m
372-242-5
JB
(2X-34-5)
合:X20得在軸上之截距為5m+6
m)(5m+6)=20
中中會考數學試題
(一)BC之兩頂點:A(3,2)及
BLI 且D (d)為BC邊之中點求
D點及C點之坐標:
(ii) 過C點且垂直於B邊之直線方程; Chip 2 ABC之平分線方程.
則
d
.C (X,40
D (4.0)
解的設汇點之坐標為(x1))
故=3
2X1-9-5=0,2
(點坐標為(733),D點坐標為(4).
垂直於B之線之斜率=-
過之而垂直於服線之方程式為
((()若LABC平分線上任一點為PC2)
ü
BA之斜率=
3-1
4-3 = -3 (x-7) 88.2x+3y-23=0.
又題設BC線方程式為2%-38-5=0
P至BC之距離為一
ODERA A (5, 10) B B (-2, 3); 苦P點與Q點分别内分及外分線段 AB,其比為3:4,求P及Q之坐樓 (1)若直線通過點P(-5,6),且與
=坐標軸所成之角形面積為20 試求此直缐之方程
·6-5m
m
25 m2 460 m +36 +40.m=0
25m2+100m+360
(5 m +18) (5 m +2)
m
一
故所求之直線為
Y-6=-(x+8) - Y-6=-3(x+5).
op 18x+54 +60.00 $ 2x+54-20=0
(三)已與圓(G)-10+920及 (C2) x2 + y2+104 +21=0 今有一圈(C),外切於圓((1).又内切於
求證圓(七)中心之軌跡為
9x2 - 1692 =-144
若圓()之中心在某一軸上,試求() 之方程.
X2 + (1-5)2 = 16. 园心為C(0.5)半径為4.
x2 + (4+5)2=-4
1** 9x-1647=-144 $£1218
·9x2-1677=-164. 由CG做只有双曲爆下. 方之一枚始適合所求
(1)美圖(C)中心在一軸上,將上段结
倦根妏心圓心應為(0-3)
¥48 √o2 +27 + 2 = 4 461
2757 12+(4+3)?=16,
Pp x2 + y2+6y-7=0.
(D) 218 fro Folle (P): yz 4ax P(XY) (P)上一點,試求(P)在點P (x) 之切線及法線方程
又若直線ax+y=1為(P)之一法線)
解:切線方程式為y=4a(x+x,
Ep 4y=zax+2aXr,
切線斜率M=
法線方程式為
8-4=-2 (X-X1)
Bp Y1X+zay = X18, +2ay,
2 (0)2-31 22 be $€ (1), (2)
其係數應比例
5
P點
钟
41 = 10 + 2(3)
(-22:0026.
C
Q點
10 −7 (3)
=31
圓心為(2 (0-5)半程為2. 若圖(C)六圓心為().
亦為+(+5+2
因(g)
為熱物绲(P)上3點:
故++(-572-4
+(+)?
\X3 +14-5)2 = √K
兩邊平方,约簡将
38€ 12 = 4ax 12 adj2=4d (-20) (4)
從或求得B
=
=
X, +2A (£4, *0)
20
2.ax
1978
中文中學會考試題預習專欄
化學科 (卅一)
宋泰初
再续總復習解答
乙部
(芳(a)(4)答:以電解法鍊銘時;
张出一
(1)所用之原料為铁铝石(bauxite)
A12030240 及冰晶石或明礬石(alunite
KAL, (SOU)-(OH)
所用之電解槽穀以石墨作為陰拯,以碟 棒作為陽極
(6)(6%)其離子方程式為:
Al2O3
電
解
4Al +302
·302+30
-3002:
-凝结
氧化鋁和冰晶石
石要襯壁
上面為以電解法治點電解槽
(£)(a) (1%) 1. ZZo3 WM2-0129, t=0°C,
P=1AP,VH=112C.C.,鎂活捉
中文中學會考試題預習專欄
英文科
(十三)
徐有祿・
English (33)
The answers to last week's
exercise are as follows:
(1) glued
--
fixed
uninvited
unwanted
-ed
intimidated
just further
only
sensible
cowed-threater
more
wise
Inform
Tell
protection
safeguard
heroic
brave
kept on
continued
(2) Jack did not hear the burglar
entering, because he was absorbed by what was shown on the television screen.
56=0.263.
I fo= Mg + √@ 3 & Ang =?.
III解:(1)在標準狀況下,支分子
鐵,即20016克,其体積為22.4公我:
2.0169 Jaill
x0.1128 -0.019.
(2) 0.019年氣需0.12g生星胶代。
鎂营量為:(劉克原子量為2008点)
-0.019=10089 ± 0.12gx
x=
1.008 2×0.129 = 12.0969
0.012
(3)檬:Dulong-Petit定律
原子量
6.4
(4)因原子價:
原量
當量
故镂之原子優=
24.33 12.096
0.763
-433.
=2.01
(5)但原子便必為整數,而求得原子德 卷小数;以2433為原子量的近似值 故。由此推得鑤原子儒為
(6)據:原子量=原子優當量 $3628=2*12.096 =243192 餐:镁之正在原子量為24.192. (b)(5)答:工,如:某人所食之砷重 0.75g,砷含於砒霜(ASD)者。
ᄑ求:此人食砒霜之為若干..
(砷原營為
III解:(1)砒霜分子量
(3) The burglar was equipped with
an iron bar and a knife. (4) The burglar disagreed with
Doon, when he said that Doon was just an actor, after Doon had said "My advice to you, ladies and gentlemen, is not to be intimidated by criminal -5".
(5) The burglar agreed with. Doon
at the point when he said "Do you hear that, boy?" after. Doon had said "
if a criminal is standing in front
don't of you with a knife, try to be heroic." (5) The boy's reply was disappoint
-ing to the burglar, because the reply was that his father −ts money was kept in the bank and the burglar could not steal the money.
It is perhaps fitting and pro- per for the candidates to do some more translation at this stage, so that they may be conversant with this phase of Paper III as they are conversant with compre-
The following passages, hension.
-≤4 - 9 = 3√x2+(y+8)2
· As2 03 = 2 As +3×0=2^?f+3×16=198.
(2)砒霜含神百分率為 A
2075 198
-x/0070-7675%.
(3)由上述结果:100g 玉石比霜含砷
7.75克,毂含0.75g.砷的砒霜蛋為求。
100g:7575g=x:0758 100gx1,758
X=
此心食砒霜0.99克。
0.999
(共)答:能被氢氧化钠溶液吸收的.
(1)二氧化碳(2)二氧化硫,(3)硫化氢 (4)(2)(6)三氧化気等 其化學反應方程式為:
(1) 2NaOH + CO2 Na2 CO2 +Ho
(2) 2NaOH +502 Na, SO3 + H20 (3):2NaOH + HIS Na2S+2H20
(4) NaOH + HCl → NaCl + H2O (1) 4 NaOH + zd2 4 Nach + 2420 +Q (6):2NO2+2NaOH NaNO3+NaNO2.
+ Hie
(6)答:置固体氫氧化钠於空氣中,能吸 收空氣中的水份而潮解成氢氧化钠的 水溶液,逐漸吸收空氣中的二氧化碳, 結果生成碳酸钠的结晶。
(NaOH+H20)+CO2(空氣).
(七)工,已知:某物質為Na2CO3 Nazcg.io.
H20;其重量為10g;加热装得9.89-3. Na2CO3.
1.求:此混合物含+水碳酸纳%。
one to be translated from English to Chinese and the other to be translated from Chinese to English are selected with this purpose in mind.
Passage One.
Translate the following passage into Chinese:
As the ferry left the Jordan Road pier, Ming Chai sat down in his usual place near the front window. He mopped his brow, wet from the exertion of pushing his way through the crowd of passeng- ers. His attention was soon drawr. to the seagulls which were circl- ing overhead, constantly on the watch for food.
He envied them their freedom of movement in the cool fresh air, but after some further thought came to the conclusion that they too had problems in life just as
he had.
Passage Two. Translate the
following passage into English:
夜深了街上祇剩下兩三個个人
III:解:(1)設粉混合
含+水碳酸鈉
之重為W,則Na2CO33重為158-N_ (2)據顯示之原子量:
Na2CO3分子量=2Na+C+3x0.
2x23+12+3x16=106
Na2CO3-10162031572=106+10x(21)
+16)=106 +180=286
(3)每克+水碳酸钠含無水碳酸之
786
743
-143-W + ( 189-w)=9.89 $$s: W=8279 (4)混合物含+水碳酸钠百台車為:
8:279
169
x100%=55:1299%
(芫鉴:A.硝酸铵B.氣氧化亞氮
D.濃硝酸氧化氮 一氧化氮 NH4NO3 + NaOH→→ N&ND; +NHLOH
(A).
NHL NOS
-→NH3↑+H2O
(B.. →N20+2H20
(9)
2NH¢NO3+HISOq->(NH),SOe+2HMGet.
HNO3+S→ 2H2O+6NO2+H2SO4
3CW +8HNO3 →→→→→ 3 Cu (NO 3 ) + Cho
DIL
+2NO
(F)
NO+O2→2NO2
空氣
(F)
-總複習解答完
在深例的北風裡急忙走着。彭先生
正想趕快回家去。正當他把雙手 掙在袋裡,轉入一條横蔥時,黑暗中 忽然明出一個衣衫襤褸的青年他 羞怯地追随着彭先生:求他救濟 先生向袋裡一摸發現自己恰巧沒 有零錢,他掏出了一張百元紙幣,對那 青年說:「來羅,讓我們到那家馆子裡 去,一同飽餐一頓再给您想辦法點』 那青年說:「先生謝謝你的好意,不過. 你看我這樣的打扮怎能隨着你進去 呢
Here is something which the candidates must remember when
they are doing translation. Translation is no magic. It is
to say in words of one language what has been said in another
language. If candidates bear
this in mind, they will find their work much easier.