頁二第張五第 日二月五年岳
̇報日僑華
WAH KIJ YAT PO
六期星
日二月六年三七九一遍公年二十六國民華中 育教儒華
1978
中文中騶會考試題預習專欄
=) (a) = {(x) = px2 + 8x + k
•試證(4)+(8) f(x)-5(4)
m=5.
= P(3-X)
原式可分解為5(x+1)(y+1)(&+)(+++7+8+8x
(三)(b)($).91+02+...+4m+ 為一收歛幾何級數,試證
中中會考高級數學試題
= P(4+8)+9.
同樣+(x)-+(4)_PX2+8x-P.397-K
(S2) Q2 + Q2 + + an 亦為一收歛幾何級數
Bp...
(a)試解下列方程式.
- 4(x+4)(1 + $ ) = exxy
解
4.
(x2 + 2)2 = 2xx?
2(x2+1)=3x4
一
今設(Si)之和為15,(52) 之和為45 試求之值:
=
P (X + Y) + Z
為一收歛幾何級數
7
P(8-X).
amil
By |r1= |an | < | Qn=aro (~_~)
m-t.
黑珠入口袋中後第二次所敗了珠黑 珠仍留工袋之或熟幣為第一0二支
故黑珠在口袋中文或然率為
吉林、黑珠在甲袋中 之或然率為一本吉
試證() (+2)≥aa
(i). (A1 + A2 + A3 + A+) ZQ1 Q2 Q3 Q4,
(ii)在()中,試取q=
你
證
· 2 ( X 2 + y2 ) = - Exy-
2 [ (x+y)2-2xy] =≤ X Y
17 (2) 4x 2(36-219)=5x4
g=8.
(4) Rp 2{(x+4)=-2xy] = -<xy
2=1:10)=8-7-1=0
H=2+(2)=64-14-1=49 亦可用47整除. 假定n=火時,f(k)=8K-7-1 可用49整除
* 8k 1k -1=49M
-7 (k + D): -
(k+1)=8k+1_
= 8.8k -7k -8
# # S2 & r = an (am)<1.
^
故亦為一收歛幾何級數
適用數學歸納法證明.f(x)=8-7121 可被49整除~為正整數..
1-4
an-
可用49整除
Xy=-72
(2) (5) ≤ | X =
2=4"
Y = 4
解:(2)%
(-) (b) zb a=log & b= log
C = log Zo, env), a, b, c k losz
(1)+(3)
2(2) +(3).
相如
a = 3 log 2 - 2 lez 3 ---
log 5-2 log 2-log 3
log 10-log2-2 log2-log
1-3 log 2 - log3:
C = 2 leg 3-log 2 - 1
at = 2
2 Roz 2-1
26+ c
-1-7672
a+26+20=-5.
=8(82-7k-1) + 41 k
= 8(49M) +494=49(8M+K)
之和為15,S2之和為45.
今已知M=1,2時 故知我=34"
f(n)可用49整除, 均可用:49 整除,故保證
225
45=
相除5=
十几
Ex(a) b) 14 (X + Y +8) 5 x 5 y£ g 5 g ma
原式= (-4+4+3)-5-(-)-535- 故消子灶,同理有因子+8,8+x 因原式為五次齊次輪換對稱式,故還有
78} #3 a fol(x2+12+8) +m{X4+48+8x)
*2 (x +7 +8)=-85-15 ge
=(x+^8) (8+8) (8 + x)[ l (x2 + y2+8?)+ m[XY+Y8+8x)]
15=26+ £ X=1, 4-18=0
-52092
·A X=1 Y=13=1
log2=(a+2b+2c)
240=8(31+3m),
BP 10 = 1 fmm
2=号9=5 第八項an=5(言)
(四)有甲乙二袋中袋有黑珠粒紅珠 3粒,2袋有紅珠4粒,若從甲袋中取 我又粒珠放入口袋中再從袋中取出 3.粒珠放回甲袋中求黑珠在甲袋及
袋之或然率:
第一次從甲袋取出2珠,黑珠取
(Ja-Ja1) "No.
Q-2 Ja, Az + Qa zo
(ii)利用(小)之結果
(+94)2
Q2 A3 A4
(1) x (2), (( 9, + Q2 X 93 + Q4 ) ] = a1 A2 As Q4
<< = {a; + A2 + A3+ 9+ ) = ( A1 + Az) Az + Qx) 澳上式比較
A1 taz tas ta+) = Q Q 2 A z Qu
+
31) B2 Qf a taxt as
代入(1)之結果
1+92+a3-
≥90693 (1+2+3)
( Q1 + Q + + Az) => Q, Q2 Q3 ( a + a2 tax).
~~ ( Q; + Q2 + az )3 > Q1 Q2 Q3
“未完,下期續
中中會考高級數學答案
〈五〉欲
張正邦
LEA
4(x + 2);(
(b) a = log
a.blog 2
= làg
(2)(a) C# f(x) = px2 + qx + k
* = [( ) ) = [( 3 ) — { ( x ) = {{P) # p{z=x}
英中會考數學試題
(
((6) (a + a + a + s )
(i) 在()中,請您
(++)"
1及
2 - (30 + 1)x 之部份分式,並試就
- (a + 1)x + ac2
之情形分別討論之
(請將f(x)成之升冪級數,並求展式中之慌
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二跳階,薪水。船與感激所放之仰們您:0。當船向該塔前行∗案,
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運用數學歸納法證明-5(1):87!可被49整除 正繁戳。
01
land
(E). (a). # (x + y + z)°
(b)
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